MAT Mock Test Series 3 | MAT Online Test Series 3 | MAT Sample Papers
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MAT Mock Test Series 3, MAT Free Online Test Series 3. Find MAT Mock Papers, MAT sample Papers & MAT Practice Online Test. You may access the MAT online mock practice test from the official MAT website. MAT Free Mock Test Exam 2021. MAT Exam Free Online Quiz 2021, MAT Full Online Mock Test Series 3rd in English. MAT Free Mock Test Series in English. MAT Free Mock Test Series 3. MAT English Language Online Test in English Series 3rd. Take MAT Online Quiz. The MAT Full online mock test paper is free for all students. MAT Question and Answers in English and Hindi Series 3. Here we are providing MAT Full Mock Test Paper in English. MAT Mock Test Series 3rd 2021. Now Test your self for MAT Exam by using below quiz…
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Question 1 of 50
1. Question
(112 * 54) = ?
Correct
(112 * 54) = 112 * (10/2)4
= (112 * 104)/24 = 1120000/16 = 70000Incorrect
(112 * 54) = 112 * (10/2)4
= (112 * 104)/24 = 1120000/16 = 70000 -
Question 2 of 50
2. Question
A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?
Correct
Suppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x – 5) and (x – 9) hours respectively to fill the tank.
1/x + 1/(x – 5) = 1/(x – 9)
(2x – 5)(x – 9) = x(x – 5)
x2 – 18x + 45 = 0
(x- 15)(x – 3) = 0 => x = 15Incorrect
Suppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x – 5) and (x – 9) hours respectively to fill the tank.
1/x + 1/(x – 5) = 1/(x – 9)
(2x – 5)(x – 9) = x(x – 5)
x2 – 18x + 45 = 0
(x- 15)(x – 3) = 0 => x = 15 -
Question 3 of 50
3. Question
On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:
Correct
Clearly, (2272 – 875) = 1397, is exactly divisible by N.
Now. 1397 = 11 * 127
The required 3-digit number is 127, the sum of whose digit is 10.Incorrect
Clearly, (2272 – 875) = 1397, is exactly divisible by N.
Now. 1397 = 11 * 127
The required 3-digit number is 127, the sum of whose digit is 10. -
Question 4 of 50
4. Question
15% of 195 + 14% of 205 = ?
Correct
15/100 * 195 + 14/100 * 205 = 15/100 * 200 + 14/100 * 200
= 30 + 28 = 58Incorrect
15/100 * 195 + 14/100 * 205 = 15/100 * 200 + 14/100 * 200
= 30 + 28 = 58 -
Question 5 of 50
5. Question
The C.I. on a certain sum for 2 years Rs.41 and the simple interest is Rs.40. What is the rate percent?
Correct
SI = 20 + 20
CI = 20 + 21
20 —- 1
100 —- ? => 5%Incorrect
SI = 20 + 20
CI = 20 + 21
20 —- 1
100 —- ? => 5% -
Question 6 of 50
6. Question
A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group?
Correct
Two men, three women and one child can be selected in ⁴C₂ * ⁶C₃ * ⁵C₁ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways.Incorrect
Two men, three women and one child can be selected in ⁴C₂ * ⁶C₃ * ⁵C₁ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways. -
Question 7 of 50
7. Question
Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours. C is closed A and B can fill the remaining par in 7 hours. The number of hours taken by C alone to fill the tank is?
Correct
Part filled in 2 hours = 2/6 = 1/3.
Remaining part = 1 – 1/3 = 2/3
(A + B)’s 1 hour work = 2/21
C’s 1 hour work = [(A + B + C)’s 1 hour work – (A + B)’s 1 hour work]
= (1/6 – 2/21) = 1/14
C alone can fill the tank in 14 hours.Incorrect
Part filled in 2 hours = 2/6 = 1/3.
Remaining part = 1 – 1/3 = 2/3
(A + B)’s 1 hour work = 2/21
C’s 1 hour work = [(A + B + C)’s 1 hour work – (A + B)’s 1 hour work]
= (1/6 – 2/21) = 1/14
C alone can fill the tank in 14 hours. -
Question 8 of 50
8. Question
A man engaged a servant on the condition that he would pay him Rs.710 and a uniform after a year service. He served only for 8 months and got Rs.460 and a uniform. Find the price of the uniform?
Correct
8/12 = 2/3 * 710 = 473.33
460.00
—————
13.33
1/3 uniform 13.33
1 ————— ? => Rs.40Incorrect
8/12 = 2/3 * 710 = 473.33
460.00
—————
13.33
1/3 uniform 13.33
1 ————— ? => Rs.40 -
Question 9 of 50
9. Question
Three years ago the average age of a family of six members was 19 years. A boy have been born, the average age of the family is the same today. What is the age of the boy?
Correct
6 * 22 = 132
7 * 19 = 133
————–
1Incorrect
6 * 22 = 132
7 * 19 = 133
————–
1 -
Question 10 of 50
10. Question
A circular path of 13 m radius has marginal walk 2 m wide all round it. Find the cost of leveling the walk at 25p per m2?
Correct
π (152 – 132) = 176
176 * 1/4 = Rs.44Incorrect
π (152 – 132) = 176
176 * 1/4 = Rs.44 -
Question 11 of 50
11. Question
I. a2 – 7a + 12 = 0,
II. b2 – 3b + 2 = 0 to solve both the equations to find the values of a and b?Correct
I.(a – 3)(a – 4) = 0
=> a = 3, 4
II. (b – 2)(b – 1) = 0
=> b = 1, 2
=> a > bIncorrect
I.(a – 3)(a – 4) = 0
=> a = 3, 4
II. (b – 2)(b – 1) = 0
=> b = 1, 2
=> a > b -
Question 12 of 50
12. Question
The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of?
Correct
4:5
3:2
——-
12:15:10
12:10
6:5Incorrect
4:5
3:2
——-
12:15:10
12:10
6:5 -
Question 13 of 50
13. Question
On an order of 5 dozen boxes of a consumer product, a retailer receives an extra dozen free. This is equivalent to allowing him a discount of:
Correct
Clearly, the retailer gets 1 dozen out of 6 dozens free.
Equivalent discount = 1/6 * 100 = 16 2/3%.Incorrect
Clearly, the retailer gets 1 dozen out of 6 dozens free.
Equivalent discount = 1/6 * 100 = 16 2/3%. -
Question 14 of 50
14. Question
If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?
Correct
9 = (1*40*R)/100
R = 22 1/2 %Incorrect
9 = (1*40*R)/100
R = 22 1/2 % -
Question 15 of 50
15. Question
The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
Correct
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l2 = 324 => l = 18.Incorrect
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l2 = 324 => l = 18. -
Question 16 of 50
16. Question
The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275, then the other is:
Correct
Other number = (11 * 7700)/275 = 308.
Incorrect
Other number = (11 * 7700)/275 = 308.
-
Question 17 of 50
17. Question
A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2460?
Correct
Incorrect
-
Question 18 of 50
18. Question
Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much?
Correct
(8000*3*2)/100 = 480
9200
——–
9680Incorrect
(8000*3*2)/100 = 480
9200
——–
9680 -
Question 19 of 50
19. Question
Ratio of the earnings of A and B is 4:7. If the earnings of A increases by 50% and those of B decreased by 25%, the new ratio of their earnings becomes 8:7. What are A’s earnings?
Correct
Let the original earnings of A and B be Rs. 4x and Rs. 7x.
New earnings of A = 150% 0f Rs. 4x = (150/100 * 4x) = Rs. 6x
New earnings of B = 75% of Rs. 7x = (75/100 * 7x) = Rs. 21x/4
6x:21x/4 = 8:7
This does not give x. So, the given data is inadequate.Incorrect
Let the original earnings of A and B be Rs. 4x and Rs. 7x.
New earnings of A = 150% 0f Rs. 4x = (150/100 * 4x) = Rs. 6x
New earnings of B = 75% of Rs. 7x = (75/100 * 7x) = Rs. 21x/4
6x:21x/4 = 8:7
This does not give x. So, the given data is inadequate. -
Question 20 of 50
20. Question
(1000)9/1024 = ?
Correct
Given Exp. = (1000)9/1024
= (103)9/1024 = 1027/1024 = 10(27 – 24) = 103 =1000Incorrect
Given Exp. = (1000)9/1024
= (103)9/1024 = 1027/1024 = 10(27 – 24) = 103 =1000 -
Question 21 of 50
21. Question
A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
Correct
Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230.Incorrect
Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230. -
Question 22 of 50
22. Question
The successive discounts 20% and 15% are equal to a single discount of?
Correct
Let the CP of an article be Rs. 100
Given that successive discounts are 20% and 15%.
SP = 85% of 80% of 100 = (85/100)(80/100)(100)
=> SP = Rs. 68
Clearly, single discount is 32%.Incorrect
Let the CP of an article be Rs. 100
Given that successive discounts are 20% and 15%.
SP = 85% of 80% of 100 = (85/100)(80/100)(100)
=> SP = Rs. 68
Clearly, single discount is 32%. -
Question 23 of 50
23. Question
Find the one which does not belong to that group ?
Correct
B+2D+2F+6L, P+2R+3U+5Z, J+2L+3O+5T, C+2E+3H+5M and I+2K+3N+5S.
Except BDFL, all other groups follows similar pattern.Incorrect
B+2D+2F+6L, P+2R+3U+5Z, J+2L+3O+5T, C+2E+3H+5M and I+2K+3N+5S.
Except BDFL, all other groups follows similar pattern. -
Question 24 of 50
24. Question
5 men and 12 boys finish a piece of work in 4 days, 7 men and 6 boys do it in 5 days. The ratio between the efficiencies of a man and boy is?
Correct
5M + 12B —– 4 days
7M + 6B ——- 5 days
20M + 48B = 35M + 30B
18B = 15M => 5M = 6B
M: B = 6:5Incorrect
5M + 12B —– 4 days
7M + 6B ——- 5 days
20M + 48B = 35M + 30B
18B = 15M => 5M = 6B
M: B = 6:5 -
Question 25 of 50
25. Question
In how many years will a sum of money doubles itself at 5% per annum on simple interest?
Correct
P = (P*5*R)/100
R = 20%Incorrect
P = (P*5*R)/100
R = 20% -
Question 26 of 50
26. Question
24 – [2.4 – {0.24 * 2 – (0.024 – ?)}] = 22.0584
Correct
24 – [2.4 – {0.24 * 2 – (0.024 – ?)}] = 22.0584
24 – [2.4 – {0.48 – (0.024 – ?)}] = 22.0584
24 – [2.4 – 0.48 + 0.024 – ?] = 22.0584
24 – 2.4 + 0.48 – 0.024 + ? = 22.0584
? = 22.0584 – 24.48 + 2.424
? = 24.2824 – 24.48 => ? = 0.0024Incorrect
24 – [2.4 – {0.24 * 2 – (0.024 – ?)}] = 22.0584
24 – [2.4 – {0.48 – (0.024 – ?)}] = 22.0584
24 – [2.4 – 0.48 + 0.024 – ?] = 22.0584
24 – 2.4 + 0.48 – 0.024 + ? = 22.0584
? = 22.0584 – 24.48 + 2.424
? = 24.2824 – 24.48 => ? = 0.0024 -
Question 27 of 50
27. Question
80 is what percent of 64?
Correct
Let x percent of 64 be 80.
64 * x/100 = 80 => x = (80 * 100)/64 => x = 125
80 is 125% of 64.Incorrect
Let x percent of 64 be 80.
64 * x/100 = 80 => x = (80 * 100)/64 => x = 125
80 is 125% of 64. -
Question 28 of 50
28. Question
Divide Rs.32000 in the ratio 3:5?
Correct
3/8 * 32000 = 12000
5/8 * 32000 = 20000Incorrect
3/8 * 32000 = 12000
5/8 * 32000 = 20000 -
Question 29 of 50
29. Question
The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?
Correct
r = 3 πr2 = 9
r = 5 πr2 = 25
25 π – 16 π
100 —- ? => 64%Incorrect
r = 3 πr2 = 9
r = 5 πr2 = 25
25 π – 16 π
100 —- ? => 64% -
Question 30 of 50
30. Question
Find the compound interest and the amount on Rs.8000 at 5% per annum for 3 years when C.I is reckoned yearly?
Correct
A = 8000(21/20)3
= 9261
= 8000
———
1261Incorrect
A = 8000(21/20)3
= 9261
= 8000
———
1261 -
Question 31 of 50
31. Question
(50 – ?/29)% of 4200 = 3√196
Correct
(50 – ?/29)% of 4200 = 3√196
Incorrect
(50 – ?/29)% of 4200 = 3√196
-
Question 32 of 50
32. Question
A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
Correct
Net part filled in 1 hour = (1/4 – 1/9) = 5/36
The cistern will be filled in 36/5 hrs i.e., 7.2 hrs.Incorrect
Net part filled in 1 hour = (1/4 – 1/9) = 5/36
The cistern will be filled in 36/5 hrs i.e., 7.2 hrs. -
Question 33 of 50
33. Question
64 boys and 40 girls form a group for social work. During their membership drive, the same number of boys and girls joined the group. How many members does the group have now, if the ratio of boys to girls is 4:3?
Correct
Let us say x boys and x girls joined the group.
(64 + x)/(40 + x) = 4/3
192 + 3x = 160 + 4x => x = 32
Number of members in the group = 64 + x + 40 + x
= 104 + 2x = 168.Incorrect
Let us say x boys and x girls joined the group.
(64 + x)/(40 + x) = 4/3
192 + 3x = 160 + 4x => x = 32
Number of members in the group = 64 + x + 40 + x
= 104 + 2x = 168. -
Question 34 of 50
34. Question
I. x2 + 3x – 18 = 0,
II. y2 + y – 30 = 0 to solve both the equations to find the values of x and y?Correct
I. x2 + 6x – 3x – 18 = 0
=>(x + 6)(x – 3) = 0 => x = -6, 3
II. y2 + 6y – 5y – 30 = 0
=>(y + 6)(y – 5) = 0 => y = -6, 5
No relationship can be established between x and y.Incorrect
I. x2 + 6x – 3x – 18 = 0
=>(x + 6)(x – 3) = 0 => x = -6, 3
II. y2 + 6y – 5y – 30 = 0
=>(y + 6)(y – 5) = 0 => y = -6, 5
No relationship can be established between x and y. -
Question 35 of 50
35. Question
The average of first five prime numbers greater than 20 is?
Correct
23 + 29 + 31 + 37 + 41 = 161/5 = 32.2
Incorrect
23 + 29 + 31 + 37 + 41 = 161/5 = 32.2
-
Question 36 of 50
36. Question
Find the greatest number which divides 83, 125 and 209 leaving the same remainder in each case.
Correct
The greatest number which divides three dividends p, q and r leaving the same remainder in each case is given by H.C.F(any two of (q – p), (r – p) and (r – q)).
For the given problem, p = 83, q = 125 and r = 209.
Hence the greatest number which divides these three leaving the same remainder in each case is H.C.F(any two of (125 – 83, 209 – 83, 209 – 125) = 42.Incorrect
The greatest number which divides three dividends p, q and r leaving the same remainder in each case is given by H.C.F(any two of (q – p), (r – p) and (r – q)).
For the given problem, p = 83, q = 125 and r = 209.
Hence the greatest number which divides these three leaving the same remainder in each case is H.C.F(any two of (125 – 83, 209 – 83, 209 – 125) = 42. -
Question 37 of 50
37. Question
When the numerator of a fraction is decreased by 25% and its denominator is decreased by 20%, the new fraction obtained is 3/4. Find the original fraction?
Correct
Let the fraction be x/y.
When the numerator decreased by 25% and the denominator decreased by 20%.
(x * 3/4)/(y * 4/5) = 3/4 => x/y = 3/4 * (4/5)/(3/4) = 4/5Incorrect
Let the fraction be x/y.
When the numerator decreased by 25% and the denominator decreased by 20%.
(x * 3/4)/(y * 4/5) = 3/4 => x/y = 3/4 * (4/5)/(3/4) = 4/5 -
Question 38 of 50
38. Question
A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 20%?
Correct
Cost price = Rs.500
profit = 20% of 500 = Rs.100
Selling price = Cost price + Profit
= 500 + 100 = 600Incorrect
Cost price = Rs.500
profit = 20% of 500 = Rs.100
Selling price = Cost price + Profit
= 500 + 100 = 600 -
Question 39 of 50
39. Question
Which one of the following numbers is exactly divisible by 11?
Correct
(4 + 5 + 2) – (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) – (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 4) = 0.
So, 415624 is divisible by 11.Incorrect
(4 + 5 + 2) – (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) – (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 4) = 0.
So, 415624 is divisible by 11. -
Question 40 of 50
40. Question
How many numbers up to 100 are divisible by 7?
Correct
100/7 = 14 2/7 => 14 Numbers
Incorrect
100/7 = 14 2/7 => 14 Numbers
-
Question 41 of 50
41. Question
A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
Correct
M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9 = 4Incorrect
M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9 = 4 -
Question 42 of 50
42. Question
Find the one which does not belong to that group ?
Correct
P-3M+6S, R-3O+6U, G-3D+6J, K-2I+4M and E-3B+6H
Except KIM, all other groups follows similar pattern.Incorrect
P-3M+6S, R-3O+6U, G-3D+6J, K-2I+4M and E-3B+6H
Except KIM, all other groups follows similar pattern. -
Question 43 of 50
43. Question
The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
Correct
Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) – (6 * 3) – 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5 = Rs. 4530Incorrect
Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) – (6 * 3) – 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5 = Rs. 4530 -
Question 44 of 50
44. Question
An amount of Rs. 3000 becomes Rs. 3600 in four years at simple interest. If the rate of interest was 1% more, then what was be the total amount?
Correct
A = P(1 + TR/100)
=> 3600 = 3000[1 + (4 * R)/100] => R = 5%
Now R = 6%
=> A = 3000[1 + (4 * 6)/100] = Rs. 3720.Incorrect
A = P(1 + TR/100)
=> 3600 = 3000[1 + (4 * R)/100] => R = 5%
Now R = 6%
=> A = 3000[1 + (4 * 6)/100] = Rs. 3720. -
Question 45 of 50
45. Question
The difference between two integers is 5. Their product is 500. Find the numbers.
Correct
Let the integers be x and (x + 5). Then,
x(x + 5) = 500
x2 + 5x – 500 = 0
(x + 25)(x – 20) = 0
x = 20
So, the numbers are 20 and 25.Incorrect
Let the integers be x and (x + 5). Then,
x(x + 5) = 500
x2 + 5x – 500 = 0
(x + 25)(x – 20) = 0
x = 20
So, the numbers are 20 and 25. -
Question 46 of 50
46. Question
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Correct
Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m.Incorrect
Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m. -
Question 47 of 50
47. Question
Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.5400. How much third person will get?
Correct
First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 54000 = 2400Incorrect
First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 54000 = 2400 -
Question 48 of 50
48. Question
[8 + {(21 * √9/441 – 1 /5 of 60% – 1/5) * 625 + 7} ÷ 4] = ?
Correct
[8 + {(21 * √9/441 – 1 /5 of 60% – 1/5) * 625 + 7} ÷ 4] = ?
=[8 + [(2/5 * 3/5 – 1/5) * 625 + 7} ÷ 4] = ?
=[8 + {(6 – 5 /25) * 625 + 7} ÷ 4 = ?
=[8 + {32} ÷ 4] = ? = 16Incorrect
[8 + {(21 * √9/441 – 1 /5 of 60% – 1/5) * 625 + 7} ÷ 4] = ?
=[8 + [(2/5 * 3/5 – 1/5) * 625 + 7} ÷ 4] = ?
=[8 + {(6 – 5 /25) * 625 + 7} ÷ 4 = ?
=[8 + {32} ÷ 4] = ? = 16 -
Question 49 of 50
49. Question
The average age of three boys is 15 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?
Correct
3x + 5x + 7x = 45
x =3
3x = 9Incorrect
3x + 5x + 7x = 45
x =3
3x = 9 -
Question 50 of 50
50. Question
The average of 35 numbers is 25. If each number is multiplied by 5, find the new average?
Correct
Sum of the 35 numbers = 35 * 25 = 875
If each number is multiplied by 5, the sum also gets multiplied by 5 and the average also gets multiplied by 5.
Thus, the new average = 25 * 5 = 125.Incorrect
Sum of the 35 numbers = 35 * 25 = 875
If each number is multiplied by 5, the sum also gets multiplied by 5 and the average also gets multiplied by 5.
Thus, the new average = 25 * 5 = 125.