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GATE Mechanical Engineering Online Test 2, GATE ME Test 2020. Take GATE 2020 Exams Online Test, GATE 2020 Mock Test, GATE 2020 Quiz. GATE Mechanical Engineering Full online mock test paper is free for all students. GATE 2020 ME Series 2 online Test 2020 in English. Take GATE 2020 Mock Test in English from below, GATE Quiz 2020 Series 2. You may also find other Subjects GATE Online Test in this page. Here we provide Graduate Aptitude Test in Engineering Question and Answers 2020. This GATE ME Online test Series 2 is very helpful for exam preparation. The GATE Mechanical Engineering Mock Test 2020 is now available for all candidates, who will be appearing in the national level engineering exams 2020. Now take GATE Mechanical Engineering Online Test Series 2 by Click on Below “Start Quiz Button”
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Load W produces a force of magnitude 120 kN in the member AB of the cantilever truss shown in figure. For this loading, forces in members AE and FE of the truss are
Blocks A and B of masses 40 kg and 60 kg respectively are placed on a smooth surface as shown in figure and the spring connected between them is stretched a distance 2 m. If they are released from rest, the speeds of both blocks the instant the spring becomes unstretched is (Take k = 150 N/m)
A 10 cm long and 5 cm diameter steel rod fits snugly between two rigid walls 10 cm apart at room temperature.
Young’s modulus of elasticity and coefficient of linear expansion of steel are 2 x 10^{6} kgf/cm^{2} and 12 x 10^{– 6} /°C respectively. The stress developed in the rod due to a 100°C rise in temperature will be
A compound train consisting of spur, bevel and spiral gears is shown in the given figure along with the teeth numbers marked against the wheels. Overall speed ratio of the train is
When a system is taken from state A to state B along the path ACB, 180 kJ of the heat flows into the system and it does 130 kJ of work (as shown in the figure below).
How much heat will flow into the system along the path ADB if the work done by it along the path is 40 kJ?
A system of 100 kg mass undergoes a process in which its specific entropy increases from 0.3 kJ/kgK to 0.4 kJ/kgK. At the same time, the entropy of the surroundings decreases from 80 kJ/K to 75 kJ/K.
The process is
The internal energy of a certain system is a function of temperature alone and is given by the formula E = 25 + 0.25t kJ. If this system executes a process in which the work done by it, per degree temperature increase, is 0.75 kNm, then the heat interaction per degree temperature increase, in kJ, is
E = 25+.25t
dE/dt= .25 kj per degree centigrate
and dW/dt = .75 kj per degree centigrate
So from the first law of tbermodynamics
dQ= dE + dW = .25 + .75 = 1.00 kj per degree centigrate
E = 25+.25t
dE/dt= .25 kj per degree centigrate
and dW/dt = .75 kj per degree centigrate
So from the first law of tbermodynamics
dQ= dE + dW = .25 + .75 = 1.00 kj per degree centigrate
The given figure shows the Klein`s construction for acceleration of the slider crank mechanism
Which one of the following quadrilaterals represents the required acceleration diagram?
In the epicyclic gear train shown in the given figure, A is fixed. A has 100 teeth and B has 20 teeth. If the arm C makes three revolutions, the number of revolutions made by B will be
A single block brake is shown in figure. The diameter of the drum is 250 mm and the angle of contact is 90°. If the operating force of 700 N is applied at the end of a lever and the coefficient of friction between the drum and the lining is 0.35, determine the torque that may be transmitted by the block brake.(Give your answer upto 2 decimal places)
Consider a gray and opaque surface at 0°C in an environment at 25°C. The surface has an emissivity of 0.8. If 300 W/m^{2}is the radiation incident on the surface, the radiosity of the surface is
Consider a horizontal 0.7 m wide and 0.85 m long plate in a room at 30°C. Top side of the plate is insulated while the bottom side is maintained at 0°C. The rate of heat transfer from the room air to the plate by natural convection is
(For air, k = 0.02476 W/m °C, Pr = 0.7323, v = 1.47 x 10^{5} m^{2}/s)
Match List I (Cycle operating between fixed temperature limits) with List II (Characteristics of cycles efficiency η temperature) and select the correct answer using the codes given below the lists:
ListI  ListII 
a. Otto cycle  1. η depends only upon temperature limits 
b. Diesel cycle  2. η depends only on pressure limits 
c. Carnot cycle  3. η depends on volume compression ratio 
d. Brayton cycle  4. η depends on cutoff ratio and volume compression ratio 
Consider the data given in the following table:
Given the fact that production in regular and overtime is limited to 650 and 150 respectively, the balance demand of 100 units in the 4^{th} period can be met by
In the 4^{th} period, since regular production is limited to 650 and overtime is limited to 150, the balance demand of 100 units in the 4^{th} period can be met by using regular production in period 1. Demand is only 500 but production capacity in regular period can he increased to 600 to meet the demand.
In the 4^{th} period, since regular production is limited to 650 and overtime is limited to 150, the balance demand of 100 units in the 4^{th} period can be met by using regular production in period 1. Demand is only 500 but production capacity in regular period can he increased to 600 to meet the demand.
Time estimates of an activity in a PERT network are optimistic time t_{o} = 9 days; pessimistic time t_{p} = 21 days and most likely time t_{m }= 15 days. The approximate probability of completion of this activity in 13 days is
The design specifications of a 2 m long solid circular transmission shaft require that the angle of twist of the shaft not exceed 3° when a torque of 9 kNm is applied.
Which of the following is the required diameter of the shaft if the shaft is made of a steel with an allowable shearing stress of 90 MPa and a modulus of rigidity of 77 GPa?(Give your answer to the nearest 1 decimal place.)
The design specifications of a 2 in long solid circular transmission shaft require that the angle of twist of the shaft not exceed 3° when a torque of 9 kNm is applied.
Which of the following is the required diameter of the shaft if the shaft is made of a brass with an allowable shearing stress of 35 MPa and a modulus of rigidity of 42 GPa?
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pressure gage reads 210 kPa. The volume of the tire is 0.025 m^{3} and the atmospheric pressure is 100 kPa.
What will be the pressure rise in the tire when the air temperature in the tire rises to 50°C?
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pressure gage reads 210 kPa. The volume of the tire is 0.025 m^{3} and the atmospheric pressure is 100 kPa.
The amount of air that must he bled off to restore pressure to its original value at this temperature, is
A uniform rectangular rod having the crosssection of 0.17 m x 0.31 m is shown in figure:
The specific weight of the rectangular rod in kN/m^{3 }will be
(Calculate the approximate answer upto 2 decimal places.)
A uniform rectangular rod having the crosssection of 0.17 m x 0.31 m is shown in figure.
What will be the tension in string?
(Give your answer in whole number and in newtons.)
A cold rolled steel cup with an inside radius of 30 mm and a thickness of 3 mm is to be drawn from a blank of diameter 40 mm. The shear yield stress and the maximum allowable stress of the material can be taken as 210 N/mm^{2} and 600 N/mm^{2} respectively.
What will be the drawing force, if the coefficient of friction µ = 0.1 and β = 0.05?
A cold rolled steel cup with an inside radius of 30 mm and a thickness of 3 mm is to be drawn from a blank of diameter 40 mm. The shear yield stress and the maximum allowable stress of the material can be taken as 210 N/mm^{2} and 600 N/mm^{2} respectively.
What will be the minimum possible radius of the cup which can he drawn from the given blank without causing a fracture?
Let N = 1421 x 1423 x 1425. What is the remainder when N is divided by 12?
When we divide N by 12, the remainder for the expression will be the same as the remainder for 5 x 7 x 9. Now 35 x 9, when divided by 12, we get the remainder 11 x 9 = 99. Finally divided it by 12, we get the reminder of N as 3.
When we divide N by 12, the remainder for the expression will be the same as the remainder for 5 x 7 x 9. Now 35 x 9, when divided by 12, we get the remainder 11 x 9 = 99. Finally divided it by 12, we get the reminder of N as 3.
There are 60 students in a class. These students are divided into three groups A, B and C of 15, 20 and 25 students each. The groups A and C are combined to form group D. What is the average weight of the students in group D?
There is no indication of weights of the students in the question, i.e. groups A, B and C. Therefore, it is not possible to find the relation between the groups A, B, C and D.
There is no indication of weights of the students in the question, i.e. groups A, B and C. Therefore, it is not possible to find the relation between the groups A, B, C and D.
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GATE Mechanical Engineering Online Test Series 1, GATE ME Online Test 2020. GATE 2020 Online Test, GATE Mechanical Engineering Full online mock test paper is free for all students. GATE 2020 ME online Test 2020 Series 1 in English. GATE Mechanical Engineering Full online mock test paper is free for all students. Take GATE 2020 Mock Test in English from below, GATE Quiz 2020 Series 1. You may also find other Subjects GATE Online Test in this page. Here we provide Graduate Aptitude Test in Engineering Question and Answers 2020. This GATE ME Online test Series 1 is very helpful for exam preparation. The GATE Mechanical Engineering Mock Test 2020 is now available for all candidates, who will be appearing in the national level engineering exams 2020. Now take GATE Mechanical Engineering Online Test Series 1 by Click on Below “Start Quiz Button”
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If f (x) = x, then
If y = log (x + √1+ x^{2}), then (1 + x)^{2 } is equal to
Given that u = e^{xyz}_{. }The is equal to
For the truss shown in the figure, the zero force members are
Consider joint D, for the truss shown in the figure. We assume force F_{1} in member DC, F_{2} in member DA and F_{3} in member DF. This joint is unloaded and the forces F_{2} and F_{3} are collinear. So, F_{1} must be zero. Similarly, forces in the members EF and HG are zero.
Consider joint D, for the truss shown in the figure. We assume force F_{1} in member DC, F_{2} in member DA and F_{3} in member DF. This joint is unloaded and the forces F_{2} and F_{3} are collinear. So, F_{1} must be zero. Similarly, forces in the members EF and HG are zero.
If shaft made from ductile material is subjected to combined bending and twisting moments. Which one of the following failure theories would give the most conservative value?
Most consecutive value means safest design i.e. largest diameter. For ductile material, maximum shear stresses of theory gives higher value of diameter.
Most consecutive value means safest design i.e. largest diameter. For ductile material, maximum shear stresses of theory gives higher value of diameter.
Match List I with List II and select the correct answer using the codes given below the lists:
List – I  List – II 
a. Interference  1. Arc of approach, arc of recess, circular pitch 
b. Dynamic load on tooth  2. Lewis equation 
c. Static load  3. Minimum number of teeth on pinion 
d. Contact ratio  4. Inaccuracies in tooth profile 
Match List I (Fluid properties) with List II (Relate terms) and select the correct answer using the codes given below the lists:
List – I  List – II 
a. Capillarity  1. Cavitation 
b. Vapour pressure  2. Density of water 
c. Viscosity  3. Shear stress 
d. Specific gravity  4. Surface tension 
Capillarity—————–> Surface tension Vapour pressure————–> cavitation
Viscosity———————> Shear stress Specific gravity—————> Density of water
Capillarity—————–> Surface tension Vapour pressure————–> cavitation
Viscosity———————> Shear stress Specific gravity—————> Density of water
The heat conduction equation in a medium is given in its simplest form as Select the wrong statement below.
The _______ number is a significant dimensionless parameter for forced parameter convection and the _______ number is a significant dimensionless for natural convection.
The Reynolds number is a significant dimensionless parameter for forced parameter convection and the Grashof number is a significant dimensionless of natural convection.
The Reynolds number is a significant dimensionless parameter for forced parameter convection and the Grashof number is a significant dimensionless of natural convection.
The marking on a grinding wheel is `51 A 36 L 5 V 93`. The code `36` represents the
To reduce consumption of synthetic resins, the ingredient added is
To reduce the consumption of synthetic resins, the ingredient added is filler. Because of their low cost, fillers are important in reducing the overall cost of polymers. Fillers may also improve the strength, hardness, toughness, abrasive resistance, dimensional stability, etc.
To reduce the consumption of synthetic resins, the ingredient added is filler. Because of their low cost, fillers are important in reducing the overall cost of polymers. Fillers may also improve the strength, hardness, toughness, abrasive resistance, dimensional stability, etc.
The compositions of some of the alloy steels are as under:
1. 18W 4Cr 1V 2. 12Mo 1W 4Cr 1V
3. 6Mo 6W 4Cr 1V 4. 18W 8Cr 1V
The compositions of commonly used high speed steels would include
The composition of commonly used high speed steels include 18W 4Cr 1V and 18W 8Cr 1V
The composition of commonly used high speed steels include 18W 4Cr 1V and 18W 8Cr 1V
Major operations in the manufacture of steel balls used for Ball bearings are given below:
1. oil lapping 2. cold heading 3. Annealing 4. Hardening 5. Rough grinding
The correct sequence of these operations is
The correct sequence of these operations is
1. Cold heading 2. Annealing 3. Hardening 4. Rough grinding 5. Oil lapping
The correct sequence of these operations is
1. Cold heading 2. Annealing 3. Hardening 4. Rough grinding 5. Oil lapping
Chills are used in moulds to
A chill is an object used to promote solidification in a specific portion of a metal casting mould. Normally the metal in the mould cools at a certain rate relative to thickness of casting. When the geometry of the moulding cavity prevents directional solidification from occurring naturally, a chill can be placed to help promote it.
A chill is an object used to promote solidification in a specific portion of a metal casting mould. Normally the metal in the mould cools at a certain rate relative to thickness of casting. When the geometry of the moulding cavity prevents directional solidification from occurring naturally, a chill can be placed to help promote it.
Carburised machine components have higher endurance limit, because carburization
Carburizing or Carburization is a heat treatment process by which carbon is introduced into a metal.
Carburization can be used to increase the surface hardness of low carbon steal. Because of carburization a compressive layer is produced on the surface which increase the hardness of the metal.
Carburizing or Carburization is a heat treatment process by which carbon is introduced into a metal.
Carburization can be used to increase the surface hardness of low carbon steal. Because of carburization a compressive layer is produced on the surface which increase the hardness of the metal.
At 100% relative humidity, the wet bulb temperature is
The thermodynamic parameters are
1. Temperature 2. Specific volume
3. Pressure 4. Enthalpy 5. Entropy
The Clapeyron Equation of state provides relationship between
The clapeyron equation dP/dT = entropy change/volume change This equation states that the slope of an univariant equilibrium plotted on a PT diagram is equal to the entropy change of the reaction divided by the volume change of the reaction.
The clapeyron equation dP/dT = entropy change/volume change This equation states that the slope of an univariant equilibrium plotted on a PT diagram is equal to the entropy change of the reaction divided by the volume change of the reaction.
Gibb`s free energy G is defined as
The solution in a transportation model (of dimension m x n) is said to be degenerate if it has
In a TP, if the number of nonnegative independent allocations is less than m + n – 1, there exists degeneracy.
In a TP, if the number of nonnegative independent allocations is less than m + n – 1, there exists degeneracy.
The management is interested to know the percentage of idle time of equipment. The trial study showed that percentage of idle time would he 20%. The number of random observations necessary for 95% level of confidence and +5% accuracy is
The series 1 + 2 + 3 + ……. + n +…. is
If V is a differentiable vector function and f is a sufficient differentiable scalar function, then curl (fV) is equal to
If r = xi + yj + zk is the position vector of point P (x, y, z) and r = r then ∇. r^{n}r is equal to
A side and face cutter of 127 mm diameter has 10 teeth. It operates at a cutting speed of 13.5 in/mm and table feed of 108 mm/mm. The maximum chip thickness for a cutting depth of 5 mm, is
The principal cutting edge is 75°, while the auxiliary (end) cutting edge is 8°. Assume 6° clearance angle, inclination angle as – 5°, and the shank as 30 x 30 mm. What will be the side rake and back rake?
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The basic idea is to let the beginners understand the operation of the Digital system and many other systems based on the principles of Digital Techniques. Any device working under Digital Techniques are called Digital Systems and the Electronic Network used to make them operational are called Digital Circuits. The subject as a whole is often referred as Modern Digital Electronics.
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Shown in the figure are the velocity time graphs of the two particles P_{1} and P_{2} moving in same straight line in same direction. Which of the following statements about their relative motion is true?
Their relative velocity
a = slope of vt graph.
a_{1} > a_{2}
v_{r} = v_{1} – v_{2} = a_{1}t – a_{2}t = (a_{1} – a_{2})t
∴ v_{r} ∝ t
a = slope of vt graph.
a_{1} > a_{2}
v_{r} = v_{1} – v_{2} = a_{1}t – a_{2}t = (a_{1} – a_{2})t
∴ v_{r} ∝ t
The displacementtime graph of a moving particle is shown below. The instantaneous velocity of the particle is negative at the point
Slope is negative at the point E.
Slope is negative at the point E.
A man is crossing a river flowing with velocity of 5 m/s. he reaches a point directly across at a distance of 60 m in 5 sec. his velocity in still water should be
A body starts from rest and is uniformly accelerated for 30s. the distance travelled in the first 10 s is x_{1}, next 10 s is x_{2} and the last 10 s is x_{3}.
Then, x_{1} ; x_{2} ; x_{3} is
x_{1} = 1/2 a(10)^{2 }= 50a
x_{2} = 1/2 a(20)^{2} – 1/2 (a) (10)^{2} = 150a
x_{3} = 1/2 a(30)^{2} – 1/2 a (20)^{2} = 250a
∴ x_{1} : x_{2} : x_{3} = 1 : 3 : 5.
x_{1} = 1/2 a(10)^{2 }= 50a
x_{2} = 1/2 a(20)^{2} – 1/2 (a) (10)^{2} = 150a
x_{3} = 1/2 a(30)^{2} – 1/2 a (20)^{2} = 250a
∴ x_{1} : x_{2} : x_{3} = 1 : 3 : 5.
Two cars start off to race with velocities 4 m/s and 2 m/s and travel in straight line with uniform accelerations 1 m/s^{2} and 2 m/s^{2} respectively. if they reach the final point at the same instant, then the length of the path is
s = 4t +1/2 (1)t^{2}= 2t +1/2(2) t^{2}
Or 4t + 0.5t^{2} = 2t + t^{2}
Or = 2t or t = 0
And t = 4s
∴ s = (4) (4) + 1/2 (1) (4)^{2} = 16 + 8 = 24 m
s = 4t +1/2 (1)t^{2}= 2t +1/2(2) t^{2}
Or 4t + 0.5t^{2} = 2t + t^{2}
Or = 2t or t = 0
And t = 4s
∴ s = (4) (4) + 1/2 (1) (4)^{2} = 16 + 8 = 24 m
The velocitytime graph of a particle in onedimensional motion is shown in figure. Which of the following formulae are correct for describing the motion of the particle over the time interval t1 to t2.
The slope of the given graph over the time interval t_{1} to t_{2} is not constant and is not uniform. It means acceleration is not constant and is not uniform, therefore relations (a), (b), (e) are not correct which is for uniform accelerated motion, but relations (c), (d) and (f) are correct, because these relation are true for both uniform or nonuniform accelerated motion.
The slope of the given graph over the time interval t_{1} to t_{2} is not constant and is not uniform. It means acceleration is not constant and is not uniform, therefore relations (a), (b), (e) are not correct which is for uniform accelerated motion, but relations (c), (d) and (f) are correct, because these relation are true for both uniform or nonuniform accelerated motion.
A ball projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6s and the ball reaches the ground after 12s. the height of the tower is (g = 10 m/s^{2})
t_{BC} = 6/2 = 3s
t_{AC} = 12/2 = 6s
∴ t_{AB} = 3 s
∴ 0 = u – (10)6
or u = 60 m/s
Further h = ut_{AB} –1/2 gt^{2}_{AB}
= (60) (3) – 1/2 (10)(3)^{2} = 135 m
t_{BC} = 6/2 = 3s
t_{AC} = 12/2 = 6s
∴ t_{AB} = 3 s
∴ 0 = u – (10)6
or u = 60 m/s
Further h = ut_{AB} –1/2 gt^{2}_{AB}
= (60) (3) – 1/2 (10)(3)^{2} = 135 m
A stone is projected from ground. Its path is as shown in figure. At which point its speed is decreasing at fastest rate?
Rate of decrease of speed = g cos θ
q is minimum at A. therefore speed is decreasing at fastest rate at A.
Rate of decrease of speed = g cos θ
q is minimum at A. therefore speed is decreasing at fastest rate at A.
Ball A is dropped from the top of a building. At the same instant ball B is thrown vertically upwards from the ground. When the balls collide, they are moving in opposite directions and the speed of A is twice the speed of B. At what fraction of the height of the building did the collision occur?
Let h be the total height and x the desired fraction. Initial velocity of ball is u and at time of collision it is v_{B}. Then,
Let h be the total height and x the desired fraction. Initial velocity of ball is u and at time of collision it is v_{B}. Then,
A large rectangular box moves vertically downward with an acceleration a. A toy gun fixed at A and aimed towards C fires a particle P.
(A) if a = g then relative acceleration to P will be zero. So path is straight line along PC.
(B) If a > g, then relative acceleration of P is upwards. therefore path of P with respect to box is as shown in figure.
So particle may hit AB or BC depending on the speed of P.
(C) If a < g, then relative acceleration of P is downwards. Therefore path of P with respect to box is as shown in figure.
So, the particle may hit CD or AD depending upon the speed of P.
(A) if a = g then relative acceleration to P will be zero. So path is straight line along PC.
(B) If a > g, then relative acceleration of P is upwards. therefore path of P with respect to box is as shown in figure.
So particle may hit AB or BC depending on the speed of P.
(C) If a < g, then relative acceleration of P is downwards. Therefore path of P with respect to box is as shown in figure.
So, the particle may hit CD or AD depending upon the speed of P.
A body released from great height falls freely towards the earth. Another body is released from the same height exactly one second later. The separation between the two bodies two second after the release of the second body is
As, ∆x = 1/2gt^{2} – 1/2 g (t – 1) ^{2}
= 1/2 g [ (t – 1)^{2}] = 1/2 g (2t – 1)
= 1/2 × 9.8× 5 m = 24.5 m
As, ∆x = 1/2gt^{2} – 1/2 g (t – 1) ^{2}
= 1/2 g [ (t – 1)^{2}] = 1/2 g (2t – 1)
= 1/2 × 9.8× 5 m = 24.5 m
A 120 m long train is moving in a direction with speed 20 m/s. a train moving with 30 m/s in the opposite direction and 130 m long crosses the first train in a time.
Total distance = 130 + 120 = 250 m
Relative velocity = 30 – ( 20) = 50 m/s
Here, 250/50 = 5 s
Total distance = 130 + 120 = 250 m
Relative velocity = 30 – ( 20) = 50 m/s
Here, 250/50 = 5 s
Rain drops fall vertically at a speed of 20 ms^{1}. At what angle do they fall on the wind screen of a car moving with a velocity of 15 ms^{1}, if the wind screen velocity inclined at an angle of 23º to the vertical?
Let the required angle is q.
tan (90^{0} – θ) = 20/15
∴ cot θ = 20/15 = 4/3
⇒ θ = 37^{0}
∴ θ = 37^{0} + 23^{0} = 60^{0}
Let the required angle is q.
tan (90^{0} – θ) = 20/15
∴ cot θ = 20/15 = 4/3
⇒ θ = 37^{0}
∴ θ = 37^{0} + 23^{0} = 60^{0}
At t = 0 projectile is fired from a point O (taken as origin) on the ground with a speed of 50 m/s at an angle of 53^{0} with the horizontal. it just passes two points A and B each at height 75 m above horizontal.
The horizontal separation between the points A and B is
Solving this equation we get.
x_{1} = 90m and x_{2} = 150 m
∴ AB = x_{2} – x_{1} = 60 m
Solving this equation we get.
x_{1} = 90m and x_{2} = 150 m
∴ AB = x_{2} – x_{1} = 60 m
The distance between two particles moving towards each other is decreasing at the rate of 6 m/s. if these particle travel with same speed and in the same direction then the separation increase at the rate of 4 m/s. the particles have speed as
when two particles moves towards each other, then v_{1} + v_{2} = 6 … (i)
When these particles moves in the same direction, then v_{1} – v_{2} = 4 … (ii)
By solving Eqs. (i) and (ii), we get v_{1} = 5 and v_{2} = 1 m/s
when two particles moves towards each other, then v_{1} + v_{2} = 6 … (i)
When these particles moves in the same direction, then v_{1} – v_{2} = 4 … (ii)
By solving Eqs. (i) and (ii), we get v_{1} = 5 and v_{2} = 1 m/s
A man can swim with a speed of 4 km/h in still water. How long does he take to cross a river 1 km wide, if the river flows steadily 3 km/h and he makes his strokes normal to the river current. How far down the river does he go when he reaches the other bank?
Given, speed of man (v_{m}) = 4 km/h
Speed of river (v_{r}) = 3 km/h
Width of the river (d) = 1 km
Time taken by the man to cross the river
distance travelled along the river = v_{r} × t = 3 ×1/4 = 3/4km = 3000/4 = 750 m
Given, speed of man (v_{m}) = 4 km/h
Speed of river (v_{r}) = 3 km/h
Width of the river (d) = 1 km
Time taken by the man to cross the river
distance travelled along the river = v_{r} × t = 3 ×1/4 = 3/4km = 3000/4 = 750 m
Two particles ‘A’ and ‘B’ are projected in a vertical plane with initial velocities having same magnitude u from points (0, 0) and (l, – h) at t = 0. The xaxis is horizontal and yaxis is vertical as shown.
The path of particle ‘A’ with respect to particle ‘B’ will be
Accelerations of both are same. Therefore relative acceleration between two is zero.
Further, vertical components of velocities of both are also same. Therefore, relative velocity in vertical direction is also zero.
Hence, the relative motion of A with respect to B is a straight line parallel to xaxis.
Accelerations of both are same. Therefore relative acceleration between two is zero.
Further, vertical components of velocities of both are also same. Therefore, relative velocity in vertical direction is also zero.
Hence, the relative motion of A with respect to B is a straight line parallel to xaxis.
Starting from rest a particle moves in a straight line with acceleration a = {2 + t – 2} m/s^{2}. Velocity of particle at the end of 4 s will be
Acceleration can be written as
a = 2 + 2 – t
or a = 4 – t for t < 2 s
and a = 2 + t – 2 or at = t for t > 2 s
therefore acceleration – time graph of the particle will be as shown below
Now since, dv = a dt
v_{f} – v_{i} = area under at graph
or v_{f} – 0 = (4 × 4) – 1/2 (4)(2) = 12 m/s
or velocity of particle at the end of 4 s is 12 m/s.
Acceleration can be written as
a = 2 + 2 – t
or a = 4 – t for t < 2 s
and a = 2 + t – 2 or at = t for t > 2 s
therefore acceleration – time graph of the particle will be as shown below
Now since, dv = a dt
v_{f} – v_{i} = area under at graph
or v_{f} – 0 = (4 × 4) – 1/2 (4)(2) = 12 m/s
or velocity of particle at the end of 4 s is 12 m/s.
In projectile motion, the modulus of rate of change of speed
Rate of change of speed = g cos θ
 cos θ  first decrease then increases.
Rate of change of speed = g cos θ
 cos θ  first decrease then increases.
A particle is moving along xaxis with constant acceleration. At t = 0, the particle is at x = 3 m and dx/dt m/s. The maximum value of x coordinate of the particle is observed 2 second later. Starting from t = 0 sec, after what time particle reaches its initial position again?
t_{AB} = t_{BA} = 2 second.
Therefore total time is, 2 + 2 = 4 s.
t_{AB} = t_{BA} = 2 second.
Therefore total time is, 2 + 2 = 4 s.
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A river model is constructed to a horizontal scale of 1:1000 and a vertical scale of 1:100. If the model discharge were 0.1 m^{3}/s, then the discharge in the river (in m^{3}/s) would be:
Correct Answer : 10^{5}
Correct Answer : 10^{5}
For an overhang beam as shown in the figure, R_{B} and R_{D} are
= 0; – 70 × 2 – 20 × 11 + R_{D }× 6 = 0R_{D} = 60 kN
+ RB + RD – 70 – 20 = 0
R_{B} = 30 kN
= 0; – 70 × 2 – 20 × 11 + R_{D }× 6 = 0R_{D} = 60 kN
+ RB + RD – 70 – 20 = 0
R_{B} = 30 kN
A twodimensional stress system has like stresses σ_{x }= 100 N/mm^{2} and σ_{y }= 200 N/mm^{2 }in two mutually perpendicular directions. The x, y coordinates of the centre of the Mohr’s circle are
Here, σ_{x}= 100 N/mm^{2}
σ_{y }= 200 N/mm^{2}
∴ Centre = = (150, 0)
Here, σ_{x}= 100 N/mm^{2}
σ_{y }= 200 N/mm^{2}
∴ Centre = = (150, 0)
The integral is equal to
The plastic modulus of a section is 4.8 x 10^{–3} m^{3}. The shape factor is 1.2. The plastic moment capacity of the section is 120 KNm. The yield stress of the material is
A 4 m high column is effectively held in position at both ends and restrained against rotation at one end. Its diameter is restricted to 400 mm. If it is required to carry a factored axial load of 1500 kN, then the reinforcement is
Column I gives a list of test methods for evaluating properties of concrete and Column II gives their list of properties :
Column I  Column II 
P. Resonant frequency test  1. Tensile strength 
Q. Rebound hammer test  2. Dynamic modulus of elasticity 
R. Split cylinder test  3. Workability 
S. Compacting factor test  4. Compressive strength 
The correct match of the tests with their respective properties is
Correct Answer : P – 2, Q – 4, R – 1, S – 3
Correct Answer : P – 2, Q – 4, R – 1, S – 3
A parabolic curve is used to connect a 5% upgrade with 4% downgrade as shown in figure. The highest point on the summit is at a distance of
(measured horizontally from the first tangent point – FTP)
Caculate your answer upto 2 decimal places.
The highest point on the summit curve is a distance Lh_{1 }/n from the FTP on the first grade n_{1 }
Lh1 /n from the FTP on the first grade n_{1 }= 150 x 5/5(4) = 150 x
The highest point on the summit curve is a distance Lh_{1 }/n from the FTP on the first grade n_{1 }
Lh1 /n from the FTP on the first grade n_{1 }= 150 x 5/5(4) = 150 x
A vehicle travelling at 40 kmph was stopped within 1.8 seconds after the application of brakes. The retardation of vehicle is(Calculate the answer to nearest 2 decimal places.)
T = 1.8 s
V = u + at
0 = 11.11 + a × 1.8
a = – 6.17 m/s^{2}
T = 1.8 s
V = u + at
0 = 11.11 + a × 1.8
a = – 6.17 m/s^{2}
Directions: Examine the given two statements carefully and select the answer using the codes given below.
Assertion A: Break point chlorination ensures a residual of free available chlorine.
Reason R: A super high chlorine dose inactivates the pathogens in a very short time.
Correct Answer : Both A and R are individually true, but R is not the correct explanation of A.
Correct Answer : Both A and R are individually true, but R is not the correct explanation of A.
At a point in a piece of stressed material the stresses are as follows:
tensile (normal)
(shearing)
Although the value of (α+β) is not known yet the principal stresses are equal to each other being (5 kN/m^{2}) . What is the radius of Mohr’s circle?
Radius of Mohr’s cycle = 0
Because principle stress are equal to each other being 5 KN per square meter
So r = (55)/2 = 0
Radius of Mohr’s cycle = 0
Because principle stress are equal to each other being 5 KN per square meter
So r = (55)/2 = 0
Directions: Read the following information and answer the given question.
Normal annual precipitation at station X = 700 mm
Normal annual precipitation at station A = 1000 mm
Normal annual precipitation at station B = 900 mm
Normal annual precipitation at station C = 800 mm
Storm precipitation at station A = 100 mm
Storm precipitation at station B = 90 mm
Storm precipitation at station C = 80 mm
Calculate the storm precipitation at station X.
A tank and a deflector are placed on a frictionless trolley. The tank issues water jet (mass density of water = 1 000 kg/m^{3}), which strikes the deflector and turns by 45°. If the velocity of jet leaving the deflector is 4 m/s and discharge is 0.1 m^{3}/s, the force recorded by the spring will be
Correct Answer : 200 √2 N
Correct Answer : 200 √2 N
A fluid jet discharging from a 40 mm diameter orifice has a diameter 30 mm at its vena contracta. Assume the coefficient of velocity to be 0.98. Determine the coefficient of discharge for the orifice.
C_{d} = C_{c} × C_{v}
∴ C_{D }= (3/4)^{2 }× 0.98.
C_{d} = C_{c} × C_{v}
∴ C_{D }= (3/4)^{2 }× 0.98.
A = and I = , , the value of A^{3} is
Correct Answer : 19A + 30I
Correct Answer : 19A + 30I
The equation x^{3} x^{2} + 4x – 4 = 0 is to be solved using the NewtonRaphson method. If x = 2 is taken as the initial approximation of the solution, the next approximation using this method will be
If a^{n} =
Then to compute a^{27}, the minimum number of multiplications and squaring required respectively are
Correct Answer : 4 and 3
Correct Answer : 4 and 3
If a^{2} + b^{2 }+ c^{2} = 0 then value of
We have a^{2} + b^{2 }+ c^{2} = 0
⇒ = = a^{2} b^{2} c^{2 } = a^{2} b^{2} c^{2 } = 4 a^{2} b^{2} c^{2}
We have a^{2} + b^{2 }+ c^{2} = 0
⇒ = = a^{2} b^{2} c^{2 } = a^{2} b^{2} c^{2 } = 4 a^{2} b^{2} c^{2}
Directions: In the question, a sentence has been divided into 4 parts and labelled (A), (B), (C) and (D). The sentence contains either a single error or no error at all. The error, if there is one, is in underlined and lettered part. If the sentence contains an error, select the one underlined part that must be changed to make the sentence correct and mark it as your answer. If the sentence is correct, select choice (D) as your answer. In choosing answers, follow the requirements of standard written English.
(A) Everyone admired the (B) golden brown colour of (C) his hairs. (D) No error
‘Hair’. The noun ‘hair’ is always used in the same form for both singular and plural purposes.
‘Hair’. The noun ‘hair’ is always used in the same form for both singular and plural purposes.
Directions: Choose the appropriate option for the blank, so as to make the sentence grammatically correct.
A high percentage of people ____ still trapped in superstitions.
Percentage is a singular noun and requires the singular form of the verb.
Percentage is a singular noun and requires the singular form of the verb.
One of the four words given in the four options does not fit the set of words. The odd word from the group, is
Correct Answer : coal
Correct Answer : coal
Directions: Choose the opposite of the word given below from the options.
Unpretentious
Correct Answer : Flaunting
Correct Answer : Flaunting
Directions: Choose the word or set of words for each blank that best fits the meaning of the sentence as a whole.
The ___________ ‘where there is a will, there is a way’ is the most used ___________.
It is understood that both the words have to be somewhat similar in meaning. The only option which holds this relation is option (1).
It is understood that both the words have to be somewhat similar in meaning. The only option which holds this relation is option (1).
A bottle of whisky contains 3/4 of whisky and the rest water. How much of the mixture must be taken away and substituted by equal quantity of water to have half whisky and half water?
Percentage of whisky in mixture = 75%
Percentage of whisky in water = 0%
Therefore, mixture and water should be mixed in the ratio 2 : 1 or we need to replace 1/3^{rd} of the mixture with water.
Percentage of whisky in mixture = 75%
Percentage of whisky in water = 0%
Therefore, mixture and water should be mixed in the ratio 2 : 1 or we need to replace 1/3^{rd} of the mixture with water.
In a class of 33 students, 20 play cricket, 25 play football, and 18 play volleyball. Also, 15 play both cricket and football, 12 play football and volleyball, 10 play cricket and volleyball. If each student plays atleast one game, find the number of students who play only cricket.
Let C, F and V denote the set of number of students who play cricket, football and volleyball respectively. Therefore, n(C) = 20, n(F) = 25, n(V) = 18
Let x represent the students who play all the three games. From above, we get (x – 5) + (x – 4) + (x – 2) + (15 – x) + (12 – x) + (10 – x) + x = 33
x = 7
The number of students who play cricket only is 7 – 5 = 2
Let C, F and V denote the set of number of students who play cricket, football and volleyball respectively. Therefore, n(C) = 20, n(F) = 25, n(V) = 18
Let x represent the students who play all the three games. From above, we get (x – 5) + (x – 4) + (x – 2) + (15 – x) + (12 – x) + (10 – x) + x = 33
x = 7
The number of students who play cricket only is 7 – 5 = 2
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Mechanical Engineering Mechanics Online Test. The Mechanical Engineering Full online mock test paper is free for all students and Very Helpful for Exam Preparation. Mechanical Engineering Question and Answers in English. Mechanical Engineering Online Mock test for Mechanical Engineering Mechanics Topic. Here we are providing Mechanical Engineering Mechanics Online Test Series in English. Check Mechanical Engineering Mock Test Series 2020.
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According to principle of conservation of energy, the total momentum of a system of masses in any direction remains constant unless acted upon by an external force in that direction.
The friction experienced by a body, when in motion, is known as
Two balls of equal mass and of perfectly elastic material are lying on the floor. One of the ball with velocity v is made to struck the second ball. Both the balls after impact will move with a velocity
The term ‘force’ may be defined as an agent which produces or tends to produce, destroys or tends to destroy motion.
The coefficient of restitution for elastic bodies is one.
The velocity ratio in case of an inclined plane inclined at angle θ to the horizontal and weight being pulled up the inclined plane by vertical effort is
The range of projectile on a downward inclined plane is __________ the range on upward inclined plane for the same velocity of projection and angle of projection.
The angle of inclination of a vehicle when moving along a circular path __________ upon its mass.
A body of weight W is required to move up on rough inclined plane whose angle of inclination with the horizontal is α. The effort applied parallel to the plane is given by(where μ = tanφ = Coefficient of friction between the plane and the body.)
If the resultant of two equal forces has the same magnitude as either of the forces, then the angle between the two forces is
A smooth cylinder lying on its convex surface remains in __________ equilibrium.
Coefficient of friction is the ratio of the limiting friction to the normal reaction between the two bodies.
The total time taken by a projectile to reach maximum height and to return back to the ground, is known as time of flight.
The range of a projectile is maximum, when the angle of projection is
The mechanical advantage of a lifting machine is the ratio of
Static friction is always __________ dynamic friction.
A body will begin to move down an inclined plane if the angle of inclination of the plane is __________ the angle of friction.
When a particle moves along a circular path with uniform velocity, there will be no tangential acceleration.
The bodies which rebound after impact are called
The maximum frictional force, which comes into play, when a body just begins to slide over the surface of the other body, is known as
The distance, between the point of projection and the point where the projectile strikes the ground, is known as range.
The algebraic sum of the resolved parts of a number of forces in a given direction is equal to the resolved part of their resultant in the same direction. This is known as
The triangle law of forces states that if two forces acting simultaneously on a particle, be represented in magnitude and direction by the two sides of a triangle taken in order, then their resultant may be represented in magnitude and direction by the third side of a triangle, taken in opposite order.
The angle between two forces when the resultant is maximum and minimum respectively are
The path of the projectile is a parabola.
A redundant frame is also called __________ frame.
A resultant force is a single force which produces the same effect as produced by all the given forces acting on a body.
When a rigid body is suspended vertically, and it oscillates with a small amplitude under the action of the force of gravity, the body is known as
If two blocks of equal mass are attached to the two ends of a light string and one of the blocks is placed over a smooth horizontal plane while the other is hung freely after passing over a smooth pulley, then the two blocks will have some motion.
During elastic impact, the relative velocity of the two bodies after impact is __________ the relative velocity of the two bodies before impact.
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GATE Electrical Engineering Online Test 2, GATE EE Test 2020 Series 2. GATE Electrical Engineering Full online mock test paper is free for all students. GATE 2020 EE online Test 2020 Series 2 in English. GATE Electrical Engineering Full online mock test paper is free for all students. Take GATE 2020 Mock Test in English from below, GATE Quiz 2020 Series 2. You may also find other Subjects GATE Online Test in this page. Here we provide Graduate Aptitude Test in Engineering Question and Answers 2020. This GATE EE Online test Series 2 is very helpful for exam preparation. The GATE Electrical Engineering Mock Test 2020 is now available for all candidates, who will be appearing in the national level engineering exams 2020. Now take GATE Electrical Engineering Online Test Series 2 by Click on Below “Start Quiz Button”
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When two wattmeters W_{1} and W_{2} are used to measure power input to a synchronous motor, each of them indicates 60 kW. If the power factor is to be changed to 0.866 leading, keeping the total input power same, the reading of W_{1}and W_{2} are respectively
Consider the following circuit and input voltage to
Consider the following circuit and input voltage to
Consider a circuit shown in figure. The circuit functions as
For a 50 MVA, 11 kV, threephase synchronous generator, it is given that threephase fault current is 2000 A and line to line fault current is 2600 A. The generator neutral is solidly grounded. The per unit value of negative sequence reactance of the generator is
A DT system has the following inputoutput relationship:
Consider the following properties:
P_{1}: System is linear.
P_{2}: System is causal.
P_{3}: System is invertible.
Which of the above properties is/are possessed by the system?
Correct Answer : Only P_{2}
Correct Answer : Only P_{2}
A 10 kW, 250 V shunt generator, having an armature resistance of 0.1 Ω and a field resistance of 250 Ω, delivers fullload at rated voltage and 800 rpm. The machine is now run as a motor while taking 10 kW at 250 V. What is the speed of the motor?
The AC bridge shown in the figure is used to measure an unknown inductance connected in CD arm. The bridge can be balanced by
A bipolar amplifier circuit shown below, exhibits the following characteristics:
An electron with velocity V = (3u_{x} + 12u_{y} − 4u_{z}) x 105 m/s experiences no net forces at a point in a magnetic field B = u_{x} + 2u_{y} + 3u_{z} nWb/m^{2}. The electric field E at that point is
Correct Answer : − 4.4u_{x} + 1.3u_{y} + 0.6u_{z} kV/m
Correct Answer : − 4.4u_{x} + 1.3u_{y} + 0.6u_{z} kV/m
Consider the following 8085 instruction:
XRA  A 
MVIB,  4AH 
SUI  4FH 
ANA  B 
HLT 
The contents of register A and B are respectively
A singlephase full bridge voltage source inverter feeds a load as shown in figure. If the load current is I0 = 540 sin ( ωt− 45°), and the V (dc )= 300. The power delivered to the load is
In the circuit shown below, the transistor parameters are V_{TN} = 1.7 V and K_{n} = 0.4 mA/V^{2}.
If I_{D} = 0.8 mA and V_{D} = 1V, the value of resistor R_{S} and R_{D} are respectively
Let Q1 = 4 µ C be located at P_{1} (3, 11, 8) while Q_{2} = − 5 µ C is at P_{2} (6, 15, 8). The force F_{2} on Q_{2} will be
A numerical solution of the equation can be obtained using Newton – Raphson method. If the starting value is x = 2 for the iteration, the value of x that is to be used in the next step is
f(x)+√(x3) = 0
f(x) = √(x3)
f'(x) =1/2√(x3)
Initial value of x = 2
x =2 (√(23))/(1/2(√(23))) = 0
f(x)+√(x3) = 0
f(x) = √(x3)
f'(x) =1/2√(x3)
Initial value of x = 2
x =2 (√(23))/(1/2(√(23))) = 0
In the Taylor series, in the expansion of exp (x) + sin (x) about the point x = π, the coefficient of (x − π)^{2} is
Correct Answer : 0.5 exp (π)
Correct Answer : 0.5 exp (π)
A 50 kW, 440 V, 50 Hz, 6pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed at full load?
A 50 kW, 440 V, 50 Hz, 6pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at fullload conditions.
What is the value of load torque?