# IPPB Prelims Online Test Series 1, IPPB Pre Mock Test Series 1

## IPPB Prelims Online Test Series 1, IPPB Pre Mock Test Series 1

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IPPB Prelims Online Test Series 1, IPPB Pre Mock Test Series 1. Take IPPB Prelims Free Quiz 2019 Series 1st .The Indian Post Payments Bank recently released the Officer Scale I admit card.**Series 1**. Here we are providing** IPPB Prelims Full Mock Test Paper in English. IPPB Prelims **Mock Test **Series 1st** 2019. Now Test your self for IPPB Prelims Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

CorrectSpeed = [54 * 5/18] m/sec = 15 m/sec.

Length of the train = (15 * 20) m = 300 m.

Let the length of the platform be x meters.

Then, x + 300 / 36 = 15

x + 300 = 540

x = 240 m.IncorrectSpeed = [54 * 5/18] m/sec = 15 m/sec.

Length of the train = (15 * 20) m = 300 m.

Let the length of the platform be x meters.

Then, x + 300 / 36 = 15

x + 300 = 540

x = 240 m. - Question 2 of 50
##### 2. Question

Find the H.C.F of 12, 16, 18 and 24?

CorrectIncorrect - Question 3 of 50
##### 3. Question

Find the least multiple of 13 which when divided by 6, 8 and 12 leaves 5, 7 and 11 as remainders respectively?

CorrectIncorrect - Question 4 of 50
##### 4. Question

Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.15of money?

CorrectP = 15(100/10)

^{2 }=> P = 1500IncorrectP = 15(100/10)

^{2 }=> P = 1500 - Question 5 of 50
##### 5. Question

A man said to his son, “I was two-third of your present age when you were born”. If the present age of the man is 48 years, find the present age of the son?

CorrectPresent age of the son be P, he was born P years ago.

The age of the man was: (48 – P).

His age when the son was born should be equal to 2/3 of P.

(48 – P) = 2/3 P

5P = 144 => P = 28.8IncorrectPresent age of the son be P, he was born P years ago.

The age of the man was: (48 – P).

His age when the son was born should be equal to 2/3 of P.

(48 – P) = 2/3 P

5P = 144 => P = 28.8 - Question 6 of 50
##### 6. Question

A and B complete a work in 6 days. A alone can do it in 10 days. If both together can do the work in how many days?

Correct1/6 + 1/10 = 8/30 = 4/15

15/4 = 3.75 daysIncorrect1/6 + 1/10 = 8/30 = 4/15

15/4 = 3.75 days - Question 7 of 50
##### 7. Question

Rahim bought 65 books for Rs.1150 from one shop and 50 books for Rs.920 from another. What is the average price he paid per book ?

CorrectAverage price per book = (1150 + 920) / (65 + 50) = 2070 / 115 = Rs.18

IncorrectAverage price per book = (1150 + 920) / (65 + 50) = 2070 / 115 = Rs.18

- Question 8 of 50
##### 8. Question

If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively:

Correct(A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4

A:B = 2:3 and B:C = 1:4 = 3:12

A:B:C = 2:3:12

A;s share = 510 * 2/17 = Rs. 60

B’s share = 510 * 3/17 = Rs. 90

C’s share = 510 * 12/17 = Rs. 360.Incorrect(A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4

A:B = 2:3 and B:C = 1:4 = 3:12

A:B:C = 2:3:12

A;s share = 510 * 2/17 = Rs. 60

B’s share = 510 * 3/17 = Rs. 90

C’s share = 510 * 12/17 = Rs. 360. - Question 9 of 50
##### 9. Question

If x % of 80 = 20% of y, then x = ? and y = ?

Correctx % of 80 = 20 % of y => x / 100 (80) = 20 / 100 (y)

=> 4x = y

i.e x / y = ¼Incorrectx % of 80 = 20 % of y => x / 100 (80) = 20 / 100 (y)

=> 4x = y

i.e x / y = ¼ - Question 10 of 50
##### 10. Question

(0.9 * 0.9 * 0.9 + 0.8 * 0.8 * 0.8) / (1.6 * 1.6 * 1.6 + 1.8 * 1.8 * 1.8) = ?

Correct(0.9 * 0.9 * 0.9 + 0.8 * 0.8 * 0.8) / (1.6 * 1.6 * 1.6 + 1.8 * 1.8 * 1.8)

= (0.9 * 0.9 * 0.9 + 0.8 * 0.8 * 0.8) / 2^{3}(0.8 * 0.8 * 0.8 + 0.9 * 0.9 * 0.9) = 1/8 = 0.125Incorrect(0.9 * 0.9 * 0.9 + 0.8 * 0.8 * 0.8) / (1.6 * 1.6 * 1.6 + 1.8 * 1.8 * 1.8)

= (0.9 * 0.9 * 0.9 + 0.8 * 0.8 * 0.8) / 2^{3}(0.8 * 0.8 * 0.8 + 0.9 * 0.9 * 0.9) = 1/8 = 0.125 - Question 11 of 50
##### 11. Question

Find the area of circle whose radius is 7m?

Correct22/7 * 7 * 7 = 154

Incorrect22/7 * 7 * 7 = 154

- Question 12 of 50
##### 12. Question

I. a

^{2}– 2a – 8 = 0,

II. b^{2}= 9 to solve both the equations to find the values of a and b?CorrectI. (a – 4)(a + 2) = 0

=> a = 4, -2

II. b^{2}= 9

=> b = ± 3

-2 < 3, -2 > -3, 4 > 3, 4 > -3,

No relation can be established between a and b.IncorrectI. (a – 4)(a + 2) = 0

=> a = 4, -2

II. b^{2}= 9

=> b = ± 3

-2 < 3, -2 > -3, 4 > 3, 4 > -3,

No relation can be established between a and b. - Question 13 of 50
##### 13. Question

A man goes from A to B at a speed of 20 kmph and comes back to A at a speed of 30 kmph. Find his average speed for the entire journey?

CorrectDistance from A and B be ‘d’

Average Speed = total distance/total time

Average Speed = (2d)/[(d/20) + (d/30)]

= (2d)/[5d/60) => 24 kmph.IncorrectDistance from A and B be ‘d’

Average Speed = total distance/total time

Average Speed = (2d)/[(d/20) + (d/30)]

= (2d)/[5d/60) => 24 kmph. - Question 14 of 50
##### 14. Question

A can do a piece of work in 4 hours; B and C together can do it in 3 hours, which A and C together can do it in 2 hours. How long will B alone take to do it?

CorrectA’s 1 hour work = 1/4;

(B + C)’s 1 hour work = 1/3;

(A + C)’s 1 hour work = 1/2

(A + B + C)’s 1 hour work = (1/4 + 1/3) = 7/12

B’s 1 hour work = (7/12 + 1/2) = 1/12

B alone will take 12 hours to do the work.IncorrectA’s 1 hour work = 1/4;

(B + C)’s 1 hour work = 1/3;

(A + C)’s 1 hour work = 1/2

(A + B + C)’s 1 hour work = (1/4 + 1/3) = 7/12

B’s 1 hour work = (7/12 + 1/2) = 1/12

B alone will take 12 hours to do the work. - Question 15 of 50
##### 15. Question

Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest?

CorrectRs.1440 – 1200 = Rs.240 is the interest on Rs.1200 for one year.

Rate of interest = (100 * 240) / (100 * 1) = 20% p.aIncorrectRs.1440 – 1200 = Rs.240 is the interest on Rs.1200 for one year.

Rate of interest = (100 * 240) / (100 * 1) = 20% p.a - Question 16 of 50
##### 16. Question

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period(in years) is?

CorrectAmount = (30000 + 4347) = Rs. 34347

Let the time be n years. Then,

30000(1 + 7/100)^{n}= 34347

= (107/100)^{n}= 34347/30000 = (107/100)^{2}

n = 2 years.IncorrectAmount = (30000 + 4347) = Rs. 34347

Let the time be n years. Then,

30000(1 + 7/100)^{n}= 34347

= (107/100)^{n}= 34347/30000 = (107/100)^{2}

n = 2 years. - Question 17 of 50
##### 17. Question

A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 6km?

CorrectM = 4

S = 2

US = 4 – 2 = 2

D = 6

T = 6/2 = 3IncorrectM = 4

S = 2

US = 4 – 2 = 2

D = 6

T = 6/2 = 3 - Question 18 of 50
##### 18. Question

The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 5 months, find for how much time did Q invest the money?

Correct7*5: 5*x = 7:10

x = 10Incorrect7*5: 5*x = 7:10

x = 10 - Question 19 of 50
##### 19. Question

A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?

CorrectNumber of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.

P liters of water added to the mixture to make water 25% of the new mixture.

Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).

(30 + P) = 25/100 * (150 + P)

120 + 4P = 150 + P => P = 10 liters.IncorrectNumber of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.

P liters of water added to the mixture to make water 25% of the new mixture.

Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).

(30 + P) = 25/100 * (150 + P)

120 + 4P = 150 + P => P = 10 liters. - Question 20 of 50
##### 20. Question

The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?

CorrectThe ratio of the times taken is 2:1.

The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1

Speed of the stream = 42/3 = 14 kmph.IncorrectThe ratio of the times taken is 2:1.

The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1

Speed of the stream = 42/3 = 14 kmph. - Question 21 of 50
##### 21. Question

A tank is filled in eight hours by three pipes A, B and C. Pipe A is twice as fast as pipe B, and B is twice as fast as C. How much time will pipe B alone take to fill the tank?

Correct1/A + 1/B + 1/C = 1/8 (Given)

Also given that A = 2B and B = 2C

=> 1/2B + 1/B + 2/B = 1/8

=> (1 + 2 + 4)/2B = 1/8

=> 2B/7 = 8

=> B = 28 hours.Incorrect1/A + 1/B + 1/C = 1/8 (Given)

Also given that A = 2B and B = 2C

=> 1/2B + 1/B + 2/B = 1/8

=> (1 + 2 + 4)/2B = 1/8

=> 2B/7 = 8

=> B = 28 hours. - Question 22 of 50
##### 22. Question

(17

^{14}* 17^{16}) / 17^{-8}= ?Correct? = 17

^{14+16-8}= 17^{22}Incorrect? = 17

^{14+16-8}= 17^{22} - Question 23 of 50
##### 23. Question

What is the least number to be subtracted from 11, 15, 21 and 30 each so that the resultant numbers become proportional?

CorrectLet the least number to be subtracted be ‘x’, then 11 – x, 15 – x, 21 – x and 30 – x are in proportion.

<=> (11 – x):(15 – x) = (21 – x):(30 -x)(21 – x)

From the options, when x = 3

=> 8 * 27 = 12 * 18 => then x = 3. => (11 – x)(30 – x) = (15 – x)(21 – x)IncorrectLet the least number to be subtracted be ‘x’, then 11 – x, 15 – x, 21 – x and 30 – x are in proportion.

<=> (11 – x):(15 – x) = (21 – x):(30 -x)(21 – x)

From the options, when x = 3

=> 8 * 27 = 12 * 18 => then x = 3. => (11 – x)(30 – x) = (15 – x)(21 – x) - Question 24 of 50
##### 24. Question

Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 48 years. What will be the age of the B ten years hence?

CorrectLet the present ages of A, B and C be a, b and c respectively.

Given, [(a – 5) + (b – 5)] / 2 = 40 => a + b = 90 — (1)

(b + c)/2 = 48 => b + c = 96 — (2)

From (1) and (2), we cannot find b.IncorrectLet the present ages of A, B and C be a, b and c respectively.

Given, [(a – 5) + (b – 5)] / 2 = 40 => a + b = 90 — (1)

(b + c)/2 = 48 => b + c = 96 — (2)

From (1) and (2), we cannot find b. - Question 25 of 50
##### 25. Question

7589 – ? = 3434

CorrectLet 7589 – x = 3434

Then x = 7589 – 3434 = 4155IncorrectLet 7589 – x = 3434

Then x = 7589 – 3434 = 4155 - Question 26 of 50
##### 26. Question

A and B rent a pasture for 10 months. A put in 80 cows for 7 months. How many can B put in for the remaining 3 months, if he pays half as much again as A?

Correct80* 7: x* 3 = 1:1 1/2

560: 3x = 2: 3

x = 280Incorrect80* 7: x* 3 = 1:1 1/2

560: 3x = 2: 3

x = 280 - Question 27 of 50
##### 27. Question

√3584 * 52.034 = ?

Correct√3600 * 52 = ?

=> ? = 60 * 52 = 3120Incorrect√3600 * 52 = ?

=> ? = 60 * 52 = 3120 - Question 28 of 50
##### 28. Question

A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit.

CorrectA:B:C = 5:6:4

Let the total profit = 100 – 30 = 70

5/15 * 70 = 70/3

A share = 70/3 + 30 = 160/3

B + C share = 100 – 160/3 = 140/3

A-(B+C) = 160/3 – 140/3 = 20/3

20/3 —- 200

100 —- ? => 3000IncorrectA:B:C = 5:6:4

Let the total profit = 100 – 30 = 70

5/15 * 70 = 70/3

A share = 70/3 + 30 = 160/3

B + C share = 100 – 160/3 = 140/3

A-(B+C) = 160/3 – 140/3 = 20/3

20/3 —- 200

100 —- ? => 3000 - Question 29 of 50
##### 29. Question

A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work?

CorrectLet A worked for x days.

x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18

A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days.IncorrectLet A worked for x days.

x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18

A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days. - Question 30 of 50
##### 30. Question

A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?

Correct72 — 9 DS = 8

? —- 1

45 —- 9 US = 5

? —- 1 S = ?

S = (8 – 5)/2 = 1.5Incorrect72 — 9 DS = 8

? —- 1

45 —- 9 US = 5

? —- 1 S = ?

S = (8 – 5)/2 = 1.5 - Question 31 of 50
##### 31. Question

How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?

CorrectLet length of tunnel is x meter

Distance = 800+x meter

Time = 1 minute = 60 seconds

Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s

Distance = Speed*Time

800+x = (65/3) * 60

800+x = 20 * 65 = 1300

x = 1300 – 800 = 500 metersIncorrectLet length of tunnel is x meter

Distance = 800+x meter

Time = 1 minute = 60 seconds

Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s

Distance = Speed*Time

800+x = (65/3) * 60

800+x = 20 * 65 = 1300

x = 1300 – 800 = 500 meters - Question 32 of 50
##### 32. Question

A can do a piece of work in 10 days and B can do the same work in 12 days. A and B worked together for 2 days. How many more days are required to complete the remaining work if they work together?

CorrectA can do 1/10 of the work in a day.

B can do 1/12 of the work in a 1 day.

Both of them together can do (1/10 + 1/12) part of work in 1 day = (6 + 5)/60 = 11/60

They take 60/11 days to complete the work together.

Given that they already worked for 2 days.

The number of days required to complete remaining work => 60/11 – 2 = 38/11 = 3 (5/11) days.IncorrectA can do 1/10 of the work in a day.

B can do 1/12 of the work in a 1 day.

Both of them together can do (1/10 + 1/12) part of work in 1 day = (6 + 5)/60 = 11/60

They take 60/11 days to complete the work together.

Given that they already worked for 2 days.

The number of days required to complete remaining work => 60/11 – 2 = 38/11 = 3 (5/11) days. - Question 33 of 50
##### 33. Question

A large tanker can be filled by two pipes A and B in 60 and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?

CorrectPart filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24

Suppose the tank is filled in x minutes.

Then, x/2(1/24 + 1/40) = 1

x/2 * 1/15 = 1 => x = 30 min.IncorrectPart filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24

Suppose the tank is filled in x minutes.

Then, x/2(1/24 + 1/40) = 1

x/2 * 1/15 = 1 => x = 30 min. - Question 34 of 50
##### 34. Question

Aamir saves 32% of his monthly salary. If he spends Rs. 27200, then find his savings?

CorrectLet the monthly salary of Aamir be Rs. x.

68% of x = 27200

=> x = (27200 * 100)/68 = 40000

His savings = 32/100 * 40000 = 12800.IncorrectLet the monthly salary of Aamir be Rs. x.

68% of x = 27200

=> x = (27200 * 100)/68 = 40000

His savings = 32/100 * 40000 = 12800. - Question 35 of 50
##### 35. Question

If 25% of x is 15 less than 15% of 1500, then x is?

Correct25% of x = x/4 ; 15% of 1500 = 15/100 * 1500 = 225

Given that, x/4 = 225 – 15 => x/4 = 210 => x = 840.Incorrect25% of x = x/4 ; 15% of 1500 = 15/100 * 1500 = 225

Given that, x/4 = 225 – 15 => x/4 = 210 => x = 840. - Question 36 of 50
##### 36. Question

Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number?

CorrectIncorrect - Question 37 of 50
##### 37. Question

The difference between simple and compound interest on Rs. 1200 for one year at 10% per annum reckoned half-yearly is?

CorrectS.I. = (1200 * 10 * 1)/100 = Rs. 120

C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3.IncorrectS.I. = (1200 * 10 * 1)/100 = Rs. 120

C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3. - Question 38 of 50
##### 38. Question

The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?

CorrectLet the sides of the rectangle be l and b respectively.

From the given data,

(√l^{2}+ b^{2}) = (1 + 108 1/3 %)lb

=> l^{2}+ b^{2}= (1 + 325/3 * 1/100)lb

= (1 + 13/12)lb

= 25/12 lb

=> (l^{2}+ b^{2})/lb = 25/12

12(l^{2}+ b^{2}) = 25lb

Adding 24lb on both sides

12l^{2}+ 12b^{2}+ 24lb = 49lb

12(l^{2}+ b^{2}+ 2lb) = 49lb

but 2(l + b) = 28 => l + b = 14

12(l + b)^{2}= 49lb=> 12(14)^{2}= 49lb=> lb = 48Since l + b = 14, l = 8 and b = 6l – b = 8 – 6 = 2m.IncorrectLet the sides of the rectangle be l and b respectively.

From the given data,

(√l^{2}+ b^{2}) = (1 + 108 1/3 %)lb

=> l^{2}+ b^{2}= (1 + 325/3 * 1/100)lb

= (1 + 13/12)lb

= 25/12 lb

=> (l^{2}+ b^{2})/lb = 25/12

12(l^{2}+ b^{2}) = 25lb

Adding 24lb on both sides

12l^{2}+ 12b^{2}+ 24lb = 49lb

12(l^{2}+ b^{2}+ 2lb) = 49lb

but 2(l + b) = 28 => l + b = 14

12(l + b)^{2}= 49lb=> 12(14)^{2}= 49lb=> lb = 48Since l + b = 14, l = 8 and b = 6l – b = 8 – 6 = 2m. - Question 39 of 50
##### 39. Question

The triplicate ratio of 1:2 is?

Correct1

^{3}: 2^{3}= 1:8Incorrect1

^{3}: 2^{3}= 1:8 - Question 40 of 50
##### 40. Question

A total of 3000 chocolates were distributed among 120 boys and girls such that each boy received 2 chocolates and each girl received 3 chocolates. Find the respective number of boys and girls?

CorrectLet the number of boys be x.

Number of girls is 120 – x.

Total number of chocolates received by boys and girls = 2x + 3(120 – x) = 300

=> 360 – x = 300 => x = 60.

So, the number of boys or girls is 60.IncorrectLet the number of boys be x.

Number of girls is 120 – x.

Total number of chocolates received by boys and girls = 2x + 3(120 – x) = 300

=> 360 – x = 300 => x = 60.

So, the number of boys or girls is 60. - Question 41 of 50
##### 41. Question

What is the difference between the largest number and the least number written with the figures 3, 4, 7, 0, 3?

Correct74330 Largest

30347 Smallest

————-

43983Incorrect74330 Largest

30347 Smallest

————-

43983 - Question 42 of 50
##### 42. Question

The average of first 10 even numbers is?

CorrectSum of 10 even numbers = 10 * 11 = 110

Average = 110/10 = 11IncorrectSum of 10 even numbers = 10 * 11 = 110

Average = 110/10 = 11 - Question 43 of 50
##### 43. Question

If x % of 80 = 20% of y, then x = ? and y = ?

Correctx % of 80 = 20 % of y => x / 100 (80) = 20 / 100 (y)

=> 4x = y

i.e x / y = ¼Incorrectx % of 80 = 20 % of y => x / 100 (80) = 20 / 100 (y)

=> 4x = y

i.e x / y = ¼ - Question 44 of 50
##### 44. Question

The ratio of the area of a square to that of the square drawn on its diagonal is?

CorrectIncorrect - Question 45 of 50
##### 45. Question

Find the one which does not belong to that group ?

Correct30 = 3

^{3}+ 3, 630 = 5^{4}+ 5, 10 = 2^{3}+ 2, 520 = 8^{3}+ 8 and 130 = 5^{3}+ 5.

30, 10, 130 and 520 can be expressed as n^{3}+ n but not 630.Incorrect30 = 3

^{3}+ 3, 630 = 5^{4}+ 5, 10 = 2^{3}+ 2, 520 = 8^{3}+ 8 and 130 = 5^{3}+ 5.

30, 10, 130 and 520 can be expressed as n^{3}+ n but not 630. - Question 46 of 50
##### 46. Question

Two pipes A and B can separately fill a tank in 12 and 15 minutes respectively. A third pipe C can drain off 45 liters of water per minute. If all the pipes are opened, the tank can be filled in 15 minutes. What is the capacity of the tank?

Correct1/12 + 1/15 – 1/x = 1/15

x = 12

12 * 45 = 540Incorrect1/12 + 1/15 – 1/x = 1/15

x = 12

12 * 45 = 540 - Question 47 of 50
##### 47. Question

The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:

CorrectSpeed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.

IncorrectSpeed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.

- Question 48 of 50
##### 48. Question

Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case?

CorrectLowest 4-digit number is 1000.

LCM of 3, 4 and 5 is 60.

Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 – 40) = 1020.

Now, add the remainder 2 that’s required. Thus, the answer is 1022.IncorrectLowest 4-digit number is 1000.

LCM of 3, 4 and 5 is 60.

Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 – 40) = 1020.

Now, add the remainder 2 that’s required. Thus, the answer is 1022. - Question 49 of 50
##### 49. Question

The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age was five times the age of the son. After 6 years, son’s age will be:

CorrectLet the age of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

3x + 20 = 2x + 40 => x = 20.

Required ratio = (3x + 10):(x + 10) = 70:30 = 7:3IncorrectLet the age of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

3x + 20 = 2x + 40 => x = 20.

Required ratio = (3x + 10):(x + 10) = 70:30 = 7:3 - Question 50 of 50
##### 50. Question

In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes?

CorrectLet the total number of valid votes be x.

70% of x = 70/100 * x = 7x/10

Number of votes secured by the other candidate = x – 7x/100 = 3x/10

Given, 7x/10 – 3x/10 = 172 => 4x/10 = 172

=> 4x = 1720 => x = 430.IncorrectLet the total number of valid votes be x.

70% of x = 70/100 * x = 7x/10

Number of votes secured by the other candidate = x – 7x/100 = 3x/10

Given, 7x/10 – 3x/10 = 172 => 4x/10 = 172

=> 4x = 1720 => x = 430.