# Aptitude Time and Work Online Test, Time and Work Mock Test 2019

## Aptitude Time and Work Online Test, Free Aptitude Quiz

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Aptitude Time and Work Online Test, Free Aptitude Quiz, Online Aptitude Time and Work Test. Aptitude Time and Work Question and Answers 2019. Aptitude Time and Work Quiz. Aptitude Time and Work Free Mock Test 2019. **Aptitude Time and Work Question and Answers in PDF. **The Aptitude Time and Work online mock test paper is free for all students.The below Aptitude questions and answers can improve your skills in order to face the Interview, Competitive examination, Govt Exams and various entrance test with full confidence.** Aptitude online test** is very useful for exam preparation and getting for Rank. Aptitude Time and Work Question and Answers in Hindi and English. Aptitude Time and Work Mock test for topic via Online Mode. Here we are providing** Aptitude Time and Work Mock Test in Hindi**. Now Test your self for “**Aptitude Time and Work Online Test in Hindi**” Exam by using below quiz…

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- Question 1 of 25
##### 1. Question

A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

CorrectA’s 1 day’s work = 1/15 ;

B’s 1 day’s work = 1/20 ;

(A + B)’s 1 day’s work = (1/15 + 1/20) = 7/60

(A + B)’s 4 day’s work = (7/60 × 4) = 7/15

Therefore, Remaining work = (1-7/15) = 8/15IncorrectA’s 1 day’s work = 1/15 ;

B’s 1 day’s work = 1/20 ;

(A + B)’s 1 day’s work = (1/15 + 1/20) = 7/60

(A + B)’s 4 day’s work = (7/60 × 4) = 7/15

Therefore, Remaining work = (1-7/15) = 8/15 - Question 2 of 25
##### 2. Question

A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?

CorrectIncorrect - Question 3 of 25
##### 3. Question

A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:

CorrectRatio of times taken by A and B = 1 : 3.

The time difference is (3 – 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes (3/2 × 60) = 90 days.

So, A takes 30 days to do the work.

A’s 1 day’s work = 1/30

B’s 1 day’s work = 1/90

(A + B)’s 1 day’s work = (1/30 + 1/90) = 4/90 = 2/45

A and B together can do the work in 45/2 = 22.5 days.IncorrectRatio of times taken by A and B = 1 : 3.

The time difference is (3 – 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes (3/2 × 60) = 90 days.

So, A takes 30 days to do the work.

A’s 1 day’s work = 1/30

B’s 1 day’s work = 1/90

(A + B)’s 1 day’s work = (1/30 + 1/90) = 4/90 = 2/45

A and B together can do the work in 45/2 = 22.5 days. - Question 4 of 25
##### 4. Question

A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?

CorrectIncorrect - Question 5 of 25
##### 5. Question

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

CorrectLet 1 man’s 1 day’s work = x and 1 boy’s 1 day’s work = y.

Then, 6x + 8y = 1/10 and 26x + 48y = 1/2 .

Solving these two equations, we get : x = 1/100 and y = 1/200 .

(15 men + 20 boy)’s 1 day’s work = (15/100 + 20/200) = 1/4

∴ 15 men and 20 boys can do the work in 4 days.IncorrectLet 1 man’s 1 day’s work = x and 1 boy’s 1 day’s work = y.

Then, 6x + 8y = 1/10 and 26x + 48y = 1/2 .

Solving these two equations, we get : x = 1/100 and y = 1/200 .

(15 men + 20 boy)’s 1 day’s work = (15/100 + 20/200) = 1/4

∴ 15 men and 20 boys can do the work in 4 days. - Question 6 of 25
##### 6. Question

A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?

CorrectA’s 1 hour’s work = 1/4 ;

(B + C)’s 1 hour’s work = 1/3 ;

(A + C)’s 1 hour’s work = 1/2 .

(A + B + C)’s 1 hour’s work = (1/4 + 1/3) = 7/20

B’s 1 hour’s work = (7/12 – 1/2) = 1/12.

∴ B alone will take 12 hours to do the work.IncorrectA’s 1 hour’s work = 1/4 ;

(B + C)’s 1 hour’s work = 1/3 ;

(A + C)’s 1 hour’s work = 1/2 .

(A + B + C)’s 1 hour’s work = (1/4 + 1/3) = 7/20

B’s 1 hour’s work = (7/12 – 1/2) = 1/12.

∴ B alone will take 12 hours to do the work. - Question 7 of 25
##### 7. Question

A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:

Correct(A + B)’s 1 day’s work = 1/10

C’s 1 day’s work = 1/50

(A + B + C)’s 1 day’s work = (1/10 + 1/50) = 6/50 = 3/25 ….(i)

A’s 1 day’s work = (B + C)’s 1 day’s work …. (ii)

From (i) and (ii), we get: 2 x (A’s 1 day’s work) = 3/25

A’s 1 day’s work = 3/50 .

⇒ B’s 1 day’s work = (1/10 – 3/50) = 2/50 = 1/25.

∴ So, B alone could do the work in 25 days.Incorrect(A + B)’s 1 day’s work = 1/10

C’s 1 day’s work = 1/50

(A + B + C)’s 1 day’s work = (1/10 + 1/50) = 6/50 = 3/25 ….(i)

A’s 1 day’s work = (B + C)’s 1 day’s work …. (ii)

From (i) and (ii), we get: 2 x (A’s 1 day’s work) = 3/25

A’s 1 day’s work = 3/50 .

⇒ B’s 1 day’s work = (1/10 – 3/50) = 2/50 = 1/25.

∴ So, B alone could do the work in 25 days. - Question 8 of 25
##### 8. Question

A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?

CorrectWhole work is done by A in ( 20 x 5/4 ) = 25 days.

Now, (1 – 4/5) i.e., 1/5 work is done by A and B in 3 days.

Whole work will be done by A and B in (3 x 5) = 15 days.

A’s 1 day’s work = 1/25 , (A + B)’s 1 day’s work = 1/15 .

Therefore B’s 1 day’s work = (1/15 – 1/25) = 4/150 = 2/75.

So, B alone would do the work in 75/2 = 37.5 days.IncorrectWhole work is done by A in ( 20 x 5/4 ) = 25 days.

Now, (1 – 4/5) i.e., 1/5 work is done by A and B in 3 days.

Whole work will be done by A and B in (3 x 5) = 15 days.

A’s 1 day’s work = 1/25 , (A + B)’s 1 day’s work = 1/15 .

Therefore B’s 1 day’s work = (1/15 – 1/25) = 4/150 = 2/75.

So, B alone would do the work in 75/2 = 37.5 days. - Question 9 of 25
##### 9. Question

A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. All the machines are started at 9 A.M. while machine P is closed at 11 A.M. and the remaining two machines complete work. Approximately at what time will the work (to print one lakh books) be finished ?

CorrectIncorrect - Question 10 of 25
##### 10. Question

A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?

CorrectB’s 10 day’s work = (1/15 × 10) = 2/3

Remaining work = (1-2/3) = 1/3.

Now, 1/18 work is done by A in 1 day.

1/3 work is done by A in ( 18 x 1/3 ) = 6 days.IncorrectB’s 10 day’s work = (1/15 × 10) = 2/3

Remaining work = (1-2/3) = 1/3.

Now, 1/18 work is done by A in 1 day.

1/3 work is done by A in ( 18 x 1/3 ) = 6 days. - Question 11 of 25
##### 11. Question

4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?

CorrectLet 1 man’s 1 day’s work = x and 1 woman’s 1 day’s work = y.

Then, 4x + 6y = 1/8 and 3x + 7y = 1/10 .

Solving the two equations, we get: x = 11/400 , y = 1/400

∴ 1 woman’s 1 day’s work = 1/400 .

⇒ 10 women’s 1 day’s work = (1/400 × 10) = 1/40.

Hence, 10 women will complete the work in 40 days.IncorrectLet 1 man’s 1 day’s work = x and 1 woman’s 1 day’s work = y.

Then, 4x + 6y = 1/8 and 3x + 7y = 1/10 .

Solving the two equations, we get: x = 11/400 , y = 1/400

∴ 1 woman’s 1 day’s work = 1/400 .

⇒ 10 women’s 1 day’s work = (1/400 × 10) = 1/40.

Hence, 10 women will complete the work in 40 days. - Question 12 of 25
##### 12. Question

A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?

Correct(A + B)’s 20 day’s work = ( 1/30 x 20 ) = 2/3 .

Remaining work = ( 1 – 2/3 ) = 1/3 .

Now, 1/3 work is done by A in 20 days.

Therefore, the whole work will be done by A in (20 x 3) = 60 days.Incorrect(A + B)’s 20 day’s work = ( 1/30 x 20 ) = 2/3 .

Remaining work = ( 1 – 2/3 ) = 1/3 .

Now, 1/3 work is done by A in 20 days.

Therefore, the whole work will be done by A in (20 x 3) = 60 days. - Question 13 of 25
##### 13. Question

10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?

Correct1 woman’s 1 day’s work = 1/70

1 child’s 1 day’s work = 1/140

(5 women + 10 children)’s day’s work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7

∴ 5 women and 10 children will complete the work in 7 days.Incorrect1 woman’s 1 day’s work = 1/70

1 child’s 1 day’s work = 1/140

(5 women + 10 children)’s day’s work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7

∴ 5 women and 10 children will complete the work in 7 days. - Question 14 of 25
##### 14. Question

X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?

CorrectIncorrect - Question 15 of 25
##### 15. Question

A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?

CorrectRatio of times taken by A and B = 100 : 130 = 10 : 13.

Suppose B takes x days to do the work.

Then, 10 : 13 :: 23 : x ⇒ x = (23×13 / 10) ⇒ x = 299/10.

A’s 1 day’s work = 1/23 ;

B’s 1 day’s work = 10/299.

(A + B)’s 1 day’s work = (1/23 + 10/299) = 23/299 = 1/13.

Therefore, A and B together can complete the work in 13 days.IncorrectRatio of times taken by A and B = 100 : 130 = 10 : 13.

Suppose B takes x days to do the work.

Then, 10 : 13 :: 23 : x ⇒ x = (23×13 / 10) ⇒ x = 299/10.

A’s 1 day’s work = 1/23 ;

B’s 1 day’s work = 10/299.

(A + B)’s 1 day’s work = (1/23 + 10/299) = 23/299 = 1/13.

Therefore, A and B together can complete the work in 13 days. - Question 16 of 25
##### 16. Question

Ravi and Kumar are working on an assignment. Ravi takes 6 hours to type 32 pages on a computer, while Kumar takes 5 hours to type 40 pages. How much time will they take, working together on two different computers to type an assignment of 110 pages?

CorrectNumber of pages typed by Ravi in 1 hour = 32/6 = 16/3 .

Number of pages typed by Kumar in 1 hour = 40/5 = 8.

Number of pages typed by both in 1 hour = (16/3 + 8) = 40/3.

Time taken by both to type 110 pages = (110 × 3/40) hours

= 8 1/4 hours (or) 8 hours 15 minutes.IncorrectNumber of pages typed by Ravi in 1 hour = 32/6 = 16/3 .

Number of pages typed by Kumar in 1 hour = 40/5 = 8.

Number of pages typed by both in 1 hour = (16/3 + 8) = 40/3.

Time taken by both to type 110 pages = (110 × 3/40) hours

= 8 1/4 hours (or) 8 hours 15 minutes. - Question 17 of 25
##### 17. Question

Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:

CorrectRatio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.

Suppose Tanya takes x days to do the work.

5 : 4 :: 20 : x ⇒ x = (4 x 20/5)

⇒ x = 16 days.

Hence, Tanya takes 16 days to complete the work.IncorrectRatio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.

Suppose Tanya takes x days to do the work.

5 : 4 :: 20 : x ⇒ x = (4 x 20/5)

⇒ x = 16 days.

Hence, Tanya takes 16 days to complete the work. - Question 18 of 25
##### 18. Question

A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:

CorrectSuppose A, B and C take x, x/2 and x/3 days respectively to finish the work.

Then, (1/x + 2/x + 3/x) = 1/2

⇒ 6/x = 1/2

⇒ x = 12.

So, B takes (12/2) = 6 days to finish the work.IncorrectSuppose A, B and C take x, x/2 and x/3 days respectively to finish the work.

Then, (1/x + 2/x + 3/x) = 1/2

⇒ 6/x = 1/2

⇒ x = 12.

So, B takes (12/2) = 6 days to finish the work. - Question 19 of 25
##### 19. Question

A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :

Correct(A + B)’s 1 day’s work = (1/15 + 1/10) = 1/6

Work done by A and B in 2 days = (1/6 × 2) = 1/3.

Remaining work = (1 – 1/3) = 2/3

Now, 1/15 work is done by A in 1 day.

∴ 2/3 work will be done by a in (15 × 2/3) = 10 days.

Hence, the total time taken = (10 + 2) = 12 days.Incorrect(A + B)’s 1 day’s work = (1/15 + 1/10) = 1/6

Work done by A and B in 2 days = (1/6 × 2) = 1/3.

Remaining work = (1 – 1/3) = 2/3

Now, 1/15 work is done by A in 1 day.

∴ 2/3 work will be done by a in (15 × 2/3) = 10 days.

Hence, the total time taken = (10 + 2) = 12 days. - Question 20 of 25
##### 20. Question

A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?

CorrectIncorrect - Question 21 of 25
##### 21. Question

A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in :

CorrectRatio of rates of working of A and B = 2 : 1.

So, ratio of times taken = 1 : 2.

B’s 1 day’s work = 1/12 .

∴ A’s 1 day’s work = 1/6 ; (2 times of B’s work)

(A + B)’s 1 day’s work = (1/6 + 1/12) = 3/12 = 1/4.

So, A and B together can finish the work in 4 days.IncorrectRatio of rates of working of A and B = 2 : 1.

So, ratio of times taken = 1 : 2.

B’s 1 day’s work = 1/12 .

∴ A’s 1 day’s work = 1/6 ; (2 times of B’s work)

(A + B)’s 1 day’s work = (1/6 + 1/12) = 3/12 = 1/4.

So, A and B together can finish the work in 4 days. - Question 22 of 25
##### 22. Question

Twenty women can do a work in sixteen days. Sixteen men can complete the same work in fifteen days. What is the ratio between the capacity of a man and a woman?

Correct(20 x 16) women can complete the work in 1 day.

1 woman’s 1 day’s work = 1/320 .

(16 x 15) men can complete the work in 1 day.

1 man’s 1 day’s work = 1/240

So, required ratio = 1/240 : 1/320

= 1/3 : 1/4

= 4 : 3 (cross multiplied)Incorrect(20 x 16) women can complete the work in 1 day.

1 woman’s 1 day’s work = 1/320 .

(16 x 15) men can complete the work in 1 day.

1 man’s 1 day’s work = 1/240

So, required ratio = 1/240 : 1/320

= 1/3 : 1/4

= 4 : 3 (cross multiplied) - Question 23 of 25
##### 23. Question

A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in :

Correct(A + B + C)’s 1 day’s work = 1/6 ;

(A + B)’s 1 day’s work = 1/8 ;

(B + C)’s 1 day’s work = 1/12 .

So, A and C together will do the work in 8 days.Incorrect(A + B + C)’s 1 day’s work = 1/6 ;

(A + B)’s 1 day’s work = 1/8 ;

(B + C)’s 1 day’s work = 1/12 .

So, A and C together will do the work in 8 days. - Question 24 of 25
##### 24. Question

A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:

Correct(B + C)’s 1 day’s work = (1/9 + 1/12) = 7/36.

Work done by B and C in 3 days = (7/36 × 3) = 7/12.

Remaining work = (1-7/12) = 5/12.

Now, 1/24 work is done by A in 1 day.

So, 5/12 work is done by A in (24 × 5/12) = 10 days.Incorrect(B + C)’s 1 day’s work = (1/9 + 1/12) = 7/36.

Work done by B and C in 3 days = (7/36 × 3) = 7/12.

Remaining work = (1-7/12) = 5/12.

Now, 1/24 work is done by A in 1 day.

So, 5/12 work is done by A in (24 × 5/12) = 10 days. - Question 25 of 25
##### 25. Question

A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?

CorrectLet A’s 1 day’s work = x and B’s 1 day’s work = y.

Then, x + y = 1/30 and 16x + 44y = 1.

Solving these two equations, we get: x = 1/60 and y = 1/60

B’s 1 day’s work = 1/60 .

Hence, B alone shall finish the whole work in 60 days.IncorrectLet A’s 1 day’s work = x and B’s 1 day’s work = y.

Then, x + y = 1/30 and 16x + 44y = 1.

Solving these two equations, we get: x = 1/60 and y = 1/60

B’s 1 day’s work = 1/60 .

Hence, B alone shall finish the whole work in 60 days.