C Programming Pointers Online Test, C Programming Online Test Series

C Programming Pointers Online Test

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C Programming Pointers Online Test. C Programming Question and Answers in English. C Programming Pointers Online mock test paper is free for all students and Very Helpful for Exam Preparation. C Programming Pointers Online Quiz. C Programming Online Mock test for Pointers Topic. Here we are providing C Programming Pointers Online Test Series in English. Check C Programming Mock Test Series 2021-2021.

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Question 1 of 30

1. Question
What is (void*)0?
- Representation of NULL pointer
- Representation of void pointer
- Error
- None of above
Correct

Incorrect
Question 2 of 30

2. Question
Can you combine the following two statements into one?
char *p; p = (char*) malloc(100);
- char p = *malloc(100);
- char *p = (char) malloc(100);
- char *p = (char*)malloc(100);
- char *p = (char *)(malloc*)(100);
Correct

Incorrect
Question 3 of 30

3. Question
In which header file is the NULL macro defined?
- stdio.h
- stddef.h
- stdio.h and stddef.h
- math.h
Correct

The macro “NULL” is defined in locale.h, stddef.h, stdio.h, stdlib.h, string.h, time.h, and wchar.h.

Incorrect

The macro “NULL” is defined in locale.h, stddef.h, stdio.h, stdlib.h, string.h, time.h, and wchar.h.
Question 4 of 30

4. Question
How many bytes are occupied by near, far and huge pointers (DOS)?
- near=2 far=4 huge=4
- near=4 far=8 huge=8
- near=2 far=4 huge=8
- near=4 far=4 huge=8
Correct

near=2, far=4 and huge=4 pointers exist only under DOS. Under windows and Linux every pointers is 4 bytes long.

Incorrect

near=2, far=4 and huge=4 pointers exist only under DOS. Under windows and Linux every pointers is 4 bytes long.
Question 5 of 30

5. Question
If a variable is a pointer to a structure, then which of the following operator is used to access data members of the structure through the pointer variable?
- .
- &
- *
- ->
Correct

Incorrect
Question 6 of 30

6. Question
What would be the equivalent pointer expression for referring the array element a[i][j][k][l]
- ((((a+i)+j)+k)+l)
- *(*(*(*(a+i)+j)+k)+l)
- (((a+i)+j)+k+l)
- ((a+i)+j+k+l)
Correct

Incorrect
Question 7 of 30

7. Question
A pointer is
- A keyword used to create variables
- A variable that stores address of an instruction
- A variable that stores address of other variable
- All of the above
Correct

Incorrect
Question 8 of 30

8. Question
The operator used to get value at address stored in a pointer variable is
- *
- &
- &&
- ||
Correct

Incorrect

Question 9 of 30

9. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    static char *s[] = {"black", "white", "pink", "violet"};
    char **ptr[] = {s+3, s+2, s+1, s}, ***p;
    p = ptr;
    ++p;
    printf("%s", **p+1);
    return 0;
}

Correct

Incorrect

Question 10 of 30

10. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    int i=3, *j, k;
    j = &i;
    printf("%d\n", i**j*i+*j);
    return 0;
}

Correct

Incorrect

Question 11 of 30

11. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    int x=30, *y, *z;
    y=&x; /* Assume address of x is 500 and integer is 4 byte size */
    z=y;
    *y++=*z++;
    x++;
    printf("x=%d, y=%d, z=%d\n", x, y, z);
    return 0;
}

x=31, y=502, z=502
x=31, y=500, z=500
x=31, y=498, z=498
x=31, y=504, z=504

Correct

Incorrect

Question 12 of 30

12. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    char str[20] = "Hello";
    char *const p=str;
    *p='M';
    printf("%s\n", str);
    return 0;
}

Mello
Hello
HMello
MHello

Correct

Incorrect

Question 13 of 30

13. Question

What will be the output of the program If the integer is 4bytes long?

#include<stdio.h>

int main()
{
    int ***r, **q, *p, i=8;
    p = &i;
    q = &p;
    r = &q;
    printf("%d, %d, %d\n", *p, **q, ***r);
    return 0;
}

8, 8, 8
4000, 4002, 4004
4000, 4004, 4008
4000, 4008, 4016

Correct

Incorrect

Question 14 of 30

14. Question

What will be the output of the program ?

#include<stdio.h>

void fun(void *p);
int i;

int main()
{
    void *vptr;
    vptr = &i;
    fun(vptr);
    return 0;
}
void fun(void *p)
{
    int **q;
    q = (int**)&p;
    printf("%d\n", **q);
}

Error: cannot convert from void** to int**
Garbage value
0
No output

Correct

Incorrect

Question 15 of 30

15. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    char *str;
    str = "%s";
    printf(str, "K\n");
    return 0;
}

Error
No output
K
%s

Correct

Incorrect

Question 16 of 30

16. Question

What will be the output of the program ?

#include<stdio.h>
int *check(static int, static int);

int main()
{
    int *c;
    c = check(10, 20);
    printf("%d\n", c);
    return 0;
}
int *check(static int i, static int j)
{
    int *p, *q;
    p = &i;
    q = &j;
    if(i >= 45)
        return (p);
    else
        return (q);
}

10
20
Error: Non portable pointer conversion
Error: cannot use static for function parameters

Correct

Incorrect

Question 17 of 30

17. Question
What will be the output of the program if the size of pointer is 4-bytes?
#include<stdio.h> int main() { printf("%d, %d\n", sizeof(NULL), sizeof("")); return 0; }
- 2, 1
- 2, 2
- 4, 1
- 4, 2
Correct

In TurboC, the output will be 2, 1 because the size of the pointer is 2 bytes in 16-bit platform.

But in Linux, the output will be 4, 1 because the size of the pointer is 4 bytes.

This difference is due to the platform dependency of C compiler.

Incorrect

In TurboC, the output will be 2, 1 because the size of the pointer is 2 bytes in 16-bit platform.

But in Linux, the output will be 4, 1 because the size of the pointer is 4 bytes.

This difference is due to the platform dependency of C compiler.

Question 18 of 30

18. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    void *vp;
    char ch=74, *cp="JACK";
    int j=65;
    vp=&ch;
    printf("%c", *(char*)vp);
    vp=&j;
    printf("%c", *(int*)vp);
    vp=cp;
    printf("%s", (char*)vp+2);
    return 0;
}

JCK
J65K
JAK
JACK

Correct

Incorrect

Question 19 of 30

19. Question

What will be the output of the program?

#include<stdio.h>

int main()
{
    int arr[2][2][2] = {10, 2, 3, 4, 5, 6, 7, 8};
    int *p, *q;
    p = &arr[1][1][1];
    q = (int*) arr;
    printf("%d, %d\n", *p, *q);
    return 0;
}

8, 10
10, 2
8, 1
Garbage values

Correct

Incorrect

Question 20 of 30

20. Question
What will be the output of the program assuming that the array begins at the location 1002 and size of an integer is 4 bytes?
#include<stdio.h> int main() { int a[3][4] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 }; printf("%u, %u, %u\n", a[0]+1, *(a[0]+1), *(*(a+0)+1)); return 0; }
- 448, 4, 4
- 520, 2, 2
- 1006, 2, 2
- Error
Correct

Incorrect

Question 21 of 30

21. Question

What will be the output of the program?

#include<stdio.h>

int main()
{
    int arr[3] = {2, 3, 4};
    char *p;
    p = arr;
    p = (char*)((int*)(p));
    printf("%d, ", *p);
    p = (int*)(p+1);
    printf("%d", *p);
    return 0;
}

2, 3
2, 0
2, Garbage value
0, 0

Correct

Incorrect

Question 22 of 30

22. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    char *str;
    str = "%d\n";
    str++;
    str++;
    printf(str-2, 300);
    return 0;
}

No output
30
3
300

Correct

Incorrect

Question 23 of 30

23. Question
What will be the output of the program ?
#include<stdio.h> int main() { printf("%c\n", 7["IndiaBIX"]); return 0; }
- Error: in printf
- Nothing will print
- print "X" of IndiaBIX
- print "7"
Correct

Incorrect

Question 24 of 30

24. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    char str[] = "peace";
    char *s = str;
    printf("%s\n", s++ +3);
    return 0;
}

peace
eace
ace
ce

Correct

Incorrect

Question 25 of 30

25. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    char *p;
    p="hello";
    printf("%s\n", *&*&p);
    return 0;
}

llo
hello
ello
h

Correct

Incorrect

Question 26 of 30

26. Question

What will be the output of the program assuming that the array begins at location 1002?

#include<stdio.h>

int main()
{
    int a[2][3][4] = { {1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 1, 2}, 
                       {2, 1, 4, 7, 6, 7, 8, 9, 0, 0, 0, 0} };
    printf("%u, %u, %u, %d\n", a, *a, **a, ***a);
    return 0;
}

1002, 2004, 4008, 2
2004, 4008, 8016, 1
1002, 1002, 1002, 1
Error

Correct

Incorrect

Question 27 of 30

27. Question

What will be the output of the program ?

#include<stdio.h>
power(int**);
int main()
{
    int a=5, *aa; /* Address of 'a' is 1000 */
    aa = &a;
    a = power(&aa);
    printf("%d\n", a);
    return 0;
}
power(int **ptr)
{
    int b;
    b = **ptr***ptr;
    return (b);
}

5
25
125
Garbage value

Correct

Incorrect

Question 28 of 30

28. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    char str1[] = "India";
    char str2[] = "BIX";
    char *s1 = str1, *s2=str2;
    while(*s1++ = *s2++)
        printf("%s", str1);

    printf("\n");
    return 0;
}

IndiaBIX
BndiaBIdiaBIXia
India
(null)

Correct

Incorrect

Question 29 of 30

29. Question

What will be the output of the program ?

#include<stdio.h>
#include<string.h>

int main()
{
    int i, n;
    char *x="Alice";
    n = strlen(x);
    *x = x[n];
    for(i=0; i<=n; i++)
    {
        printf("%s ", x);
        x++;
    }
    printf("\n", x);
    return 0;
}

Alice
ecilA
Alice lice ice ce e
lice ice ce e

Correct

If you compile and execute this program in windows platform with Turbo C, it will give “lice ice ce e”.

It may give different output in other platforms (depends upon compiler and machine). The online C compiler given in this site will give the Option C as output (it runs on Linux platform).

Incorrect

If you compile and execute this program in windows platform with Turbo C, it will give “lice ice ce e”.

It may give different output in other platforms (depends upon compiler and machine). The online C compiler given in this site will give the Option C as output (it runs on Linux platform).

Question 30 of 30

30. Question

What will be the output of the program ?

#include<stdio.h>

int main()
{
    int i, a[] = {2, 4, 6, 8, 10};
    change(a, 5);
    for(i=0; i<=4; i++)
        printf("%d, ", a[i]);
    return 0;
}
void change(int *b, int n)
{
    int i;
    for(i=0; i<n; i++)
        *(b+1) = *(b+i)+5;
}

7, 9, 11, 13, 15
2, 15, 6, 8, 10
2 4 6 8 10
3, 1, -1, -3, -5

Correct

Incorrect