# DCCB Mock Test in English Series 4, DCCB Online Test, DCCB MCQ

## DCCB Mock Test in English Series 4, DCCB Online Test Series 4

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DCCB Mock Test in English Series 4, DCCB Online Test Series 4, DCCB Free Online Test Series 4. RRB Exam Online Test 2020, DCCB Free Mock Test Exam 2020. DCCB Exam Free Online Quiz 2020, DCCB Full Online Mock Test **Series 4th** in English. RRB Online Test for All Subjects, DCCB Free Mock Test Series in English. DCCB Free Mock Test **Series 4.** DCCB English Language Online Test in English **Series 4th**. DCCB Quantitative Aptitude Quiz 2020, DCCB Reasoning Ability Free Online Test. Take DCCB Online Quiz. The DCCB Full online mock test paper is free for all students. DCCB Question and Answers in English and Hindi **Series 4**. Here we are providing** DCCB Full Mock Test Paper in English. DCCB **Mock Test **Series 4th** 2020. Now Test your self for DCCB Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years?

Correct160 = (180*4*R)/100

R = 5%Incorrect160 = (180*4*R)/100

R = 5% - Question 2 of 50
##### 2. Question

Varma can read a book in k minutes. What part of the book can he read in 8 minutes?(k>8)

CorrectPart of the book he can read in 1 minute = 1/k

Part of the book he can read in 8 minutes =8/k.IncorrectPart of the book he can read in 1 minute = 1/k

Part of the book he can read in 8 minutes =8/k. - Question 3 of 50
##### 3. Question

Solve for m if 36 (6

^{m}) = (216)^{3m+4}Correct36 (6

^{m}) = (216)^{3m+4}=> 6^{2}6^{m}= (6^{3})^{3m+4}=> 6^{2+m}= 6^{9m+12}Equating powers of 6 on both sides.

m + 2 = 9m + 12 => -10 = 8m => m = -5/4Incorrect36 (6

^{m}) = (216)^{3m+4}=> 6^{2}6^{m}= (6^{3})^{3m+4}=> 6^{2+m}= 6^{9m+12}Equating powers of 6 on both sides.

m + 2 = 9m + 12 => -10 = 8m => m = -5/4 - Question 4 of 50
##### 4. Question

A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?

CorrectAlong one edge, the number of small cubes that can be cut

= 100/10 = 10

Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut = 10 * 10 * 10 = 1000IncorrectAlong one edge, the number of small cubes that can be cut

= 100/10 = 10

Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut = 10 * 10 * 10 = 1000 - Question 5 of 50
##### 5. Question

7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/6 equals -.

Correct7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/16

= 7 + 5 – (3/2 * 1/4) * 2/7 + 7/2 * 1/16 = 7 + 5 – 3/28 + 7/32

= 12 + 3/28 + 7/32 = 12 + (7 * 7 – 3 * 8)/224

= 12 + 25/224 = 12 25/224Incorrect7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/16

= 7 + 5 – (3/2 * 1/4) * 2/7 + 7/2 * 1/16 = 7 + 5 – 3/28 + 7/32

= 12 + 3/28 + 7/32 = 12 + (7 * 7 – 3 * 8)/224

= 12 + 25/224 = 12 25/224 - Question 6 of 50
##### 6. Question

A, B and C are entered into a partnership. A invested Rs.6500 for 6 months, B invested Rs.8400 for 5 months and C invested for Rs.10000 for 3 months. A is a working partner and gets 5% of the total profit for the same. Find the share of C in a total profit of Rs.7400.

Correct65 * 6 : 84 * 5 : 100 * 3

26:28:20

C share = 74000 * 95/100 = 7030 * 20/74 => 1900Incorrect65 * 6 : 84 * 5 : 100 * 3

26:28:20

C share = 74000 * 95/100 = 7030 * 20/74 => 1900 - Question 7 of 50
##### 7. Question

An amount of Rs.1560 was divided among A, B and C in the ratio 1/2:1/3:1/4. Find the share of C?

CorrectLet the shares of A, B and C be a, b and c respectively.

a:b:c = 1/2:1/3:1/4

a:b:c = 6/12:4/12:3:12 = 6:4:3

Share of C = 3/13 * 1560 = Rs.360.IncorrectLet the shares of A, B and C be a, b and c respectively.

a:b:c = 1/2:1/3:1/4

a:b:c = 6/12:4/12:3:12 = 6:4:3

Share of C = 3/13 * 1560 = Rs.360. - Question 8 of 50
##### 8. Question

Some persons can do a piece of work in 12 days. Two times the number of these people will do half of that work in?

Correct12/ (2 * 2) = 3 days

Incorrect12/ (2 * 2) = 3 days

- Question 9 of 50
##### 9. Question

The number of sequences in which 7 players can throw a ball, so that the youngest player may not be the last is -.

Correctx Not younger_______ ↑

The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in ⁶P₆ ways.

The required number of ways = 6(6!) = 4320Incorrectx Not younger_______ ↑

The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in ⁶P₆ ways.

The required number of ways = 6(6!) = 4320 - Question 10 of 50
##### 10. Question

The length and breadth of a rectangle is increased by 10% and 25% respectively. What is the increase in the area?

Correct100 * 100 = 10000

110 * 125 = 13750

———–

3750

10000 —— 3750

100 ——- ? => 37.5%Incorrect100 * 100 = 10000

110 * 125 = 13750

———–

3750

10000 —— 3750

100 ——- ? => 37.5% - Question 11 of 50
##### 11. Question

Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 3 days?

CorrectA’s one day’s work = 1/30

B’s one day’s work = 1/45

(A + B)’s one day’s work = 1/30 + 1/45 = 1/18

The part of the work completed in 3 days = 3 (1/18) = 1/6.IncorrectA’s one day’s work = 1/30

B’s one day’s work = 1/45

(A + B)’s one day’s work = 1/30 + 1/45 = 1/18

The part of the work completed in 3 days = 3 (1/18) = 1/6. - Question 12 of 50
##### 12. Question

If 25% of x is 15 less than 15% of 1500, then x is?

Correct25% of x = x/4 ; 15% of 1500 = 15/100 * 1500 = 225

Given that, x/4 = 225 – 15 => x/4 = 210 => x = 840.Incorrect25% of x = x/4 ; 15% of 1500 = 15/100 * 1500 = 225

Given that, x/4 = 225 – 15 => x/4 = 210 => x = 840. - Question 13 of 50
##### 13. Question

A man engaged a servant on the condition that he would pay him Rs.900 and a uniform after one year service. He served only for 9 months and received uniform and Rs.650, find the price of the uniform?

Correct9/12 = 3/4 * 900 = 675

650

————-

25

1/4 ——– 25

1 ——— ? => Rs.100Incorrect9/12 = 3/4 * 900 = 675

650

————-

25

1/4 ——– 25

1 ——— ? => Rs.100 - Question 14 of 50
##### 14. Question

There is 60% increase in an amount in 6 years at S.I. What will be the C.I. of Rs. 12,000 after 3 years at the same rate?

CorrectLet P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R = (100 * 60)/(100 * 6) = 10% p.a.

Now, P = Rs. 12000, T = 3 years and R = 10% p.a.

C.I. = [12000 * {(1 + 10/100)^{3}– 1}]

= 12000 * 331/1000 = Rs. 3972IncorrectLet P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R = (100 * 60)/(100 * 6) = 10% p.a.

Now, P = Rs. 12000, T = 3 years and R = 10% p.a.

C.I. = [12000 * {(1 + 10/100)^{3}– 1}]

= 12000 * 331/1000 = Rs. 3972 - Question 15 of 50
##### 15. Question

How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?

CorrectSpeed of train relative to man = 63 – 3 = 60 km/hr.

= 60 * 5/18 = 50/3 m/sec.

Time taken to pass the man = 500 * 3/50 = 30 sec.IncorrectSpeed of train relative to man = 63 – 3 = 60 km/hr.

= 60 * 5/18 = 50/3 m/sec.

Time taken to pass the man = 500 * 3/50 = 30 sec. - Question 16 of 50
##### 16. Question

The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).

CorrectCalculated average height of 35 boys = 180 cm.

Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm

= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm

= 180 cm – 1.71 cm = 178.29 cm.IncorrectCalculated average height of 35 boys = 180 cm.

Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm

= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm

= 180 cm – 1.71 cm = 178.29 cm. - Question 17 of 50
##### 17. Question

There are two positive numbers in the ratio 5:8. If the larger number exceeds the smaller by 15, then find the smaller number?

CorrectLet the two positive numbers be 5x and 8x respectively.

8x – 5x = 15

3x = 15 => x = 5

=> Smaller number = 5x = 25.IncorrectLet the two positive numbers be 5x and 8x respectively.

8x – 5x = 15

3x = 15 => x = 5

=> Smaller number = 5x = 25. - Question 18 of 50
##### 18. Question

The area of a base of a cone is 30 cm

^{2}. If the height of the cone is 6cm, find its volume?Correctπr

^{2}= 30 h = 6

1/3 * 30 * 6 = 60Incorrectπr

^{2}= 30 h = 6

1/3 * 30 * 6 = 60 - Question 19 of 50
##### 19. Question

Excluding stoppages, the speed of a bus is 54 km/hr and including stoppages, it is 45 km/hr. For how many minutes does the bus stop per hour?

CorrectDue to stoppages, it covers 9 km less.

Time taken to cover 9 km = 9/54 * 60 = 10 min.IncorrectDue to stoppages, it covers 9 km less.

Time taken to cover 9 km = 9/54 * 60 = 10 min. - Question 20 of 50
##### 20. Question

What is the difference between the largest number and the least number written with the digits 7, 3, 1, 4?

Correct1347

7431

————

6084Incorrect1347

7431

————

6084 - Question 21 of 50
##### 21. Question

A man purchased 15 pens, 12 books, 10 pencils and 5 erasers. The cost of each pen is Rs.36, each book is Rs.45, each pencil is Rs.8, and the cost of each eraser is Rs.40 less than the combined costs of pen and pencil. Find the total amount spent?

CorrectIncorrect - Question 22 of 50
##### 22. Question

Subtracting 10% from X is the same as multiplying X by what number?

CorrectX – (10/100) X = X * ?

? = 90%IncorrectX – (10/100) X = X * ?

? = 90% - Question 23 of 50
##### 23. Question

What is the unit digit in 7

^{105}?CorrectUnit digit in 7

^{105}= unit digit in [(7^{4})^{26}* 7]

But, unit digit in (7^{4})^{26}= 1

unit digit in 7^{105}= (1 * 7) = 7IncorrectUnit digit in 7

^{105}= unit digit in [(7^{4})^{26}* 7]

But, unit digit in (7^{4})^{26}= 1

unit digit in 7^{105}= (1 * 7) = 7 - Question 24 of 50
##### 24. Question

Divide Rs.118000 among three persons A, B and C such that the ratio of the shares of A and B is 3:4 and that of B:C is 5:6?

CorrectCompound ratio of A:B:C

A:B = 3:4

B:C = 5:6

———-

A:B:C = 15:20:24

We can divide Rs.118000 in this ratio.

Share of A = 15/59 * 118000 = 30000

Share of B = 20/59 * 118000 = 40000

Share of C = 24/59 * 118000 = 48000IncorrectCompound ratio of A:B:C

A:B = 3:4

B:C = 5:6

———-

A:B:C = 15:20:24

We can divide Rs.118000 in this ratio.

Share of A = 15/59 * 118000 = 30000

Share of B = 20/59 * 118000 = 40000

Share of C = 24/59 * 118000 = 48000 - Question 25 of 50
##### 25. Question

A money lender finds that due to a fall in the annual rate of interest from 8% to 7 3/4 % his yearly income diminishes by Rs. 61.50, his capital is?

CorrectLet the capital be Rs. x. Then,

(x * 8 * 1)/100 – (x * 31/4 * 1/100) = 61.50

32x – 31x = 6150 * 4

x = 24,600.IncorrectLet the capital be Rs. x. Then,

(x * 8 * 1)/100 – (x * 31/4 * 1/100) = 61.50

32x – 31x = 6150 * 4

x = 24,600. - Question 26 of 50
##### 26. Question

(3

^{a+1}9^{a+2}27^{a}) / (3^{a-1}9^{a}27^{a+1}) = ?Correct(3

^{a+1}9^{a+2}27^{a}) / (3^{a-1}9^{a}27^{a+1}) = [3^{a+1}3^{2(a+2)}(3^{3})^{a}] / [3^{a-1}(3^{2})^{a}(3^{3})^{a+1}] = 3^{6a+5}/ 3^{6a+2}= 3^{3}= 27.Incorrect(3

^{a+1}9^{a+2}27^{a}) / (3^{a-1}9^{a}27^{a+1}) = [3^{a+1}3^{2(a+2)}(3^{3})^{a}] / [3^{a-1}(3^{2})^{a}(3^{3})^{a+1}] = 3^{6a+5}/ 3^{6a+2}= 3^{3}= 27. - Question 27 of 50
##### 27. Question

The ratio of the length and the breadth of a rectangle is 4 : 3 and the area of the rectangle is 6912 sq cm. Find the ratio of the breadth and the area of the rectangle?

CorrectLet the length and the breadth of the rectangle be 4x cm and 3x respectively.

(4x)(3x) = 6912

12x^{2}= 6912

x^{2}= 576 = 4 * 144 = 2^{2}* 12^{2}(x > 0)

=> x = 2 * 12 = 24

Ratio of the breadth and the areas = 3x : 12x^{2}= 1 : 4x = 1: 96.IncorrectLet the length and the breadth of the rectangle be 4x cm and 3x respectively.

(4x)(3x) = 6912

12x^{2}= 6912

x^{2}= 576 = 4 * 144 = 2^{2}* 12^{2}(x > 0)

=> x = 2 * 12 = 24

Ratio of the breadth and the areas = 3x : 12x^{2}= 1 : 4x = 1: 96. - Question 28 of 50
##### 28. Question

A rectangular field has area equal to 150 sq m and perimeter 50 m. Its length and breadth must be?

Correctlb = 150

2(l + b) = 50 => l + b = 25

l – b = 5

l = 15 b = 10Incorrectlb = 150

2(l + b) = 50 => l + b = 25

l – b = 5

l = 15 b = 10 - Question 29 of 50
##### 29. Question

After allowing a discount of 15% on the marked price, the selling price is Rs. 6800 for an article. If it was sold at marked price, there would have been a profit of 60%. The cost price of the article is?

CorrectGiven SP = Rs. 6800

Marked price = [SP(100)]/(100 – d%) = (6800 * 100)/(100 – 15) = Rs. 8000

If SP = Rs. 8000, profit = 60%

CP = [SP(100)]/(100 + 60) = (8000 * 100)/160 = Rs. 5000IncorrectGiven SP = Rs. 6800

Marked price = [SP(100)]/(100 – d%) = (6800 * 100)/(100 – 15) = Rs. 8000

If SP = Rs. 8000, profit = 60%

CP = [SP(100)]/(100 + 60) = (8000 * 100)/160 = Rs. 5000 - Question 30 of 50
##### 30. Question

Two trains of equal length, running with the speeds of 60 and 40 kmph, take 50 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions?

CorrectRS = 60 -40 = 20 * 5/18 = 100/18

T = 50

D = 50 * 100/18 = 2500/9

RS = 60 + 40 = 100 * 5/18

T = 2500/9 * 18/500 = 10 secIncorrectRS = 60 -40 = 20 * 5/18 = 100/18

T = 50

D = 50 * 100/18 = 2500/9

RS = 60 + 40 = 100 * 5/18

T = 2500/9 * 18/500 = 10 sec - Question 31 of 50
##### 31. Question

The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?

Correct2C + 3T = 1300 — (1)

3C + 3T = 1200 — (2)

Subtracting 2nd from 1st, we get

-C + T = 100 => T – C = 100Incorrect2C + 3T = 1300 — (1)

3C + 3T = 1200 — (2)

Subtracting 2nd from 1st, we get

-C + T = 100 => T – C = 100 - Question 32 of 50
##### 32. Question

The average of 35 students in a class is 16 years. The average age of 21 students is 14. What is the average age of remaining 14 students?

CorrectSum of the ages of 14 students

= (16 * 35) – (14 * 21) = 560 – 294 = 266

Required average = (266/14) = 19 years.IncorrectSum of the ages of 14 students

= (16 * 35) – (14 * 21) = 560 – 294 = 266

Required average = (266/14) = 19 years. - Question 33 of 50
##### 33. Question

96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?

Correctx/7 = y/9 => x:y = 7:9

7/16 * 96 = 42Incorrectx/7 = y/9 => x:y = 7:9

7/16 * 96 = 42 - Question 34 of 50
##### 34. Question

If p, q and r are positive integers and satisfy x = (p + q – r)/r = (p – q + r)/q = (q + r – p)/p, then the value of x is?

CorrectHence, x = (p + q – r)/r = (p – q + r)/q = (q + r – p)/p

=> x = (p + q – r + p – q + r + q + r – p)/(r + q + p)

=> x = (p + q + r)/(r + q + p) = 1.IncorrectHence, x = (p + q – r)/r = (p – q + r)/q = (q + r – p)/p

=> x = (p + q – r + p – q + r + q + r – p)/(r + q + p)

=> x = (p + q + r)/(r + q + p) = 1. - Question 35 of 50
##### 35. Question

At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years?

CorrectLet sum = x. Then, S.I. = 2x/5, Time = 10 years.

Rate = (100 * 2x) / (x * 5 * 10) = 4%IncorrectLet sum = x. Then, S.I. = 2x/5, Time = 10 years.

Rate = (100 * 2x) / (x * 5 * 10) = 4% - Question 36 of 50
##### 36. Question

Find the number of factors of 300 excluding 1 and itself.

Correct300 = 4.75 = 4.25.3 = 2

^{2}.5^{2}.3^{1}

Number of factors of 300 = (2 + 1)(2 + 1)(1 + 1) = 18.

There are 16 factors of 300 excluding 1 and itself.Incorrect300 = 4.75 = 4.25.3 = 2

^{2}.5^{2}.3^{1}

Number of factors of 300 = (2 + 1)(2 + 1)(1 + 1) = 18.

There are 16 factors of 300 excluding 1 and itself. - Question 37 of 50
##### 37. Question

Find the roots of quadratic equation: x

^{2}+ x – 42 = 0?Correctx

^{2}+ 7x – 6x + 42 = 0

x(x + 7) – 6(x + 7) = 0

(x + 7)(x – 6) = 0 => x = -7, 6Incorrectx

^{2}+ 7x – 6x + 42 = 0

x(x + 7) – 6(x + 7) = 0

(x + 7)(x – 6) = 0 => x = -7, 6 - Question 38 of 50
##### 38. Question

The average salary of workers in an industry is Rs.200 the average salary of technicians being Rs.400 and that of non-technicians being Rs.125. What is the total number of workers?

CorrectIncorrect - Question 39 of 50
##### 39. Question

Find the one which does not belong to that group ?

CorrectCrocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.

IncorrectCrocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.

- Question 40 of 50
##### 40. Question

The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages.

CorrectLet their present ages be 4x, 7x and 9x years respectively.

Then, (4x – 8) + (7x – 8) + (9x – 8) = 56

20x = 80 => x = 4

Their present ages are 16, 28 and 36 years respectively.IncorrectLet their present ages be 4x, 7x and 9x years respectively.

Then, (4x – 8) + (7x – 8) + (9x – 8) = 56

20x = 80 => x = 4

Their present ages are 16, 28 and 36 years respectively. - Question 41 of 50
##### 41. Question

Rs.800 amounts to Rs.920 in 3 years at simple interest. If the interest is increased by 3%, it would amount to how much?

Correct(800*3*3)/100 = 72

920 + 72 = 992Incorrect(800*3*3)/100 = 72

920 + 72 = 992 - Question 42 of 50
##### 42. Question

A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?

CorrectIncome = Rs. 100

Expenditure = Rs. 80

Savings = Rs. 20

Present Expenditure 80*(20/100) = Rs. 96

Present Savings = 100 – 96 =Rs. 4

100 —— 4

? ——— 200 => 5000IncorrectIncome = Rs. 100

Expenditure = Rs. 80

Savings = Rs. 20

Present Expenditure 80*(20/100) = Rs. 96

Present Savings = 100 – 96 =Rs. 4

100 —— 4

? ——— 200 => 5000 - Question 43 of 50
##### 43. Question

Find the one which does not belong to that group ?

CorrectExcept 4242, all other numbers are divisible by 11.

IncorrectExcept 4242, all other numbers are divisible by 11.

- Question 44 of 50
##### 44. Question

Which of the following number is divisible by 4 and 9?

CorrectFor a number to be divisible by 4, the number formed by the last two digits of that number must be divisible by 4.

For a number to be divisible by 9, the sum of its digits must be divisible by 9.

Among the choices, choices (a) and (b) are divisible by 4 but of the first two choices, only choice (b) is divisible by 9.

Hence choice (b) is divisible by both 4 and 9.IncorrectFor a number to be divisible by 4, the number formed by the last two digits of that number must be divisible by 4.

For a number to be divisible by 9, the sum of its digits must be divisible by 9.

Among the choices, choices (a) and (b) are divisible by 4 but of the first two choices, only choice (b) is divisible by 9.

Hence choice (b) is divisible by both 4 and 9. - Question 45 of 50
##### 45. Question

A certain sum of money is invested for one year at a certain rate of simple interest. If the rate of interest is 3% higher, then the invest earned will be 25% more than the interest earned earlier. What is the earlier rate of interest?

CorrectIf the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate.

Let the earlier rate of interest be x%.

Now it will be (x + 3)%

% increase = (x + 3) – x/x * 100 = 25

=> x = 12IncorrectIf the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate.

Let the earlier rate of interest be x%.

Now it will be (x + 3)%

% increase = (x + 3) – x/x * 100 = 25

=> x = 12 - Question 46 of 50
##### 46. Question

How many figures are required to number the pages the pages of a book containing 365 pages?

Correct1 to 9 = 9 * 1 = 9

10 to 99 = 90 * 2 = 180

100 to 365 = 266 * 3 = 798

———–

987Incorrect1 to 9 = 9 * 1 = 9

10 to 99 = 90 * 2 = 180

100 to 365 = 266 * 3 = 798

———–

987 - Question 47 of 50
##### 47. Question

A 180 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train?

CorrectS = 180/6 * 18/5 = 108 kmph

IncorrectS = 180/6 * 18/5 = 108 kmph

- Question 48 of 50
##### 48. Question

Ten percent of Ram’s monthly salary is equal to eight percent of Shyam’s monthly salary. Shyam’s monthly salary is twice Abhinav’s monthly salary. If Abhinav’s annual salary is Rs. 1.92 lakhs, find Ram’s monthly salary?

CorrectLet the monthly salaries of Ram and Shyam be Rs. r and Rs. s respectively.

10/100 r = 8/100 s

r = 4/5 s

Monthly salary of Abhinav = (1.92 lakhs)/12 = Rs. 0.16 lakhs

s = 2(0.16 lakhs) = 0.32 lakhs

r = 4/5(0.32 lakhs) = Rs. 25600IncorrectLet the monthly salaries of Ram and Shyam be Rs. r and Rs. s respectively.

10/100 r = 8/100 s

r = 4/5 s

Monthly salary of Abhinav = (1.92 lakhs)/12 = Rs. 0.16 lakhs

s = 2(0.16 lakhs) = 0.32 lakhs

r = 4/5(0.32 lakhs) = Rs. 25600 - Question 49 of 50
##### 49. Question

In what time a sum of money double itself at 3% per annum simple interest?

CorrectP = (P*3*R)/100

R = 33 1/3%IncorrectP = (P*3*R)/100

R = 33 1/3% - Question 50 of 50
##### 50. Question

The number of ways in which six boys and six girls can be seated in a row for a photograph so that no two girls sit together is -.

CorrectWe can initially arrange the six boys in 6! ways.

Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.

Hence required number of ways = 6! * ⁷P₆IncorrectWe can initially arrange the six boys in 6! ways.

Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.

Hence required number of ways = 6! * ⁷P₆