# MAT MCQ Series 2 | MAT Mock Test Series 2 | MAT Sample Papers |

## MAT Online Test Series 2 | MAT Mock Test Series 2 | MAT Sample Papers |

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- Question 1 of 50
##### 1. Question

A sum of money becomes double itself in 8 years at simple interest. How many times will it become 10 years at the same rate?

CorrectP —- 2P —- 8 years

2 1/4 P —- 10 yearsIncorrectP —- 2P —- 8 years

2 1/4 P —- 10 years - Question 2 of 50
##### 2. Question

The bus fare for two persons for travelling between Agra and Aligarh id four-thirds the train fare between the same places for one person. The total fare paid by 6 persons travelling by bus and 8 persons travelling by train between the two places is Rs.1512. Find the train fare between the two places for one person?

CorrectLet the train fare between the two places for one person be Rs.t

Bus fare between the two places for two persons Rs.4/3 t

=> 6/2 (4/3 t) + 8(t) = 1512

=> 12t = 1512 => t = 126.IncorrectLet the train fare between the two places for one person be Rs.t

Bus fare between the two places for two persons Rs.4/3 t

=> 6/2 (4/3 t) + 8(t) = 1512

=> 12t = 1512 => t = 126. - Question 3 of 50
##### 3. Question

A bag contains five white and four red balls. Two balls are picked at random from the bag. What is the probability that they both are different color?

CorrectTwo balls can be picked from nine balls in ⁹C₂ ways.

We select one white ball and one red ball from five white balls and four red balls. This can be done ⁵C₁ . ⁴C₁ ways.

The required probability = (5 * 4)/⁹C₂ = 20/36 = 5/9IncorrectTwo balls can be picked from nine balls in ⁹C₂ ways.

We select one white ball and one red ball from five white balls and four red balls. This can be done ⁵C₁ . ⁴C₁ ways.

The required probability = (5 * 4)/⁹C₂ = 20/36 = 5/9 - Question 4 of 50
##### 4. Question

On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:

CorrectClearly, (2272 – 875) = 1397, is exactly divisible by N.

Now. 1397 = 11 * 127

The required 3-digit number is 127, the sum of whose digit is 10.IncorrectClearly, (2272 – 875) = 1397, is exactly divisible by N.

Now. 1397 = 11 * 127

The required 3-digit number is 127, the sum of whose digit is 10. - Question 5 of 50
##### 5. Question

If Re.1 amounts to Rs.9 over a period of 20 years. What is the rate of simple interest?

Correct8 = (1*20*R)/100

R = 40%Incorrect8 = (1*20*R)/100

R = 40% - Question 6 of 50
##### 6. Question

The average age of a husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:

CorrectSum of the present ages of husband, wife and child = (23 * 2 + 5 * 2) = 57 years.

Required average = 57/3 = 19 years.IncorrectSum of the present ages of husband, wife and child = (23 * 2 + 5 * 2) = 57 years.

Required average = 57/3 = 19 years. - Question 7 of 50
##### 7. Question

Two pipes A and B can fill a cistern in 37 1/2 minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the pipe B is turned off after?

CorrectLet B be turned off after x minutes. Then, part filled by (A + B) in x min + part filled by A in (30 – x) min = 1.

x(2/75 + 1/45) + (30- x) 2/75 = 1

11x + 180 – 6x = 225 => x = 9IncorrectLet B be turned off after x minutes. Then, part filled by (A + B) in x min + part filled by A in (30 – x) min = 1.

x(2/75 + 1/45) + (30- x) 2/75 = 1

11x + 180 – 6x = 225 => x = 9 - Question 8 of 50
##### 8. Question

The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?

CorrectP = 144(100/5)

^{2}=> P = 3600IncorrectP = 144(100/5)

^{2}=> P = 3600 - Question 9 of 50
##### 9. Question

Find the length of the wire required to go 15 times round a square field containing 69696 m

^{2}.Correcta

^{2}= 69696 => a = 264

4a = 1056

1056 * 15 = 15840Incorrecta

^{2}= 69696 => a = 264

4a = 1056

1056 * 15 = 15840 - Question 10 of 50
##### 10. Question

The ratio of the radius of two circles is 1: 3, and then the ratio of their areas is?

Correctr

_{1}: r_{2}= 1: 3

Πr_{1}^{2}: Πr_{2}^{2}

r_{1}^{2}: r_{2}^{2 }= 1: 9Incorrectr

_{1}: r_{2}= 1: 3

Πr_{1}^{2}: Πr_{2}^{2}

r_{1}^{2}: r_{2}^{2 }= 1: 9 - Question 11 of 50
##### 11. Question

A metallic sphere of radius 12 cm is melted and drawn into a wire, whose radius of cross section is 16 cm. What is the length of the wire?

CorrectVolume of the wire (in Cylindrical shape) is equal to the volume of the sphere.

π(16)^{2}* h = (4/3)π (12)^{3}=> h = 9 cmIncorrectVolume of the wire (in Cylindrical shape) is equal to the volume of the sphere.

π(16)^{2}* h = (4/3)π (12)^{3}=> h = 9 cm - Question 12 of 50
##### 12. Question

A brick measures 20 cm * 10 cm * 7.5 cm how many bricks will be required for a wall 25 m * 2 m * 0.75 m?

Correct25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x

25 = 1/100 * x => x = 25000Incorrect25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x

25 = 1/100 * x => x = 25000 - Question 13 of 50
##### 13. Question

If the numerator of a fraction is increased by 20% and its denominator is diminished by 25% value of the fraction is 2/15. Find the original fraction.

CorrectX * (120/100)

—————- = 2/15

Y * (75/100)

X/Y = 1/12IncorrectX * (120/100)

—————- = 2/15

Y * (75/100)

X/Y = 1/12 - Question 14 of 50
##### 14. Question

A bag contains a total of 93 coins in the form of one rupee and 50 paise coins. If the total value of coins in the bag is Rs.56, find the number of 50 paise coins in the bag?

CorrectLet the number of one rupee coins in the bag be x.

Number of 50 paise coins in the bag is 93 – x.

Total value of coins

[100x + 50(93 – x)]paise = 5600 paise

=> x = 74IncorrectLet the number of one rupee coins in the bag be x.

Number of 50 paise coins in the bag is 93 – x.

Total value of coins

[100x + 50(93 – x)]paise = 5600 paise

=> x = 74 - Question 15 of 50
##### 15. Question

A and B enter into partnership with capital as 7:9. At the end of 8 months, A withdraws. If they receive the profits in the ratio of 8:9 find how long B’s capital was used?

Correct7 * 8 : 9 * x = 8:9 => x= 7

Incorrect7 * 8 : 9 * x = 8:9 => x= 7

- Question 16 of 50
##### 16. Question

A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work?

CorrectLet A worked for x days.

x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18

A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days.IncorrectLet A worked for x days.

x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18

A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days. - Question 17 of 50
##### 17. Question

Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work?

Correct(5m + 9w)10 = (6m + 12w)8

=> 50m + 90w = 48w + 96 w => 2m = 6w => 1m = 3w 5m + 9w = 5m + 3m = 8m

8 men can do the work in 10 days.

3m +3w = 3m + 1w = 4m

So, 4 men can do the work in (10 * 8)/4 = 20 days.Incorrect(5m + 9w)10 = (6m + 12w)8

=> 50m + 90w = 48w + 96 w => 2m = 6w => 1m = 3w 5m + 9w = 5m + 3m = 8m

8 men can do the work in 10 days.

3m +3w = 3m + 1w = 4m

So, 4 men can do the work in (10 * 8)/4 = 20 days. - Question 18 of 50
##### 18. Question

The speed of a train is 90 kmph. What is the distance covered by it in 10 minutes?

Correct90 * 10/60 = 15 kmph

Incorrect90 * 10/60 = 15 kmph

- Question 19 of 50
##### 19. Question

Find the one which does not belong to that group ?

CorrectG

^{-1}F^{+3}I, Q^{-2}O^{+3}R, L^{-1}K^{+3}N, Y^{-1}X^{+3}A and T^{-1}S^{+3}V.

Except QOR, all other groups follows similar pattern.IncorrectG

^{-1}F^{+3}I, Q^{-2}O^{+3}R, L^{-1}K^{+3}N, Y^{-1}X^{+3}A and T^{-1}S^{+3}V.

Except QOR, all other groups follows similar pattern. - Question 20 of 50
##### 20. Question

252 can be expressed as a product of primes as:

CorrectClearly, 252 = 2 * 2 * 3 * 3 * 7

IncorrectClearly, 252 = 2 * 2 * 3 * 3 * 7

- Question 21 of 50
##### 21. Question

Find the smallest number which when divided by 13 and 16 leaves respective remainders of 2 and 5.

CorrectLet ‘N’ is the smallest number which divided by 13 and 16 leaves respective remainders of 2 and 5.

Required number = (LCM of 13 and 16) – (common difference of divisors and remainders) = (208) – (11) = 197.IncorrectLet ‘N’ is the smallest number which divided by 13 and 16 leaves respective remainders of 2 and 5.

Required number = (LCM of 13 and 16) – (common difference of divisors and remainders) = (208) – (11) = 197. - Question 22 of 50
##### 22. Question

A pipe can fill a cistern in 20 minutes whereas the cistern when fill can be emptied by a leak in 28 minutes. When both pipes are opened, find when the cistern will be full?

Correct1/20 – 1/28 = 1/70

70 minutesIncorrect1/20 – 1/28 = 1/70

70 minutes - Question 23 of 50
##### 23. Question

(17

^{14}* 17^{16}) / 17^{-8}= ?Correct? = 17

^{14+16-8}= 17^{22}Incorrect? = 17

^{14+16-8}= 17^{22} - Question 24 of 50
##### 24. Question

An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?

CorrectHCF of 4956, 3894 = 354

(4956 – 3894)/354 = 3IncorrectHCF of 4956, 3894 = 354

(4956 – 3894)/354 = 3 - Question 25 of 50
##### 25. Question

Dacid obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?

CorrectAverage = (76 + 65 + 82 + 67 + 85)/5 = 375/5 = 75.

IncorrectAverage = (76 + 65 + 82 + 67 + 85)/5 = 375/5 = 75.

- Question 26 of 50
##### 26. Question

A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is -.

CorrectTotal fruits = 9

Since there must be at least two apples,

(⁵C₂ * ⁴C₁)/⁹C₃ + ⁵C₃/⁹C₃ = 25/42.IncorrectTotal fruits = 9

Since there must be at least two apples,

(⁵C₂ * ⁴C₁)/⁹C₃ + ⁵C₃/⁹C₃ = 25/42. - Question 27 of 50
##### 27. Question

If a man lost 4% by selling oranges at the rate of 12 a rupee at how many a rupee must he sell them to gain 44%?

Correct96% —- 12

144% —- ?

96/144 * 12 = 8Incorrect96% —- 12

144% —- ?

96/144 * 12 = 8 - Question 28 of 50
##### 28. Question

If 3 workers collect 48 kg of cotton in 4 days, how many kg of cotton will 9 workers collect in 2 days?

Correct(3 * 4)/48 = (9 * 2)/ x

x = 72 kgIncorrect(3 * 4)/48 = (9 * 2)/ x

x = 72 kg - Question 29 of 50
##### 29. Question

HCF of 3/16, 5/12, 7/8 is:

CorrectHCF of numerators = 1

LCM of denominators = 48

=> 1/48IncorrectHCF of numerators = 1

LCM of denominators = 48

=> 1/48 - Question 30 of 50
##### 30. Question

The sum of three numbers is 98. If the ratio of the first to the second is 2:3. And that of the second to the third is 5:8, then the second number is:

CorrectLet the three parts A, B, C.

Then, A:B = 2:3 and B:C = 5:8

= (5 * 3/5) : (8 * 3/5) = 3:24/5

A:B:C = 2:3:24/5

= 10:15:24 => B = 98 * 15/49 = 30.IncorrectLet the three parts A, B, C.

Then, A:B = 2:3 and B:C = 5:8

= (5 * 3/5) : (8 * 3/5) = 3:24/5

A:B:C = 2:3:24/5

= 10:15:24 => B = 98 * 15/49 = 30. - Question 31 of 50
##### 31. Question

The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs. ) is?

CorrectLet the sum be Rs. x. Then,

[x (1 + 4/100)^{2}– x] = (676/625 x – x) = 51/625 x

S.I. = (x * 4 * 2)/100 = 2x/25

51x/625 – 2x/25 = 1 or x = 625.IncorrectLet the sum be Rs. x. Then,

[x (1 + 4/100)^{2}– x] = (676/625 x – x) = 51/625 x

S.I. = (x * 4 * 2)/100 = 2x/25

51x/625 – 2x/25 = 1 or x = 625. - Question 32 of 50
##### 32. Question

Income and expenditure of a person are in the ratio 5:4. If the income of the person is Rs.18000, then find his savings?

CorrectLet the income and the expenditure of the person be Rs.5x and Rs.4x respectively.

Income, 5x = 18000 => x = 3600

Savings = Income – expenditure = 5x – 4x = x

So, savings = Rs.3600.IncorrectLet the income and the expenditure of the person be Rs.5x and Rs.4x respectively.

Income, 5x = 18000 => x = 3600

Savings = Income – expenditure = 5x – 4x = x

So, savings = Rs.3600. - Question 33 of 50
##### 33. Question

Tanya’s grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. Eight years ago, what was the ratio of Tanya’s age to that of her grandfather?

Correct16 years ago, let T = x years and G = 8x years. After 8 years from now, T = (x + 16 + 8) years and G = (8x + 16 + 8) years.

8x + 24 = 3(x + 24) => 5x = 48

8 years ago, T/G = (x + 8)/(8x + 8) = (48/5 + 8) / (8 * 48/5 + 8) = 88/424 = 11/53Incorrect16 years ago, let T = x years and G = 8x years. After 8 years from now, T = (x + 16 + 8) years and G = (8x + 16 + 8) years.

8x + 24 = 3(x + 24) => 5x = 48

8 years ago, T/G = (x + 8)/(8x + 8) = (48/5 + 8) / (8 * 48/5 + 8) = 88/424 = 11/53 - Question 34 of 50
##### 34. Question

Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?

Correct1/10 + 1/15 – 1/x = 1/18

x = 9Incorrect1/10 + 1/15 – 1/x = 1/18

x = 9 - Question 35 of 50
##### 35. Question

A train speeds past a pole in 15 sec and a platform 100 m long in 25 sec, its length is?

CorrectLet the length of the train be x m and its speed be y m/sec.

Then, x/y = 15 => y = x/15

(x + 100)/25 = x/15 => x = 150 m.IncorrectLet the length of the train be x m and its speed be y m/sec.

Then, x/y = 15 => y = x/15

(x + 100)/25 = x/15 => x = 150 m. - Question 36 of 50
##### 36. Question

The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?

Correctr = 3 πr

^{2}= 9

r = 5 πr^{2}= 25

25 π – 16 π

100 —- ? => 64%Incorrectr = 3 πr

^{2}= 9

r = 5 πr^{2}= 25

25 π – 16 π

100 —- ? => 64% - Question 37 of 50
##### 37. Question

Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?

Correctx + y = 80

x – 4y = 5

x = 65 y = 15Incorrectx + y = 80

x – 4y = 5

x = 65 y = 15 - Question 38 of 50
##### 38. Question

Which one of the following is the least number of four digits divisible by 71?

Correct1000/71 = 14 6/71

1000 + 71 – 6 = 1065Incorrect1000/71 = 14 6/71

1000 + 71 – 6 = 1065 - Question 39 of 50
##### 39. Question

Find the 37.5% of 976 =

Correct37.5 % of 976

= 37.5/100 * 976 = 375/1000 * 976 = 3/8 * 976

= 3 * 122 = 366.Incorrect37.5 % of 976

= 37.5/100 * 976 = 375/1000 * 976 = 3/8 * 976

= 3 * 122 = 366. - Question 40 of 50
##### 40. Question

Rajan got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. Rajan’s sister was 10 years younger to him at the time of his marriage. The age of Rajan’s sister is:

CorrectLet Rajan’s present age be x years.

Then, his age at the time of marriage = (x – 8) years.

x = 6/5 (x – 8)

5x = 6x – 48 => x = 48

Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = 30 years.

Rajan’s sister’s present age = (30 + 8) = 38 years.IncorrectLet Rajan’s present age be x years.

Then, his age at the time of marriage = (x – 8) years.

x = 6/5 (x – 8)

5x = 6x – 48 => x = 48

Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = 30 years.

Rajan’s sister’s present age = (30 + 8) = 38 years. - Question 41 of 50
##### 41. Question

Find the one which does not belong to that group ?

Correct20 = 4

^{2}+ 4, 42 = 6^{2}+ 6, 58 = 7^{2}+ 9, 72 = 8^{2}+ 8 and 90 = 9^{2}+ 9.

20, 42, 72 and 90 can be expressed in n^{2}+ n form but not 58.Incorrect20 = 4

^{2}+ 4, 42 = 6^{2}+ 6, 58 = 7^{2}+ 9, 72 = 8^{2}+ 8 and 90 = 9^{2}+ 9.

20, 42, 72 and 90 can be expressed in n^{2}+ n form but not 58. - Question 42 of 50
##### 42. Question

A and B can do a work in 4 hours and 12 hours respectively. A starts the work at 6AM and they work alternately for one hour each. When will the work be completed?

CorrectWork done by A and B in the first two hours, working alternately = First hour A + Second hour B = 1/4 + 1/12 = 1/3.

Total time required to complete the work = 2 * 3 = 6 days.IncorrectWork done by A and B in the first two hours, working alternately = First hour A + Second hour B = 1/4 + 1/12 = 1/3.

Total time required to complete the work = 2 * 3 = 6 days. - Question 43 of 50
##### 43. Question

A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook?

CorrectLet the price of each note book be Rs.x.

Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.

Hence xy = 300

=> y = 300/x

(x + 5)(y – 10) = 300 => xy + 5y – 10x – 50 = xy

=>5(300/x) – 10x – 50 = 0 => -150 + x^{2}+ 5x = 0

multiplying both sides by -1/10x

=> x^{2}+ 15x – 10x – 150 = 0

=> x(x + 15) – 10(x + 15) = 0

=> x = 10 or -15

As x>0, x = 10.IncorrectLet the price of each note book be Rs.x.

Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.

Hence xy = 300

=> y = 300/x

(x + 5)(y – 10) = 300 => xy + 5y – 10x – 50 = xy

=>5(300/x) – 10x – 50 = 0 => -150 + x^{2}+ 5x = 0

multiplying both sides by -1/10x

=> x^{2}+ 15x – 10x – 150 = 0

=> x(x + 15) – 10(x + 15) = 0

=> x = 10 or -15

As x>0, x = 10. - Question 44 of 50
##### 44. Question

A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?

CorrectSuppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x – 5) and (x – 9) hours respectively to fill the tank.

1/x + 1/(x – 5) = 1/(x – 9)

(2x – 5)(x – 9) = x(x – 5)

x^{2}– 18x + 45 = 0

(x- 15)(x – 3) = 0 => x = 15IncorrectSuppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x – 5) and (x – 9) hours respectively to fill the tank.

1/x + 1/(x – 5) = 1/(x – 9)

(2x – 5)(x – 9) = x(x – 5)

x^{2}– 18x + 45 = 0

(x- 15)(x – 3) = 0 => x = 15 - Question 45 of 50
##### 45. Question

Find the one which does not belong to that group ?

Correct41, 43, 47 and 53 are prime numbers, but not 57.

Incorrect41, 43, 47 and 53 are prime numbers, but not 57.

- Question 46 of 50
##### 46. Question

Salaries of Ravi and Sumit are in the ratio 2:3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40:57. What is Sumit’s present salary?

CorrectLet the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.

Then, (2x + 4000)/(3x + 4000) = 40/57

6x = 68000 => 3x = 34000

Sumit’s present salary = (3x + 4000) = 34000 + 4000 = Rs. 38,000.IncorrectLet the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.

Then, (2x + 4000)/(3x + 4000) = 40/57

6x = 68000 => 3x = 34000

Sumit’s present salary = (3x + 4000) = 34000 + 4000 = Rs. 38,000. - Question 47 of 50
##### 47. Question

A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?

CorrectGiven that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.

Hence, the required number of ways = 4^{5}– 1.

= 2^{10}– 1 = 1024 – 1 = 1023IncorrectGiven that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.

Hence, the required number of ways = 4^{5}– 1.

= 2^{10}– 1 = 1024 – 1 = 1023 - Question 48 of 50
##### 48. Question

The proportion of copper and zinc in the brass is 13:7. How much zinc will there be in 100 kg of brass?

Correct7/20 * 100 = 35

Incorrect7/20 * 100 = 35

- Question 49 of 50
##### 49. Question

A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?

CorrectM = 4.5

S = x

DS = 4.5 + x

US = 4.5 + x

4.5 + x = (4.5 – x)2

4.5 + x = 9 -2x

3x = 4.5

x = 1.5IncorrectM = 4.5

S = x

DS = 4.5 + x

US = 4.5 + x

4.5 + x = (4.5 – x)2

4.5 + x = 9 -2x

3x = 4.5

x = 1.5 - Question 50 of 50
##### 50. Question

A man gains 20% by selling an article for a certain price. If the sells it at double the price, the percentage of profit will be:

CorrectLet C.P. = Rs. x.

Then, S.P. = Rs. (12% of x) = Rs. 6x/5

New S.P. = 2 * 6x/5 = Rs. 12x/5

Profit = 12x/5 – x = Rs. 7x/5

Profit = 7x/5 * 1/x * 100 = 140%.IncorrectLet C.P. = Rs. x.

Then, S.P. = Rs. (12% of x) = Rs. 6x/5

New S.P. = 2 * 6x/5 = Rs. 12x/5

Profit = 12x/5 – x = Rs. 7x/5

Profit = 7x/5 * 1/x * 100 = 140%.