IPPB Mains Mock Test Series 2nd, IPPB Mains Online Test Series 2
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IPPB Mains Mock Test Series 2nd, IPPB Mains Online Test Series 2. IPPB Mains Free Mock Test Exam 2021. IPPB Mains Exam Free Online Quiz 2021. IPPB Mains Full Online Mock Test Series 2nd in English. candidates who want to make sure whether their preparation level is up to date then they take this online test series without paying anything. CAknowledge provide IPPB Online Test Series 2021 in order to let you excel in the examination. The IPPB Mains Full online mock test paper is free for all students. IPPB Mains Question and Answers in English and Hindi Series 2. Here we are providing IPPB Mains Full Mock Test Paper in English. IPPB Mains Mock Test Series 2nd 2021. Now Test your self for IPPB Mains Exam by using below quiz…
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Question 1 of 50
1. Question
I. x^{2} + 5x + 6 = 0,
II. y^{2} + 9y +14 = 0 to solve both the equations to find the values of x and y?Correct
I. x^{2} + 3x + 2x + 6 = 0
=> (x + 3)(x + 2) = 0 => x = 3 or 2
II. y^{2} + 7y + 2y + 14 = 0
=> (y + 7)(y + 2) = 0 => y = 7 or 2
No relationship can be established between x and y.Incorrect
I. x^{2} + 3x + 2x + 6 = 0
=> (x + 3)(x + 2) = 0 => x = 3 or 2
II. y^{2} + 7y + 2y + 14 = 0
=> (y + 7)(y + 2) = 0 => y = 7 or 2
No relationship can be established between x and y. 
Question 2 of 50
2. Question
At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years?
Correct
Let sum = x. Then, S.I. = 2x/5, Time = 10 years.
Rate = (100 * 2x) / (x * 5 * 10) = 4%Incorrect
Let sum = x. Then, S.I. = 2x/5, Time = 10 years.
Rate = (100 * 2x) / (x * 5 * 10) = 4% 
Question 3 of 50
3. Question
A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
Correct
Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230.Incorrect
Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230. 
Question 4 of 50
4. Question
Two cylinders are of the same height. Their radii are in the ratio 1: 3. If the volume of the first cylinder is 40 cc. Find the volume of the second cylinder?
Correct
r_{1} = x r_{2} = 3x
Π * x^{2} * h = 40
Π9 x^{2}h = 40 * 9 = 360Incorrect
r_{1} = x r_{2} = 3x
Π * x^{2} * h = 40
Π9 x^{2}h = 40 * 9 = 360 
Question 5 of 50
5. Question
A can do half the work in one day where as B can do it full. B can also do half the work of C in one day. Ratio in their efficiency will be?
Correct
WC of A: B = 1:2
B: C = 1:2
———————
A: B: C = 1:2:4Incorrect
WC of A: B = 1:2
B: C = 1:2
———————
A: B: C = 1:2:4 
Question 6 of 50
6. Question
In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case?
Correct
Assume X soldiers join the fort. 1200 soldiers have provision for 1200(days for which provisions last them)(rate of consumption of each soldier)
= 1200(30)(3) kg
Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg
As the same provisions are available
=> 1200(30)(3) = (1200 + x)(25)(2.5)
x = [1200(30)(3)]/[(25)(2.5)] – 1200
x = 528Incorrect
Assume X soldiers join the fort. 1200 soldiers have provision for 1200(days for which provisions last them)(rate of consumption of each soldier)
= 1200(30)(3) kg
Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg
As the same provisions are available
=> 1200(30)(3) = (1200 + x)(25)(2.5)
x = [1200(30)(3)]/[(25)(2.5)] – 1200
x = 528 
Question 7 of 50
7. Question
Find the nearest to 25268 which is exactly divisible by 467?
Correct
Incorrect

Question 8 of 50
8. Question
A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?
Correct
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x – 49x/50 = x/50
x/50 = 400 => x = 20000Incorrect
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x – 49x/50 = x/50
x/50 = 400 => x = 20000 
Question 9 of 50
9. Question
10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
Correct
1 man’s 1 day work = 1/100
(10 men + 15 women)’s 1 day work = 1/6
15 women’s 1 day work = (1/6 – 10/100) = 1/15
1 woman’s 1 day work = 1/225
1 woman alone can complete the work in 225 days.Incorrect
1 man’s 1 day work = 1/100
(10 men + 15 women)’s 1 day work = 1/6
15 women’s 1 day work = (1/6 – 10/100) = 1/15
1 woman’s 1 day work = 1/225
1 woman alone can complete the work in 225 days. 
Question 10 of 50
10. Question
A group of 10 representatives is to be selected out of 12 seniors and 10 juniors. In how many different ways can the group be selected, if it should have 5 seniors and 5 juniors?
Correct
Here, five seniors out of 12 seniors can be selected in ¹²C₅ ways. Also, five juniors out of ten juniors can be selected ¹⁰C₅ ways. Hence the total number of different ways of selection = ¹²C₅ * ¹⁰C₅ = ¹²C₇ * ¹⁰C₅
= ¹²C₅ = ¹²C₇Incorrect
Here, five seniors out of 12 seniors can be selected in ¹²C₅ ways. Also, five juniors out of ten juniors can be selected ¹⁰C₅ ways. Hence the total number of different ways of selection = ¹²C₅ * ¹⁰C₅ = ¹²C₇ * ¹⁰C₅
= ¹²C₅ = ¹²C₇ 
Question 11 of 50
11. Question
A delegation of 5 members has to be formed from 3 ladies and 5 gentlemen. In how many ways the delegation can be formed, if 2 particular ladies are always included in the delegation?
Correct
There are three ladies and five gentlemen and a committee of 5 members to be formed.
Number of ways such that two ladies are always included in the committee = ⁶C₃ = (6 * 5 * 4)/6 = 20.Incorrect
There are three ladies and five gentlemen and a committee of 5 members to be formed.
Number of ways such that two ladies are always included in the committee = ⁶C₃ = (6 * 5 * 4)/6 = 20. 
Question 12 of 50
12. Question
Two pipes can fill a tank in 18 minutes and 15 minutes. An outlet pipe can empty the tank in 45 minutes. If all the pipes are opened when the tank is empty, then how many minutes will it take to fill the tank?
Correct
Part of the filled by all the three pipes in one minute
= 1/18 + 1/15 – 1/45 = (5 + 6 – 2)/90 = 9/90 = 1/10
So, the tank becomes full in 10 minutes.Incorrect
Part of the filled by all the three pipes in one minute
= 1/18 + 1/15 – 1/45 = (5 + 6 – 2)/90 = 9/90 = 1/10
So, the tank becomes full in 10 minutes. 
Question 13 of 50
13. Question
A man can do a job in 15 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together?
Correct
1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300
So, all three together will complete the work in 300/47 = 6.4 days.Incorrect
1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300
So, all three together will complete the work in 300/47 = 6.4 days. 
Question 14 of 50
14. Question
Find the 37.5% of 976 =
Correct
37.5 % of 976
= 37.5/100 * 976 = 375/1000 * 976 = 3/8 * 976
= 3 * 122 = 366.Incorrect
37.5 % of 976
= 37.5/100 * 976 = 375/1000 * 976 = 3/8 * 976
= 3 * 122 = 366. 
Question 15 of 50
15. Question
If x is the interest on y and y is the interest on z, the rate and time is the same on both the cases. What is the relation between x, y and z?
Correct
X = (Y*NR)/100 Y = (Z*NR)/100
X/Y = NR/100 Y/Z = NR/100
X/Y = Y/Z
Y^{2} = XZIncorrect
X = (Y*NR)/100 Y = (Z*NR)/100
X/Y = NR/100 Y/Z = NR/100
X/Y = Y/Z
Y^{2} = XZ 
Question 16 of 50
16. Question
A sum of money is put out at compound interest for 2 years at 20%. It would fetch Rs.482 more if the interest were payable halfyearly, then it were pay able yearly. Find the sum.
Correct
P(11/10)^{4} – P(6/5)^{2} = 482
P = 2000Incorrect
P(11/10)^{4} – P(6/5)^{2} = 482
P = 2000 
Question 17 of 50
17. Question
Two pipes A and B can separately fill a tank in 12 and 15 minutes respectively. A third pipe C can drain off 45 liters of water per minute. If all the pipes are opened, the tank can be filled in 15 minutes. What is the capacity of the tank?
Correct
1/12 + 1/15 – 1/x = 1/15
x = 12
12 * 45 = 540Incorrect
1/12 + 1/15 – 1/x = 1/15
x = 12
12 * 45 = 540 
Question 18 of 50
18. Question
A man on tour travels first 160 km at 64 km/he and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is?
Correct
Total time taken = (160/64 + 160/8) = 9/2 hrs.
Average speed = 320 * 2/9 = 71.11 km/hr.Incorrect
Total time taken = (160/64 + 160/8) = 9/2 hrs.
Average speed = 320 * 2/9 = 71.11 km/hr. 
Question 19 of 50
19. Question
A and B together can complete a work in 12 days. A alone can complete it in 20 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work?
Correct
B’s 1 day work = (1/12 – 1/20) = 1/30
Now, (A + B)’s 1 day work = (1/20 + 1/60) = 1/15
So, A and B together will complete the work in 15 days.Incorrect
B’s 1 day work = (1/12 – 1/20) = 1/30
Now, (A + B)’s 1 day work = (1/20 + 1/60) = 1/15
So, A and B together will complete the work in 15 days. 
Question 20 of 50
20. Question
If the area of circle is 616 sq cm then its circumference?
Correct
22/7 r^{2} = 616 => r = 14
2 * 22/7 * 14 = 88Incorrect
22/7 r^{2} = 616 => r = 14
2 * 22/7 * 14 = 88 
Question 21 of 50
21. Question
On dividing a number by 68, we get 269 as quotient and 0 as remainder. On dividing the same number by 67, what will be the remainder?
Correct
Number = 269 * 68 + 0 = 18292
67) 18292 (273
18291
——–
1
Required number = 1.Incorrect
Number = 269 * 68 + 0 = 18292
67) 18292 (273
18291
——–
1
Required number = 1. 
Question 22 of 50
22. Question
A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that exactly three bulbs are good.
Correct
Required probability = (⁵C₃ . ⁴C₁)/⁹C₄ = (10 * 4)/126 = 20/63
Incorrect
Required probability = (⁵C₃ . ⁴C₁)/⁹C₄ = (10 * 4)/126 = 20/63

Question 23 of 50
23. Question
The average of first five prime numbers greater than 20 is?
Correct
23 + 29 + 31 + 37 + 41 = 161/5 = 32.2
Incorrect
23 + 29 + 31 + 37 + 41 = 161/5 = 32.2

Question 24 of 50
24. Question
What is the greater of the two numbers whose product is 2560, given that the sum of the two numbers exceeds their difference by 64?
Correct
Let the greater and the smaller number be g and s respectively.
gs = 2560
g + s exceeds g – s by 64 i.e., g + s – (g – s) = 64
i.e., 2s = 64 => s = 32.
g = 2560/s = 80.Incorrect
Let the greater and the smaller number be g and s respectively.
gs = 2560
g + s exceeds g – s by 64 i.e., g + s – (g – s) = 64
i.e., 2s = 64 => s = 32.
g = 2560/s = 80. 
Question 25 of 50
25. Question
Two same glasses are respectively 1/4th 1/5th full of milk. They are then filled with water and the contents mixed in a tumbler. The ratio of milk and water in the tumbler is?
Correct
1/4 : 3/4 = (1:3)5 = 5:15
1/5 : 4/5 = (1:4)4 = 4:16
——
9:31Incorrect
1/4 : 3/4 = (1:3)5 = 5:15
1/5 : 4/5 = (1:4)4 = 4:16
——
9:31 
Question 26 of 50
26. Question
Sixty men can stitch 200 shirts in 30 days working 8 hours a day. In how many days can 45 men stitch 300 shirts working 6 hours a day?
Correct
We have M_{1} D_{1} H_{1} / W_{1} = M_{2} D_{2} H_{2} / W_{2} (Variation rule)
(60 * 30 * 8)/ 200 = (45 * D_{2} * 6) / 300
D_{2} = (60 * 30 * 8 * 300) / (200 * 45 * 6) => D_{2} = 80.Incorrect
We have M_{1} D_{1} H_{1} / W_{1} = M_{2} D_{2} H_{2} / W_{2} (Variation rule)
(60 * 30 * 8)/ 200 = (45 * D_{2} * 6) / 300
D_{2} = (60 * 30 * 8 * 300) / (200 * 45 * 6) => D_{2} = 80. 
Question 27 of 50
27. Question
A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
Correct
Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25) = 40 secondsIncorrect
Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25) = 40 seconds 
Question 28 of 50
28. Question
4000 was divided into two parts such a way that when first part was invested at 3% and the second at 5%, the whole annual interest from both the investments is Rs.144, how much was put at 3%?
Correct
(x*3*1)/100 + [(4000 – x)*5*1]/100 = 144
3x/100 + 200 – 5x/100 = 144
2x/100 = 56 → x = 2800Incorrect
(x*3*1)/100 + [(4000 – x)*5*1]/100 = 144
3x/100 + 200 – 5x/100 = 144
2x/100 = 56 → x = 2800 
Question 29 of 50
29. Question
A and B can do a work in 12 days, B and C in 15 days, C and A in 20 days. If A, B and C work together, they will complete the work in?
Correct
(A + B)’s 1 day work = 1/12;
(B + C)’s 1 day work = 1/15;
(A + C)’s 1 day work = 1/20
Adding, we get: 2(A + B + C)’s 1 day work = (1/12 + 1/15 + 1/20) = 1/5
(A + B + C)’s 1 day work = 1/10
So, A, B and C together can complete the work in 10 days.Incorrect
(A + B)’s 1 day work = 1/12;
(B + C)’s 1 day work = 1/15;
(A + C)’s 1 day work = 1/20
Adding, we get: 2(A + B + C)’s 1 day work = (1/12 + 1/15 + 1/20) = 1/5
(A + B + C)’s 1 day work = 1/10
So, A, B and C together can complete the work in 10 days. 
Question 30 of 50
30. Question
3 men or 6 women can do a piece of work in 20 days. In how many days will 12 men and 8 women do the same work?
Correct
3M = 6W — 20 days
12M + 8W —–?
24W + 8 W = 32W —?
6W — 20 32 —–?
6 * 20 = 32 * x => x = 15/4 daysIncorrect
3M = 6W — 20 days
12M + 8W —–?
24W + 8 W = 32W —?
6W — 20 32 —–?
6 * 20 = 32 * x => x = 15/4 days 
Question 31 of 50
31. Question
An engineering student has to secure 36% marks to pass. He gets 130 marks and fails by 14 marks. The maximum No. of marks obtained by him is?
Correct
130
14
——
361—— 144
100%——? => 400Incorrect
130
14
——
361—— 144
100%——? => 400 
Question 32 of 50
32. Question
5/8 * 2^{(2/5 – 5/4)} / 1 ^{1/4 } = ?
Correct
(5/8 * 12/5 – 5/4)/(5/4) (3/2 5/4)/(5/4) = 1/5
Incorrect
(5/8 * 12/5 – 5/4)/(5/4) (3/2 5/4)/(5/4) = 1/5

Question 33 of 50
33. Question
A vessel of capacity 90 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution?
Correct
Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T – y)/T]^{n} * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 – 9)/90]^{2} (90) = 72.9 litres.Incorrect
Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T – y)/T]^{n} * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 – 9)/90]^{2} (90) = 72.9 litres. 
Question 34 of 50
34. Question
There were two candidates in an election. Winner candidate received 62% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate?
Correct
W = 62% L = 38%
62% – 38% = 24%
24% ——– 288
62% ——– ? => 744Incorrect
W = 62% L = 38%
62% – 38% = 24%
24% ——– 288
62% ——– ? => 744 
Question 35 of 50
35. Question
A number is doubled and 9 is added. If the resultant is trebled, it becomes 75. What is that number?
Correct
Let the number be x. Then,
3(2x + 9) = 75
2x = 16 => x = 8Incorrect
Let the number be x. Then,
3(2x + 9) = 75
2x = 16 => x = 8 
Question 36 of 50
36. Question
A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?
Correct
Incorrect

Question 37 of 50
37. Question
The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles.
Correct
Let the radii of the smaller and the larger circles be s m and l m respectively.
2∏s = 264 and 2∏l = 352
s = 264/2∏ and l = 352/2∏
Difference between the areas = ∏l^{2} – ∏s^{2}
= ∏{176^{2}/∏^{2} – 132^{2}/∏^{2}}
= 176^{2}/∏ – 132^{2}/∏
= (176 – 132)(176 + 132)/∏
= (44)(308)/(22/7) = (2)(308)(7) = 4312 sq mIncorrect
Let the radii of the smaller and the larger circles be s m and l m respectively.
2∏s = 264 and 2∏l = 352
s = 264/2∏ and l = 352/2∏
Difference between the areas = ∏l^{2} – ∏s^{2}
= ∏{176^{2}/∏^{2} – 132^{2}/∏^{2}}
= 176^{2}/∏ – 132^{2}/∏
= (176 – 132)(176 + 132)/∏
= (44)(308)/(22/7) = (2)(308)(7) = 4312 sq m 
Question 38 of 50
38. Question
If Rs.3250 be divided among Ram, Shyam and Mohan in the ratio of 1/2:1/3:1/4 then the share of each are?
Correct
1/2:1/3:1/4 = 6:4:3
Ram = 6/13 * 3250 = 1500
Shyam = 4/13 * 3250 = 1000
Mohan = 3/13 * 3250 = 750Incorrect
1/2:1/3:1/4 = 6:4:3
Ram = 6/13 * 3250 = 1500
Shyam = 4/13 * 3250 = 1000
Mohan = 3/13 * 3250 = 750 
Question 39 of 50
39. Question
How many numbers up to 100 and 300 are divisible by 11?
Correct
(300 – 100)/11 = 200/11 = 18 2/11
18 NumbersIncorrect
(300 – 100)/11 = 200/11 = 18 2/11
18 Numbers 
Question 40 of 50
40. Question
Find the one which does not belong to that group ?
Correct
All are blood relation except Daughterinlaw.
Incorrect
All are blood relation except Daughterinlaw.

Question 41 of 50
41. Question
Find the least number when successively divided by 2, 3 and 7 leaves remainders 1, 2 and 3 respectively?
Correct
2) 65 (32 3) 32 (10 7) 10 (1
64 30 7
——– ——– – —–
1 2 3
=> 65Incorrect
2) 65 (32 3) 32 (10 7) 10 (1
64 30 7
——– ——– – —–
1 2 3
=> 65 
Question 42 of 50
42. Question
The height of two right circular cones are in the ratio 1:2 and their perimeters of their bases are in the ratio 3:4, the ratio of their volume is?
Correct
Incorrect

Question 43 of 50
43. Question
(24 * 5 * 7 * 9) / ? = 216
Correct
? = (24 * 5 * 7 * 9) / 216 = 35
Incorrect
? = (24 * 5 * 7 * 9) / 216 = 35

Question 44 of 50
44. Question
One root of the quadratic equation x^{2} – 12x + a = 0, is thrice the other. Find the value of a?
Correct
Let the roots of the quadratic equation be x and 3x.
Sum of roots = (12) = 12
a + 3a = 4a = 12 => a = 3
Product of the roots = 3a^{2} = 3(3)^{2} = 27.Incorrect
Let the roots of the quadratic equation be x and 3x.
Sum of roots = (12) = 12
a + 3a = 4a = 12 => a = 3
Product of the roots = 3a^{2} = 3(3)^{2} = 27. 
Question 45 of 50
45. Question
A car after covering ½ of a journey of 100 km develops engine trouble and later travels at ½ of its original speed. As a result, it arrives 2 hours late than its normal time. What is the normal speed of the car is?
Correct
[50/x + 50/(x/2)] – 100/x = 2
x = 25Incorrect
[50/x + 50/(x/2)] – 100/x = 2
x = 25 
Question 46 of 50
46. Question
35 + 15 * 1.5 = ?
Correct
Given Exp. = 35 + 15 * 3/2
= 35 + 45/2 = 35 + 22.5 = 57.5Incorrect
Given Exp. = 35 + 15 * 3/2
= 35 + 45/2 = 35 + 22.5 = 57.5 
Question 47 of 50
47. Question
The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers?
Correct
Let the two consecutive positive integers be x and x + 1
x^{2} + (x + 1)^{2} – x(x + 1) = 91
x^{2} + x – 90 = 0
(x + 10)(x – 9) = 0 => x = 10 or 9.
As x is positive x = 9
Hence the two consecutive positive integers are 9 and 10.Incorrect
Let the two consecutive positive integers be x and x + 1
x^{2} + (x + 1)^{2} – x(x + 1) = 91
x^{2} + x – 90 = 0
(x + 10)(x – 9) = 0 => x = 10 or 9.
As x is positive x = 9
Hence the two consecutive positive integers are 9 and 10. 
Question 48 of 50
48. Question
A train 150 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform?
Correct
D = 72 * 5/18 = 25 = 500 – 150 = 350
Incorrect
D = 72 * 5/18 = 25 = 500 – 150 = 350

Question 49 of 50
49. Question
A bag contains nine yellow balls, three white balls and four red balls. In how many ways can two balls be drawn from the bag?
Correct
Total number of balls = 9 + 3 + 4
Two balls can be drawn from 16 balls in ¹⁶C₂ ways.Incorrect
Total number of balls = 9 + 3 + 4
Two balls can be drawn from 16 balls in ¹⁶C₂ ways. 
Question 50 of 50
50. Question
A person bought an article and sold it at a loss of 10%. If he had bought it for 20% less and sold it for Rs.75 less, he could have gained 25%. What is the cost price?
Correct
CP_{1} = 100 SP_{1} = 90
CP_{2} = 80 SP_{2} = 80 * (140/100) = 112
22 —– 100
55 —– ? => Rs.250Incorrect
CP_{1} = 100 SP_{1} = 90
CP_{2} = 80 SP_{2} = 80 * (140/100) = 112
22 —– 100
55 —– ? => Rs.250