IPPB Prelims Mock Test Series 2, IPPB Pre Online Test Series 2
Finish Quiz
0 of 50 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50
Information
IPPB Prelims Mock Test Series 2, IPPB Pre Online Test Series 2. IPPB Prelims Exam Free Online Quiz 2021, IPPB Online Test Series 2nd in English. Indian Post Payment Bank Probationary exam preparation, IPPB online test series 2021 with complete syllabus and based on latest pattern for the pre exam. The IPPB Prelims Full online mock test paper is free for all students. IPPB Prelims Question and Answers in English and Hindi Series 2. Here we are providing IPPB Prelims Full Mock Test Paper in English. IPPB Prelims Mock Test Series 2nd 2021. Now Test your self for IPPB Prelims Exam by using below quiz…
This paper has 50 questions.
Time allowed is 50 minutes.
The IPPB Prelims Online Test Series 2nd, IPPB Prelims Free Online Test Exam is Very helpful for all students. Now Scroll down below n click on “Start Quiz” or “Start Test” and Test yourself.
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 50 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
| Average score |
|
| Your score |
|
Categories
- Not categorized 0%
| Pos. | Name | Entered on | Points | Result |
|---|---|---|---|---|
| Table is loading | ||||
| No data available | ||||
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50
- Answered
- Review
-
Question 1 of 50
1. Question
What is the present worth of Rs. 132 due in 2 years at 5% simple interest per annum?
Correct
Let the present worth be Rs. x. Then,
S.I. = (132 – x)
(x * 5 * 2) / 100 = (132 – x)
10x = 13200 – 100x
110x = 13200 => x = 120.Incorrect
Let the present worth be Rs. x. Then,
S.I. = (132 – x)
(x * 5 * 2) / 100 = (132 – x)
10x = 13200 – 100x
110x = 13200 => x = 120. -
Question 2 of 50
2. Question
Pipes A and B can fill a cistern in 8 and 24 minutes respectively. They are opened an alternate minutes. Find how many minutes, the cistern shall be full?
Correct
1/8 + 1/24 = 1/6
6 * 2 = 12Incorrect
1/8 + 1/24 = 1/6
6 * 2 = 12 -
Question 3 of 50
3. Question
There are two positive numbers in the ratio 5:8. If the larger number exceeds the smaller by 15, then find the smaller number?
Correct
Let the two positive numbers be 5x and 8x respectively.
8x – 5x = 15
3x = 15 => x = 5
=> Smaller number = 5x = 25.Incorrect
Let the two positive numbers be 5x and 8x respectively.
8x – 5x = 15
3x = 15 => x = 5
=> Smaller number = 5x = 25. -
Question 4 of 50
4. Question
The sum of three consecutive numbers is 87. The greatest among these three number is:
Correct
Let the numbers be x, x + 1 and x + 2
Then,
x + (x + 1) + (x + 2) = 87
3x = 84
x = 28
Greatest number, (x + 2) = 30.Incorrect
Let the numbers be x, x + 1 and x + 2
Then,
x + (x + 1) + (x + 2) = 87
3x = 84
x = 28
Greatest number, (x + 2) = 30. -
Question 5 of 50
5. Question
Amar takes as much time in running 18 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.6 km?
Correct
Distance covered by Amar = 18/4.8 (1.6km) = 3/8(1600) = 600 m
Incorrect
Distance covered by Amar = 18/4.8 (1.6km) = 3/8(1600) = 600 m
-
Question 6 of 50
6. Question
The product of two successive numbers is 4556. Which of the following is the larger of the two numbers?
Correct
Let the two successive numbers be n, n + 1.
It is given that n(n + 1) = 4556.
=> n2 + n – 4556 = 0
=> n2 + 68n – 67n – 4556 = 0
=> n(n + 68) – 67(n + 68) = 0
=> n = 67 and (n + 1) = 68.Incorrect
Let the two successive numbers be n, n + 1.
It is given that n(n + 1) = 4556.
=> n2 + n – 4556 = 0
=> n2 + 68n – 67n – 4556 = 0
=> n(n + 68) – 67(n + 68) = 0
=> n = 67 and (n + 1) = 68. -
Question 7 of 50
7. Question
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Correct
Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 2/25 = 40 secIncorrect
Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 2/25 = 40 sec -
Question 8 of 50
8. Question
If one-third of one fourth of a number is 15, then three-tenth of that number is:
Correct
Let the number be x. Then,
1/3 of 1/4 of x = 15
x = 15 * 12 = 180
So, required number = (3/10 * 180) = 54.Incorrect
Let the number be x. Then,
1/3 of 1/4 of x = 15
x = 15 * 12 = 180
So, required number = (3/10 * 180) = 54. -
Question 9 of 50
9. Question
A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is -.
Correct
Total fruits = 9
Since there must be at least two apples,
(⁵C₂ * ⁴C₁)/⁹C₃ + ⁵C₃/⁹C₃ = 25/42.Incorrect
Total fruits = 9
Since there must be at least two apples,
(⁵C₂ * ⁴C₁)/⁹C₃ + ⁵C₃/⁹C₃ = 25/42. -
Question 10 of 50
10. Question
If 6 (A’s capital) = 8 (B’s capital) = 10 (C’s capital). Then the ratio of their capitals is:
Correct
6A = 8B = 10 C
A:B:C = 1/6:1/8:1/10
= 20:15:12Incorrect
6A = 8B = 10 C
A:B:C = 1/6:1/8:1/10
= 20:15:12 -
Question 11 of 50
11. Question
The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
Correct
1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 – 550 = 56Incorrect
1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 – 550 = 56 -
Question 12 of 50
12. Question
(800 / 64) * (1296 / 36) = ?
Correct
Given Exp. = 800/64 * 1296/36
= 12.5 * 36 = 450Incorrect
Given Exp. = 800/64 * 1296/36
= 12.5 * 36 = 450 -
Question 13 of 50
13. Question
A certain sum of money is invested for one year at a certain rate of simple interest. If the rate of interest is 3% higher, then the invest earned will be 25% more than the interest earned earlier. What is the earlier rate of interest?
Correct
If the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate.
Let the earlier rate of interest be x%.
Now it will be (x + 3)%
% increase = (x + 3) – x/x * 100 = 25
=> x = 12Incorrect
If the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate.
Let the earlier rate of interest be x%.
Now it will be (x + 3)%
% increase = (x + 3) – x/x * 100 = 25
=> x = 12 -
Question 14 of 50
14. Question
3251 + 587 + 369 – ? = 3007
Correct
Let 4207 – x = 3007
Then, x = 4207 – 3007 = 1200Incorrect
Let 4207 – x = 3007
Then, x = 4207 – 3007 = 1200 -
Question 15 of 50
15. Question
A man spends 10% of his income in house rent, 20% of the rest on his children’s education, 25% of the rest miscellaneous causes. If he now posses Rs. 1944 then his income is?
Correct
X * (90/100) * (80/100) * (75/100) = 1944
X * 0.9 * 0.8 * 0.75
X = 1944/0.54
X = 3600Incorrect
X * (90/100) * (80/100) * (75/100) = 1944
X * 0.9 * 0.8 * 0.75
X = 1944/0.54
X = 3600 -
Question 16 of 50
16. Question
If the annual rate of simple interest increases from 10% to 12 1/2 %, a man’s yearly income increases by Rs. 1250. His principal in Rs. is?
Correct
Let the sum be Rs. x. Then,
(x * 25/2 * 1/100) – (x * 10 * 1)/100 = 1250
25x – 20x = 250000
x = 50000Incorrect
Let the sum be Rs. x. Then,
(x * 25/2 * 1/100) – (x * 10 * 1)/100 = 1250
25x – 20x = 250000
x = 50000 -
Question 17 of 50
17. Question
Find the least number by which (59)(36)(17) has to be multiplied to obtain a perfect square?
Correct
For any perfect square the index of the power of each of its prime factors is even. in the given number the power of 5 and 17 have odd indices, while 3 has an even index.
The least number = (5)(17) = 85.Incorrect
For any perfect square the index of the power of each of its prime factors is even. in the given number the power of 5 and 17 have odd indices, while 3 has an even index.
The least number = (5)(17) = 85. -
Question 18 of 50
18. Question
15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men?
Correct
3W = 2M
15M —— 21 * 8 hours
21 W —— x * 6 hours
14 M —— x * 6
15 * 21 * 8 = 14 * x * 6
x = 30Incorrect
3W = 2M
15M —— 21 * 8 hours
21 W —— x * 6 hours
14 M —— x * 6
15 * 21 * 8 = 14 * x * 6
x = 30 -
Question 19 of 50
19. Question
A train passes a man standing on the platform. If the train is 170 meters long and its speed is 72 kmph, how much time it took in doing so?
Correct
D = 170
S = 72 * 5/18 = 20 mps
T = 170/20 = 8 ½ secIncorrect
D = 170
S = 72 * 5/18 = 20 mps
T = 170/20 = 8 ½ sec -
Question 20 of 50
20. Question
A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
Correct
Let A be the amount received at the end of the three years.
A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.7920
So the interest = 7920 – 4800 = Rs.3120Incorrect
Let A be the amount received at the end of the three years.
A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.7920
So the interest = 7920 – 4800 = Rs.3120 -
Question 21 of 50
21. Question
Find the one which does not belong to that group ?
Correct
30 = 33 + 3, 630 = 54 + 5, 10 = 23 + 2, 520 = 83 + 8 and 130 = 53 + 5.
30, 10, 130 and 520 can be expressed as n3 + n but not 630.Incorrect
30 = 33 + 3, 630 = 54 + 5, 10 = 23 + 2, 520 = 83 + 8 and 130 = 53 + 5.
30, 10, 130 and 520 can be expressed as n3 + n but not 630. -
Question 22 of 50
22. Question
A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
Correct
The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12 = 108 ways.Incorrect
The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12 = 108 ways. -
Question 23 of 50
23. Question
A can do a piece of work in 10 days. He works at it for 4 days and then B finishes it in 9 days. In how many days can A and B together finish the work?
Correct
4/10 + 9/x = 1 => x = 15
1/10 + 1/15 = 1/6 => 6 daysIncorrect
4/10 + 9/x = 1 => x = 15
1/10 + 1/15 = 1/6 => 6 days -
Question 24 of 50
24. Question
Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
Correct
Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125 = 48 sec.Incorrect
Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125 = 48 sec. -
Question 25 of 50
25. Question
Walking 7/6 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school?
Correct
Speed Ratio = 1:7/6 = 6:7
Time Ratio = 7:6
1 ——– 7
4 ——— ? è 28 mIncorrect
Speed Ratio = 1:7/6 = 6:7
Time Ratio = 7:6
1 ——– 7
4 ——— ? è 28 m -
Question 26 of 50
26. Question
LCM of 18 and 27 is:
Correct
Incorrect
-
Question 27 of 50
27. Question
Identify the greatest numbers: 450, 2100, 1625
Correct
450 = (22)50 = 2100 => 1625 = (24)25 = 2100
Hence, 450, 2100 and 16425 are all equal.Incorrect
450 = (22)50 = 2100 => 1625 = (24)25 = 2100
Hence, 450, 2100 and 16425 are all equal. -
Question 28 of 50
28. Question
A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
Correct
(x*8*3)/100 = ((2665 – x)*3*5)/100
24x/100 = 39975/100 – 15x/100
39x = 39975 => x = 1025
Second sum = 2665 – 1025 = 1640Incorrect
(x*8*3)/100 = ((2665 – x)*3*5)/100
24x/100 = 39975/100 – 15x/100
39x = 39975 => x = 1025
Second sum = 2665 – 1025 = 1640 -
Question 29 of 50
29. Question
The side of a rhombus is 26 m and length of one of its diagonals is 20 m. The area of the rhombus is?
Correct
262 – 102 = 242
d1 = 20 d2 = 48
1/2 * 20 * 48 = 480Incorrect
262 – 102 = 242
d1 = 20 d2 = 48
1/2 * 20 * 48 = 480 -
Question 30 of 50
30. Question
If a man can cover 12 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?
Correct
12 m/s = 12 * 18/5 kmph
3 hours 45 minutes = 3 3/4 hours = 15/4 hours
Distance = speed * time = 12 * 18/5 * 15/4 km = 162 km.Incorrect
12 m/s = 12 * 18/5 kmph
3 hours 45 minutes = 3 3/4 hours = 15/4 hours
Distance = speed * time = 12 * 18/5 * 15/4 km = 162 km. -
Question 31 of 50
31. Question
Which of the following groups of fractions is in descending order?
Correct
The fractions considered are 8/15 9/13 6/11
To compare them we make the denominators the same. So the fractions are
(8 * 13 * 11)/2145, (9 * 15 * 11)/2145 and (6 * 15 * 13)/2145
1144/2145, 1485/2145 and 1170/2145
so in descending order the fractions will be
1485/2145, 1170/2145 and 1144/2145 i.e., 9/13 , 6/11 , 8/15Incorrect
The fractions considered are 8/15 9/13 6/11
To compare them we make the denominators the same. So the fractions are
(8 * 13 * 11)/2145, (9 * 15 * 11)/2145 and (6 * 15 * 13)/2145
1144/2145, 1485/2145 and 1170/2145
so in descending order the fractions will be
1485/2145, 1170/2145 and 1144/2145 i.e., 9/13 , 6/11 , 8/15 -
Question 32 of 50
32. Question
A sum of money placed at C.I. interest doubles itself in 5 years. It will amount to eight times itself at the same rate of interest in?
Correct
P(1 + R/100)5 = 2P => (1 + R/100)5 = 2
Let P(1 + R/100)n = 8P
=> (1 + R/100)n = 8 = 23 = {(1 + R/100)5}3
=> (1 + R/100)n = (1 + R/100)15 => n = 15 Required time = 15 years.Incorrect
P(1 + R/100)5 = 2P => (1 + R/100)5 = 2
Let P(1 + R/100)n = 8P
=> (1 + R/100)n = 8 = 23 = {(1 + R/100)5}3
=> (1 + R/100)n = (1 + R/100)15 => n = 15 Required time = 15 years. -
Question 33 of 50
33. Question
26.98% of 6002 + 45.01% of 4199 = ?
Correct
27% of 6000 + 45% of 4200 = ?
=> ? = 27/100 * 6000 + 45/100 * 4200
=> ? = 1620 + 1890 = 3510 = 3500Incorrect
27% of 6000 + 45% of 4200 = ?
=> ? = 27/100 * 6000 + 45/100 * 4200
=> ? = 1620 + 1890 = 3510 = 3500 -
Question 34 of 50
34. Question
Two trains are running in opposite directions with the same speed. If the length of each train is 120 m and they cross each other in 12 sec, then the speed of each train is?
Correct
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12 => x = 10
Speed of each train = 10 m/sec.
= 10 * 18/5 =- 36 km/hr.Incorrect
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12 => x = 10
Speed of each train = 10 m/sec.
= 10 * 18/5 =- 36 km/hr. -
Question 35 of 50
35. Question
The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions.
Correct
In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm = 704 mIncorrect
In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm = 704 m -
Question 36 of 50
36. Question
Ten percent of Ram’s monthly salary is equal to eight percent of Shyam’s monthly salary. Shyam’s monthly salary is twice Abhinav’s monthly salary. If Abhinav’s annual salary is Rs. 1.92 lakhs, find Ram’s monthly salary?
Correct
Let the monthly salaries of Ram and Shyam be Rs. r and Rs. s respectively.
10/100 r = 8/100 s
r = 4/5 s
Monthly salary of Abhinav = (1.92 lakhs)/12 = Rs. 0.16 lakhs
s = 2(0.16 lakhs) = 0.32 lakhs
r = 4/5(0.32 lakhs) = Rs. 25600Incorrect
Let the monthly salaries of Ram and Shyam be Rs. r and Rs. s respectively.
10/100 r = 8/100 s
r = 4/5 s
Monthly salary of Abhinav = (1.92 lakhs)/12 = Rs. 0.16 lakhs
s = 2(0.16 lakhs) = 0.32 lakhs
r = 4/5(0.32 lakhs) = Rs. 25600 -
Question 37 of 50
37. Question
Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?
Correct
1/10 + 1/15 = 1/6 * 4 = 2/3
1 – 2/3 = 1/3
1/10 + 1/15 – 1/x = 1/3
x = 8Incorrect
1/10 + 1/15 = 1/6 * 4 = 2/3
1 – 2/3 = 1/3
1/10 + 1/15 – 1/x = 1/3
x = 8 -
Question 38 of 50
38. Question
The simple interest on a sum of money will be Rs.600 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
Correct
P — 10 —- 600
P — 5 —– 300
3P — 5 —– 900
——
=> 1200Incorrect
P — 10 —- 600
P — 5 —– 300
3P — 5 —– 900
——
=> 1200 -
Question 39 of 50
39. Question
A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
Correct
Speed downstream = d/t = 85/(2 1/2) = 34 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (34 – 18)/2 = 8 kmphIncorrect
Speed downstream = d/t = 85/(2 1/2) = 34 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (34 – 18)/2 = 8 kmph -
Question 40 of 50
40. Question
Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is?
Correct
3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 1/2 = Rs.125Incorrect
3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 1/2 = Rs.125 -
Question 41 of 50
41. Question
In how many ways can live boys and three girls sit in a row such that all boys sit together?
Correct
Treat all boys as one unit. Now there are four students and they can be arranged in 4! ways. Again five boys can be arranged among themselves in 5! ways.
Required number of arrangements = 4! * 5! = 24 * 120 = 2880.Incorrect
Treat all boys as one unit. Now there are four students and they can be arranged in 4! ways. Again five boys can be arranged among themselves in 5! ways.
Required number of arrangements = 4! * 5! = 24 * 120 = 2880. -
Question 42 of 50
42. Question
The sum of three consecutive even numbers is 42. Find the middle number of the three?
Correct
Three consecutive even numbers (2P – 2), 2P, (2P + 2).
(2P – 2) + 2P + (2P + 2) = 42
6P = 42 => P = 7.
The middle number is: 2P = 14.Incorrect
Three consecutive even numbers (2P – 2), 2P, (2P + 2).
(2P – 2) + 2P + (2P + 2) = 42
6P = 42 => P = 7.
The middle number is: 2P = 14. -
Question 43 of 50
43. Question
A vessel of capacity 90 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution?
Correct
Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T – y)/T]n * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 – 9)/90]2 (90) = 72.9 litres.Incorrect
Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T – y)/T]n * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 – 9)/90]2 (90) = 72.9 litres. -
Question 44 of 50
44. Question
The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?
Correct
2x * x = 128 => x= 8
Incorrect
2x * x = 128 => x= 8
-
Question 45 of 50
45. Question
√3584 * 52.034 = ?
Correct
√3600 * 52 = ?
=> ? = 60 * 52 = 3120Incorrect
√3600 * 52 = ?
=> ? = 60 * 52 = 3120 -
Question 46 of 50
46. Question
The difference between the simple interest received from two different sources on Rs. 1500 for 3 years is Rs. 13.50. The difference between their rates of interest is?
Correct
(1500 * R1 * 3)/100 – (1500 * R2 * 3)/100 = 13.50 4500(R1 – R2) = 1350
R1 – R2 = 0.3%Incorrect
(1500 * R1 * 3)/100 – (1500 * R2 * 3)/100 = 13.50 4500(R1 – R2) = 1350
R1 – R2 = 0.3% -
Question 47 of 50
47. Question
Two numbers are in the ratio 3:5. If 9 is subtracted from each, the new numbers are in the ratio 12:23. The smaller number is:
Correct
Let the numbers be 3x and 5x.
Then, (3x – 9)/(5x – 9) = 12/23
9x = 99 => x = 11
The smallest number = 3 * 11 = 33.Incorrect
Let the numbers be 3x and 5x.
Then, (3x – 9)/(5x – 9) = 12/23
9x = 99 => x = 11
The smallest number = 3 * 11 = 33. -
Question 48 of 50
48. Question
Some pens are divided among A, B, C and D. A gets twice the number of pens that B gets. C gets the same number of pens as D gets. If A gets 25 pens more than D and the ratio of the number of pens that B and C get is 2:3, then find the number of pens that D gets?
Correct
Let the number of pens that A, B, C and D get be a, b, c and d respectively.
a:b = 2:1
a = c + 25
b:c = 2:3
a:b:c:d = 4:2:3:3a, d get 4p, 3p pens
=> 4p – 3p = 25 => p = 25
=> D gets 3p = 3 * 25 = 75 pens.Incorrect
Let the number of pens that A, B, C and D get be a, b, c and d respectively.
a:b = 2:1
a = c + 25
b:c = 2:3
a:b:c:d = 4:2:3:3a, d get 4p, 3p pens
=> 4p – 3p = 25 => p = 25
=> D gets 3p = 3 * 25 = 75 pens. -
Question 49 of 50
49. Question
Find the smallest number which should be multiplied with 520 to make it a perfect square.
Correct
520 = 26 * 20 = 2 * 13 * 22 * 5 = 23 * 13 * 5
Required smallest number = 2 * 13 * 5 = 130
130 is the smallest number which should be multiplied with 520 to make it a perfect square.Incorrect
520 = 26 * 20 = 2 * 13 * 22 * 5 = 23 * 13 * 5
Required smallest number = 2 * 13 * 5 = 130
130 is the smallest number which should be multiplied with 520 to make it a perfect square. -
Question 50 of 50
50. Question
Which of the following is the greatest?
Correct
In choice (b), the base 333 lies between 243 = (35) and 729 = (36) 3333 lies between 37 and 38Hence 3333 lies between (35)3 and (36)3, i.e., between 315 and 318In choice (c), the base 33 lies between 27 = (33) and 81 = (34).Hence 3333 lies between (33)33 and (34)33 i.e., between 399 and 3132. Hence
is greatest.Incorrect
In choice (b), the base 333 lies between 243 = (35) and 729 = (36) 3333 lies between 37 and 38Hence 3333 lies between (35)3 and (36)3, i.e., between 315 and 318In choice (c), the base 33 lies between 27 = (33) and 81 = (34).Hence 3333 lies between (33)33 and (34)33 i.e., between 399 and 3132. Hence is greatest.