# GATE Civil Engineering Online Test Series 2, GATE Mock Test Series

## GATE Civil Engineering Online Test Series 2, GATE Online Quiz

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**GATE Civil Engineering Online Test Series 2, GATE Online Quiz**. GATE 2019 CE Online Test, GATE Mock Test Exam 2019.GATE Civil Engineering Full online mock test paper is free for all students. Take GATE 2019 Exams Online Test, GATE 2019 Quiz. GATE 2019 CE Series 2 online Test 2019 in English. Take GATE 2019 Mock Test in English from below, GATE Quiz 2019 Series 2. You may also find other Subjects GATE Online Test in this page. Here we provide Graduate Aptitude Test in Engineering Question and Answers 2019. This GATE CE Online test Series 2 is very helpful for exam preparation. The GATE Civil Engineering Mock Test 2019 is now available for all candidates, who will be appearing in the national level engineering exams 2019. Now take GATE Civil Engineering Online Test Series 1 by Click on Below “**Start Quiz Button**”

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- Question 1 of 25
##### 1. Question

A river model is constructed to a horizontal scale of 1:1000 and a vertical scale of 1:100. If the model discharge were 0.1 m

^{3}/s, then the discharge in the river (in m^{3}/s) would be:CorrectCorrect Answer : 10

^{5}IncorrectCorrect Answer : 10

^{5} - Question 2 of 25
##### 2. Question

For an overhang beam as shown in the figure, R

_{B}and R_{D}are

Correct= 0; – 70 × 2 – 20 × 11 + R

_{D }× 6 = 0R_{D}= 60 kN

+ RB + RD – 70 – 20 = 0

R_{B}= 30 kNIncorrect= 0; – 70 × 2 – 20 × 11 + R

_{D }× 6 = 0R_{D}= 60 kN

+ RB + RD – 70 – 20 = 0

R_{B}= 30 kN - Question 3 of 25
##### 3. Question

A two-dimensional stress system has like stresses σ

_{x }= 100 N/mm^{2}and σ_{y }= 200 N/mm^{2 }in two mutually perpendicular directions. The x, y coordinates of the centre of the Mohr’s circle areCorrectHere, σ

_{x}= 100 N/mm^{2}

σ_{y }= 200 N/mm^{2}

∴ Centre = = (150, 0)IncorrectHere, σ

_{x}= 100 N/mm^{2}

σ_{y }= 200 N/mm^{2}

∴ Centre = = (150, 0) - Question 4 of 25
##### 4. Question

The integral is equal to

Correct

Incorrect

- Question 5 of 25
##### 5. Question

The plastic modulus of a section is 4.8 x 10

^{–3}m^{3}. The shape factor is 1.2. The plastic moment capacity of the section is 120 KNm. The yield stress of the material isCorrectIncorrect - Question 6 of 25
##### 6. Question

A 4 m high column is effectively held in position at both ends and restrained against rotation at one end. Its diameter is restricted to 400 mm. If it is required to carry a factored axial load of 1500 kN, then the reinforcement is

CorrectIncorrect - Question 7 of 25
##### 7. Question

Column I gives a list of test methods for evaluating properties of concrete and Column II gives their list of properties :

**Column I****Column II**P. Resonant frequency test 1. Tensile strength Q. Rebound hammer test 2. Dynamic modulus of elasticity R. Split cylinder test 3. Workability S. Compacting factor test 4. Compressive strength The correct match of the tests with their respective properties is

CorrectCorrect Answer : P – 2, Q – 4, R – 1, S – 3

IncorrectCorrect Answer : P – 2, Q – 4, R – 1, S – 3

- Question 8 of 25
##### 8. Question

A parabolic curve is used to connect a 5% upgrade with 4% downgrade as shown in figure. The highest point on the summit is at a distance of

(measured horizontally from the first tangent point – FTP)

Caculate your answer upto 2 decimal places.

CorrectThe highest point on the summit curve is a distance Lh

_{1 }/n from the FTP on the first grade n_{1 }Lh1 /n from the FTP on the first grade n

_{1 }= 150 x 5/5-(-4) = 150 xIncorrectThe highest point on the summit curve is a distance Lh

_{1 }/n from the FTP on the first grade n_{1 }Lh1 /n from the FTP on the first grade n

_{1 }= 150 x 5/5-(-4) = 150 x - Question 9 of 25
##### 9. Question

A vehicle travelling at 40 kmph was stopped within 1.8 seconds after the application of brakes. The retardation of vehicle is(Calculate the answer to nearest 2 decimal places.)

CorrectT = 1.8 s

V = u + at

0 = 11.11 + a × 1.8

a = – 6.17 m/s^{2}IncorrectT = 1.8 s

V = u + at

0 = 11.11 + a × 1.8

a = – 6.17 m/s^{2} - Question 10 of 25
##### 10. Question

**Directions:**Examine the given two statements carefully and select the answer using the codes given below.**Assertion A:**Break point chlorination ensures a residual of free available chlorine.

**Reason R:**A super high chlorine dose inactivates the pathogens in a very short time.CorrectCorrect Answer : Both A and R are individually true, but R is not the correct explanation of A.

IncorrectCorrect Answer : Both A and R are individually true, but R is not the correct explanation of A.

- Question 11 of 25
##### 11. Question

At a point in a piece of stressed material the stresses are as follows:

tensile (normal)

(shearing)

Although the value of (α+β) is not known yet the principal stresses are equal to each other being (5 kN/m^{2}) . What is the radius of Mohr’s circle?CorrectRadius of Mohr’s cycle = 0

Because principle stress are equal to each other being 5 KN per square meter

So r = (5-5)/2 = 0IncorrectRadius of Mohr’s cycle = 0

Because principle stress are equal to each other being 5 KN per square meter

So r = (5-5)/2 = 0 - Question 12 of 25
##### 12. Question

**Directions:**Read the following information and answer the given question.Normal annual precipitation at station X = 700 mm

Normal annual precipitation at station A = 1000 mm

Normal annual precipitation at station B = 900 mm

Normal annual precipitation at station C = 800 mm

Storm precipitation at station A = 100 mm

Storm precipitation at station B = 90 mm

Storm precipitation at station C = 80 mmCalculate the storm precipitation at station X.

CorrectIncorrect - Question 13 of 25
##### 13. Question

A tank and a deflector are placed on a frictionless trolley. The tank issues water jet (mass density of water = 1 000 kg/m

^{3}), which strikes the deflector and turns by 45°. If the velocity of jet leaving the deflector is 4 m/s and discharge is 0.1 m^{3}/s, the force recorded by the spring will be

CorrectCorrect Answer : 200 √2 N

IncorrectCorrect Answer : 200 √2 N

- Question 14 of 25
##### 14. Question

A fluid jet discharging from a 40 mm diameter orifice has a diameter 30 mm at its vena contracta. Assume the coefficient of velocity to be 0.98. Determine the coefficient of discharge for the orifice.

CorrectC

_{d}= C_{c}× C_{v}

∴ C_{D }= (3/4)^{2 }× 0.98.IncorrectC

_{d}= C_{c}× C_{v}

∴ C_{D }= (3/4)^{2 }× 0.98. - Question 15 of 25
##### 15. Question

A = and I = , , the value of A

^{3}isCorrectCorrect Answer : 19A + 30I

IncorrectCorrect Answer : 19A + 30I

- Question 16 of 25
##### 16. Question

The equation x

^{3}-x^{2}+ 4x – 4 = 0 is to be solved using the Newton-Raphson method. If x = 2 is taken as the initial approximation of the solution, the next approximation using this method will beCorrectIncorrect - Question 17 of 25
##### 17. Question

If a

^{n}=

Then to compute a^{27}, the minimum number of multiplications and squaring required respectively areCorrectCorrect Answer : 4 and 3

IncorrectCorrect Answer : 4 and 3

- Question 18 of 25
##### 18. Question

If a

^{2}+ b^{2 }+ c^{2}= 0 then value ofCorrectWe have a

^{2}+ b^{2 }+ c^{2}= 0⇒ = = a

^{2}b^{2}c^{2 }= a^{2}b^{2}c^{2 }= 4 a^{2}b^{2}c^{2}IncorrectWe have a

^{2}+ b^{2 }+ c^{2}= 0⇒ = = a

^{2}b^{2}c^{2 }= a^{2}b^{2}c^{2 }= 4 a^{2}b^{2}c^{2} - Question 19 of 25
##### 19. Question

**Directions:**In the question, a sentence has been divided into 4 parts and labelled (A), (B), (C) and (D). The sentence contains either a single error or no error at all. The error, if there is one, is in underlined and lettered part. If the sentence contains an error, select the one underlined part that must be changed to make the sentence correct and mark it as your answer. If the sentence is correct, select choice (D) as your answer. In choosing answers, follow the requirements of standard written English.(A) Everyone admired the (B) golden brown colour of (C) his hairs. (D) No error

Correct‘Hair’. The noun ‘hair’ is always used in the same form for both singular and plural purposes.

Incorrect‘Hair’. The noun ‘hair’ is always used in the same form for both singular and plural purposes.

- Question 20 of 25
##### 20. Question

**Directions:**Choose the appropriate option for the blank, so as to make the sentence grammatically correct.A high percentage of people ____ still trapped in superstitions.

CorrectPercentage is a singular noun and requires the singular form of the verb.

IncorrectPercentage is a singular noun and requires the singular form of the verb.

- Question 21 of 25
##### 21. Question

One of the four words given in the four options does not fit the set of words. The odd word from the group, is

CorrectCorrect Answer : coal

IncorrectCorrect Answer : coal

- Question 22 of 25
##### 22. Question

**Directions:**Choose the opposite of the word given below from the options.Unpretentious

CorrectCorrect Answer : Flaunting

IncorrectCorrect Answer : Flaunting

- Question 23 of 25
##### 23. Question

**Directions:**Choose the word or set of words for each blank that best fits the meaning of the sentence as a whole.The ___________ ‘where there is a will, there is a way’ is the most used ___________.

CorrectIt is understood that both the words have to be somewhat similar in meaning. The only option which holds this relation is option (1).

IncorrectIt is understood that both the words have to be somewhat similar in meaning. The only option which holds this relation is option (1).

- Question 24 of 25
##### 24. Question

A bottle of whisky contains 3/4 of whisky and the rest water. How much of the mixture must be taken away and substituted by equal quantity of water to have half whisky and half water?

CorrectPercentage of whisky in mixture = 75%

Percentage of whisky in water = 0%

Therefore, mixture and water should be mixed in the ratio 2 : 1 or we need to replace 1/3^{rd}of the mixture with water.IncorrectPercentage of whisky in mixture = 75%

Percentage of whisky in water = 0%

Therefore, mixture and water should be mixed in the ratio 2 : 1 or we need to replace 1/3^{rd}of the mixture with water. - Question 25 of 25
##### 25. Question

In a class of 33 students, 20 play cricket, 25 play football, and 18 play volleyball. Also, 15 play both cricket and football, 12 play football and volleyball, 10 play cricket and volleyball. If each student plays atleast one game, find the number of students who play only cricket.

CorrectLet C, F and V denote the set of number of students who play cricket, football and volleyball respectively. Therefore, n(C) = 20, n(F) = 25, n(V) = 18

Let x represent the students who play all the three games. From above, we get (x – 5) + (x – 4) + (x – 2) + (15 – x) + (12 – x) + (10 – x) + x = 33

x = 7

The number of students who play cricket only is 7 – 5 = 2IncorrectLet C, F and V denote the set of number of students who play cricket, football and volleyball respectively. Therefore, n(C) = 20, n(F) = 25, n(V) = 18

Let x represent the students who play all the three games. From above, we get (x – 5) + (x – 4) + (x – 2) + (15 – x) + (12 – x) + (10 – x) + x = 33

x = 7

The number of students who play cricket only is 7 – 5 = 2