# RBI Assistant Online Test, RBI Assistant Mains Online Test Series 4

## RBI Assistant Online Test, RBI Assistant Mains Online Test Series 4

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RBI Assistant Online Test, RBI Assistant Mains Online Test Series 4. RBI Exam Online Test 2020. CAknowledge RBI Assistant Mains Free Mock Test Exam 2020. RBI Assistant Mains Exam Free Online Quiz 2020, RBI Assistant Mains Full Online Mock Test **Series 4th** in English.To Analyse your preparation, one should attempt the test series on a regular basis to score more in the examination. Start FREE mock test and get top rank among all applicants whoever are participating in the exam. RBI Assistant Mains Question and Answers in English and Hindi **Series 4**. Here we are providing** RBI Assistant Mains Full Mock Test Paper in English. RBI Assistant Mains **Mock Test **Series 4th** 2020. Now Test your self for RBI Assistant Mains Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

43% of 784 = ?

Correct? = 43/100 * 784 = 337.12

Incorrect? = 43/100 * 784 = 337.12

- Question 2 of 50
##### 2. Question

The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275, then the other is:

CorrectOther number = (11 * 7700)/275 = 308.

IncorrectOther number = (11 * 7700)/275 = 308.

- Question 3 of 50
##### 3. Question

A is twice as fast as B. If B alone can do a piece of work in 30 days, in what time can A and B together complete the work?

CorrectA can do the work in 30/2 i.e., 15 days.

A and B’s one day’s work = 1/15 + 1/30 = (2 + 1)/30 = 1/10

So A and B together can do the work in 10 days.IncorrectA can do the work in 30/2 i.e., 15 days.

A and B’s one day’s work = 1/15 + 1/30 = (2 + 1)/30 = 1/10

So A and B together can do the work in 10 days. - Question 4 of 50
##### 4. Question

Divide Rs.118000 among three persons A, B and C such that the ratio of the shares of A and B is 3:4 and that of B:C is 5:6?

CorrectCompound ratio of A:B:C

A:B = 3:4

B:C = 5:6

———-

A:B:C = 15:20:24

We can divide Rs.118000 in this ratio.

Share of A = 15/59 * 118000 = 30000

Share of B = 20/59 * 118000 = 40000

Share of C = 24/59 * 118000 = 48000IncorrectCompound ratio of A:B:C

A:B = 3:4

B:C = 5:6

———-

A:B:C = 15:20:24

We can divide Rs.118000 in this ratio.

Share of A = 15/59 * 118000 = 30000

Share of B = 20/59 * 118000 = 40000

Share of C = 24/59 * 118000 = 48000 - Question 5 of 50
##### 5. Question

The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of time will they come together in the same position?

CorrectTime for one revolution = 60/15 = 4

60/ 20 = 3

60/48 = 5/4

LCM of 4, 3, 5/4

LCM of Numerators/HCF of Denominators =

60/1 = 60IncorrectTime for one revolution = 60/15 = 4

60/ 20 = 3

60/48 = 5/4

LCM of 4, 3, 5/4

LCM of Numerators/HCF of Denominators =

60/1 = 60 - Question 6 of 50
##### 6. Question

What is the least number, which is perfect square but contains 2700 as its factor?

Correct900 * 3 * 3 = 8100

Incorrect900 * 3 * 3 = 8100

- Question 7 of 50
##### 7. Question

Nitin borrowed some money at the rate of 6% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is Rs. 8160, how much money did he borrow?

CorrectLet the sum be Rs. x. Then,

[(x * 6 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 8160

18x + 45x + 39x = (8160 * 100)

102x = 816000 => x = 8000.IncorrectLet the sum be Rs. x. Then,

[(x * 6 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 8160

18x + 45x + 39x = (8160 * 100)

102x = 816000 => x = 8000. - Question 8 of 50
##### 8. Question

A man gets a simple interest of Rs.500 on a certain principal at the rate of 5% p.a in two years. Find the compound interest the man will get on twice the principal in two years at the same rate.

CorrectLet the principal be Rs.P

S.I at 5% p.a in 8 years on Rs.P = Rs.500

(P)(8)(5)/100 = 500

P = 1250

C.I on Rs.2P i.e., Rs.2500 at 5% p.a in two years

=2500{ [1 + 5/100]^{2}– 1} = 2500{ 21^{2}– 20^{2}/20^{2}}

= 2500/400(441 – 400)

= 25/4(41) = 1025/4 = Rs.256.25IncorrectLet the principal be Rs.P

S.I at 5% p.a in 8 years on Rs.P = Rs.500

(P)(8)(5)/100 = 500

P = 1250

C.I on Rs.2P i.e., Rs.2500 at 5% p.a in two years

=2500{ [1 + 5/100]^{2}– 1} = 2500{ 21^{2}– 20^{2}/20^{2}}

= 2500/400(441 – 400)

= 25/4(41) = 1025/4 = Rs.256.25 - Question 9 of 50
##### 9. Question

What is the probability that a leap year has 53 Sundays and 52 Mondays?

CorrectA leap year has 52 weeks and two days

Total number of cases = 7

Number of favourable cases = 1

i.e., {Saturday, Sunday}

Required Probability = 1/7IncorrectA leap year has 52 weeks and two days

Total number of cases = 7

Number of favourable cases = 1

i.e., {Saturday, Sunday}

Required Probability = 1/7 - Question 10 of 50
##### 10. Question

Find the least number of five digits which is exactly divisible by 12, 15 and 18?

CorrectLCM = 180

180) 10000 (55

9900

———

100

10000 + 180 – 100 = 10080IncorrectLCM = 180

180) 10000 (55

9900

———

100

10000 + 180 – 100 = 10080 - Question 11 of 50
##### 11. Question

A shopkeeper sold an article offering a discount of 5% and earned a profit of 23.5%. What would have been the percentage of profit earned if no discount was offered?

CorrectLet C.P. be Rs. 100.

Then, S.P. = Rs. 123.50

Let marked price be Rs. x. Then, 95/100 x = 123.50

x = 12350/95 = Rs. 130

Now, S.P. = Rs. 130, C.P. = Rs. 100

Profit % = 30%.IncorrectLet C.P. be Rs. 100.

Then, S.P. = Rs. 123.50

Let marked price be Rs. x. Then, 95/100 x = 123.50

x = 12350/95 = Rs. 130

Now, S.P. = Rs. 130, C.P. = Rs. 100

Profit % = 30%. - Question 12 of 50
##### 12. Question

31.2 * 14.5 * 9.6 = ?

CorrectIncorrect - Question 13 of 50
##### 13. Question

A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?

CorrectM = 6

S = 1.2

DS = 6 + 1.2 = 7.2

US = 6 – 1.2 = 4.8

x/7.2 + x/4.8 = 1

x = 2.88IncorrectM = 6

S = 1.2

DS = 6 + 1.2 = 7.2

US = 6 – 1.2 = 4.8

x/7.2 + x/4.8 = 1

x = 2.88 - Question 14 of 50
##### 14. Question

If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?

CorrectX * (105/100) * (105/100) * (105/100) = 138915

X = 138915/1.157625

X = 120000IncorrectX * (105/100) * (105/100) * (105/100) = 138915

X = 138915/1.157625

X = 120000 - Question 15 of 50
##### 15. Question

Two pipes A and B can fill a tank in 4 and 5 hours respectively. If they are turned up alternately for one hour each, the time taken to fill the tank is?

Correct1/4 + 1/5 = 9/20

20/9 = 2 2/9

9/20 * 2 = 9/10 —- 4 hours

WR = 1 – 9/10 = 1/10

1 h —- 1/4

? —– 1/10

2/5 * 60 = 24 = 4 hrs 24 minIncorrect1/4 + 1/5 = 9/20

20/9 = 2 2/9

9/20 * 2 = 9/10 —- 4 hours

WR = 1 – 9/10 = 1/10

1 h —- 1/4

? —– 1/10

2/5 * 60 = 24 = 4 hrs 24 min - Question 16 of 50
##### 16. Question

An amount of Rs. 3000 becomes Rs. 3600 in four years at simple interest. If the rate of interest was 1% more, then what was be the total amount?

CorrectA = P(1 + TR/100)

=> 3600 = 3000[1 + (4 * R)/100] => R = 5%

Now R = 6%

=> A = 3000[1 + (4 * 6)/100] = Rs. 3720.IncorrectA = P(1 + TR/100)

=> 3600 = 3000[1 + (4 * R)/100] => R = 5%

Now R = 6%

=> A = 3000[1 + (4 * 6)/100] = Rs. 3720. - Question 17 of 50
##### 17. Question

Convert the 13/36 m/s into kilometers per hour?

Correct13/36 m/s = 13/36 * 18/5 = 13/10 = 1.3 kmph.

Incorrect13/36 m/s = 13/36 * 18/5 = 13/10 = 1.3 kmph.

- Question 18 of 50
##### 18. Question

A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?

Correct45*12 : 54*x = 2: 1

x = 5

12 -5 = 7Incorrect45*12 : 54*x = 2: 1

x = 5

12 -5 = 7 - Question 19 of 50
##### 19. Question

In how many ways can a committee consisting of three men and four women be formed from a group of six men and seven women?

CorrectThe group contain six men and seven women

Three men can be selected from six men in ⁶C₃ ways.

Four women can be selected from seven women in ⁷C₄ ways.

Total number of ways = (⁷C₄)(⁶C₃).IncorrectThe group contain six men and seven women

Three men can be selected from six men in ⁶C₃ ways.

Four women can be selected from seven women in ⁷C₄ ways.

Total number of ways = (⁷C₄)(⁶C₃). - Question 20 of 50
##### 20. Question

Find the mean proportional of the following pairs of numbers 50 and 512.

CorrectMean proportional of two numbers a and b is defined as √ab

a = 50, b = 512

Mean proportional = √(50)(512) = 160IncorrectMean proportional of two numbers a and b is defined as √ab

a = 50, b = 512

Mean proportional = √(50)(512) = 160 - Question 21 of 50
##### 21. Question

The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?

CorrectLet the length and the breadth of the floor be l m and b m respectively.

l = b + 200% of b = l + 2b = 3b

Area of the floor = 324/3 = 108 sq m

l b = 108 i.e., l * l/3 = 108

l^{2}= 324 => l = 18.IncorrectLet the length and the breadth of the floor be l m and b m respectively.

l = b + 200% of b = l + 2b = 3b

Area of the floor = 324/3 = 108 sq m

l b = 108 i.e., l * l/3 = 108

l^{2}= 324 => l = 18. - Question 22 of 50
##### 22. Question

The side of a square is increased by 25% then how much % does its area increases?

Correcta = 100 a

^{2}= 10000

a = 125 a^{2}= 15625

—————-

10000 ——— 5625

100 ——-? => 56.25 %Incorrecta = 100 a

^{2}= 10000

a = 125 a^{2}= 15625

—————-

10000 ——— 5625

100 ——-? => 56.25 % - Question 23 of 50
##### 23. Question

What is the difference between the largest number and the least number written with the digits 7, 3, 1, 4?

Correct1347

7431

————

6084Incorrect1347

7431

————

6084 - Question 24 of 50
##### 24. Question

A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?

CorrectGiven that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.

Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green

= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂

= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7

= 46/70 = 23/35IncorrectGiven that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.

Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green

= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂

= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7

= 46/70 = 23/35 - Question 25 of 50
##### 25. Question

Find the one which does not belong to that group ?

CorrectBoxing, Chess, Wrestling and Squash are individual events, while Baseball is a team event.

IncorrectBoxing, Chess, Wrestling and Squash are individual events, while Baseball is a team event.

- Question 26 of 50
##### 26. Question

5 * 5 ÷ 5 + 5 ÷ 5 = ?

Correct(5 * 5)/5 + 1/5 * 5 = 5 + 1 = 6

Incorrect(5 * 5)/5 + 1/5 * 5 = 5 + 1 = 6

- Question 27 of 50
##### 27. Question

By selling 12 toffees for a rupee, a man loses 20%. How many for a rupee should be sell to get a gain of 20%?

CorrectLet S.P. of 12 toffees be Rs. x.

Then, 80:1 = 120:x or x = 120/180 = 3/2

For Rs. 3/2, toffees sold = 12.

For Re. 1, toffees sold = 12 * 2/3 = 8IncorrectLet S.P. of 12 toffees be Rs. x.

Then, 80:1 = 120:x or x = 120/180 = 3/2

For Rs. 3/2, toffees sold = 12.

For Re. 1, toffees sold = 12 * 2/3 = 8 - Question 28 of 50
##### 28. Question

What sum of money put at C.I amounts in 2 years to Rs.8820 and in 3 years to Rs.9261?

Correct8820 —- 441

100 —- ? => 5%

x *105/100 * 105/100 = 8820

x*1.1025=8820

x=8820/1.1025 => 8000Incorrect8820 —- 441

100 —- ? => 5%

x *105/100 * 105/100 = 8820

x*1.1025=8820

x=8820/1.1025 => 8000 - Question 29 of 50
##### 29. Question

The number obtained by interchanging the two digits of a two-digit number is less than the original number by 45. If the sum of the two digits of the number so obtained is 13, then what is the original number?

CorrectLet the number be in the form of 10a + b

Number formed by interchanging a and b = 10b + a.

a + b = 13 — (1)

10b + a = 10a + b – 45

45 = 9a – 9b => a – b = 5 — (2)

Adding (1) and (2), we get

2a = 18 => a = 9 and b = 4

The number is: 94.IncorrectLet the number be in the form of 10a + b

Number formed by interchanging a and b = 10b + a.

a + b = 13 — (1)

10b + a = 10a + b – 45

45 = 9a – 9b => a – b = 5 — (2)

Adding (1) and (2), we get

2a = 18 => a = 9 and b = 4

The number is: 94. - Question 30 of 50
##### 30. Question

If one-third of one fourth of a number is 15, then three-tenth of that number is:

CorrectLet the number be x. Then,

1/3 of 1/4 of x = 15

x = 15 * 12 = 180

So, required number = (3/10 * 180) = 54.IncorrectLet the number be x. Then,

1/3 of 1/4 of x = 15

x = 15 * 12 = 180

So, required number = (3/10 * 180) = 54. - Question 31 of 50
##### 31. Question

LCM of 87 and 145 is:

CorrectIncorrect - Question 32 of 50
##### 32. Question

The ratio of the length and the breadth of a rectangle is 4 : 3 and the area of the rectangle is 6912 sq cm. Find the ratio of the breadth and the area of the rectangle?

CorrectLet the length and the breadth of the rectangle be 4x cm and 3x respectively.

(4x)(3x) = 6912

12x^{2}= 6912

x^{2}= 576 = 4 * 144 = 2^{2}* 12^{2}(x > 0)

=> x = 2 * 12 = 24

Ratio of the breadth and the areas = 3x : 12x^{2}= 1 : 4x = 1: 96.IncorrectLet the length and the breadth of the rectangle be 4x cm and 3x respectively.

(4x)(3x) = 6912

12x^{2}= 6912

x^{2}= 576 = 4 * 144 = 2^{2}* 12^{2}(x > 0)

=> x = 2 * 12 = 24

Ratio of the breadth and the areas = 3x : 12x^{2}= 1 : 4x = 1: 96. - Question 33 of 50
##### 33. Question

4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?

CorrectLet 1 man’s 1 day work = x and 1 woman’s 1 day work = y.

Then, 4x + 6y = 1/8 and 3x + 7y = 1/10

Solving these two equations, we get:

x = 11/400 and y = 1/400

1 woman’s 1 day work = (1/400 * 10) = 1/40.

Hence, 10 women will complete the work in 40 days.IncorrectLet 1 man’s 1 day work = x and 1 woman’s 1 day work = y.

Then, 4x + 6y = 1/8 and 3x + 7y = 1/10

Solving these two equations, we get:

x = 11/400 and y = 1/400

1 woman’s 1 day work = (1/400 * 10) = 1/40.

Hence, 10 women will complete the work in 40 days. - Question 34 of 50
##### 34. Question

Ram professes to sell his goods at the cost price but he made use of 900 grms instead of a kg, what is the gain percent?

Correct900 — 100

100 — ? => 11 1/9%Incorrect900 — 100

100 — ? => 11 1/9% - Question 35 of 50
##### 35. Question

The average monthly salary of laborers and supervisors in a factory is Rs.1250 per month; where as the average monthly salary of 6 supervisors is Rs.2450. If the average monthly salary of the laborers is Rs.950 find the number of laborers?

Correct

1 —— 6

4 ——? → 24Incorrect

1 —— 6

4 ——? → 24 - Question 36 of 50
##### 36. Question

20 women can do a work in 9 days. After they have worked for 6 days. 6 more men join them. How many days will they take to complete the remaining work?

Correct(20 * 16) women can complete the work in 1 day.

1 woman’s 1 day work = 1/320

(16 * 15) men can complete the work in 1 day

1 man’s 1 day work = 1/240

So, required ratio = 1/240 : 1/320 = 4:3.Incorrect(20 * 16) women can complete the work in 1 day.

1 woman’s 1 day work = 1/320

(16 * 15) men can complete the work in 1 day

1 man’s 1 day work = 1/240

So, required ratio = 1/240 : 1/320 = 4:3. - Question 37 of 50
##### 37. Question

Nine men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?

CorrectAverage of 9 = x

9x = 8 * 3 + x * 2 x = 3.25

Total = 9 * 3.25 = 29.25IncorrectAverage of 9 = x

9x = 8 * 3 + x * 2 x = 3.25

Total = 9 * 3.25 = 29.25 - Question 38 of 50
##### 38. Question

A person takes 20 minutes more to cover a certain distance by decreasing his speed by 20%. What is the time taken to cover the distance at his original speed?

CorrectLet the distance and original speed be d km and k kmph respectively.

d/0.8k – d/k = 20/60 => 5d/4k – d/k = 1/3

=> (5d – 4d)/4k = 1/3 => d = 4/3 k

Time taken to cover the distance at original speed

= d/k = 4/3 hours = 1 hour 20 minutes.IncorrectLet the distance and original speed be d km and k kmph respectively.

d/0.8k – d/k = 20/60 => 5d/4k – d/k = 1/3

=> (5d – 4d)/4k = 1/3 => d = 4/3 k

Time taken to cover the distance at original speed

= d/k = 4/3 hours = 1 hour 20 minutes. - Question 39 of 50
##### 39. Question

(84 ÷ 14 ÷ 2 ÷ 9) * ? = 33⅓

Correct(84 ÷ 14 ÷ 2 ÷ 9) * ? = 33⅓

=> (6 ÷ 2 ÷ 9) * ? = 100 / 3

=> 3 / 9 * ? = 100 / 3

=> ? = 100Incorrect(84 ÷ 14 ÷ 2 ÷ 9) * ? = 33⅓

=> (6 ÷ 2 ÷ 9) * ? = 100 / 3

=> 3 / 9 * ? = 100 / 3

=> ? = 100 - Question 40 of 50
##### 40. Question

The area of the cardboard(in cm

^{2}) needed to make a box of size 25 cm * 15 cm * 8 cm will be?Correct2(25 * 15 + 15 * 8 + 25 * 8)

2(375 + 120 + 200) => 1390Incorrect2(25 * 15 + 15 * 8 + 25 * 8)

2(375 + 120 + 200) => 1390 - Question 41 of 50
##### 41. Question

The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?

Correcta

^{2}= 3136 => a = 56

56 * 4 * 3 = 672 – 6 = 666 * 1.5 = 999Incorrecta

^{2}= 3136 => a = 56

56 * 4 * 3 = 672 – 6 = 666 * 1.5 = 999 - Question 42 of 50
##### 42. Question

(0.456 * 0.456 – 0.228 * 0.228) / (0.456 + 0.228) = ?

Correct(0.456 * 0.456 – 0.228 * 0.228) / (0.456 + 0.228)

This is the form of 7x/60 = 7 = a – b = 0.466 – 0.228 = 0.228Incorrect(0.456 * 0.456 – 0.228 * 0.228) / (0.456 + 0.228)

This is the form of 7x/60 = 7 = a – b = 0.466 – 0.228 = 0.228 - Question 43 of 50
##### 43. Question

The edges of a cuboid are respectively 3cm, 4cm and 12 cm. Find the length of the diagonal of cuboid.

CorrectIncorrect - Question 44 of 50
##### 44. Question

With a uniform speed a car covers the distance in 8 hours. Had the speed been increased by 4 km/hr, the same distance could have been covered in 7 1/2 hours. What is the distance covered?

CorrectLet the distance be x km. Then,

x/(7 1/2) – x/8 = 4

2x/15 – x/8 = 4 => x = 480 km.IncorrectLet the distance be x km. Then,

x/(7 1/2) – x/8 = 4

2x/15 – x/8 = 4 => x = 480 km. - Question 45 of 50
##### 45. Question

The radius of a circle is increased by 1%. Find how much % does its area increases?

Correctr = 100 r = 101

r^{2}= 10000 r^{2}= 10201

10000 —- 201

100 —- ? => 2.01%Incorrectr = 100 r = 101

r^{2}= 10000 r^{2}= 10201

10000 —- 201

100 —- ? => 2.01% - Question 46 of 50
##### 46. Question

A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18000. A’s share is?

Correctx* 12 : 2x* 6: 3x* 4

1:1:1

1/3 * 18000 = 6000Incorrectx* 12 : 2x* 6: 3x* 4

1:1:1

1/3 * 18000 = 6000 - Question 47 of 50
##### 47. Question

A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?

Correct40*(40/100) = 16 — 64

? — 12 => Rs.3Incorrect40*(40/100) = 16 — 64

? — 12 => Rs.3 - Question 48 of 50
##### 48. Question

25 2/5 + 8 4/5 + 4/5 = ?

Correct25 2/5 + 8 4/5 + 4/5 = 34 4/5 ≡ 35

Incorrect25 2/5 + 8 4/5 + 4/5 = 34 4/5 ≡ 35

- Question 49 of 50
##### 49. Question

The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager’s salary is added, then the average salary increases by Rs. 100. What is the manager’s monthly salary?

CorrectManager’s monthly salary

= Rs. (1600 * 21 – 1500 * 20) = Rs. 3600IncorrectManager’s monthly salary

= Rs. (1600 * 21 – 1500 * 20) = Rs. 3600 - Question 50 of 50
##### 50. Question

A paper is in a square form whose one side is 20 cm. Two semi circles are drawn on its opposites as diameters. If these semi circles are cut down what is the area of the remaining paper?

CorrectIncorrect