Aptitude Time and Distance Online Test, Free Aptitude Quiz

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Question 1 of 15

1. Question

A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?

Correct

Incorrect

Question 2 of 15

2. Question

An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 2/3, it must travel at a speed of:

Correct

Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 2/3 hours as 5/3 hours]

Incorrect

Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 2/3 hours as 5/3 hours]

Question 3 of 15

3. Question

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

Correct

Let the actual distance travelled be x km.
Then, X/10 = X+20/14
⇒ 14x = 10x + 200
⇒ 4x = 200
⇒ x = 50 km.

Incorrect

Let the actual distance travelled be x km.
Then, X/10 = X+20/14
⇒ 14x = 10x + 200
⇒ 4x = 200
⇒ x = 50 km.

Question 4 of 15

4. Question

A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

Correct

Incorrect

Question 5 of 15

5. Question

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

Correct

Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/54 × 60) min = 10 min.

Incorrect

Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/54 × 60) min = 10 min.

Question 6 of 15

6. Question

In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:

Correct

Incorrect

Question 7 of 15

7. Question

A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

Correct

Incorrect

Question 8 of 15

8. Question

The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, then the speed of the first train is:

Correct

Incorrect

Question 9 of 15

9. Question

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:

Correct

Incorrect

Question 10 of 15

10. Question

A car travelling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car.

Correct

Incorrect

Question 11 of 15

11. Question

In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay’s speed is:

Correct

Let Abhay’s speed be x km/hr.
Then, 30/x – 30/2x = 3
⇒ 6x = 30
⇒ x = 5 km/hr.

Incorrect

Let Abhay’s speed be x km/hr.
Then, 30/x – 30/2x = 3
⇒ 6x = 30
⇒ x = 5 km/hr.

Question 12 of 15

12. Question

Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?

Correct

Let the distance travelled by x km.
Then, x/10 – x/15 = 2
⇒ 3x – 2x = 60
⇒ x = 60 km.
Time taken to travel 60 km at 10 km/hr = (60/10) hrs = 6 hrs.
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
Required speed = (60/5) kmph. = 12 kmph.

Incorrect

Let the distance travelled by x km.
Then, x/10 – x/15 = 2
⇒ 3x – 2x = 60
⇒ x = 60 km.
Time taken to travel 60 km at 10 km/hr = (60/10) hrs = 6 hrs.
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
Required speed = (60/5) kmph. = 12 kmph.

Question 13 of 15

13. Question

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is:

Correct

Let the speed of the train be x km/hr and that of the car be y km/hr.

Solving (i) and (ii), we get: x = 60 and y = 80.
∴ Ratio of speeds = 60 : 80 = 3 : 4.

Incorrect

Let the speed of the train be x km/hr and that of the car be y km/hr.

Solving (i) and (ii), we get: x = 60 and y = 80.
∴ Ratio of speeds = 60 : 80 = 3 : 4.

Question 14 of 15

14. Question

A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance travelled on foot is:

Correct

Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
So, x/4 + (61-x)/9 = 9
⇒ 9x + 4(61 -x) = 9 x 36
⇒ 5x = 80
⇒ x = 16 km.

Incorrect

Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
So, x/4 + (61-x)/9 = 9
⇒ 9x + 4(61 -x) = 9 x 36
⇒ 5x = 80
⇒ x = 16 km.

Question 15 of 15

15. Question

A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:

Correct

Let distance = x km and usual rate = y kmph.
Then, x/y – x/y+3 = 30/60 ⇒ 2y(y+3) = 9x…..(i)
And, x/y-2 – x/y = 40/60 ⇒ y(y-2) = 3x…..(ii)
On dividing (i) by (ii), we get: x = 40.

Incorrect

Let distance = x km and usual rate = y kmph.
Then, x/y – x/y+3 = 30/60 ⇒ 2y(y+3) = 9x…..(i)
And, x/y-2 – x/y = 40/60 ⇒ y(y-2) = 3x…..(ii)
On dividing (i) by (ii), we get: x = 40.