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Aptitude Partnership Online Test, Free Aptitude Quiz, Online Aptitude Partnership Test. Aptitude Partnership Question and Answers 2020. Aptitude Partnership Quiz. Aptitude Partnership Free Mock Test 2020. Aptitude Partnership Question and Answers in PDF. The Aptitude Partnership online mock test paper is free for all students.The below Aptitude questions and answers can improve your skills in order to face the Interview, Competitive examination, Govt Exams and various entrance test with full confidence. Aptitude online test is very useful for exam preparation and getting for Rank. Aptitude Partnership Question and Answers in Hindi and English. Aptitude Partnership Mock test for topic via Online Mode. Here we are providing Aptitude Partnership Mock Test in Hindi. Now Test your self for “Aptitude Partnership Online Test in Hindi” Exam by using below quiz…
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A and B invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and A’s share is Rs. 855, the total profit is:
Let the total profit be Rs. 100.
After paying to charity, A’s share = Rs. (95 × 3/5) = Rs. 57.
If A’s share is Rs. 57, total profit = Rs. 100.
If A’s share Rs. 855, total profit = (100/57 × 855) = 1500.
Let the total profit be Rs. 100.
After paying to charity, A’s share = Rs. (95 × 3/5) = Rs. 57.
If A’s share is Rs. 57, total profit = Rs. 100.
If A’s share Rs. 855, total profit = (100/57 × 855) = 1500.
A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of B in the profit.
For managing, A received = 5% of Rs. 7400 = Rs. 370.
Balance = Rs. (7400 – 370) = Rs. 7030.
Ratio of their investments = (6500 × 6) : (8400 × 5) : (10000 × 3)
= 39000 : 42000 : 30000
= 13 : 14 : 10
∴ B’s share = Rs. (7030 × 14/37) = Rs. 2660.
For managing, A received = 5% of Rs. 7400 = Rs. 370.
Balance = Rs. (7400 – 370) = Rs. 7030.
Ratio of their investments = (6500 × 6) : (8400 × 5) : (10000 × 3)
= 39000 : 42000 : 30000
= 13 : 14 : 10
∴ B’s share = Rs. (7030 × 14/37) = Rs. 2660.
A, B and C enter into a partnership in the ratio 7/2 : 4/3 : 6/5. After 4 months, A increases his share 50%. If the total profit at the end of one year be Rs. 21,600, then B’s share in the profit is:
A, B, C subscribe Rs. 50,000 for a business. A subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 35,000, A receives:
Let C = x.
Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000
⇒ 3x = 36000
⇒ x = 12000
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
∴ A’s share = Rs. (35000 x 21 /50) = Rs. 14,700.
Let C = x.
Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000
⇒ 3x = 36000
⇒ x = 12000
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
∴ A’s share = Rs. (35000 x 21 /50) = Rs. 14,700.
Three partners shared the profit in a business in the ratio 5 : 7 : 8. They had partnered for 14 months, 8 months and 7 months respectively. What was the ratio of their investments?
Let their investments be Rs. x for 14 months, Rs. y for 8 months and Rs. z for 7 months respectively.
Let their investments be Rs. x for 14 months, Rs. y for 8 months and Rs. z for 7 months respectively.
A starts business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the capital?
Let B’s capital be Rs. x.
Then, (3500 × 12/7x = 2/3)
⇒ 14x = 126000
⇒ x = 9000.
Let B’s capital be Rs. x.
Then, (3500 × 12/7x = 2/3)
⇒ 14x = 126000
⇒ x = 9000.
A and B entered into partnership with capitals in the ratio 4 : 5. After 3 months, A withdrew 1/4 of his capital and B withdrew 1/5 of his capital. The gain at the end of 10 months was Rs. 760. A’s share in this profit is:
A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined then after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A, B and C?
Let the initial investments of A and B be 3x and 5x.
A : B : C = (3x × 12) : (5x × 12) : (5x × 6) = 36 : 60 : 30 = 6 : 10 : 5.
Let the initial investments of A and B be 3x and 5x.
A : B : C = (3x × 12) : (5x × 12) : (5x × 6) = 36 : 60 : 30 = 6 : 10 : 5.
A, B, C rent a pasture. A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs. 175, how much must C pay as his share of rent?
A : B : C = (10 x 7) : (12 x 5) : (15 x 3) = 70 : 60 : 45 = 14 : 12 : 9.
∴ C’s rent = Rs. (175 × 9/35) = Rs. 45.
A : B : C = (10 x 7) : (12 x 5) : (15 x 3) = 70 : 60 : 45 = 14 : 12 : 9.
∴ C’s rent = Rs. (175 × 9/35) = Rs. 45.
A and B started a business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months, C joined them with Rs. 20,000. What will be B’s share in total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business?
A : B : C = (20,000 × 24) : (15,000 × 24) : (20,000 × 18) = 4 : 3 : 3.
∴ B’s share = Rs. (25000 × 3/10) = Rs. 7,500.
A : B : C = (20,000 × 24) : (15,000 × 24) : (20,000 × 18) = 4 : 3 : 3.
∴ B’s share = Rs. (25000 × 3/10) = Rs. 7,500.
A began a business with Rs. 85,000. He was joined afterwards by B with Rs. 42,500. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1?
Suppose B joined for x months. Then,
Then, (85000 × 12/42500 × x = 3/1)
⇒ x = 85000 × 12/42500 × 3 = 8.
So, B joined for 8 months.
Suppose B joined for x months. Then,
Then, (85000 × 12/42500 × x = 3/1)
⇒ x = 85000 × 12/42500 × 3 = 8.
So, B joined for 8 months.
Aman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs.. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?
Aman : Rakhi : Sagar = (70,000 x 36) : (1,05,000 x 30) : (1,40,000 x 24) = 12 : 15 : 16.
Aman : Rakhi : Sagar = (70,000 x 36) : (1,05,000 x 30) : (1,40,000 x 24) = 12 : 15 : 16.
Arun, Kamal and Vinay invested Rs. 8000, Rs. 4000 and Rs. 8000 respectively in a business. Arun left after six months. If after eight months, there was a gain of Rs. 4005, then what will be the share of Kamal?
Arun : Kamal : Vinay = (8,000 x 6) : (4,000 x 8) : (8,000 x 8)
= 48 : 32 : 64
= 3 : 2 : 4.
∴ Kamal’s share = Rs. (4005 x 2/9) = Rs. 890.
Arun : Kamal : Vinay = (8,000 x 6) : (4,000 x 8) : (8,000 x 8)
= 48 : 32 : 64
= 3 : 2 : 4.
∴ Kamal’s share = Rs. (4005 x 2/9) = Rs. 890.
Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran’s share in the profit?
Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.
∴ Simran’s share = Rs. (24500 x 3/7) = Rs. 10,500.
Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.
∴ Simran’s share = Rs. (24500 x 3/7) = Rs. 10,500.
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
How much did Rohit get as profit at the yearend in the business done by Nitin, Rohit and Kunal?
I. Kunal invested Rs. 8000 for nine months, his profit was 3/2 times that of Rohit’s and his investment was four times that of Nitin.
II. Nitin and Rohit invested for one year in the proportion 1 : 2 respectively.
III. The three together got Rs. 1000 as profit at the year end.
I and II give:
K = Rs. (8000 × 9) for 1 month = Rs. 72000 for 1 month.
N = Rs. (1/4 × 8000 × 12) for 1 month = Rs. 24000 for 1 month.
R = Rs. 48000 for 1 month.
∴ K : N : R = 72000 : 24000 : 48000 = 3 : 1 : 2.
III gives, total profit = Rs. 1000.
∴ Rohit’s share = Rs. (1000 × 2/6) = Rs. 333.33 1
∴ Correct answer is (D).
I and II give:
K = Rs. (8000 × 9) for 1 month = Rs. 72000 for 1 month.
N = Rs. (1/4 × 8000 × 12) for 1 month = Rs. 24000 for 1 month.
R = Rs. 48000 for 1 month.
∴ K : N : R = 72000 : 24000 : 48000 = 3 : 1 : 2.
III gives, total profit = Rs. 1000.
∴ Rohit’s share = Rs. (1000 × 2/6) = Rs. 333.33 1
∴ Correct answer is (D).
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
What is R’s share of profit in a joit venture?
I. Q started business investing Rs. 80,000.
II. R joined him after 3 months.
III. P joined after 4 months with a capital of Rs. 1,20,000 and got Rs. 6000 as his share profit.
From I, II and III, we get P : Q : R = (120000 x 8) : (80000 x 12) : (x x 9).
Since R’s investment is not given, the above ratio cannot be give.
∴ Given data is inadequate.
From I, II and III, we get P : Q : R = (120000 x 8) : (80000 x 12) : (x x 9).
Since R’s investment is not given, the above ratio cannot be give.
∴ Given data is inadequate.
Each of these questions is followed by three statements. You have to study the question and all the three statements given to decide whether any information provided in the statement(s) is redundant and can be dispensed with while answering the given question.
Three friends, P, Q and R started a partnership business investing money in the ratio of 5 : 4 : 2 respectively for a period of 3 years. What is the amount received by P as his share profit?
I. Total amount invested in the business in Rs. 22,000.
II. Profit earned at the end of 3 years is 3/8 of the total investment.
III. The average amount of profit earned per year is Rs. 2750.
I and II give, profit after 3 years = Rs. (3/8 x 22000) = Rs. 8250.
From III also, profit after 3 years = Rs. (2750 x 3) = Rs. 8250.
∴ P’s share = Rs. (8250 x 5/11) = Rs. 3750.
Thus, (either III is redundant [or] I and II are redundant).
∴ Correct answer is (B).
I and II give, profit after 3 years = Rs. (3/8 x 22000) = Rs. 8250.
From III also, profit after 3 years = Rs. (2750 x 3) = Rs. 8250.
∴ P’s share = Rs. (8250 x 5/11) = Rs. 3750.
Thus, (either III is redundant [or] I and II are redundant).
∴ Correct answer is (B).
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
Ravi, Gagan and Nitin are running a business firm in partnership. What is Gagan’s share in the profit earned by them?
I. Ravi, Gagan and Nitin invested the amounts in the ratio of 2 : 4 : 7.
II. Nitin’s share in the profit is Rs. 8750.
Let us name Ravi, Gagan and Nitin by R, G and N respectively.
I. R : G : N = 2 : 4 : 7.
II. N = 8750..
From I and II, we get:
When N = 7, then G = 4.
When N = 8750, then G = (4/7 x 8750) = 5000.
Thus, both I and II are needed to get the answer.
∴ Correct answer is (E).
Let us name Ravi, Gagan and Nitin by R, G and N respectively.
I. R : G : N = 2 : 4 : 7.
II. N = 8750..
From I and II, we get:
When N = 7, then G = 4.
When N = 8750, then G = (4/7 x 8750) = 5000.
Thus, both I and II are needed to get the answer.
∴ Correct answer is (E).
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
Rahul, Anurag and Vivek started a business together. In what proportion would the annual profit be distributed among them?
I. Rahul got onefourth of the profit.
II. Rahul and Vivek contributed 75% of the total investment.
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SSC CHSL General Knowledge Online Test in Hindi Series 2, SSC CHSL GK Free Mock Test. SSC CHSL General Knowledge Series 2nd Online Test in Hindi. SSC CHSL GK Quiz 2020. The SSC CHSL General Knowledge Full online mock test paper is free for all students. Staff Selection Commission CHSL Exam Online test in Hindi Language. SSC CHSL online test is very useful for exam preparation and getting for Rank. SSC CHSL General Knowledge Series – 2nd Question and Answers in Hindi and English. SSC CHSL General Knowledge Mock test for Word Formation Topic Via Online Mode. Here we are providing SSC CHSL General Knowledge Full Mock Test in Hindi – Series 2nd. SSC CHSL General Knowledge Mock Test 2020. Now Test your self for “SSC CHSL General Knowledge Series – 2nd Online Test in Hindi” Exam by using below quiz…
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भारत निम्न में से किसका सदस्य नहीं है?
रियो हार की समीक्षा समिति का मुखिया कौन है ?
SAARC के सदस्य देशों की संख्या है –
किस शहर ने प्रथम BRICS फिल्म महोत्सव की मेजबानी की?
किस महिला खिलाड़ी ने सर्वाधिक ग्रैंड स्लैम मैच जीते हैं ?
निम्न में से किस देश की मुद्रा डॉलर है ?
साक्षी मलिक ने किस प्रतियोगिता में रियो ओलम्पिक में भारत को पहला पदक जिताया है ?
भगवान कृष्ण का जन्म कहाँ हुआ था ?
रांची निम्न में से किस राज्य की राजधानी है ?
हाइड्रोजन का रासायनिक प्रतीक क्या है ?
ताजमहल किस नदी के किनारे स्थित है ?
हाजी अली दरगाह किस शहर में है ?
संविधान की आठवीं अनुसूची में कौन सी भाषा शामिल नहीं है ?
राष्ट्रीय नाटक विद्यालय कहाँ है ?
हिंदी का पहला दैनिक समाचार पत्र कौन सा था ?
सुलुर एयरफोर्स स्टेशन कहाँ है?
भारत में इस समय कितने राज्य हैं ?
निम्न में से कौन सी नदी बंगाल की खाड़ी में नहीं गिरती ?
निम्नलिखित नदियों में से किस नदी को दक्षिण की गंगा कहा जाता है ?
अमरनाथ गुफ़ा जो भगवान शिव का स्थल है वह किस राज्य में है ?
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Computer Awareness Abbreviations Online Test in English Series 1. Computer Awareness Abbreviations Question for SBI, IBPS, Bank PO, Clerk Exams. Computer Awareness Abbreviations Series 1 Quiz for Bank PO’s and Clerk Exams 2020. Computer Awareness Abbreviations SBI PO & SBI Clerk online Quiz Series 1 in English. Computer Awareness Abbreviations Full online mock test paper is free for all students. Computer Awareness Abbreviations Free Online Tests in English Series 1. Computer Awareness Online Test is very helpful for all the candidates who appeared in Bank PO and Clerk Exams. Computer Awareness Abbreviations Question & Answers Online Mock Test Series 1 is Free. General Knowledge, General Quiz, SBI General Knowledge Online test in English Series 1 2020. Computer Awareness Abbreviations Question & Answers Very helpful for all students. Computer Awareness Abbreviations Full online mock test Series 1 in English and Free mock test paper.
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What is full form of ARPANET?
What is full form of USB ?
What is full form of ROM?
What is full form of ISDN?
What is meaning of FORTRAN?
In terms of network what is meaning of SAP?
What is full form of WWW?
What is full form of PHP?
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What is full form of PDF?
What is full form of CSS?
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What is full form of SOA?
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Computer abbreviation KBPS Means?
Computer abbreviation KB Means?
Computer abbreviation ESC Means?
Computer abbreviation DEL Means?
Computer abbreviation RTF Means?
Computer abbreviation IRC Means?
Computer abbreviation DB Means?
Computer abbreviation BPS Means?
Computer abbreviation BIT Means?
Computer abbreviation Y2K Means?
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Aptitude Problems on Trains Online Test, Free Aptitude Quiz, Online Aptitude Problems on Trains Test. Aptitude Problems on Trains Question and Answers 2020. Aptitude Problems on Trains Quiz. Aptitude Problems on Trains Free Mock Test 2020. Aptitude Problems on Trains Question and Answers in PDF. The Aptitude Problems on Trains online mock test paper is free for all students.The below Aptitude questions and answers can improve your skills in order to face the Interview, Competitive examination, Govt Exams and various entrance test with full confidence. Aptitude online test is very useful for exam preparation and getting for Rank. Aptitude Problems on Trains Question and Answers in Hindi and English. Aptitude Problems on Trains Mock test for topic via Online Mode. Here we are providing Aptitude Problems on Trains Mock Test in Hindi. Now Test your self for “Aptitude Problems on Trains Online Test in Hindi” Exam by using below quiz…
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A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:
A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is:
A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train?
A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Two, trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:
A train travelling at a speed of 75 mph enters a tunnel 3 1/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
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Aptitude Problems on Ages Online Test, Free Aptitude Quiz, Online Aptitude Problems on Ages Test. Aptitude Problems on Ages Question and Answers 2020. Aptitude Problems on Ages Quiz. Aptitude Problems on Ages Free Mock Test 2020. Aptitude Problems on Ages Question and Answers in PDF. The Aptitude Problems on Ages online mock test paper is free for all students.The below Aptitude questions and answers can improve your skills in order to face the Interview, Competitive examination, Govt Exams and various entrance test with full confidence. Aptitude online test is very useful for exam preparation and getting for Rank. Aptitude Problems on Ages Question and Answers in Hindi and English. Aptitude Problems on Ages Mock test for topic via Online Mode. Here we are providing Aptitude Problems on Ages Mock Test in Hindi. Now Test your self for “Aptitude Problems on Ages Online Test in Hindi” Exam by using below quiz…
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Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?
Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
∴ (4x + 8) = 5/2 (x + 8)
⇒ 8x + 16 = 5x + 40
⇒ 3x = 24
⇒ x = 8.
Hence, required ratio = (4x+16) / (x+16) = 48/24 = 2.
Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
∴ (4x + 8) = 5/2 (x + 8)
⇒ 8x + 16 = 5x + 40
⇒ 3x = 24
⇒ x = 8.
Hence, required ratio = (4x+16) / (x+16) = 48/24 = 2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
⇒ 5x = 20
⇒ x = 4.
∴ Age of the youngest child = x = 4 years.
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
⇒ 5x = 20
⇒ x = 4.
∴ Age of the youngest child = x = 4 years.
A father said to his son, “I was as old as you are at the present at the time of your birth”. If the father’s age is 38 years now, the son’s age five years back was:
Let the son’s present age be x years. Then, (38 – x) = x
⇒ 2x = 38.
⇒ x = 19.
∴ Son’s age 5 years back (19 – 5) = 14 years.
Let the son’s present age be x years. Then, (38 – x) = x
⇒ 2x = 38.
⇒ x = 19.
∴ Son’s age 5 years back (19 – 5) = 14 years.
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.
∴ (2x + 2) + 2x + x = 27
⇒ 5x = 25
⇒ x = 5.
Hence, B’s age = 2x = 10 years.
Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.
∴ (2x + 2) + 2x + x = 27
⇒ 5x = 25
⇒ x = 5.
Hence, B’s age = 2x = 10 years.
Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand’s present age in years?
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then, 5x+3 / 4x+3 = 11/9
⇒ 9(5x + 3) = 11(4x + 3)
⇒ 45x + 27 = 44x + 33
⇒ 45x – 44x = 33 – 27
⇒ x = 6.
∴ Anand’s present age = 4x = 24 years.
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then, 5x+3 / 4x+3 = 11/9
⇒ 9(5x + 3) = 11(4x + 3)
⇒ 45x + 27 = 44x + 33
⇒ 45x – 44x = 33 – 27
⇒ x = 6.
∴ Anand’s present age = 4x = 24 years.
A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
Let the son’s present age be x years. Then, man’s present age = (x + 24) years.
∴ (x + 24) + 2 = 2(x + 2)
⇒ x + 26 = 2x + 4
⇒ x = 22.
Let the son’s present age be x years. Then, man’s present age = (x + 24) years.
∴ (x + 24) + 2 = 2(x + 2)
⇒ x + 26 = 2x + 4
⇒ x = 22.
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar’s age at present?
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then,(6x+6)+4 / (5x+6)+4 = 11/10
⇒ 10(6x + 10) = 11(5x + 10)
⇒ 5x = 10
⇒ x = 2.
∴ Sagar’s present age = (5x + 6) = 16 years.
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then,(6x+6)+4 / (5x+6)+4 = 11/10
⇒ 10(6x + 10) = 11(5x + 10)
⇒ 5x = 10
⇒ x = 2.
∴ Sagar’s present age = (5x + 6) = 16 years.
The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be:
Let the present ages of son and father be x and (60 x) years respectively.
Then, (60 – x) – 6 = 5(x – 6)
⇒ 54 – x = 5x – 30
⇒ 6x = 84
⇒ x = 14.
∴ Son’s age after 6 years = (x+ 6) = 20 years..
Let the present ages of son and father be x and (60 x) years respectively.
Then, (60 – x) – 6 = 5(x – 6)
⇒ 54 – x = 5x – 30
⇒ 6x = 84
⇒ x = 14.
∴ Son’s age after 6 years = (x+ 6) = 20 years..
At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun’s age will be 26 years. What is the age of Deepak at present ?
Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,
4x + 6 = 26 ⇔ 4x = 20
x = 5.
∴ Deepak’s age = 3x = 15 years.
Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,
4x + 6 = 26 ⇔ 4x = 20
x = 5.
∴ Deepak’s age = 3x = 15 years.
Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin?
Let Rahul’s age be x years.
Then, Sachin’s age = (x – 7) years.
∴ x7/x = 7/9
⇒ 9x – 63 = 7x
⇒ 2x = 63
⇒ x = 31.5
Hence, Sachin’s age =(x – 7) = 24.5 years.
Let Rahul’s age be x years.
Then, Sachin’s age = (x – 7) years.
∴ x7/x = 7/9
⇒ 9x – 63 = 7x
⇒ 2x = 63
⇒ x = 31.5
Hence, Sachin’s age =(x – 7) = 24.5 years.
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
⇒ 20x = 80
⇒ x = 4.
∴ Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
⇒ 20x = 80
⇒ x = 4.
∴ Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Ayesha’s father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
Mother’s age when Ayesha’s brother was born = 36 years.
Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.
∴ Required difference = (42 – 36) years = 6 years.
Mother’s age when Ayesha’s brother was born = 36 years.
Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.
∴ Required difference = (42 – 36) years = 6 years.
A person’s present age is twofifth of the age of his mother. After 8 years, he will be onehalf of the age of his mother. How old is the mother at present?
Let the mother’s present age be x years.
Then, the person’s present age = (2/5x)years.
∴ (2/5x+8) = 1/2(x+8)
⇒ 2(2x + 40) = 5(x + 8)
⇒ x = 40.
Let the mother’s present age be x years.
Then, the person’s present age = (2/5x)years.
∴ (2/5x+8) = 1/2(x+8)
⇒ 2(2x + 40) = 5(x + 8)
⇒ x = 40.
Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q’s age?
Given that:
1. The difference of age b/w R and Q = The difference of age b/w Q and T.
2. Sum of age of R and T is 50 i.e. (R + T) = 50.
Question: R – Q = ?.
Explanation:
R – Q = Q – T
(R + T) = 2Q
Now given that, (R + T) = 50
So, 50 = 2Q and therefore Q = 25.
Question is (R – Q) = ?
Here we know the value(age) of Q (25), but we don’t know the age of R.
Therefore, (RQ) cannot be determined.
Given that:
1. The difference of age b/w R and Q = The difference of age b/w Q and T.
2. Sum of age of R and T is 50 i.e. (R + T) = 50.
Question: R – Q = ?.
Explanation:
R – Q = Q – T
(R + T) = 2Q
Now given that, (R + T) = 50
So, 50 = 2Q and therefore Q = 25.
Question is (R – Q) = ?
Here we know the value(age) of Q (25), but we don’t know the age of R.
Therefore, (RQ) cannot be determined.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. The ratio of their present ages is:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
⇒ 3x + 20 = 2x + 40
⇒ x = 20.
∴ Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
⇒ 3x + 20 = 2x + 40
⇒ x = 20.
∴ Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
What is Sonia’s present age?
I. Sonia’s present age is five times Deepak’s present age.
II. Five years ago her age was twentyfive times Deepak’s age at that time.
I. S = 5D D = S/5 ….(i)
II. S – 5 = 25 (D – 5) ⇔ S = 25D – 120 ….(ii)
Using (i) in (ii), we get S = (25 × S/5) – 120
⇒ 4S = 120.
⇒ S = 30.
Thus, I and II both together give the answer. So, correct answer is (E).
I. S = 5D D = S/5 ….(i)
II. S – 5 = 25 (D – 5) ⇔ S = 25D – 120 ….(ii)
Using (i) in (ii), we get S = (25 × S/5) – 120
⇒ 4S = 120.
⇒ S = 30.
Thus, I and II both together give the answer. So, correct answer is (E).
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
Average age of employees working in a department is 30 years. In the next year, ten workers will retire. What will be the average age in the next year?
I. Retirement age is 60 years.
II. There are 50 employees in the department.
I. Retirement age is 60 years.
II. There are 50 employees in the department.
Average age of 50 employees = 30 years.
Total age of 50 employees = (50 x 30) years = 1500 years.
Number of employees next year = 40.
Total age of 40 employees next year (1500 + 40 – 60 x 10) = 940.
Average age next year = 940/40 years = 23.5 years.
Thus, I and II together give the answer. So, correct answer is (E).
I. Retirement age is 60 years.
II. There are 50 employees in the department.
Average age of 50 employees = 30 years.
Total age of 50 employees = (50 x 30) years = 1500 years.
Number of employees next year = 40.
Total age of 40 employees next year (1500 + 40 – 60 x 10) = 940.
Average age next year = 940/40 years = 23.5 years.
Thus, I and II together give the answer. So, correct answer is (E).
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
Divya is twice as old as Shruti. What is the difference in their ages?
I. Five years hence, the ratio of their ages would be 9 : 5.
II. Ten years back, the ratio of their ages was 3 : 1.
Let Divya’s present age be D years and Shruti’s present age b S years
Then, D = 2 x S ⇔ D – 2S = 0 ….(i)
I. D + 5 / S + 5 = 9/5 ….(ii)
II. D – 10 / S – 10 = 3/1 ….(iii)
From (ii), we get : 5D + 25 = 9S + 45 ⇔ 5D – 9S = 20 ….(iv)
From (iii), we get : D – 10 = 3S – 30 ⇔ D – 3S = 20 ….(v)
Thus, from (i) and (ii), we get the answer.
Also, from (i) and (iii), we get the answer.
∴ I alone as well as II alone give the answer. Hence, the correct answer is (C).
Let Divya’s present age be D years and Shruti’s present age b S years
Then, D = 2 x S ⇔ D – 2S = 0 ….(i)
I. D + 5 / S + 5 = 9/5 ….(ii)
II. D – 10 / S – 10 = 3/1 ….(iii)
From (ii), we get : 5D + 25 = 9S + 45 ⇔ 5D – 9S = 20 ….(iv)
From (iii), we get : D – 10 = 3S – 30 ⇔ D – 3S = 20 ….(v)
Thus, from (i) and (ii), we get the answer.
Also, from (i) and (iii), we get the answer.
∴ I alone as well as II alone give the answer. Hence, the correct answer is (C).
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
What is Arun’s present age?
I. Five years ago, Arun’s age was double that of his son’s age at that time.
II. Present ages of Arun and his son are in the ratio of 11 : 6 respectively.
III. Five years hence, the respective ratio of Arun’s age and his son’s age will become 12 : 7.
I. 5 years ago, Arun’s age = 2 x His son’s age.
II. Let the present ages of Arun and his son be 11x and 6x years respectively.
III. 5 years hence, Arun’s Age / Son’s age = 12/7
Clearly, any two of the above will give Arun’s present age.
∴ Correct answer is (D).
I. 5 years ago, Arun’s age = 2 x His son’s age.
II. Let the present ages of Arun and his son be 11x and 6x years respectively.
III. 5 years hence, Arun’s Age / Son’s age = 12/7
Clearly, any two of the above will give Arun’s present age.
∴ Correct answer is (D).
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
What is Ravi’s present age?
I. The present age of Ravi is half of that of his father.
II. After 5 years, the ratio of Ravi’s age to that of his father’s age will be 6 : 11.
III. Ravi is 5 years younger than his brother.
I. Let Ravi’s present age be x years. Then, his father’s present age = 2x years.
II. After 5 years, Ravi’s age / Father’s age = 6/11
III. Ravi is younger than his brother.
From I and II, we get x + 5 / 2x + 5 = 6/11 . This gives x, the answer.
Thus, I and II together give the answer. Clearly, III is redundant.
Correct answer is (A).
I. Let Ravi’s present age be x years. Then, his father’s present age = 2x years.
II. After 5 years, Ravi’s age / Father’s age = 6/11
III. Ravi is younger than his brother.
From I and II, we get x + 5 / 2x + 5 = 6/11 . This gives x, the answer.
Thus, I and II together give the answer. Clearly, III is redundant.
Correct answer is (A).
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