# Indian Bank PO Prelims Quiz, Indian Bank PO Pre Online Test 2019

## Indian Bank PO Prelims Quiz Series 3rd, Indian Bank PO Pre Online Test Series 3rd

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**Indian Bank PO Prelims Quiz Series 3rd, Indian Bank PO Pre Online Test Series 3rd**. Indian Bank PO Prelims Free Mock Test Exam 2019. Indian Bank PO Pre. Exam Free Online Quiz 2019, Indian Bank PO Pre Full Online Mock Test **Series 3rd** in English. Take Indian Bank PO Pre Online Quiz. Indian Bank every year invites application from the young and bright candidates for the post of JMG I as Probationary officers. Question and Answers in English and Hindi **Series 3**. Here we are providing** Indian Bank PO Pre. Full Mock Test Paper in English. Indian Bank PO Pre. **Mock Test **Series 3rd** 2019. Now Test your self for Indian Bank PO Pre. Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 496.80?

CorrectCP = Rs. 540, MP = 540 + 15% of 540 = Rs. 621

SP = Rs. 496.80, Discount = 621 – 496.80 = 124.20

Discount % = 124.2/621 * 100 = 20%IncorrectCP = Rs. 540, MP = 540 + 15% of 540 = Rs. 621

SP = Rs. 496.80, Discount = 621 – 496.80 = 124.20

Discount % = 124.2/621 * 100 = 20% - Question 2 of 50
##### 2. Question

The side of a square is increased by 25% then how much % does its area increases?

Correcta = 100 a

^{2}= 10000

a = 125 a^{2}= 15625

—————-

10000 ——— 5625

100 ——-? => 56.25 %Incorrecta = 100 a

^{2}= 10000

a = 125 a^{2}= 15625

—————-

10000 ——— 5625

100 ——-? => 56.25 % - Question 3 of 50
##### 3. Question

Sam invested Rs. 15000 @ 10% per annum for one year. If the interest is compounded half-yearly, then the amount received by Sam at the end of the year will be?

CorrectP = Rs. 15000; R = 10% p.a. = 5% per half-year; T = 1 year = 2 half-year

Amount = [15000 * (1 + 5/100)^{2}]

= (15000 * 21/20 * 21/20) = Rs. 16537.50IncorrectP = Rs. 15000; R = 10% p.a. = 5% per half-year; T = 1 year = 2 half-year

Amount = [15000 * (1 + 5/100)^{2}]

= (15000 * 21/20 * 21/20) = Rs. 16537.50 - Question 4 of 50
##### 4. Question

A can do a piece of work in 4 days. B can do it in 5 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?

CorrectC = 1/2 – 1/4 – 1/5 = 1/20 => 20 days

IncorrectC = 1/2 – 1/4 – 1/5 = 1/20 => 20 days

- Question 5 of 50
##### 5. Question

A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.75 less, he could have gained 25%. What is the cost price?

CorrectCP

_{1}= 100 SP_{1}= 120

CP_{2}= 80 SP_{2}= 80 * (125/100) = 100

20 —– 100

75 —– ? => 375IncorrectCP

_{1}= 100 SP_{1}= 120

CP_{2}= 80 SP_{2}= 80 * (125/100) = 100

20 —– 100

75 —– ? => 375 - Question 6 of 50
##### 6. Question

The ratio of the prices of three articles X, Y and Z is 8 : 5 : 3. If the prices of X , Y and Z are increased by 25%, 20% and 33 1/3% respectively, then what would be the ratio of the new prices of X, Y and Z?

CorrectLet the prices of X, Y and Z be 8k, 5k and 3k respectively.

After increase

Price of X = 8k * 125/100 = 10k

Price of Y = 5k * 120/100 = 6k

Price of Z = 3k * (133 1/3)/100 = 4k

Required ratio = 10k : 6k : 4k = 5 : 3 : 2.IncorrectLet the prices of X, Y and Z be 8k, 5k and 3k respectively.

After increase

Price of X = 8k * 125/100 = 10k

Price of Y = 5k * 120/100 = 6k

Price of Z = 3k * (133 1/3)/100 = 4k

Required ratio = 10k : 6k : 4k = 5 : 3 : 2. - Question 7 of 50
##### 7. Question

The least number which when add 3 to it, completely divided 8, 12 and 18 is?

CorrectLCM = 72

72 – 3 = 69IncorrectLCM = 72

72 – 3 = 69 - Question 8 of 50
##### 8. Question

Twelve men can complete a piece of work in 32 days. The same work can be completed by 16 women in 36 days and by 48 boys in 16 days. Find the time taken by one man, one woman and one boy working together to complete the work?

Correct12 men take 32 days to complete the work.

One man will take (12 * 32) days to complete it.

Similarly one woman will take (16 * 36) days to complete it and one boy will take (48 * 16) days to complete it.

One man, one woman and one boy working together will complete = 1/(12 * 32) + 1/(16 * 36) + 1/(48 * 16)

= 1/(4 * 3 * 16 * 2) + 1/(16 * 4 * 9) + 1/(16 * 3 * 4 * 4)

= 1/64(1/6 + 1/9 + 1/12) = 1/64 * 13/36 of the work in a day.

They will take (64 * 36)/13 days to complete the work working together.Incorrect12 men take 32 days to complete the work.

One man will take (12 * 32) days to complete it.

Similarly one woman will take (16 * 36) days to complete it and one boy will take (48 * 16) days to complete it.

One man, one woman and one boy working together will complete = 1/(12 * 32) + 1/(16 * 36) + 1/(48 * 16)

= 1/(4 * 3 * 16 * 2) + 1/(16 * 4 * 9) + 1/(16 * 3 * 4 * 4)

= 1/64(1/6 + 1/9 + 1/12) = 1/64 * 13/36 of the work in a day.

They will take (64 * 36)/13 days to complete the work working together. - Question 9 of 50
##### 9. Question

Train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds. The length of train P is three-fourths the length of train Q. What is the ratio of the speed of train P to that of train Q?

CorrectGiven that train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds.

Let the length of train P be L_{P}and that of train Q be L_{Q}

given that L_{P}= 3/4 L_{Q}

As the train P and Q crosses the pole in 30 seconds and 75 seconds respectively,

=> Speed of train P = V_{P}= L_{P}/30

Speed of train Q = V_{Q}= L_{Q}/75

L_{P}= 3/4 L_{Q}

=> V_{P}= 3/4 L_{Q}/(30) = L_{Q}/40

Ratio of their speeds = V_{P}: V_{Q}

= L_{Q}/40 : L_{Q}/75 => 1/40 : 1/75 = 15 : 8IncorrectGiven that train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds.

Let the length of train P be L_{P}and that of train Q be L_{Q}

given that L_{P}= 3/4 L_{Q}

As the train P and Q crosses the pole in 30 seconds and 75 seconds respectively,

=> Speed of train P = V_{P}= L_{P}/30

Speed of train Q = V_{Q}= L_{Q}/75

L_{P}= 3/4 L_{Q}

=> V_{P}= 3/4 L_{Q}/(30) = L_{Q}/40

Ratio of their speeds = V_{P}: V_{Q}

= L_{Q}/40 : L_{Q}/75 => 1/40 : 1/75 = 15 : 8 - Question 10 of 50
##### 10. Question

The ratio between the school ages of Neelam and Shaan is 5:6 respectively. If the ratio between the one-third age of Neelam and half of Shaan’s age of 5:9, then what is the school age of Shaan?

CorrectLet the school ages of Neelam and Shaan be 5x and 6x years respectively.

Then, (1/3 * 5x)/(1/2 * 6x) = 5/9

15 = 15

Thus, Shaan’s age cannot be determined.IncorrectLet the school ages of Neelam and Shaan be 5x and 6x years respectively.

Then, (1/3 * 5x)/(1/2 * 6x) = 5/9

15 = 15

Thus, Shaan’s age cannot be determined. - Question 11 of 50
##### 11. Question

At what rate percent on simple interest will Rs.750 amount to Rs.900 in 5 years?

Correct150 = (750*5*R)/100

R = 4%Incorrect150 = (750*5*R)/100

R = 4% - Question 12 of 50
##### 12. Question

A, B and C can do a work in 90, 30 and 45 days respectively. If they work together, in how many days will they complete the work?

CorrectOne days’s work of A, B and C = 1/90 + 1/30 + 1/45

= (1 + 3 + 2)/90 = 1/15

A, B and C together can do the work in 15 days.IncorrectOne days’s work of A, B and C = 1/90 + 1/30 + 1/45

= (1 + 3 + 2)/90 = 1/15

A, B and C together can do the work in 15 days. - Question 13 of 50
##### 13. Question

– 84 * 29 + 365 = ?

CorrectGiven Exp. = – 84 * (30 – 1) + 365

= – (84 * 30) + 84 + 365

= – 2520 + 449 = – 2071IncorrectGiven Exp. = – 84 * (30 – 1) + 365

= – (84 * 30) + 84 + 365

= – 2520 + 449 = – 2071 - Question 14 of 50
##### 14. Question

A sum of money placed at C.I. interest doubles itself in 5 years. It will amount to eight times itself at the same rate of interest in?

CorrectP(1 + R/100)

^{5}= 2P => (1 + R/100)^{5}= 2

Let P(1 + R/100)^{n}= 8P

=> (1 + R/100)^{n}= 8 = 2^{3}= {(1 + R/100)^{5}}^{3}

=> (1 + R/100)^{n}= (1 + R/100)^{15}=> n = 15 Required time = 15 years.IncorrectP(1 + R/100)

^{5}= 2P => (1 + R/100)^{5}= 2

Let P(1 + R/100)^{n}= 8P

=> (1 + R/100)^{n}= 8 = 2^{3}= {(1 + R/100)^{5}}^{3}

=> (1 + R/100)^{n}= (1 + R/100)^{15}=> n = 15 Required time = 15 years. - Question 15 of 50
##### 15. Question

The ratio between the radii of two spheres is 1:3. Find the ratio between their volumes?

Correctr

_{1}: r_{2}= 1:3

r_{1}^{3}: r_{2}^{3}= 1:27Incorrectr

_{1}: r_{2}= 1:3

r_{1}^{3}: r_{2}^{3}= 1:27 - Question 16 of 50
##### 16. Question

(830 + ? * 3 * 14 / 100) – (830 * 14 * 3 / 100) = 20.16

Correct(830 + ? * 3 * 14 / 100) – (830 * 14 * 3 / 100) = 20.16

=> 830 + ? * 42 – 830 * 42 = 2018

=> ? * 42 = 2018 + 830 * 42 – 830

=> ? * 42 = 42 * 48 + 830 * 42 – 830

=> ? = 48 + 830 – (830 / 42)

=> ? = 48 + 830 – 19.76

=> ? = 858.24Incorrect(830 + ? * 3 * 14 / 100) – (830 * 14 * 3 / 100) = 20.16

=> 830 + ? * 42 – 830 * 42 = 2018

=> ? * 42 = 2018 + 830 * 42 – 830

=> ? * 42 = 42 * 48 + 830 * 42 – 830

=> ? = 48 + 830 – (830 / 42)

=> ? = 48 + 830 – 19.76

=> ? = 858.24 - Question 17 of 50
##### 17. Question

The G.C.D of 1.08, 0.36 and 0.9 is

CorrectGiven numbers are 1.08, 0.36 and 0.90.

H.C.F of 108, 36 and 90 is 18.

H.C.F of a given numbers = 0.18IncorrectGiven numbers are 1.08, 0.36 and 0.90.

H.C.F of 108, 36 and 90 is 18.

H.C.F of a given numbers = 0.18 - Question 18 of 50
##### 18. Question

Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours. C is closed A and B can fill the remaining par in 7 hours. The number of hours taken by C alone to fill the tank is?

CorrectPart filled in 2 hours = 2/6 = 1/3.

Remaining part = 1 – 1/3 = 2/3

(A + B)’s 1 hour work = 2/21

C’s 1 hour work = [(A + B + C)’s 1 hour work – (A + B)’s 1 hour work]

= (1/6 – 2/21) = 1/14

C alone can fill the tank in 14 hours.IncorrectPart filled in 2 hours = 2/6 = 1/3.

Remaining part = 1 – 1/3 = 2/3

(A + B)’s 1 hour work = 2/21

C’s 1 hour work = [(A + B + C)’s 1 hour work – (A + B)’s 1 hour work]

= (1/6 – 2/21) = 1/14

C alone can fill the tank in 14 hours. - Question 19 of 50
##### 19. Question

One half of a two digit number exceeds its one third by 6. What is the sum of the digits of the number?

Correctx/2 – x/3 = 6 => x =6

3 + 6 = 9Incorrectx/2 – x/3 = 6 => x =6

3 + 6 = 9 - Question 20 of 50
##### 20. Question

If p, q and r are positive integers and satisfy x = (p + q – r)/r = (p – q + r)/q = (q + r – p)/p, then the value of x is?

CorrectHence, x = (p + q – r)/r = (p – q + r)/q = (q + r – p)/p

=> x = (p + q – r + p – q + r + q + r – p)/(r + q + p)

=> x = (p + q + r)/(r + q + p) = 1.IncorrectHence, x = (p + q – r)/r = (p – q + r)/q = (q + r – p)/p

=> x = (p + q – r + p – q + r + q + r – p)/(r + q + p)

=> x = (p + q + r)/(r + q + p) = 1. - Question 21 of 50
##### 21. Question

Which of the following is the greatest?

Correct5 > 4 and 1/2 > 1/4

5^{1/2}> 4^{1/4}

4^{1/4}cannot be the greatest. Hence 3^{1/4}also cannot be the greatest.

3^{7/10}= (3^{7})^{1/10}= (2187)^{1/10}

5^{1/2}= 5^{5/10}= (5^{5})^{1/10}= (3125)^{1/10}

6^{1/5}= 6^{2/10}= (6^{2})^{1/10}= (36)^{1/10}

As (3125)^{1/10}> (2187)^{1/10}> (36)^{1/10}, 5^{1/2}is the greatest.Incorrect5 > 4 and 1/2 > 1/4

5^{1/2}> 4^{1/4}

4^{1/4}cannot be the greatest. Hence 3^{1/4}also cannot be the greatest.

3^{7/10}= (3^{7})^{1/10}= (2187)^{1/10}

5^{1/2}= 5^{5/10}= (5^{5})^{1/10}= (3125)^{1/10}

6^{1/5}= 6^{2/10}= (6^{2})^{1/10}= (36)^{1/10}

As (3125)^{1/10}> (2187)^{1/10}> (36)^{1/10}, 5^{1/2}is the greatest. - Question 22 of 50
##### 22. Question

The list price of an article is Rs.65. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?

Correct65*(90/100)*((100-x)/100) = 56.16

x = 4%Incorrect65*(90/100)*((100-x)/100) = 56.16

x = 4% - Question 23 of 50
##### 23. Question

The difference between two integers is 5. Their product is 500. Find the numbers.

CorrectLet the integers be x and (x + 5). Then,

x(x + 5) = 500

x^{2}+ 5x – 500 = 0

(x + 25)(x – 20) = 0

x = 20

So, the numbers are 20 and 25.IncorrectLet the integers be x and (x + 5). Then,

x(x + 5) = 500

x^{2}+ 5x – 500 = 0

(x + 25)(x – 20) = 0

x = 20

So, the numbers are 20 and 25. - Question 24 of 50
##### 24. Question

A certain sum of money at simple interest amounted Rs.840 in 10 years at 3% per annum, find the sum?

Correct840 = P [1 + (10*3)/100]

P = 646Incorrect840 = P [1 + (10*3)/100]

P = 646 - Question 25 of 50
##### 25. Question

There are four prime numbers written in ascending order of magnitude. The product of the first three is 7429 and of the last three is 12673. Find the fourth number?

Correct(7429/12673) = 17/29 Fourth Number is 29

Incorrect(7429/12673) = 17/29 Fourth Number is 29

- Question 26 of 50
##### 26. Question

(1000)9/1024 = ?

CorrectGiven Exp. = (1000)

^{9}/10^{24}

= (10^{3})^{9}/10^{24}= 10^{27}/10^{24}= 10^{(27 – 24)}= 10^{3}=1000IncorrectGiven Exp. = (1000)

^{9}/10^{24}

= (10^{3})^{9}/10^{24}= 10^{27}/10^{24}= 10^{(27 – 24)}= 10^{3}=1000 - Question 27 of 50
##### 27. Question

An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq m?

CorrectLength of the first carpet = (1.44)(6) = 8.64 cm

Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)

= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m

Cost of the second carpet = (45)(12.96 * 7) = 315 (13 – 0.04) = 4095 – 12.6 = Rs. 4082.40IncorrectLength of the first carpet = (1.44)(6) = 8.64 cm

Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)

= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m

Cost of the second carpet = (45)(12.96 * 7) = 315 (13 – 0.04) = 4095 – 12.6 = Rs. 4082.40 - Question 28 of 50
##### 28. Question

On dividing a number by 68, we get 269 as quotient and 0 as remainder. On dividing the same number by 67, what will be the remainder?

CorrectNumber = 269 * 68 + 0 = 18292

67) 18292 (273

18291

——–

1

Required number = 1.IncorrectNumber = 269 * 68 + 0 = 18292

67) 18292 (273

18291

——–

1

Required number = 1. - Question 29 of 50
##### 29. Question

Find the size of the largest square slabs which can be paved on the floor of a room 5 meters 44 cm long and 3 meters 74 cm broad?

CorrectHCF of 374, 544 = 34

IncorrectHCF of 374, 544 = 34

- Question 30 of 50
##### 30. Question

If a man walks to his office at ¾ of his usual rate, he reaches office 1/3 of an hour late than usual. What is his usual time to reach office?

CorrectSpeed Ratio = 1:3/4 = 4:3

Time Ratio = 3:4

1 ——– 1/3

3 ——— ? → 1 hourIncorrectSpeed Ratio = 1:3/4 = 4:3

Time Ratio = 3:4

1 ——– 1/3

3 ——— ? → 1 hour - Question 31 of 50
##### 31. Question

On an order of 5 dozen boxes of a consumer product, a retailer receives an extra dozen free. This is equivalent to allowing him a discount of:

CorrectClearly, the retailer gets 1 dozen out of 6 dozens free.

Equivalent discount = 1/6 * 100 = 16 2/3%.IncorrectClearly, the retailer gets 1 dozen out of 6 dozens free.

Equivalent discount = 1/6 * 100 = 16 2/3%. - Question 32 of 50
##### 32. Question

The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 50% profit?

CorrectLet C.P. = Rs. x.

Then, 832 – x = x – 448

2x = 1280 => x = 640

Required S.P. = 150% of Rs. 640 = 150/100 * 640 = Rs. 960.IncorrectLet C.P. = Rs. x.

Then, 832 – x = x – 448

2x = 1280 => x = 640

Required S.P. = 150% of Rs. 640 = 150/100 * 640 = Rs. 960. - Question 33 of 50
##### 33. Question

The area of a sector of a circle of radius 5 cm formed by an arc of length 3.5 cm is?

Correct(5 * 3.5)/2 = 8.75

Incorrect(5 * 3.5)/2 = 8.75

- Question 34 of 50
##### 34. Question

Ajay spends 45% of his monthly income on household items, 25% of his monthly income on buying cloths, 7.5% of his monthly income on medicines and saves the remaining amount which is Rs. 9000. Find his monthly income.

CorrectLet the monthly income of Ajay be Rs. x

Savings of Ajay = x – (45 + 25 + 7.5)/100 * x = 22.5/100 x

22.5/100 x = 9000

x = 40000.IncorrectLet the monthly income of Ajay be Rs. x

Savings of Ajay = x – (45 + 25 + 7.5)/100 * x = 22.5/100 x

22.5/100 x = 9000

x = 40000. - Question 35 of 50
##### 35. Question

How many of the following numbers are divisible by 132?

264, 396, 462, 792, 968, 2178, 5184, 6336Correct132 = 11 * 3 * 4

Clearly, 968 is not divisible by 3

None of 462 and 2178 is divisible by 4

And, 5284 is not divisible by 11

Each one of the remaining four numbers is divisible by each one of 4, 3 and 11.

So, there are 4 such numbers.Incorrect132 = 11 * 3 * 4

Clearly, 968 is not divisible by 3

None of 462 and 2178 is divisible by 4

And, 5284 is not divisible by 11

Each one of the remaining four numbers is divisible by each one of 4, 3 and 11.

So, there are 4 such numbers. - Question 36 of 50
##### 36. Question

Out of 10 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?

CorrectP(at least one graduate) = 1 – P(no graduates) =

1 – ⁶C₃/¹⁰C₃ = 1 – (6 * 5 * 4)/(10 * 9 * 8) = 5/6IncorrectP(at least one graduate) = 1 – P(no graduates) =

1 – ⁶C₃/¹⁰C₃ = 1 – (6 * 5 * 4)/(10 * 9 * 8) = 5/6 - Question 37 of 50
##### 37. Question

(4300731) – ? = 2535618

CorrectLet 4300731 – x = 2535618

Then, x = 4300731 – 2535618 = 1765113IncorrectLet 4300731 – x = 2535618

Then, x = 4300731 – 2535618 = 1765113 - Question 38 of 50
##### 38. Question

P, Q and R have Rs.6000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R?

CorrectLet the amount with R be Rs.r

r = 2/3 (total amount with P and Q)

r = 2/3(6000 – r) => 3r = 12000 – 2r

=> 5r = 12000 => r = 2400.IncorrectLet the amount with R be Rs.r

r = 2/3 (total amount with P and Q)

r = 2/3(6000 – r) => 3r = 12000 – 2r

=> 5r = 12000 => r = 2400. - Question 39 of 50
##### 39. Question

What is the are of an equilateral triangle of side 16 cm?

CorrectArea of an equilateral triangle = √3/4 S

^{2}

If S = 16, Area of triangle = √3/4 * 16 * 16 = 64√3 cm^{2};IncorrectArea of an equilateral triangle = √3/4 S

^{2}

If S = 16, Area of triangle = √3/4 * 16 * 16 = 64√3 cm^{2}; - Question 40 of 50
##### 40. Question

A, B and C can do a work in 6 days, 8 days and 12 days respectively. In how many days can all three of them working together, complete the work?

CorrectWork done by all three of them in one day = 1/6 + 1/8 + 1/12 = 3/8.

The number of days required = 8/3 = 2 2/3 days.IncorrectWork done by all three of them in one day = 1/6 + 1/8 + 1/12 = 3/8.

The number of days required = 8/3 = 2 2/3 days. - Question 41 of 50
##### 41. Question

The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of?

Correct4:5

3:2

——-

12:15:10

12:10

6:5Incorrect4:5

3:2

——-

12:15:10

12:10

6:5 - Question 42 of 50
##### 42. Question

52 * 40.1 = ?

CorrectSince, 40.1 = 40

52 * 40 = 2080IncorrectSince, 40.1 = 40

52 * 40 = 2080 - Question 43 of 50
##### 43. Question

The sum of money at compound interest amounts to thrice itself in 3 years. In how many years will it be 9 times itself?

Correct100 —- 300 — 3

900 — 3

—-

6 yearsIncorrect100 —- 300 — 3

900 — 3

—-

6 years - Question 44 of 50
##### 44. Question

A, B and C rents a pasture for Rs.870. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should C pay?

Correct12*8 :16*9 = 18*6

8: 12: 9

9/29 * 870 = 270Incorrect12*8 :16*9 = 18*6

8: 12: 9

9/29 * 870 = 270 - Question 45 of 50
##### 45. Question

Amar, Bhavan and Chetan divide an amount of Rs.5600 among themselves in the ratio 3:6:5. If an amount of Rs.400 is deducted from each of their shares, what will be the new ratio of their shares of the amount?

CorrectLet the shares of Amar, Bhavan and Chetan be 3x, 6x and 5x respectively.

3x + 6x + 5x = 5600

14x = 5600 => x = 400

Required ratio = 3x – 400 : 6x – 400 : 5x – 400

= 3x – x : 6x – x : 5x – x

= 2x : 5x : 4x => 2:5:4IncorrectLet the shares of Amar, Bhavan and Chetan be 3x, 6x and 5x respectively.

3x + 6x + 5x = 5600

14x = 5600 => x = 400

Required ratio = 3x – 400 : 6x – 400 : 5x – 400

= 3x – x : 6x – x : 5x – x

= 2x : 5x : 4x => 2:5:4 - Question 46 of 50
##### 46. Question

30.9 * 3000 – 10.1 * 1100 + 8298 – 4302 = ?

Correct9 * 3000 – 10.1 * 1100 + 8238 – 4302

31 * 3000 – 1010 * 11 + 8298 – 4302

93000 + 8298 – 11110 – 4302 = 101298 – 15412

= 85886 = 85000Incorrect9 * 3000 – 10.1 * 1100 + 8238 – 4302

31 * 3000 – 1010 * 11 + 8298 – 4302

93000 + 8298 – 11110 – 4302 = 101298 – 15412

= 85886 = 85000 - Question 47 of 50
##### 47. Question

If the price of gold increases by 50%, find by how much the quantity of ornaments must be reduced, so that the expenditure may remain the same as before?

Correct100

150

——

150——-50

100——-? => 331/3%Incorrect100

150

——

150——-50

100——-? => 331/3% - Question 48 of 50
##### 48. Question

The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is?

Correct10 * 15 + 36 – 26 = 160/10 = 16

Incorrect10 * 15 + 36 – 26 = 160/10 = 16

- Question 49 of 50
##### 49. Question

Rs. 1300 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4?

Correct1/2:1/3:1/4 = 6:4:3

3/13*1300 = 300Incorrect1/2:1/3:1/4 = 6:4:3

3/13*1300 = 300 - Question 50 of 50
##### 50. Question

A tank is filled in eight hours by three pipes A, B and C. Pipe A is twice as fast as pipe B, and B is twice as fast as C. How much time will pipe B alone take to fill the tank?

Correct1/A + 1/B + 1/C = 1/8 (Given)

Also given that A = 2B and B = 2C

=> 1/2B + 1/B + 2/B = 1/8

=> (1 + 2 + 4)/2B = 1/8

=> 2B/7 = 8

=> B = 28 hours.Incorrect1/A + 1/B + 1/C = 1/8 (Given)

Also given that A = 2B and B = 2C

=> 1/2B + 1/B + 2/B = 1/8

=> (1 + 2 + 4)/2B = 1/8

=> 2B/7 = 8

=> B = 28 hours.