# SEBI Online Mock Test Series 4th, SEBI Online Test Series, SEBI MCQ

## SEBI Online Mock Test 4, SEBI Online Test in English Series 4

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**SEBI Online Mock Test 4, SEBI Online Test in English Series 4**, SEBI Free Online Test Series 4. SEBI Exam Online Test 2019, SEBI Free Mock Test Exam 2019. SEBI Exam Free Online Quiz 2019, SEBI Full Online Mock Test **Series 4th** in English. RRB Online Test for All Subjects, SEBI Free Mock Test Series in English. SEBI Free Mock Test **Series 4.** SEBI English Language Online Test in English **Series 4th**. SEBI Quantitative Aptitude Quiz 2019, SEBI Reasoning Ability Free Online Test. Take SEBI Online Quiz. The SEBI Full online mock test paper is free for all students. SEBI Question and Answers in English and Hindi **Series 4**. Here we are providing** SEBI Full Mock Test Paper in English. SEBI **Mock Test **Series 4th** 2019. Now Test your self for SEBI Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

P alone can complete a piece of work in 6 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?

CorrectWork done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.

Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total

They would take 9/2 days = 4 (1/2) days to complete the work working together.IncorrectWork done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.

Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total

They would take 9/2 days = 4 (1/2) days to complete the work working together. - Question 2 of 50
##### 2. Question

The sum of five numbers is 655. The average of the first two numbers is 85 and the third number is 125. Find the average of the two numbers?

CorrectLet the five numbers be P, Q, R, S and T.

=> P + Q + R + S + T = 655.

(P + Q)/2 = 85 and R = 125

P + Q = 170 and R = 125

P + Q + R = 295

S + T = 655 – (P + Q + R) = 360

Average of the last two numbers = (S + T)/2 = 180.IncorrectLet the five numbers be P, Q, R, S and T.

=> P + Q + R + S + T = 655.

(P + Q)/2 = 85 and R = 125

P + Q = 170 and R = 125

P + Q + R = 295

S + T = 655 – (P + Q + R) = 360

Average of the last two numbers = (S + T)/2 = 180. - Question 3 of 50
##### 3. Question

Find the one which does not belong to that group ?

CorrectExcept in 862, in all other numbers sum of first two digits is same as the last digit.

IncorrectExcept in 862, in all other numbers sum of first two digits is same as the last digit.

- Question 4 of 50
##### 4. Question

The diameters of two spheres are in the ratio 1:2 what is the ratio of their surface area?

CorrectIncorrect - Question 5 of 50
##### 5. Question

Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?

Correctx + y = 80

x – 4y = 5

x = 65 y = 15Incorrectx + y = 80

x – 4y = 5

x = 65 y = 15 - Question 6 of 50
##### 6. Question

At what rate percent on simple interest will a sum of money double itself in 30 years?

CorrectP = (P*30*R)/100

R = 3 1/3%IncorrectP = (P*30*R)/100

R = 3 1/3% - Question 7 of 50
##### 7. Question

A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?

Correct15:25 => 3:5

9600*10/100 = 960

9600 – 960 = 8640

8640*3/8 = 3240 + 960

= 4200Incorrect15:25 => 3:5

9600*10/100 = 960

9600 – 960 = 8640

8640*3/8 = 3240 + 960

= 4200 - Question 8 of 50
##### 8. Question

Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction?

CorrectRS = 5 ¾ – 4 ½ = 1 ¼

T = 3 ½ h.

D = 5/4 * 7/2 = 35/8 = 4 3/8 kmIncorrectRS = 5 ¾ – 4 ½ = 1 ¼

T = 3 ½ h.

D = 5/4 * 7/2 = 35/8 = 4 3/8 km - Question 9 of 50
##### 9. Question

A number when, 28 subtracted from it reduces to its one third. What is the value of 50% of that number?

Correct2/3 x = 28 => x = 42

42 * 1/2 = 21Incorrect2/3 x = 28 => x = 42

42 * 1/2 = 21 - Question 10 of 50
##### 10. Question

A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train.

CorrectSpeed = 60*(5/18) m/sec = 50/3 m/sec

Length of Train (Distance) = Speed * Time

(50/3) * 9 = 150 meterIncorrectSpeed = 60*(5/18) m/sec = 50/3 m/sec

Length of Train (Distance) = Speed * Time

(50/3) * 9 = 150 meter - Question 11 of 50
##### 11. Question

Rs. 6000 is lent out in two parts. One part is lent at 7% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?

CorrectLet the amount lent at 7% be Rs. x

Amount lent at 10% is Rs. (6000 – x)

Total interest for one year on the two sums lent

= 7/100 x + 10/100 (6000 – x) = 600 – 3x/100

=> 600 – 3/100 x = 450 => x = 5000

Amount lent at 10% = 1000

Required ratio = 5000 : 1000 = 5 : 1

Learn more problems on : AveragesIncorrectLet the amount lent at 7% be Rs. x

Amount lent at 10% is Rs. (6000 – x)

Total interest for one year on the two sums lent

= 7/100 x + 10/100 (6000 – x) = 600 – 3x/100

=> 600 – 3/100 x = 450 => x = 5000

Amount lent at 10% = 1000

Required ratio = 5000 : 1000 = 5 : 1

Learn more problems on : Averages - Question 12 of 50
##### 12. Question

1/3 of 2/6 of 1/7 of 2/28 of 2140 = ?

Correct1/3 * 1/3 * 1/7 * 1/9 * 2140 = ?

? = 3.77Incorrect1/3 * 1/3 * 1/7 * 1/9 * 2140 = ?

? = 3.77 - Question 13 of 50
##### 13. Question

At what rate percent of simple interest will a sum of money double itself in 12 years?

CorrectLet sum = x. Then, S.I. = x.

Rate = (100 * S.I.) / (P * T) = (100 * x) / (x * 12)

= 25/3 = 8 1/3 %IncorrectLet sum = x. Then, S.I. = x.

Rate = (100 * S.I.) / (P * T) = (100 * x) / (x * 12)

= 25/3 = 8 1/3 % - Question 14 of 50
##### 14. Question

Anand and Deepak started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak’s share is:

CorrectRatio of their shares = 22500 : 35000 = 9:14

Deepak’s share = 13800 * 14/23 = Rs. 8400.IncorrectRatio of their shares = 22500 : 35000 = 9:14

Deepak’s share = 13800 * 14/23 = Rs. 8400. - Question 15 of 50
##### 15. Question

What will be the difference between simple and compound interest at 10% per annum on a sum of Rs. 1000 after 4 years?

CorrectS.I. = (1000 * 10 * 4)/100 = Rs. 400

C.I. = [1000 * (1 + 10/100)^{4}– 1000] = Rs. 464.10 Difference = (464.10 – 400) = Rs. 64.10IncorrectS.I. = (1000 * 10 * 4)/100 = Rs. 400

C.I. = [1000 * (1 + 10/100)^{4}– 1000] = Rs. 464.10 Difference = (464.10 – 400) = Rs. 64.10 - Question 16 of 50
##### 16. Question

The area of a square is equal to five times the area of a rectangle of dimensions 125 cm * 64 cm. What is the perimeter of the square?

CorrectArea of the square = s * s = 5(125 * 64)

=> s = 25 * 8 = 200 cm

Perimeter of the square = 4 * 200 = 800 cm.IncorrectArea of the square = s * s = 5(125 * 64)

=> s = 25 * 8 = 200 cm

Perimeter of the square = 4 * 200 = 800 cm. - Question 17 of 50
##### 17. Question

A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is?

CorrectS.I. for 1 year = (854 – 815) = Rs. 39

S.I. for 3 years = 39 * 3 = Rs. 117

Principal = (815 – 117) = Rs. 698.IncorrectS.I. for 1 year = (854 – 815) = Rs. 39

S.I. for 3 years = 39 * 3 = Rs. 117

Principal = (815 – 117) = Rs. 698. - Question 18 of 50
##### 18. Question

Rajan got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. Rajan’s sister was 10 years younger to him at the time of his marriage. The age of Rajan’s sister is:

CorrectLet Rajan’s present age be x years.

Then, his age at the time of marriage = (x – 8) years.

x = 6/5 (x – 8)

5x = 6x – 48 => x = 48

Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = 30 years.

Rajan’s sister’s present age = (30 + 8) = 38 years.IncorrectLet Rajan’s present age be x years.

Then, his age at the time of marriage = (x – 8) years.

x = 6/5 (x – 8)

5x = 6x – 48 => x = 48

Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = 30 years.

Rajan’s sister’s present age = (30 + 8) = 38 years. - Question 19 of 50
##### 19. Question

Twelve men can complete a piece of work in 32 days. The same work can be completed by 16 women in 36 days and by 48 boys in 16 days. Find the time taken by one man, one woman and one boy working together to complete the work?

Correct12 men take 32 days to complete the work.

One man will take (12 * 32) days to complete it.

Similarly one woman will take (16 * 36) days to complete it and one boy will take (48 * 16) days to complete it.

One man, one woman and one boy working together will complete = 1/(12 * 32) + 1/(16 * 36) + 1/(48 * 16)

= 1/(4 * 3 * 16 * 2) + 1/(16 * 4 * 9) + 1/(16 * 3 * 4 * 4)

= 1/64(1/6 + 1/9 + 1/12) = 1/64 * 13/36 of the work in a day.

They will take (64 * 36)/13 days to complete the work working together.Incorrect12 men take 32 days to complete the work.

One man will take (12 * 32) days to complete it.

Similarly one woman will take (16 * 36) days to complete it and one boy will take (48 * 16) days to complete it.

One man, one woman and one boy working together will complete = 1/(12 * 32) + 1/(16 * 36) + 1/(48 * 16)

= 1/(4 * 3 * 16 * 2) + 1/(16 * 4 * 9) + 1/(16 * 3 * 4 * 4)

= 1/64(1/6 + 1/9 + 1/12) = 1/64 * 13/36 of the work in a day.

They will take (64 * 36)/13 days to complete the work working together. - Question 20 of 50
##### 20. Question

If x = 3 – √7, then find the value of x + 1/x.

Correctx = -√7

1/x = 1/(3 – √7) = 3 + √7/(3 – √7) (3 + √7)

= (3 + √7)/2 => x + 1/x = (9 – √7)/2Incorrectx = -√7

1/x = 1/(3 – √7) = 3 + √7/(3 – √7) (3 + √7)

= (3 + √7)/2 => x + 1/x = (9 – √7)/2 - Question 21 of 50
##### 21. Question

Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?

Correct4/12 + x/15 = 1

x = 10Incorrect4/12 + x/15 = 1

x = 10 - Question 22 of 50
##### 22. Question

80 is what percent of 64?

CorrectLet x percent of 64 be 80.

64 * x/100 = 80 => x = (80 * 100)/64 => x = 125

80 is 125% of 64.IncorrectLet x percent of 64 be 80.

64 * x/100 = 80 => x = (80 * 100)/64 => x = 125

80 is 125% of 64. - Question 23 of 50
##### 23. Question

If a: b = 3:4, b:c = 7:9, c:d = 5:7, find a:d?

Correcta/d = (3/4)*(7/9)*(5/7) => 5/12

Incorrecta/d = (3/4)*(7/9)*(5/7) => 5/12

- Question 24 of 50
##### 24. Question

The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?

Correct2x * x = 128 => x= 8

Incorrect2x * x = 128 => x= 8

- Question 25 of 50
##### 25. Question

The average of 1

^{st}3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 13. What is the last numbers?CorrectA + B + C = 48

B + C + D = 45

A + D = 13

A – D = 3

A + D = 132D = 10

D = 5IncorrectA + B + C = 48

B + C + D = 45

A + D = 13

A – D = 3

A + D = 132D = 10

D = 5 - Question 26 of 50
##### 26. Question

A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?

CorrectLet C’s age be x years.

Then, B’s age = 2x years.

A’s age = (2x + 2) years.

(2x + 2) + 2x + x = 27

5x = 25 => x = 5

Hence, B’s age = 2x = 10 years.IncorrectLet C’s age be x years.

Then, B’s age = 2x years.

A’s age = (2x + 2) years.

(2x + 2) + 2x + x = 27

5x = 25 => x = 5

Hence, B’s age = 2x = 10 years. - Question 27 of 50
##### 27. Question

The difference between C.I. and S.I. on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?

Correct[15000 * (1 + R/100)

^{2}– 15000] – (15000 * R * 2)/100 = 96

15000[(1 + R/100)^{2}– 1 – 2R/100] = 96

15000[(100 + R)^{2}– 10000 – 200R]/10000 = 96

R^{2}= (96 * 2)/3 = 64 => R = 8

Rate = 8%Incorrect[15000 * (1 + R/100)

^{2}– 15000] – (15000 * R * 2)/100 = 96

15000[(1 + R/100)^{2}– 1 – 2R/100] = 96

15000[(100 + R)^{2}– 10000 – 200R]/10000 = 96

R^{2}= (96 * 2)/3 = 64 => R = 8

Rate = 8% - Question 28 of 50
##### 28. Question

A sum of money is borrowed and paid back in two annual installments of Rs. 882 each allowing 5% C.I. The sum borrowed was?

CorrectPrincipal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)

= [882/(1 + 5/100) + 882/(1 + 5/100)^{2}]

= (882 * 20)/21 + (882 * 400)/441 = Rs. 1640.IncorrectPrincipal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)

= [882/(1 + 5/100) + 882/(1 + 5/100)^{2}]

= (882 * 20)/21 + (882 * 400)/441 = Rs. 1640. - Question 29 of 50
##### 29. Question

What amount does Kiran get if he invests Rs. 18000 at 15% p.a. simple interest for four years?

CorrectSimple interest = (18000 * 4 * 15)/100 = Rs. 10800

Amount = P + I = 18000 + 10800 = Rs. 28800IncorrectSimple interest = (18000 * 4 * 15)/100 = Rs. 10800

Amount = P + I = 18000 + 10800 = Rs. 28800 - Question 30 of 50
##### 30. Question

The sum of two numbers is 22. Five times one number is equal to 6 times the other. The bigger of the two numbers is:

CorrectLet the numbers be x and (22 – x). Then,

5x = 6(22 – x)

11x = 132 => x = 12

So, the numbers are 12 and 10.IncorrectLet the numbers be x and (22 – x). Then,

5x = 6(22 – x)

11x = 132 => x = 12

So, the numbers are 12 and 10. - Question 31 of 50
##### 31. Question

A man can row 30 km downstream and 20 km upstream in 4 hours. He can row 45 km downstream and 40 km upstream in 7 hours. Find the speed of man in still water?

CorrectLet the speed of the man in still water be a kmph and let the speed of the stream be b kmph.

Now 30/(a + b) + 20/(a – b) = 4 and 45/(a + b) + 40/(a – b) = 7

Solving the equation, the speed of man in still water is 12.5 kmph.IncorrectLet the speed of the man in still water be a kmph and let the speed of the stream be b kmph.

Now 30/(a + b) + 20/(a – b) = 4 and 45/(a + b) + 40/(a – b) = 7

Solving the equation, the speed of man in still water is 12.5 kmph. - Question 32 of 50
##### 32. Question

If the wheel is 14 cm then the number of revolutions to cover a distance of 1056 cm is?

Correct2 * 22/7 * 14 * x = 1056 => x = 12

Incorrect2 * 22/7 * 14 * x = 1056 => x = 12

- Question 33 of 50
##### 33. Question

A and B can do a piece of work in 7 days. With the help of C they finish the work in 5 days. C alone can do that piece of work in?

CorrectC = 1/5 – 1/6 = 1/30 => 30 days

IncorrectC = 1/5 – 1/6 = 1/30 => 30 days

- Question 34 of 50
##### 34. Question

The S.I. on a certain sum of money for 3 years at 8% per annum is half the C.I. on Rs. 4000 for 2 years at 10% per annum. The sum placed on S.I. is?

CorrectC.I. = [4000 * (1 + 10/100)

^{2}– 4000]

= (4000 * 11/10 * 11/10 – 4000) = Rs. 840.

Sum = (420 * 100)/(3 * 8) = Rs. 1750IncorrectC.I. = [4000 * (1 + 10/100)

^{2}– 4000]

= (4000 * 11/10 * 11/10 – 4000) = Rs. 840.

Sum = (420 * 100)/(3 * 8) = Rs. 1750 - Question 35 of 50
##### 35. Question

If the price of an article went up by 20%, then by what percent should it be brought down to bring it back to its original price?

CorrectLet the price of the article be Rs. 100.

20% of 100 = 20.

New price = 100 + 20 = Rs. 120

Required percentage = (120 – 100)/120 * 100

= 20/120 * 100 = 50/3 = 16 2/3%.IncorrectLet the price of the article be Rs. 100.

20% of 100 = 20.

New price = 100 + 20 = Rs. 120

Required percentage = (120 – 100)/120 * 100

= 20/120 * 100 = 50/3 = 16 2/3%. - Question 36 of 50
##### 36. Question

How many shots of 1cm radius can be prepared from a sphere of 3cm radius?

Correct4/3 π * 3 * 3 * 3 = 4/3 π * 1 * 1 * 1 * x

x = 27Incorrect4/3 π * 3 * 3 * 3 = 4/3 π * 1 * 1 * 1 * x

x = 27 - Question 37 of 50
##### 37. Question

The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?

Correct1500 —- 270

100 —- ? => 18%Incorrect1500 —- 270

100 —- ? => 18% - Question 38 of 50
##### 38. Question

A room is 4 meters 37 cm long and 3 meters 23cm broad. It is required to pave the floor with minimum square slabs. Find the number of slabs required for this purpose?

CorrectHCF of 323, 437 = 19

323 * 437 = 19 * 19 * x

x = 391IncorrectHCF of 323, 437 = 19

323 * 437 = 19 * 19 * x

x = 391 - Question 39 of 50
##### 39. Question

Kiran travels from A to B by car and returns from B to A by cycle in 7 hours. If he travels both ways by car he saves 3 hours. What is the time taken to cover both ways by cycle?

CorrectLet the time taken to cover from A to B in car and cycle be x hours and y hours respectively.

x + y = 7 — (1) ; 2x = 4 — (2)

solving both the equations, we get y = 5

So, time taken to cover both ways by cycle = 2y hours = 10 hours.IncorrectLet the time taken to cover from A to B in car and cycle be x hours and y hours respectively.

x + y = 7 — (1) ; 2x = 4 — (2)

solving both the equations, we get y = 5

So, time taken to cover both ways by cycle = 2y hours = 10 hours. - Question 40 of 50
##### 40. Question

Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran’s share in the profit?

CorrectSimran : Nanda = (50000 * 36) : (80000 * 30) = 3:4

Simran’s share = 24500 * 3/7 = Rs. 10500IncorrectSimran : Nanda = (50000 * 36) : (80000 * 30) = 3:4

Simran’s share = 24500 * 3/7 = Rs. 10500 - Question 41 of 50
##### 41. Question

The smallest number when increased by ” 1 ” is exactly divisible by 12, 18, 24, 32 and 40 is:

CorrectLCM = 1440

1440 – 1 = 1439IncorrectLCM = 1440

1440 – 1 = 1439 - Question 42 of 50
##### 42. Question

Two trains of length 120 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?

CorrectRelative speed = (42 + 30) * 5/18 = 4 * 5 = 20 mps.

Distance covered in passing each other = 120 + 280 = 400 m.

The time required = d/s = 400/20 = 20 sec.IncorrectRelative speed = (42 + 30) * 5/18 = 4 * 5 = 20 mps.

Distance covered in passing each other = 120 + 280 = 400 m.

The time required = d/s = 400/20 = 20 sec. - Question 43 of 50
##### 43. Question

Find the one which does not belong to that group ?

CorrectExcept Austriala : Pound, all others are correction combination of country and its currency.

IncorrectExcept Austriala : Pound, all others are correction combination of country and its currency.

- Question 44 of 50
##### 44. Question

Tanya’s grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. Eight years ago, what was the ratio of Tanya’s age to that of her grandfather?

Correct16 years ago, let T = x years and G = 8x years. After 8 years from now, T = (x + 16 + 8) years and G = (8x + 16 + 8) years.

8x + 24 = 3(x + 24) => 5x = 48

8 years ago, T/G = (x + 8)/(8x + 8) = (48/5 + 8) / (8 * 48/5 + 8) = 88/424 = 11/53Incorrect16 years ago, let T = x years and G = 8x years. After 8 years from now, T = (x + 16 + 8) years and G = (8x + 16 + 8) years.

8x + 24 = 3(x + 24) => 5x = 48

8 years ago, T/G = (x + 8)/(8x + 8) = (48/5 + 8) / (8 * 48/5 + 8) = 88/424 = 11/53 - Question 45 of 50
##### 45. Question

A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in?

CorrectWork done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.

IncorrectWork done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.

- Question 46 of 50
##### 46. Question

Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?

CorrectLet the length of each train be x m.

Then, distance covered = 2x m.

Relative speed = 46 – 36 = 10 km/hr.

= 10 * 5/18 = 25/9 m/sec.

2x/36 = 25/9 => x = 50.IncorrectLet the length of each train be x m.

Then, distance covered = 2x m.

Relative speed = 46 – 36 = 10 km/hr.

= 10 * 5/18 = 25/9 m/sec.

2x/36 = 25/9 => x = 50. - Question 47 of 50
##### 47. Question

The curved surface of a sphere is 64 π cm

^{2}. Find its radius?Correct4 πr

^{2 }= 64 => r = 4Incorrect4 πr

^{2 }= 64 => r = 4 - Question 48 of 50
##### 48. Question

Kim can do a work in 3 days while David can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Kim?

CorrectKim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3

Kim’s share = 2/5 * 150 = Rs. 60IncorrectKim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3

Kim’s share = 2/5 * 150 = Rs. 60 - Question 49 of 50
##### 49. Question

2003 * 2004 – 2001 * 2002 = ?

Correct(2000 + 3)(2000 + 4) – (2000 + 1)(2000 + 2) = ?

Since (2000 * 2000) – (2000 * 2000) is equal to zero. ?

= (8000 + 6000 + 12) – (4000 + 2000 + 2)

=> ? = 14012 – 6002 = 8010Incorrect(2000 + 3)(2000 + 4) – (2000 + 1)(2000 + 2) = ?

Since (2000 * 2000) – (2000 * 2000) is equal to zero. ?

= (8000 + 6000 + 12) – (4000 + 2000 + 2)

=> ? = 14012 – 6002 = 8010 - Question 50 of 50
##### 50. Question

0.003 * ? * 0.0003 = 0.00000027

Correct0.003 * ? * 0.0003 = 0.00000027

3/1000 * ? * 3/10000 = 3/1000 * 3/1000 * 3/100

? = 3/10 = 0.3Incorrect0.003 * ? * 0.0003 = 0.00000027

3/1000 * ? * 3/10000 = 3/1000 * 3/1000 * 3/100

? = 3/10 = 0.3