LIC ADO Online Test Series 2, LIC ADO Mock Test Series 2, LIC ADO Quiz
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LIC ADO Online Test Series 2, LIC ADO Mock Test Series 2, LIC ADO Quiz.Take this LIC ADO Mock Test  Free Online Test and find out how much you score before you appear for your next interview and written test. LIC ADO English Language Online Test in English Series 2nd. Take LIC ADO Online Quiz. The LIC ADO Full online mock test paper is free for all students. LIC ADO Question and Answers in English and Hindi Series 2.Most of the organizations are opting for computer based online mode of examination. So, a student needs to practice the question papers in online mod before appearing for the exam. Here we are providing LIC ADO Full Mock Test Paper in English. LIC ADO Mock Test Series 2nd 2021. Now Test your self for LIC ADO Exam by using below quiz…
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Question 1 of 50
1. Question
The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
Correct
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l^{2} = 324 => l = 18.Incorrect
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l^{2} = 324 => l = 18. 
Question 2 of 50
2. Question
Find the least number with which 16200 should be multiplied, to make it a perfect cube.
Correct
16200 = 2^{3} * 3^{4} * 5^{2}
A perfect cube has a property of having the indices of all its prime factors divisible by 3.
Required number = 3^{2} * 5 = 45.Incorrect
16200 = 2^{3} * 3^{4} * 5^{2}
A perfect cube has a property of having the indices of all its prime factors divisible by 3.
Required number = 3^{2} * 5 = 45. 
Question 3 of 50
3. Question
Calculate the number of bricks, each measuring 25 cm * 15 cm * 8 cm required to construct a wall of dimensions 10 m * 4 m * 5 m when 10% of its volume is occupied by mortar?
Correct
10 * 4/100 * 5 * 90/100 = 25/100 * 15/100 * 8/100 * x
10 * 20 * 90 = 15 * 2 * x => x = 6000Incorrect
10 * 4/100 * 5 * 90/100 = 25/100 * 15/100 * 8/100 * x
10 * 20 * 90 = 15 * 2 * x => x = 6000 
Question 4 of 50
4. Question
Two cylinders are of the same height. Their radii are in the ratio 1: 3. If the volume of the first cylinder is 40 cc. Find the volume of the second cylinder?
Correct
r_{1} = x r_{2} = 3x
Π * x^{2} * h = 40
Π9 x^{2}h = 40 * 9 = 360Incorrect
r_{1} = x r_{2} = 3x
Π * x^{2} * h = 40
Π9 x^{2}h = 40 * 9 = 360 
Question 5 of 50
5. Question
Two pipes can fill a tank in 18 minutes and 15 minutes. An outlet pipe can empty the tank in 45 minutes. If all the pipes are opened when the tank is empty, then how many minutes will it take to fill the tank?
Correct
Part of the filled by all the three pipes in one minute
= 1/18 + 1/15 – 1/45 = (5 + 6 – 2)/90 = 9/90 = 1/10
So, the tank becomes full in 10 minutes.Incorrect
Part of the filled by all the three pipes in one minute
= 1/18 + 1/15 – 1/45 = (5 + 6 – 2)/90 = 9/90 = 1/10
So, the tank becomes full in 10 minutes. 
Question 6 of 50
6. Question
(64 + 9 + 9) / (2 * 20 + 1) = ?
Correct
(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2
Incorrect
(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2

Question 7 of 50
7. Question
The difference between simple and compound interest on Rs. 1200 for one year at 10% per annum reckoned halfyearly is?
Correct
S.I. = (1200 * 10 * 1)/100 = Rs. 120
C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3.Incorrect
S.I. = (1200 * 10 * 1)/100 = Rs. 120
C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3. 
Question 8 of 50
8. Question
(24 * 5 * 7 * 9) / ? = 216
Correct
? = (24 * 5 * 7 * 9) / 216 = 35
Incorrect
? = (24 * 5 * 7 * 9) / 216 = 35

Question 9 of 50
9. Question
A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train?
Correct
Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 250)/26 = 20
x = 270 m.Incorrect
Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 250)/26 = 20
x = 270 m. 
Question 10 of 50
10. Question
The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).
Correct
Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm
= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm
= 180 cm – 1.71 cm = 178.29 cm.Incorrect
Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm
= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm
= 180 cm – 1.71 cm = 178.29 cm. 
Question 11 of 50
11. Question
In a colony of 70 residents, the ratio of the number of men and women is 4:3. Among the women, the ratio of the educated to the uneducated is 1:4. If the ratio of the number of education to uneducated persons is 8:27, then find the ratio of the number of educated and uneducated men in the colony?
Correct
Number of men in the colony = 4/7 (70) = 40
Number of women in the colony = 3/7 (70) = 30
Number of educated women in the colony = 1/5 (30) = 6
Number of uneducated women in the colony = 4/5 (30) = 24
Number of educated persons in the colony = 8/35 (70) = 16
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 40 – 10 = 30
Number of educated men and uneducated men are in the ratio 10:30 => 1:3Incorrect
Number of men in the colony = 4/7 (70) = 40
Number of women in the colony = 3/7 (70) = 30
Number of educated women in the colony = 1/5 (30) = 6
Number of uneducated women in the colony = 4/5 (30) = 24
Number of educated persons in the colony = 8/35 (70) = 16
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 40 – 10 = 30
Number of educated men and uneducated men are in the ratio 10:30 => 1:3 
Question 12 of 50
12. Question
64309 – 8703 + 798 – 437 = ?
Correct
64309 – 8703 + 798 – 437 => 65107 – 9140 = 55967
Incorrect
64309 – 8703 + 798 – 437 => 65107 – 9140 = 55967

Question 13 of 50
13. Question
When the numerator of a fraction is decreased by 25% and its denominator is decreased by 20%, the new fraction obtained is 3/4. Find the original fraction?
Correct
Let the fraction be x/y.
When the numerator decreased by 25% and the denominator decreased by 20%.
(x * 3/4)/(y * 4/5) = 3/4 => x/y = 3/4 * (4/5)/(3/4) = 4/5Incorrect
Let the fraction be x/y.
When the numerator decreased by 25% and the denominator decreased by 20%.
(x * 3/4)/(y * 4/5) = 3/4 => x/y = 3/4 * (4/5)/(3/4) = 4/5 
Question 14 of 50
14. Question
Find the one which does not belong to that group ?
Correct
Star, Moon, Comet and Planet are natural celestial bodies, while Rocket is man made.
Incorrect
Star, Moon, Comet and Planet are natural celestial bodies, while Rocket is man made.

Question 15 of 50
15. Question
(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = ?
Correct
(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = (22 * 33 * 15 + 9 * 99 * 2 * 22) / (33 * 22 * 8 + 5 * 11 * 22 * 12)
= (22 * 33 * 15 + 22 * 33 * 54) / (33 * 22 * 8 + 33 * 22 * 20) = [22 * 33(15 + 54)] / [33 * 22(8 + 20)] = 69/28Incorrect
(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = (22 * 33 * 15 + 9 * 99 * 2 * 22) / (33 * 22 * 8 + 5 * 11 * 22 * 12)
= (22 * 33 * 15 + 22 * 33 * 54) / (33 * 22 * 8 + 33 * 22 * 20) = [22 * 33(15 + 54)] / [33 * 22(8 + 20)] = 69/28 
Question 16 of 50
16. Question
A train passes a man standing on the platform. If the train is 170 meters long and its speed is 72 kmph, how much time it took in doing so?
Correct
D = 170
S = 72 * 5/18 = 20 mps
T = 170/20 = 8 ½ secIncorrect
D = 170
S = 72 * 5/18 = 20 mps
T = 170/20 = 8 ½ sec 
Question 17 of 50
17. Question
On dividing a number by 68, we get 269 as quotient and 0 as remainder. On dividing the same number by 67, what will be the remainder?
Correct
Number = 269 * 68 + 0 = 18292
67) 18292 (273
18291
——–
1
Required number = 1.Incorrect
Number = 269 * 68 + 0 = 18292
67) 18292 (273
18291
——–
1
Required number = 1. 
Question 18 of 50
18. Question
The least number of four digits which is divisible by 15, 25, 40 and 75 is:
Correct
Greatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399. Required number = 9999 – 399 = 9600Incorrect
Greatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399. Required number = 9999 – 399 = 9600 
Question 19 of 50
19. Question
A man swims downstream 30 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?
Correct
30 — 3 DS = 10
? — 1
18 — 3 US = 6
? — 1 M = ?
M = (10 + 6)/2 = 8Incorrect
30 — 3 DS = 10
? — 1
18 — 3 US = 6
? — 1 M = ?
M = (10 + 6)/2 = 8 
Question 20 of 50
20. Question
Express 25 mps in kmph?
Correct
25 * 18/5 = 90 kmph
Incorrect
25 * 18/5 = 90 kmph

Question 21 of 50
21. Question
A can do a piece of work in 4 hours; B and C together can do it in 3 hours, which A and C together can do it in 2 hours. How long will B alone take to do it?
Correct
A’s 1 hour work = 1/4;
(B + C)’s 1 hour work = 1/3;
(A + C)’s 1 hour work = 1/2
(A + B + C)’s 1 hour work = (1/4 + 1/3) = 7/12
B’s 1 hour work = (7/12 + 1/2) = 1/12
B alone will take 12 hours to do the work.Incorrect
A’s 1 hour work = 1/4;
(B + C)’s 1 hour work = 1/3;
(A + C)’s 1 hour work = 1/2
(A + B + C)’s 1 hour work = (1/4 + 1/3) = 7/12
B’s 1 hour work = (7/12 + 1/2) = 1/12
B alone will take 12 hours to do the work. 
Question 22 of 50
22. Question
Rs.4500 amounts to Rs.5544 in two years at compound interest, compounded annually. If the rate of the interest for the first year is 12%, find the rate of interest for the second year?
Correct
Let the rate of interest during the second year be R%. Given,
4500 * {(100 + 12)/100} * {(100 + R)/100} = 5544
R = 10%Incorrect
Let the rate of interest during the second year be R%. Given,
4500 * {(100 + 12)/100} * {(100 + R)/100} = 5544
R = 10% 
Question 23 of 50
23. Question
A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?
Correct
Given that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.
Hence, the required number of ways = 4^{5} – 1.
= 2^{10} – 1 = 1024 – 1 = 1023Incorrect
Given that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.
Hence, the required number of ways = 4^{5} – 1.
= 2^{10} – 1 = 1024 – 1 = 1023 
Question 24 of 50
24. Question
If a : b = 4 : 1, then find (a – 3b)/(2a – b).
Correct
a : b = 4 : 1
a/b = 4/1 => a = 4b
(a – 3b)/(2a – b) = (4b – 3b)/[2(4b) – b]
= b/(8b – b) = b/7b => 1/7Incorrect
a : b = 4 : 1
a/b = 4/1 => a = 4b
(a – 3b)/(2a – b) = (4b – 3b)/[2(4b) – b]
= b/(8b – b) = b/7b => 1/7 
Question 25 of 50
25. Question
A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that all the four bulbs are defective.
Correct
Out of nine, five are good and four are defective. Required probability = ⁴C₄/⁹C₄ = 1/126
Incorrect
Out of nine, five are good and four are defective. Required probability = ⁴C₄/⁹C₄ = 1/126

Question 26 of 50
26. Question
The average of 35 students in a class is 16 years. The average age of 21 students is 14. What is the average age of remaining 14 students?
Correct
Sum of the ages of 14 students
= (16 * 35) – (14 * 21) = 560 – 294 = 266
Required average = (266/14) = 19 years.Incorrect
Sum of the ages of 14 students
= (16 * 35) – (14 * 21) = 560 – 294 = 266
Required average = (266/14) = 19 years. 
Question 27 of 50
27. Question
The salary of a worker is first increased by 30% and afterwards reduced by 30%. What is net change in his salary?
Correct
(30 * 30)/100 = 9% decrease
Incorrect
(30 * 30)/100 = 9% decrease

Question 28 of 50
28. Question
A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?
Correct
Speed downstream = 20 + 6 = 26 kmph.
Time required to cover 60 km downstream = d/s = 60/26 = 30/13 hours.Incorrect
Speed downstream = 20 + 6 = 26 kmph.
Time required to cover 60 km downstream = d/s = 60/26 = 30/13 hours. 
Question 29 of 50
29. Question
A is twice as good a workman as B and they took 7 days together to do the work B alone can do it in.
Correct
WC = 2:1
2x + x = 1/7
x = 1/21 => 21 daysIncorrect
WC = 2:1
2x + x = 1/7
x = 1/21 => 21 days 
Question 30 of 50
30. Question
After decreasing 24% in the price of an article costs Rs.912. Find the actual cost of an article?
Correct
CP* (76/100) = 912
CP= 12 * 100 => CP = 1200Incorrect
CP* (76/100) = 912
CP= 12 * 100 => CP = 1200 
Question 31 of 50
31. Question
The smallest ratio out of 1:1, 2:1, 1:3 and 3:1 is?
Correct
Incorrect

Question 32 of 50
32. Question
Sachin is younger than Rahul by 4 years. If their ages are in the respective ratio of 7:9, how old is Sachin?
Correct
Let Rahul’s age be x years.
Then, Sachin’s age = (x – 7) years.
(x – 7)/x = 7/9
2x = 63 => x = 31.5
Hence, Sachin’s age = (x – 7) = 24.5 years.Incorrect
Let Rahul’s age be x years.
Then, Sachin’s age = (x – 7) years.
(x – 7)/x = 7/9
2x = 63 => x = 31.5
Hence, Sachin’s age = (x – 7) = 24.5 years. 
Question 33 of 50
33. Question
A is faster than B. A and B each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then, A’s speed is equal to?
Correct
Let A’s speed = x km/hr. Then, B’s speed = (7 – x) km/ hr.
So, 24/x + 24/(7 – x) = 14
x^{2} – 98x + 168 = 0
(x – 3)(x – 4) = 0 => x = 3 or 4.
Since, A is faster than B, so A’s speed = 4 km/hr and B’s speed = 3 km/hr.Incorrect
Let A’s speed = x km/hr. Then, B’s speed = (7 – x) km/ hr.
So, 24/x + 24/(7 – x) = 14
x^{2} – 98x + 168 = 0
(x – 3)(x – 4) = 0 => x = 3 or 4.
Since, A is faster than B, so A’s speed = 4 km/hr and B’s speed = 3 km/hr. 
Question 34 of 50
34. Question
A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
Correct
Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m.Incorrect
Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m. 
Question 35 of 50
35. Question
A man can do a job in 15 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together?
Correct
1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300
So, all three together will complete the work in 300/47 = 6.4 days.Incorrect
1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300
So, all three together will complete the work in 300/47 = 6.4 days. 
Question 36 of 50
36. Question
A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clocks at a gain of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs. 40 less. The cost price of each clock is:
Correct
Let C.P. of clock be Rs. x.
Then, C.P. of 90 clocks = Rs. 90x.
[(110% of 40x) + (120% of 50x)] – (115% of 90x) = 40
44x + 60x – 103.5x = 40
0.5x = 40 => x = 80Incorrect
Let C.P. of clock be Rs. x.
Then, C.P. of 90 clocks = Rs. 90x.
[(110% of 40x) + (120% of 50x)] – (115% of 90x) = 40
44x + 60x – 103.5x = 40
0.5x = 40 => x = 80 
Question 37 of 50
37. Question
Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 18000, then find his savings.
Correct
Let the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.
Income, 5x = 18000 => x = 3600
Savings = Income – expenditure = 5x – 4x = x
So, savings = Rs. 3600.Incorrect
Let the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.
Income, 5x = 18000 => x = 3600
Savings = Income – expenditure = 5x – 4x = x
So, savings = Rs. 3600. 
Question 38 of 50
38. Question
What is the unit digit in 7^{105} ?
Correct
Unit digit in 7^{105} = unit digit in [(7^{4})^{26} * 7]
But, unit digit in (7^{4})^{26} = 1
unit digit in 7^{105} = (1 * 7) = 7Incorrect
Unit digit in 7^{105} = unit digit in [(7^{4})^{26} * 7]
But, unit digit in (7^{4})^{26} = 1
unit digit in 7^{105} = (1 * 7) = 7 
Question 39 of 50
39. Question
What percent of 125 is 16?
Correct
Let the required percentage be x%.
x% of 125 = 16 => x/100 * 125 = 16
=> x = 1600/125 = 64/5 = 12 4/5Incorrect
Let the required percentage be x%.
x% of 125 = 16 => x/100 * 125 = 16
=> x = 1600/125 = 64/5 = 12 4/5 
Question 40 of 50
40. Question
Rs. 6000 is lent out in two parts. One part is lent at 7% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
Correct
Let the amount lent at 7% be Rs. x
Amount lent at 10% is Rs. (6000 – x)
Total interest for one year on the two sums lent
= 7/100 x + 10/100 (6000 – x) = 600 – 3x/100
=> 600 – 3/100 x = 450 => x = 5000
Amount lent at 10% = 1000
Required ratio = 5000 : 1000 = 5 : 1Incorrect
Let the amount lent at 7% be Rs. x
Amount lent at 10% is Rs. (6000 – x)
Total interest for one year on the two sums lent
= 7/100 x + 10/100 (6000 – x) = 600 – 3x/100
=> 600 – 3/100 x = 450 => x = 5000
Amount lent at 10% = 1000
Required ratio = 5000 : 1000 = 5 : 1 
Question 41 of 50
41. Question
√3584 * 52.034 = ?
Correct
√3600 * 52 = ?
=> ? = 60 * 52 = 3120Incorrect
√3600 * 52 = ?
=> ? = 60 * 52 = 3120 
Question 42 of 50
42. Question
Sum of two consecutive even terms lacks by 98 from their product. Find the sum of these numbers?
Correct
x(x + 2) – (x + x + 2) = 98
Incorrect
x(x + 2) – (x + x + 2) = 98

Question 43 of 50
43. Question
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Correct
Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.
Incorrect
Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.

Question 44 of 50
44. Question
Find the one which does not belong to that group ?
Correct
20 = 4^{2} + 4, 42 = 6^{2} + 6, 58 = 7^{2} + 9, 72 = 8^{2} + 8 and 90 = 9^{2} + 9.
20, 42, 72 and 90 can be expressed in n^{2} + n form but not 58.Incorrect
20 = 4^{2} + 4, 42 = 6^{2} + 6, 58 = 7^{2} + 9, 72 = 8^{2} + 8 and 90 = 9^{2} + 9.
20, 42, 72 and 90 can be expressed in n^{2} + n form but not 58. 
Question 45 of 50
45. Question
21345 * 45 = 4270 * ?
Correct
? = (21345 * 45) / 4270
? = 225Incorrect
? = (21345 * 45) / 4270
? = 225 
Question 46 of 50
46. Question
The sum of three numbers is 98. If the ratio of the first to the second is 2:3. And that of the second to the third is 5:8, then the second number is:
Correct
Let the three parts A, B, C.
Then, A:B = 2:3 and B:C = 5:8
= (5 * 3/5) : (8 * 3/5) = 3:24/5
A:B:C = 2:3:24/5
= 10:15:24 => B = 98 * 15/49 = 30.Incorrect
Let the three parts A, B, C.
Then, A:B = 2:3 and B:C = 5:8
= (5 * 3/5) : (8 * 3/5) = 3:24/5
A:B:C = 2:3:24/5
= 10:15:24 => B = 98 * 15/49 = 30. 
Question 47 of 50
47. Question
Rahim bought 65 books for Rs.1150 from one shop and 50 books for Rs.920 from another. What is the average price he paid per book ?
Correct
Average price per book = (1150 + 920) / (65 + 50) = 2070 / 115 = Rs.18
Incorrect
Average price per book = (1150 + 920) / (65 + 50) = 2070 / 115 = Rs.18

Question 48 of 50
48. Question
The radius of a cylindrical vessel is 7cm and height is 3cm. Find the whole surface of the cylinder?
Correct
r = 7 h = 3
2πr(h + r) = 2 * 22/7 * 7(10) = 440Incorrect
r = 7 h = 3
2πr(h + r) = 2 * 22/7 * 7(10) = 440 
Question 49 of 50
49. Question
7 2/5 of 110 / ? = 844
Correct
? = 844 – 7 2/5 of 110 = 844 – 37 * 22 = 30
Incorrect
? = 844 – 7 2/5 of 110 = 844 – 37 * 22 = 30

Question 50 of 50
50. Question
A can do a piece of work in 12 days. When he had worked for 2 days B joins him. If the complete work was finished in 8 days. In how many days B alone can finish the work?
Correct
8/12 + 6/x = 1
X = 18 daysIncorrect
8/12 + 6/x = 1
X = 18 days