# DCCB Mock Test in English Series 3, DCCB Online Test Series 3

## DCCB Mock Test in English Series 3, DCCB Online Test Series 3

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**DCCB Mock Test in English Series 3, DCCB Online Test Series 3**, DCCB Free Online Test Series 3. RRB Exam Online Test 2020, DCCB Free Mock Test Exam 2020. DCCB Exam Free Online Quiz 2020, DCCB Full Online Mock Test **Series 3rd** in English. RRB Online Test for All Subjects, DCCB Free Mock Test Series in English. DCCB Free Mock Test **Series 3.** DCCB English Language Online Test in English **Series 3rd**. Our DCCB Staff Assistant Mock Test follows the exact Exam Pattern.**Series 3**. Here we are providing** DCCB Full Mock Test Paper in English. DCCB **Mock Test **Series 3rd** 2020. Now Test your self for DCCB Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

If the sides of a cube are in the ratio 4:3. What is the ratio of their diagonals?

Correcta

_{1}:a_{2}= 4:3

d_{1}:d_{2}= 4:3Incorrecta

_{1}:a_{2}= 4:3

d_{1}:d_{2}= 4:3 - Question 2 of 50
##### 2. Question

Find the one which does not belong to that group ?

CorrectY

^{+4}C^{-2}A^{+4}E^{-2}C, K^{+4}O^{-2}M^{+4}Q^{-2}O, P^{+4}T^{-2}R^{+3}U^{-1}T, G^{+4}K^{-2}I^{+4}M^{-2}K and D^{+4}H^{-2}F^{+4}J^{-2}H.

Except PTRUT, all other groups follow similar pattern.IncorrectY

^{+4}C^{-2}A^{+4}E^{-2}C, K^{+4}O^{-2}M^{+4}Q^{-2}O, P^{+4}T^{-2}R^{+3}U^{-1}T, G^{+4}K^{-2}I^{+4}M^{-2}K and D^{+4}H^{-2}F^{+4}J^{-2}H.

Except PTRUT, all other groups follow similar pattern. - Question 3 of 50
##### 3. Question

A man sells two articles for Rs.3600 each and he gains 30% on the first and loses 30% on the next. Find his total gain or loss?

Correct(30*30)/100 = 9%loss

Incorrect(30*30)/100 = 9%loss

- Question 4 of 50
##### 4. Question

How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction?

CorrectThe distance to be covered = Sum of their lengths = 200 + 300 = 500 m.

Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.

Time required = d/s = 500/10 = 50 sec.IncorrectThe distance to be covered = Sum of their lengths = 200 + 300 = 500 m.

Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.

Time required = d/s = 500/10 = 50 sec. - Question 5 of 50
##### 5. Question

I. a

^{2}– 7a + 12 = 0,

II. b^{2}– 3b + 2 = 0 to solve both the equations to find the values of a and b?CorrectI.(a – 3)(a – 4) = 0

=> a = 3, 4

II. (b – 2)(b – 1) = 0

=> b = 1, 2

=> a > bIncorrectI.(a – 3)(a – 4) = 0

=> a = 3, 4

II. (b – 2)(b – 1) = 0

=> b = 1, 2

=> a > b - Question 6 of 50
##### 6. Question

If an article is sold at 19% profit instead of 12% profit, then the profit would be Rs. 105 more. What is the cost price?

CorrectLet the cost price of an article be Rs. x.

(19% of x) – (12% of x) = 105

19x/100 – 12x/100 = 105 => 7x = 105 * 100

=> x = 1500

Cost price = Rs. 1500IncorrectLet the cost price of an article be Rs. x.

(19% of x) – (12% of x) = 105

19x/100 – 12x/100 = 105 => 7x = 105 * 100

=> x = 1500

Cost price = Rs. 1500 - Question 7 of 50
##### 7. Question

(64 + 9 + 9) / (2 * 20 + 1) = ?

Correct(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2

Incorrect(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2

- Question 8 of 50
##### 8. Question

All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?

CorrectB has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.

Quantity of water in B = 8k – 5k = 3k.

Quantity of water in container C = 8k – 3k = 5k

Container: A B C

Quantity of water: 8k 3k 5k

It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.

5k – 148 = 3k + 148 => 2k = 296 => k = 148

The initial quantity of water in A = 8k = 8 * 148 = 1184 liters.IncorrectB has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.

Quantity of water in B = 8k – 5k = 3k.

Quantity of water in container C = 8k – 3k = 5k

Container: A B C

Quantity of water: 8k 3k 5k

It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.

5k – 148 = 3k + 148 => 2k = 296 => k = 148

The initial quantity of water in A = 8k = 8 * 148 = 1184 liters. - Question 9 of 50
##### 9. Question

The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?

Correct2(3x + x) = 96

l = 36 b = 12

lb = 36 * 12 = 432Incorrect2(3x + x) = 96

l = 36 b = 12

lb = 36 * 12 = 432 - Question 10 of 50
##### 10. Question

The least number of five digits that have 144 their HCF is?

Correct144) 10000 (69

9936

——–

64

10000 + 144 – 64 = 10080Incorrect144) 10000 (69

9936

——–

64

10000 + 144 – 64 = 10080 - Question 11 of 50
##### 11. Question

x varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to:

CorrectGiven x = k/y

^{2}, where k is a constant.

Now, y = 2 and x = 1 gives k = 4.

x = 4/y^{2}=> x = 4/6^{2}, when

y = 6 => x = 4/36 = 1/9.IncorrectGiven x = k/y

^{2}, where k is a constant.

Now, y = 2 and x = 1 gives k = 4.

x = 4/y^{2}=> x = 4/6^{2}, when

y = 6 => x = 4/36 = 1/9. - Question 12 of 50
##### 12. Question

If the area of circle is 616 sq cm then its circumference?

Correct22/7 r

^{2}= 616 => r = 14

2 * 22/7 * 14 = 88Incorrect22/7 r

^{2}= 616 => r = 14

2 * 22/7 * 14 = 88 - Question 13 of 50
##### 13. Question

In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 5:6:2. If there are in all Rs.42, the number of 25 paisa coins is?

Correct5x 6x 2x

50 25 100

250x + 150x + 200x = 4200

600x = 4200

x = 7 => 6x = 42Incorrect5x 6x 2x

50 25 100

250x + 150x + 200x = 4200

600x = 4200

x = 7 => 6x = 42 - Question 14 of 50
##### 14. Question

A can finish a work in 18 days B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?

CorrectB’s 10 day’s work = 1/15 * 10 = 2/3

Remaining work = (1 – 2/3) = 1/3

Now, 1/18 work is done by A in 1 day.

1/3 work is done by A in (18 * 1/3) = 6 days.IncorrectB’s 10 day’s work = 1/15 * 10 = 2/3

Remaining work = (1 – 2/3) = 1/3

Now, 1/18 work is done by A in 1 day.

1/3 work is done by A in (18 * 1/3) = 6 days. - Question 15 of 50
##### 15. Question

A, B and C completed a piece of work, A worked for 6 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1480?

Correct3x 4x 5x

6 9 4

18x + 36x + 20x = 1480

74x = 1480 => x = 20

5x = 100 Rs.Incorrect3x 4x 5x

6 9 4

18x + 36x + 20x = 1480

74x = 1480 => x = 20

5x = 100 Rs. - Question 16 of 50
##### 16. Question

7394 – 1236 – 4652 = ?

CorrectIncorrect - Question 17 of 50
##### 17. Question

If x;Y = 5:2, then (8x + 9y):(8x + 2y) is :

CorrectLet x = 5k and y = 2k.

Then, (8x + 9y)/(8x + 2y)

= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22

(8x + 9y):(8x + 2y) = 29:22IncorrectLet x = 5k and y = 2k.

Then, (8x + 9y)/(8x + 2y)

= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22

(8x + 9y):(8x + 2y) = 29:22 - Question 18 of 50
##### 18. Question

A student scored an average of 80 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics?

CorrectGiven M + P + C = 80 * 3 = 240 — (1)

M + P = 90 * 2 = 180 — (2)

P + C = 70 * 2 = 140 — (3)

Where M, P and C are marks obtained by the student in Mathematics, Physics and Chemistry.

P = (2) + (3) – (1) = 180 + 140 – 240 = 80IncorrectGiven M + P + C = 80 * 3 = 240 — (1)

M + P = 90 * 2 = 180 — (2)

P + C = 70 * 2 = 140 — (3)

Where M, P and C are marks obtained by the student in Mathematics, Physics and Chemistry.

P = (2) + (3) – (1) = 180 + 140 – 240 = 80 - Question 19 of 50
##### 19. Question

Find the nearest to 25268 which is exactly divisible by 467?

CorrectIncorrect - Question 20 of 50
##### 20. Question

What is the difference between the compound interest on Rs.12000 at 20% p.a. for one year when compounded yearly and half yearly?

CorrectWhen compounded annually, interest

= 12000[1 + 20/100]^{1}– 12000 = Rs.2400

When compounded semi-annually, interest

= 12000[1 + 10/100]^{2}– 12000 = Rs.2520

Required difference = 2520 – 2400 = Rs.120IncorrectWhen compounded annually, interest

= 12000[1 + 20/100]^{1}– 12000 = Rs.2400

When compounded semi-annually, interest

= 12000[1 + 10/100]^{2}– 12000 = Rs.2520

Required difference = 2520 – 2400 = Rs.120 - Question 21 of 50
##### 21. Question

How many three letter words are formed using the letters of the word TIME?

CorrectThe number of letters in the given word is four.

The number of three letter words that can be formed using these four letters is ⁴P₃ = 4 * 3 * 2 = 24.IncorrectThe number of letters in the given word is four.

The number of three letter words that can be formed using these four letters is ⁴P₃ = 4 * 3 * 2 = 24. - Question 22 of 50
##### 22. Question

If p, q and r are positive integers and satisfy x = (p + q -r)/r = (p – q + r)/q = (q + r – p)/p, then the value of x is?

CorrectWhen two or more ratios are equal, each of the ratios are equal to sum of the numerators divided by the sum of the denominators, provided sum of the denominators is non-zero.

Hence, x = (p + q -r)/r = (p – q + r)/q = (q + r – p)/p

=> x = (p + q – r + p – q + r + q + r – p) / (r + q + p)

=> x = (r + q + p) / (r + q + p) = 1

p + q + r is non-zero.IncorrectWhen two or more ratios are equal, each of the ratios are equal to sum of the numerators divided by the sum of the denominators, provided sum of the denominators is non-zero.

Hence, x = (p + q -r)/r = (p – q + r)/q = (q + r – p)/p

=> x = (p + q – r + p – q + r + q + r – p) / (r + q + p)

=> x = (r + q + p) / (r + q + p) = 1

p + q + r is non-zero. - Question 23 of 50
##### 23. Question

If a: b = 3:4, b:c = 7:9, c:d = 5:7, find a:d?

Correcta/d = (3/4)*(7/9)*(5/7) => 5/12

Incorrecta/d = (3/4)*(7/9)*(5/7) => 5/12

- Question 24 of 50
##### 24. Question

Solve for m if 36 (6

^{m}) = (216)^{3m+4}Correct36 (6

^{m}) = (216)^{3m+4}=> 6^{2}6^{m}= (6^{3})^{3m+4}=> 6^{2+m}= 6^{9m+12}Equating powers of 6 on both sides.

m + 2 = 9m + 12 => -10 = 8m => m = -5/4Incorrect36 (6

^{m}) = (216)^{3m+4}=> 6^{2}6^{m}= (6^{3})^{3m+4}=> 6^{2+m}= 6^{9m+12}Equating powers of 6 on both sides.

m + 2 = 9m + 12 => -10 = 8m => m = -5/4 - Question 25 of 50
##### 25. Question

X men can do a work in 120 days. If there were 20 men less, the work would have taken 60 days more. What is the value of X?

CorrectWe have M

_{1}D_{1}= M_{2}D_{2}

120X = (X – 20)180

=> 2X = (X – 20) 3 => 2X = 3X – 60

=> X = 60IncorrectWe have M

_{1}D_{1}= M_{2}D_{2}

120X = (X – 20)180

=> 2X = (X – 20) 3 => 2X = 3X – 60

=> X = 60 - Question 26 of 50
##### 26. Question

Which of the following groups of fractions is in descending order?

CorrectThe fractions considered are 8/15 9/13 6/11

To compare them we make the denominators the same. So the fractions are

(8 * 13 * 11)/2145, (9 * 15 * 11)/2145 and (6 * 15 * 13)/2145

1144/2145, 1485/2145 and 1170/2145

so in descending order the fractions will be

1485/2145, 1170/2145 and 1144/2145 i.e., 9/13 , 6/11 , 8/15IncorrectThe fractions considered are 8/15 9/13 6/11

To compare them we make the denominators the same. So the fractions are

(8 * 13 * 11)/2145, (9 * 15 * 11)/2145 and (6 * 15 * 13)/2145

1144/2145, 1485/2145 and 1170/2145

so in descending order the fractions will be

1485/2145, 1170/2145 and 1144/2145 i.e., 9/13 , 6/11 , 8/15 - Question 27 of 50
##### 27. Question

The least number which when diminished by 7 is divisible by 21, 28, 36 and 45 is?

CorrectLCM = 1260

1260 + 7 = 1267IncorrectLCM = 1260

1260 + 7 = 1267 - Question 28 of 50
##### 28. Question

A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?

CorrectA runs 1000 m while B runs 900 m and C runs 800 m.

The number of meters that C runs when B runs 1000 m,

= (1000 * 800)/900 = 8000/9 = 888.88 m.

B can give C = 1000 – 888.88 = 111.12 m.IncorrectA runs 1000 m while B runs 900 m and C runs 800 m.

The number of meters that C runs when B runs 1000 m,

= (1000 * 800)/900 = 8000/9 = 888.88 m.

B can give C = 1000 – 888.88 = 111.12 m. - Question 29 of 50
##### 29. Question

64 boys and 40 girls form a group for social work. During their membership drive, same number of boys and girls joined the group. How many members does the group have now, if the ratio of boys to girls is 4 : 3?

CorrectLet us say x boys and x girls joined the group.

(64 + x) / (40 + x) = 4/3

192 + 3x = 160 + 4x => x = 32

Number of members in the group = 64 + x + 40 + x

= 104 + 2x = 168.IncorrectLet us say x boys and x girls joined the group.

(64 + x) / (40 + x) = 4/3

192 + 3x = 160 + 4x => x = 32

Number of members in the group = 64 + x + 40 + x

= 104 + 2x = 168. - Question 30 of 50
##### 30. Question

If the price has fallen by 10% what percent of its consumption be: increased so that the expenditure may be the same as before?

Correct100 – 10 = 90

90——10

100——? => 11 1/9%Incorrect100 – 10 = 90

90——10

100——? => 11 1/9% - Question 31 of 50
##### 31. Question

A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 350 m long platform?

CorrectLet the length of the train be x m.

When a train crosses an electric pole, the distance covered is its own length.

So, x = 12 * 36 * 5 /18 m = 120 m.

Time taken to cross the platform = (120 +350)/ 36 * 5/18 = 47 min.IncorrectLet the length of the train be x m.

When a train crosses an electric pole, the distance covered is its own length.

So, x = 12 * 36 * 5 /18 m = 120 m.

Time taken to cross the platform = (120 +350)/ 36 * 5/18 = 47 min. - Question 32 of 50
##### 32. Question

Two trains of equal length, running with the speeds of 60 and 40 kmph, take 50 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions?

CorrectRS = 60 -40 = 20 * 5/18 = 100/18

T = 50

D = 50 * 100/18 = 2500/9

RS = 60 + 40 = 100 * 5/18

T = 2500/9 * 18/500 = 10 secIncorrectRS = 60 -40 = 20 * 5/18 = 100/18

T = 50

D = 50 * 100/18 = 2500/9

RS = 60 + 40 = 100 * 5/18

T = 2500/9 * 18/500 = 10 sec - Question 33 of 50
##### 33. Question

The average salary of workers in an industry is Rs.200 the average salary of technicians being Rs.400 and that of non-technicians being Rs.125. What is the total number of workers?

CorrectIncorrect - Question 34 of 50
##### 34. Question

A can do a half of certain work in 70 days and B one third of the same in 35 days. They together will do the whole work in.

CorrectA = 140 days

B = 105 days

1/140 + 1/105 = 7/420 = 1/60

=>60 daysIncorrectA = 140 days

B = 105 days

1/140 + 1/105 = 7/420 = 1/60

=>60 days - Question 35 of 50
##### 35. Question

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the car is?

CorrectLet the speed of the train be x km/hr and that of the car be y km/hr.

Then, 120/x + 480/y = 8 or 1/x + 4/y = 1/15 — (i)

And, 200/x + 400/y = 25/3 or 1/x + 2/y = 1/24 — (ii)

Solving (i) and (ii), we get x = 60 and y = 80

Ratio of speeds = 60:80 = 3:4IncorrectLet the speed of the train be x km/hr and that of the car be y km/hr.

Then, 120/x + 480/y = 8 or 1/x + 4/y = 1/15 — (i)

And, 200/x + 400/y = 25/3 or 1/x + 2/y = 1/24 — (ii)

Solving (i) and (ii), we get x = 60 and y = 80

Ratio of speeds = 60:80 = 3:4 - Question 36 of 50
##### 36. Question

A man purchases 8 pens for Rs.9 and sells 9 pens for Rs.8, how much profit or loss does he make?

Correct

81 —- 17

100 —– ? è 20.98%lossIncorrect

81 —- 17

100 —– ? è 20.98%loss - Question 37 of 50
##### 37. Question

A and B can do a piece of work in 3 days, B and C in 4 days, C and A in 6 days. How long will C take to do it?

Correct2c = ¼ + 1/6 – 1/3 = 1/12

c = 1/24 => 24 daysIncorrect2c = ¼ + 1/6 – 1/3 = 1/12

c = 1/24 => 24 days - Question 38 of 50
##### 38. Question

Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case?

CorrectCalculate the differences, taking two numbers at a time as follows:

(215-47) = 168

(365-215) = 150

(365-47) = 318

HCF of 168, 150 and 318 we get 6, which is the greatest number, which while dividing 47, 215 and 365 gives the same remainder in each cases is 5.IncorrectCalculate the differences, taking two numbers at a time as follows:

(215-47) = 168

(365-215) = 150

(365-47) = 318

HCF of 168, 150 and 318 we get 6, which is the greatest number, which while dividing 47, 215 and 365 gives the same remainder in each cases is 5. - Question 39 of 50
##### 39. Question

Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.15 per cubic meter?

Correct22/7 * 14 * 3/2 * 3/2 = 99 m

^{2}

99 * 15 = 1485Incorrect22/7 * 14 * 3/2 * 3/2 = 99 m

^{2}

99 * 15 = 1485 - Question 40 of 50
##### 40. Question

[50 – {20 + 60% of (26/13 + 24/12 + 21) – 2} + 8] = 625/?

Correct[50 – {20 + 60% of (26/13 + 24/12 + 21) – 2} + 8] = 625/x => [50 – {20 + 3/5 of (25) – 2} + 8] = 625/x

=> [50 – 33 + 8] = 625/x => x = 25Incorrect[50 – {20 + 60% of (26/13 + 24/12 + 21) – 2} + 8] = 625/x => [50 – {20 + 3/5 of (25) – 2} + 8] = 625/x

=> [50 – 33 + 8] = 625/x => x = 25 - Question 41 of 50
##### 41. Question

The average marks in mathematics scored by the pupils of a school at the public examination were 39. If four of these pupils who actually scored 5, 12, 15 and 19 marks at the examination had not been sent up, the average marks for the school would have been 44. Find the number of pupils sent up for examination from the school?

Correct39x = 5 + 12 + 15 + 19 + (x – 4)44

x = 25Incorrect39x = 5 + 12 + 15 + 19 + (x – 4)44

x = 25 - Question 42 of 50
##### 42. Question

Surface area of two spheres are in the ratio 1:4 what is the ratio of their volumes?

CorrectIncorrect - Question 43 of 50
##### 43. Question

A tank 3 m long, 2 m wide and 1.5 m deep is dug in a field 20 m long and 14 m wide. If the earth dug out is evenly spread out over the field, the level of the field will raise by nearly?

CorrectIncorrect - Question 44 of 50
##### 44. Question

The average of five consecutive odd numbers is 61. What is the difference between the highest and lowest numbers?

CorrectLet the numbers x, x + 2, x + 4, x + 6 and x + 8

Then, [x + (x + 2) + (x + 4) + (x + 6) + (x + 8)]5 = 61

or 5x + 20 = 305 => x = 57

So, required difference = (57 + 8) – 57 = 8.IncorrectLet the numbers x, x + 2, x + 4, x + 6 and x + 8

Then, [x + (x + 2) + (x + 4) + (x + 6) + (x + 8)]5 = 61

or 5x + 20 = 305 => x = 57

So, required difference = (57 + 8) – 57 = 8. - Question 45 of 50
##### 45. Question

If the cost price of 50 articles is equal to the selling price of 40 articles, then the gain or loss percent is?

CorrectGiven that, cost price of 50 article is equal to selling price of 40 articles.

Let cost price of one article = Rs. 1

Selling price of 40 articles = Rs. 50

But Cost price of 40 articles = Rs. 40

Therefore, the trader made profit.\Percentage of profit = 10/40 * 100 = 25%IncorrectGiven that, cost price of 50 article is equal to selling price of 40 articles.

Let cost price of one article = Rs. 1

Selling price of 40 articles = Rs. 50

But Cost price of 40 articles = Rs. 40

Therefore, the trader made profit.\Percentage of profit = 10/40 * 100 = 25% - Question 46 of 50
##### 46. Question

The least number which when divided by 8, 12 and 16, leave in each remainder 3, is?

CorrectLCM = 48 + 3 = 51

IncorrectLCM = 48 + 3 = 51

- Question 47 of 50
##### 47. Question

(0.9 * 0.9 – 0.8 * 0.8)/1.7 = ?

CorrectAs numerator is of the form a

^{2}– b^{2}= (a + b) (a – b), so the given expression simplifying becomes

(0.9^{2}– 0.8^{2})/(0.9 + 0.8) (0.9 + 0.8) (0.9 – 0.8)/0.9 + 0.8 = 0.1IncorrectAs numerator is of the form a

^{2}– b^{2}= (a + b) (a – b), so the given expression simplifying becomes

(0.9^{2}– 0.8^{2})/(0.9 + 0.8) (0.9 + 0.8) (0.9 – 0.8)/0.9 + 0.8 = 0.1 - Question 48 of 50
##### 48. Question

If a number is chosen at random from the set {1, 2, 3, …., 100}, then the probability that the chosen number is a perfect cube is -.

CorrectWe have 1, 8, 27 and 64 as perfect cubes from 1 to 100.

Thus, the probability of picking a perfect cube is

4/100 = 1/25.IncorrectWe have 1, 8, 27 and 64 as perfect cubes from 1 to 100.

Thus, the probability of picking a perfect cube is

4/100 = 1/25. - Question 49 of 50
##### 49. Question

The price of a VCR is marked at Rs. 12,000. If successive discounts of 15%, 10% and 5% be allowed, then at what price does a customer buy it?

CorrectActual price = 95% of 90% of 85% of Rs. 12000

= 95/100 * 90/100 * 85/100 * 12000 = Rs. 8721.IncorrectActual price = 95% of 90% of 85% of Rs. 12000

= 95/100 * 90/100 * 85/100 * 12000 = Rs. 8721. - Question 50 of 50
##### 50. Question

Ravi can do a piece of work in 30 days while Prakash can do it in 40 days. In how many days will they finish it together?

Correct1/30 + 1/40 = 7/120

120/7 = 17 1/7 daysIncorrect1/30 + 1/40 = 7/120

120/7 = 17 1/7 days