# DCCB Online Test Series 2, DCCB Mock Test in English Series 2

## DCCB Online Test Series 2, DCCB Mock Test in English Series 2

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DCCB Online Test Series 2, DCCB Mock Test in English Series 2, DCCB Free Online Test Series 2. RRB Exam Online Test 2019, DCCB Free Mock Test Exam 2019. DCCB Exam Free Online Quiz 2019, DCCB Full Online Mock Test **Series 2nd** in English. RRB Online Test for All Subjects, DCCB Free Mock Test Series in English. DCCB Free Mock Test **Series 2.** DCCB English Language Online Test in English **Series 2nd**. DCCB Quantitative Aptitude Quiz 2019, DCCB Reasoning Ability Free Online Test. Take DCCB Online Quiz. The DCCB Full online mock test paper is free for all students. DCCB Question and Answers in English and Hindi **Series 2**. Here we are providing** DCCB Full Mock Test Paper in English. DCCB **Mock Test **Series 2nd** 2019. Now Test your self for DCCB Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?

CorrectRelative speed of the thief and policeman = 11 – 10 = 1 km/hr.

Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.

Distance between the thief and policeman = 200 – 100 = 100 m.IncorrectRelative speed of the thief and policeman = 11 – 10 = 1 km/hr.

Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.

Distance between the thief and policeman = 200 – 100 = 100 m. - Question 2 of 50
##### 2. Question

If 10% of x = 20% of y, then x:y is equal to:

Correct10% of x = 20% of y

10x/100 = 20y/100 => x/10 = y/5

x/y = 10/5 = 2/1

x:y = 2:1.Incorrect10% of x = 20% of y

10x/100 = 20y/100 => x/10 = y/5

x/y = 10/5 = 2/1

x:y = 2:1. - Question 3 of 50
##### 3. Question

The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?

Correct2x * x = 128 => x= 8

Incorrect2x * x = 128 => x= 8

- Question 4 of 50
##### 4. Question

A water tank is two-fifth full. Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes. If both the pipes are open, how long will it take to empty or fill the tank completely?

CorrectClearly, pipe B is faster than pipe A and so, the tank will be emptied.

Part to be emptied = 2/5

Part emptied by (A + B) in 1 minute = (1/6 – 1/10) = 1/15

1/15 : 2/5 :: 1 : x

x = (2/5 * 1 * 15) = 6 min.

So, the tank will be emptied in 6 min.IncorrectClearly, pipe B is faster than pipe A and so, the tank will be emptied.

Part to be emptied = 2/5

Part emptied by (A + B) in 1 minute = (1/6 – 1/10) = 1/15

1/15 : 2/5 :: 1 : x

x = (2/5 * 1 * 15) = 6 min.

So, the tank will be emptied in 6 min. - Question 5 of 50
##### 5. Question

LCM of 1/3, 5/6, 5/4, 10/7 is:

CorrectLCM of numerators = 10

HCF of denominators = 1

=> 10/1 = 10IncorrectLCM of numerators = 10

HCF of denominators = 1

=> 10/1 = 10 - Question 6 of 50
##### 6. Question

(830 + ? * 3 * 14 / 100) – (830 * 14 * 3 / 100) = 20.16

Correct(830 + ? * 3 * 14 / 100) – (830 * 14 * 3 / 100) = 20.16

=> 830 + ? * 42 – 830 * 42 = 2018

=> ? * 42 = 2018 + 830 * 42 – 830

=> ? * 42 = 42 * 48 + 830 * 42 – 830

=> ? = 48 + 830 – (830 / 42)

=> ? = 48 + 830 – 19.76

=> ? = 858.24Incorrect(830 + ? * 3 * 14 / 100) – (830 * 14 * 3 / 100) = 20.16

=> 830 + ? * 42 – 830 * 42 = 2018

=> ? * 42 = 2018 + 830 * 42 – 830

=> ? * 42 = 42 * 48 + 830 * 42 – 830

=> ? = 48 + 830 – (830 / 42)

=> ? = 48 + 830 – 19.76

=> ? = 858.24 - Question 7 of 50
##### 7. Question

What is the are of an equilateral triangle of side 16 cm?

CorrectArea of an equilateral triangle = √3/4 S

^{2}

If S = 16, Area of triangle = √3/4 * 16 * 16 = 64√3 cm^{2};IncorrectArea of an equilateral triangle = √3/4 S

^{2}

If S = 16, Area of triangle = √3/4 * 16 * 16 = 64√3 cm^{2}; - Question 8 of 50
##### 8. Question

Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill cistern. How much time will be taken by A to fill the cistern separately?

CorrectLet the cistern be filled by pipe A alone in x hours.

Then, pipe B will fill it in (x + 6) hours.

1/x + 1/(x + 6) = 1/4

x^{2}– 2x – 24 = 0

(x – 6)(x + 4) = 0 => x = 6.IncorrectLet the cistern be filled by pipe A alone in x hours.

Then, pipe B will fill it in (x + 6) hours.

1/x + 1/(x + 6) = 1/4

x^{2}– 2x – 24 = 0

(x – 6)(x + 4) = 0 => x = 6. - Question 9 of 50
##### 9. Question

A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?

Correct90%

104%

——–

14% —- 140

100% —- ? => Rs.1000Incorrect90%

104%

——–

14% —- 140

100% —- ? => Rs.1000 - Question 10 of 50
##### 10. Question

The area of a square is 4096 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square.

CorrectLet the length and the breadth of the rectangle be l cm and b cm respectively. Let the side of the square be a cm.

a2 = 4096 = 2^{12}

a = (2^{12})^{1/2}= 2^{6}= 64

L = 2a and b = a – 24

b : l = a – 24 : 2a = 40 : 128 = 5 : 16IncorrectLet the length and the breadth of the rectangle be l cm and b cm respectively. Let the side of the square be a cm.

a2 = 4096 = 2^{12}

a = (2^{12})^{1/2}= 2^{6}= 64

L = 2a and b = a – 24

b : l = a – 24 : 2a = 40 : 128 = 5 : 16 - Question 11 of 50
##### 11. Question

9 men and 12 boys finish a job in 12 days, 12 men and 12 boys finish it in 10 days. 10 men and 10 boys shall finish it in how many days?

Correct9M + 12B —– 12 days

12M + 12B ——- 10 days

10M + 10B ——-?

108M + 144B = 120M +120B

24B = 12M => 1M = 2B

18B + 12B = 30B —- 12 days

20B + 10B = 30B —–? => 12 daysIncorrect9M + 12B —– 12 days

12M + 12B ——- 10 days

10M + 10B ——-?

108M + 144B = 120M +120B

24B = 12M => 1M = 2B

18B + 12B = 30B —- 12 days

20B + 10B = 30B —–? => 12 days - Question 12 of 50
##### 12. Question

A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work?

CorrectLet A worked for x days.

x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18

A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days.IncorrectLet A worked for x days.

x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18

A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days. - Question 13 of 50
##### 13. Question

150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?

CorrectRate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day

Let us say 70 men take x days to consume 150 kg.

Quantity consumed by each item in x days = 7x/30 kg.

Quantity consumed by 70 men in x days = (7x/30)(70)kg

(7x/30)(70) = 980

x = (980 * 30)/490 => x = 60 daysIncorrectRate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day

Let us say 70 men take x days to consume 150 kg.

Quantity consumed by each item in x days = 7x/30 kg.

Quantity consumed by 70 men in x days = (7x/30)(70)kg

(7x/30)(70) = 980

x = (980 * 30)/490 => x = 60 days - Question 14 of 50
##### 14. Question

The salary of a worker is first increased by 30% and afterwards reduced by 30%. What is net change in his salary?

Correct(30 * 30)/100 = 9% decrease

Incorrect(30 * 30)/100 = 9% decrease

- Question 15 of 50
##### 15. Question

A train passes a man standing on the platform. If the train is 170 meters long and its speed is 72 kmph, how much time it took in doing so?

CorrectD = 170

S = 72 * 5/18 = 20 mps

T = 170/20 = 8 ½ secIncorrectD = 170

S = 72 * 5/18 = 20 mps

T = 170/20 = 8 ½ sec - Question 16 of 50
##### 16. Question

A lends Rs. 2500 to B and a certain to C at the same time at 7% p.a. simple interest. If after 4 years, A altogether receives Rs. 1120 as interest from B and C, then the sum lent to C is?

CorrectLet the sum lent to C be Rs. x. Then,

(2500 * 7 * 4) / 100 + (x * 7 * 4) / 100 = 1120

7/25 x = (1120 – 700) => x = 1500IncorrectLet the sum lent to C be Rs. x. Then,

(2500 * 7 * 4) / 100 + (x * 7 * 4) / 100 = 1120

7/25 x = (1120 – 700) => x = 1500 - Question 17 of 50
##### 17. Question

The smallest ratio out of 1:1, 2:1, 1:3 and 3:1 is?

CorrectIncorrect - Question 18 of 50
##### 18. Question

Find the fraction which has the same ratio to 2/13 that 5/34 has to 7/48.

CorrectP : 2/13 = 5/34 : 7/48

As the product of the means is equal to the product of the extremes.

P*7/48 = 2/13 * 5/34

P*7/48 = 10/442

P = 480/3094 => P = 240/1547IncorrectP : 2/13 = 5/34 : 7/48

As the product of the means is equal to the product of the extremes.

P*7/48 = 2/13 * 5/34

P*7/48 = 10/442

P = 480/3094 => P = 240/1547 - Question 19 of 50
##### 19. Question

A train travelled from station P to Q in 8 hours and came back from station Q to P is 6 hours. What would be the ratio of the speed of the train while traveling from station P to Q to that from station Q to P?

CorrectSince S # 1/t

S_{1}: S_{2}= 1/t_{1}: 1/t_{2}= 1/8 : 1/6 = 3 : 4IncorrectSince S # 1/t

S_{1}: S_{2}= 1/t_{1}: 1/t_{2}= 1/8 : 1/6 = 3 : 4 - Question 20 of 50
##### 20. Question

A certain sum amounts to Rs.1725 in 3 years and Rs.1875 in 5 years. Find the rate % per annum?

Correct3 — 1725

5 — 1875

————–

2 — 150

N = 1 I = 75 R = ?

P = 1725 – 225 = 1500

75 = (1500*1*R)/100

R = 5%Incorrect3 — 1725

5 — 1875

————–

2 — 150

N = 1 I = 75 R = ?

P = 1725 – 225 = 1500

75 = (1500*1*R)/100

R = 5% - Question 21 of 50
##### 21. Question

The volumes of two cones are in the ratio 1 : 10 and the radii of the cones are in the ratio of 1 : 2. What is the length of the wire?

CorrectThe volume of the cone = (1/3)πr

^{2}h

Only radius (r) and height (h) are varying.

Hence, (1/3)π may be ignored.

V_{1}/V_{2}= r_{1}^{2}h_{1}/r_{2}^{2}h_{2}=> 1/10 = (1)2h_{1}/(2)^{2}h_{2}

=> h_{1}/h_{2}= 2/5

i.e. h_{1}: h_{2}= 2 : 5IncorrectThe volume of the cone = (1/3)πr

^{2}h

Only radius (r) and height (h) are varying.

Hence, (1/3)π may be ignored.

V_{1}/V_{2}= r_{1}^{2}h_{1}/r_{2}^{2}h_{2}=> 1/10 = (1)2h_{1}/(2)^{2}h_{2}

=> h_{1}/h_{2}= 2/5

i.e. h_{1}: h_{2}= 2 : 5 - Question 22 of 50
##### 22. Question

The difference between the two digit number and the number obtained by interchanging its digits is 54. The difference between the digits is?

Correct(10x + y) – (10y + x) = 54

x – y = 6Incorrect(10x + y) – (10y + x) = 54

x – y = 6 - Question 23 of 50
##### 23. Question

The number which exceeds 16% of it by 42 is?

CorrectLet the number be x.

Then, x – 16% of x = 42.

x – 16/100 x = 42

x = (42 * 25)/21 = 50IncorrectLet the number be x.

Then, x – 16% of x = 42.

x – 16/100 x = 42

x = (42 * 25)/21 = 50 - Question 24 of 50
##### 24. Question

Find the greatest number which leaves the same remainder when it divides 25, 57 and 105.

Correct105 – 57 = 48

57 – 25 = 32

105 – 25 = 80

The H.C.F of 32, 48 and 80 is 16.Incorrect105 – 57 = 48

57 – 25 = 32

105 – 25 = 80

The H.C.F of 32, 48 and 80 is 16. - Question 25 of 50
##### 25. Question

The average of first 10 even numbers is?

CorrectSum of 10 even numbers = 10 * 11 = 110

Average = 110/10 = 11IncorrectSum of 10 even numbers = 10 * 11 = 110

Average = 110/10 = 11 - Question 26 of 50
##### 26. Question

√3584 * 52.034 = ?

Correct√3600 * 52 = ?

=> ? = 60 * 52 = 3120Incorrect√3600 * 52 = ?

=> ? = 60 * 52 = 3120 - Question 27 of 50
##### 27. Question

40% of Ram’s marks is equal to 20% of Rahim’s marks which percent is equal to 30% of Robert’s marks. If Robert’s marks is 80, then find the average marks of Ram and Rahim?

CorrectGiven, 40% of Ram’s marks = 20% of Rahim’s marks = 30% of Robert’s marks.

Given, marks of Robert = 80

30% of 80 = 30/100 * 8 = 24

Given, 40% of Ram’s marks = 24.

=> Ram’s marks = (24 * 100)/40 = 60

Also, 20% of Rahim’s marks = 24

=> Rahim’s marks = (24 * 100)/20 = 120

Average marks of Ram and Rahim = (60 + 120)/2 = 90.IncorrectGiven, 40% of Ram’s marks = 20% of Rahim’s marks = 30% of Robert’s marks.

Given, marks of Robert = 80

30% of 80 = 30/100 * 8 = 24

Given, 40% of Ram’s marks = 24.

=> Ram’s marks = (24 * 100)/40 = 60

Also, 20% of Rahim’s marks = 24

=> Rahim’s marks = (24 * 100)/20 = 120

Average marks of Ram and Rahim = (60 + 120)/2 = 90. - Question 28 of 50
##### 28. Question

A sum of money becomes double itself in 8 years at simple interest. How many times will it become 10 years at the same rate?

CorrectP —- 2P —- 8 years

2 1/4 P —- 10 yearsIncorrectP —- 2P —- 8 years

2 1/4 P —- 10 years - Question 29 of 50
##### 29. Question

The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years?

CorrectLet P’s age and Q’s age be 6x and 7x years respectively.

Then, 7x – 6x = 4 => x = 4

Required ratio = (6x + 4) : (7x + 4)

28 : 32 = 7:8IncorrectLet P’s age and Q’s age be 6x and 7x years respectively.

Then, 7x – 6x = 4 => x = 4

Required ratio = (6x + 4) : (7x + 4)

28 : 32 = 7:8 - Question 30 of 50
##### 30. Question

³√216400 + √280 + √322 = ?

Correct³√216400 + √280 + √322

= 60 + 16.5 + 18 = 94.5 = 95Incorrect³√216400 + √280 + √322

= 60 + 16.5 + 18 = 94.5 = 95 - Question 31 of 50
##### 31. Question

15% of 195 + 14% of 205 = ?

Correct15/100 * 195 + 14/100 * 205 = 15/100 * 200 + 14/100 * 200

= 30 + 28 = 58Incorrect15/100 * 195 + 14/100 * 205 = 15/100 * 200 + 14/100 * 200

= 30 + 28 = 58 - Question 32 of 50
##### 32. Question

If the sum of a number and its square is 182, what is the number?

CorrectLet the number be x. Then,

x + x^{2}= 182

(x + 14)(x – 13) = 0

x = 13IncorrectLet the number be x. Then,

x + x^{2}= 182

(x + 14)(x – 13) = 0

x = 13 - Question 33 of 50
##### 33. Question

Two pipes function simultaneously the reservoir will be filled in 12 hours. One pipe fills reservoir 10 hours faster than the other. How many hours does the faster pipe take to fill the reservoir?

Correct1/x + 1/(x + 10) = 1/12

x = 20Incorrect1/x + 1/(x + 10) = 1/12

x = 20 - Question 34 of 50
##### 34. Question

A shopkeeper buys two articles for Rs.1000 each and then sells them, making 20% profit on the first article and 20% loss on second article. Find the net profit or loss percent?

CorrectProfit on first article = 20% of 1000 = 200.

This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.IncorrectProfit on first article = 20% of 1000 = 200.

This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss. - Question 35 of 50
##### 35. Question

What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?

Correct70 = (P*4*7/2)/100

P = 500Incorrect70 = (P*4*7/2)/100

P = 500 - Question 36 of 50
##### 36. Question

The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?

CorrectLength of the two trains = 600m + 400m

Speed of the first train = X

Speed of the second train= 48 Kmph

1000/X – 48 = 180

1000/x – 48 * 5/18 = 180

50 = 9X – 120

X = 68 KmphIncorrectLength of the two trains = 600m + 400m

Speed of the first train = X

Speed of the second train= 48 Kmph

1000/X – 48 = 180

1000/x – 48 * 5/18 = 180

50 = 9X – 120

X = 68 Kmph - Question 37 of 50
##### 37. Question

What percent of 120 are 90?

Correct(?% /100) * 120 = 90

? = 75%Incorrect(?% /100) * 120 = 90

? = 75% - Question 38 of 50
##### 38. Question

The least number which when divided by 16, 18 and 21, leave the remainder 3, 5 and 8 respectively is:

CorrectIncorrect - Question 39 of 50
##### 39. Question

2222.2 + 222.22 + 22.222 = ?

CorrectIncorrect - Question 40 of 50
##### 40. Question

If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is?

CorrectA = 7500(26/25)

^{2}= 8112IncorrectA = 7500(26/25)

^{2}= 8112 - Question 41 of 50
##### 41. Question

men are equal to as many women as are equal to 8 boys. All of them earn Rs.90 only. Men’s wages are?

Correct5M = xW = 8B

5M + xW + 8B —– 90 Rs.

5M + 5M + 5M —– 90 Rs.

15M —— 90 Rs. => 1M = 6Rs.Incorrect5M = xW = 8B

5M + xW + 8B —– 90 Rs.

5M + 5M + 5M —– 90 Rs.

15M —— 90 Rs. => 1M = 6Rs. - Question 42 of 50
##### 42. Question

25 * 25 / 25 + 15 * 40 = ?

Correct(25 * 25)/25 + 15 * 40 = 25 + 600 = 625.

Incorrect(25 * 25)/25 + 15 * 40 = 25 + 600 = 625.

- Question 43 of 50
##### 43. Question

The sum of the digits of a two-digit number is 15 and the difference between the digits is 3. What is the two-digit number?

CorrectLet the ten’s digit be x and unit’s digit by y

Then, x + y = 15 and x – y = 3 or y – x = 3

Solving x + y = 15 and x – y = 3, we get: x = 9, y = 6

Solving x + y = 15 and y – x = 3, we get: x = 6, y = 9

So, the number is either 96 or 69.

Hence, the number cannot be determined.IncorrectLet the ten’s digit be x and unit’s digit by y

Then, x + y = 15 and x – y = 3 or y – x = 3

Solving x + y = 15 and x – y = 3, we get: x = 9, y = 6

Solving x + y = 15 and y – x = 3, we get: x = 6, y = 9

So, the number is either 96 or 69.

Hence, the number cannot be determined. - Question 44 of 50
##### 44. Question

Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?

CorrectD = 250 m + 250 m = 500 m

RS = 80 + 70 = 150 * 5/18 = 125/3

T = 500 * 3/125 = 12 secIncorrectD = 250 m + 250 m = 500 m

RS = 80 + 70 = 150 * 5/18 = 125/3

T = 500 * 3/125 = 12 sec - Question 45 of 50
##### 45. Question

What is the difference between the compound interest on Rs.12000 at 20% p.a. for one year when compounded yearly and half yearly?

CorrectWhen compounded annually, interest

= 12000[1 + 20/100]^{1}– 12000 = Rs.2400

When compounded semi-annually, interest

= 12000[1 + 10/100]^{2}– 12000 = Rs.2520

Required difference = 2520 – 2400 = Rs.120IncorrectWhen compounded annually, interest

= 12000[1 + 20/100]^{1}– 12000 = Rs.2400

When compounded semi-annually, interest

= 12000[1 + 10/100]^{2}– 12000 = Rs.2520

Required difference = 2520 – 2400 = Rs.120 - Question 46 of 50
##### 46. Question

60 + 5 * 12 / (180/3) = ?

Correct60 + 5 * 12 / (180/3) = 60 + 5 * 12 / (60)

= 60 + (5 * 12)/60 = 60 + 1 = 61.Incorrect60 + 5 * 12 / (180/3) = 60 + 5 * 12 / (60)

= 60 + (5 * 12)/60 = 60 + 1 = 61. - Question 47 of 50
##### 47. Question

Find the one which does not belong to that group ?

CorrectPart, Cart, Dart and Mart are rhyming words, but Trap does not sound similarly.

IncorrectPart, Cart, Dart and Mart are rhyming words, but Trap does not sound similarly.

- Question 48 of 50
##### 48. Question

A and B together can do a piece of work in 8 days. If A alone can do the same work in 12 days, then B alone can do the same work in?

CorrectB = 1/8 – 1/2 = 1/24 => 24 days

IncorrectB = 1/8 – 1/2 = 1/24 => 24 days

- Question 49 of 50
##### 49. Question

Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together?

CorrectLCM = 300/60 = 5 min

IncorrectLCM = 300/60 = 5 min

- Question 50 of 50
##### 50. Question

Find the one which does not belong to that group ?

CorrectAll are organs of our body which are in pairs except fingers.

IncorrectAll are organs of our body which are in pairs except fingers.