RBI Assistant Mock Test, RBI Assistant Prelims Online Test Series 2
RBI Assistant Mock Test, RBI Assistant Prelims Online Test Series 2
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RBI Assistant Mock Test, RBI Assistant Prelims Online Test Series 2 RBI Exam Online Test 2021. Take CAknowledge Free RBI Assistant Pre Mock Test Exam 2021. RBI Online Test for All Subjects, RBI Assistant Pre Free Mock Test Series in English. RBI Assistant Pre. Free Mock Test Series 2. To Analyse your preparation, one should attempt the test series on a regular basis to score more in the examination. Start FREE mock test and get top rank among all applicants whoever are participating in the exam. Question and Answers in English and Hindi Series 2. Here we are providing RBI Assistant Pre Full Mock Test Paper in English. Now Test your self for RBI Assistant Pre. Exam by using below quiz…
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Question 1 of 50
1. Question
The product of two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is:
Correct
Let the numbers be 37a and 37b.
Then, 37a * 37 b = 4107 => ab = 3
Now, coprimes with product 3 are (1, 3).
So, the required numbers are (37 * 1, 37 * 3) i.e., (1, 111).
Greater number = 111.Incorrect
Let the numbers be 37a and 37b.
Then, 37a * 37 b = 4107 => ab = 3
Now, coprimes with product 3 are (1, 3).
So, the required numbers are (37 * 1, 37 * 3) i.e., (1, 111).
Greater number = 111. 
Question 2 of 50
2. Question
Rs.800 amounts to Rs.920 in 3 years at simple interest. If the interest is increased by 3%, it would amount to how much?
Correct
(800*3*3)/100 = 72
920 + 72 = 992Incorrect
(800*3*3)/100 = 72
920 + 72 = 992 
Question 3 of 50
3. Question
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Correct
Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr. x – 5 = 45 ==> x = 50 km/hr.
Incorrect
Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr. x – 5 = 45 ==> x = 50 km/hr.

Question 4 of 50
4. Question
If 70% of an equal to 40% of b, then ratio between a and b is?
Correct
70 a = 40 b
a: b = 4: 7Incorrect
70 a = 40 b
a: b = 4: 7 
Question 5 of 50
5. Question
Find the one which does not belong to that group ?
Correct
525 => 5 5^{2},
39 => 3 3^{2},
24 => 2 2^{2},
636 => 6 6^{2}. The above pattern is not followed in 426.Incorrect
525 => 5 5^{2},
39 => 3 3^{2},
24 => 2 2^{2},
636 => 6 6^{2}. The above pattern is not followed in 426. 
Question 6 of 50
6. Question
The ratio of the ages of Anil and his son at present is 7 : 3. Six years hence, the ratio of the ages of the Anil’s wife and the son will be 2 : 1. Find the ratio of the present ages of Anil and his wife?
Correct
Let the present ages of Anil and his son be 7x and 3x years respectively.
Let the present age of the son’s mother be m years.
(m + 6) / (3x + 6) = 2/1
m + 6 = 6x + 12 => m = 6x + 6
Ratio of the present ages of Anil and the son’s mother = 7x / (6x + 6).
This cannot be found uniquely.Incorrect
Let the present ages of Anil and his son be 7x and 3x years respectively.
Let the present age of the son’s mother be m years.
(m + 6) / (3x + 6) = 2/1
m + 6 = 6x + 12 => m = 6x + 6
Ratio of the present ages of Anil and the son’s mother = 7x / (6x + 6).
This cannot be found uniquely. 
Question 7 of 50
7. Question
A 180 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train?
Correct
S = 180/6 * 18/5 = 108 kmph
Incorrect
S = 180/6 * 18/5 = 108 kmph

Question 8 of 50
8. Question
A and B can finish a work in 16 days while A alone can do the same work in 24 days. In how many days B alone will complete the work?
Correct
B = 1/16 – 1/24 = 1/48 => 48 days
Incorrect
B = 1/16 – 1/24 = 1/48 => 48 days

Question 9 of 50
9. Question
There are two positive numbers in the ratio 5 : 8. If the larger number exceeds the smaller by 15, then find the smaller number?
Correct
Let the two positive numbers be 5x and 8x respectively.
8x – 5x = 15 => 3x = 15 => x = 5.
Smaller number = 5x = 25.Incorrect
Let the two positive numbers be 5x and 8x respectively.
8x – 5x = 15 => 3x = 15 => x = 5.
Smaller number = 5x = 25. 
Question 10 of 50
10. Question
5 * 5 ÷ 5 + 5 ÷ 5 = ?
Correct
(5 * 5)/5 + 1/5 * 5 = 5 + 1 = 6
Incorrect
(5 * 5)/5 + 1/5 * 5 = 5 + 1 = 6

Question 11 of 50
11. Question
A and B together have Rs. 1210. If 4/15 of A’s amount is equal to 2/5 of B’s amount, how much amount does B have?
Correct
4/15 A = 2/5 B => A = (2/5 * 15/4)B
A =3/2 B => A/B = 3/2 => A:B = 3:2
B’s share = 1210 * 2/5 = Rs. 484.Incorrect
4/15 A = 2/5 B => A = (2/5 * 15/4)B
A =3/2 B => A/B = 3/2 => A:B = 3:2
B’s share = 1210 * 2/5 = Rs. 484. 
Question 12 of 50
12. Question
A reduction of 20% in the price of salt enables a lady to obtain 10kgs more for Rs.100, find the original price per kg?
Correct
100*(20/100) = 20 — 10
? — 1 => Rs.2
100 — 80
? — 2 => Rs.2.5Incorrect
100*(20/100) = 20 — 10
? — 1 => Rs.2
100 — 80
? — 2 => Rs.2.5 
Question 13 of 50
13. Question
A cistern is filled by a tap in 3 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how long will it take the leak to empty it?
Correct
2/7 – 1/x = 1/4
x = 28Incorrect
2/7 – 1/x = 1/4
x = 28 
Question 14 of 50
14. Question
A man can row downstream at 18 kmph and upstream at 10 kmph. Find the speed of the man in still water and the speed of stream respectively?
Correct
Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 18 — (1)
and x – y = 10 — (2)
From (1) & (2) 2x = 28 => x = 14, y = 4.Incorrect
Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 18 — (1)
and x – y = 10 — (2)
From (1) & (2) 2x = 28 => x = 14, y = 4. 
Question 15 of 50
15. Question
A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
Correct
Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m.Incorrect
Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m. 
Question 16 of 50
16. Question
12(13/18) + 16(11/27) – 10(5/9) = ?
Correct
12 + 16 – 10 = 18
and 13/18 + 11/27 – 5/9 = (39 + 22 – 30)/(9 * 2 * 3) = 31/54 The answer is 18 (31/54)Incorrect
12 + 16 – 10 = 18
and 13/18 + 11/27 – 5/9 = (39 + 22 – 30)/(9 * 2 * 3) = 31/54 The answer is 18 (31/54) 
Question 17 of 50
17. Question
A and B start a business jointly. A invests Rs.16000 for 8 months and B remains in the business for 4 months. Out of the total profit B claims 2/7th share. How much money is contributed by B?
Correct
16*8: x*4 = 5:2
x = 12.8 => Rs.12800Incorrect
16*8: x*4 = 5:2
x = 12.8 => Rs.12800 
Question 18 of 50
18. Question
The radius of a circular wheel is 1.75 m, how many revolutions will it make in traveling 1 km?
Correct
2 * 22/7 * 1.75 * x = 11000
x = 1000Incorrect
2 * 22/7 * 1.75 * x = 11000
x = 1000 
Question 19 of 50
19. Question
666 / 6 / 3 = ?
Correct
Given Exp. = 666 * 1/6 * 1/3 = 37
Incorrect
Given Exp. = 666 * 1/6 * 1/3 = 37

Question 20 of 50
20. Question
Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?
Correct
64000* 9/8 * 9/8 = 81000
Incorrect
64000* 9/8 * 9/8 = 81000

Question 21 of 50
21. Question
Find the one which does not belong to that group ?
Correct
Part, Cart, Dart and Mart are rhyming words, but Trap does not sound similarly.
Incorrect
Part, Cart, Dart and Mart are rhyming words, but Trap does not sound similarly.

Question 22 of 50
22. Question
12.5 + 10 1/4 of 100 ÷ 10% of 10 = ?
Correct
12.5 + 10 1/4 of 100 ÷ 10% of 10
= 12.5 + 41/4 of 100 ÷ 10/100 of 10
= 12.5 + 41(25) ÷ 1 = 12.5 + 1025 = 1037.5Incorrect
12.5 + 10 1/4 of 100 ÷ 10% of 10
= 12.5 + 41/4 of 100 ÷ 10/100 of 10
= 12.5 + 41(25) ÷ 1 = 12.5 + 1025 = 1037.5 
Question 23 of 50
23. Question
If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
Correct
The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle = 1/2 * 24 * 10 = 120 cm^{2}Incorrect
The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle = 1/2 * 24 * 10 = 120 cm^{2} 
Question 24 of 50
24. Question
The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
Correct
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l^{2} = 324 => l = 18.Incorrect
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l^{2} = 324 => l = 18. 
Question 25 of 50
25. Question
A room is 4 meters 37 cm long and 3 meters 23cm broad. It is required to pave the floor with minimum square slabs. Find the number of slabs required for this purpose?
Correct
HCF of 323, 437 = 19
323 * 437 = 19 * 19 * x
x = 391Incorrect
HCF of 323, 437 = 19
323 * 437 = 19 * 19 * x
x = 391 
Question 26 of 50
26. Question
In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?
Correct
Speed = 144 * 5/18 = 40 m/sec
Time taken = 100/40 = 2.5 sec.Incorrect
Speed = 144 * 5/18 = 40 m/sec
Time taken = 100/40 = 2.5 sec. 
Question 27 of 50
27. Question
A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Correct
Speed of train relative to jogger = 45 – 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.Incorrect
Speed of train relative to jogger = 45 – 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec. 
Question 28 of 50
28. Question
The roots of the equation 3x^{2} – 12x + 10 = 0 are?
Correct
The discriminant of the quadratic equation is (12)^{2} – 4(3)(10) i.e., 24. As this is positive but not a perfect square, the roots are irrational and unequal.
Incorrect
The discriminant of the quadratic equation is (12)^{2} – 4(3)(10) i.e., 24. As this is positive but not a perfect square, the roots are irrational and unequal.

Question 29 of 50
29. Question
The population of a city increases at the rate of 4% p.a. but there is an additional annual increase of 1% in the population due to some job seekers. The percentage increase in the population after 2 years is?
Correct
100
5 — I
5
0.25 — II
———–
10.25%Incorrect
100
5 — I
5
0.25 — II
———–
10.25% 
Question 30 of 50
30. Question
A and B starts a business with Rs.8000 each, and after 4 months, B withdraws half of his capital . How should they share the profits at the end of the 18 months?
Correct
A invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000. So, the investment of B for remaining 14 months is Rs.4000 only.
A : B
8000*18 : (8000*4) + (4000*14)
14400 : 88000
A:B = 18:11Incorrect
A invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000. So, the investment of B for remaining 14 months is Rs.4000 only.
A : B
8000*18 : (8000*4) + (4000*14)
14400 : 88000
A:B = 18:11 
Question 31 of 50
31. Question
Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction?
Correct
RS = 5 ¾ – 4 ½ = 1 ¼
T = 3 ½ h.
D = 5/4 * 7/2 = 35/8 = 4 3/8 kmIncorrect
RS = 5 ¾ – 4 ½ = 1 ¼
T = 3 ½ h.
D = 5/4 * 7/2 = 35/8 = 4 3/8 km 
Question 32 of 50
32. Question
In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
Correct
When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.
In a race of 1000 m, A beats C by (1000 – 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 = 127.5 m.Incorrect
When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.
In a race of 1000 m, A beats C by (1000 – 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 = 127.5 m. 
Question 33 of 50
33. Question
Nine men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?
Correct
Average of 9 = x
9x = 8 * 3 + x * 2 x = 3.25
Total = 9 * 3.25 = 29.25Incorrect
Average of 9 = x
9x = 8 * 3 + x * 2 x = 3.25
Total = 9 * 3.25 = 29.25 
Question 34 of 50
34. Question
Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a.
Correct
Let the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.
r = 15000(1 – 4/100) = 15000 – 600
m = 8000(1 + 10/100) = 8000 + 800
Total SP – Total CP = r + m – (15000 + 8000) = 600 + 800 = Rs. 200
As this is positive, an overall profit of Rs. 200 was made.Incorrect
Let the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.
r = 15000(1 – 4/100) = 15000 – 600
m = 8000(1 + 10/100) = 8000 + 800
Total SP – Total CP = r + m – (15000 + 8000) = 600 + 800 = Rs. 200
As this is positive, an overall profit of Rs. 200 was made. 
Question 35 of 50
35. Question
The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?
Correct
The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(21) = 3/1 = 3:1
Speed of the stream = 42/3 = 14 kmph.Incorrect
The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(21) = 3/1 = 3:1
Speed of the stream = 42/3 = 14 kmph. 
Question 36 of 50
36. Question
The population of a town is 45000; 5/9th of them are males and the rest females 40% of the males are married. What is the percentage of married females?
Correct
Male = 45,000* 5/9 = 25,000
Female = 45,000* 4/9 = 20,000
Married Male = 25,000* 40/100 = 10,000
Married Female = 10,000
20,000 ———— 10,000
100 ———— ? => 50%Incorrect
Male = 45,000* 5/9 = 25,000
Female = 45,000* 4/9 = 20,000
Married Male = 25,000* 40/100 = 10,000
Married Female = 10,000
20,000 ———— 10,000
100 ———— ? => 50% 
Question 37 of 50
37. Question
Find the one which does not belong to that group ?
Correct
Except mirage, all others are sources of water.
Incorrect
Except mirage, all others are sources of water.

Question 38 of 50
38. Question
5/8 * 2^{(2/5 – 5/4)} / 1 ^{1/4 } = ?
Correct
(5/8 * 12/5 – 5/4)/(5/4) (3/2 5/4)/(5/4) = 1/5
Incorrect
(5/8 * 12/5 – 5/4)/(5/4) (3/2 5/4)/(5/4) = 1/5

Question 39 of 50
39. Question
Two pipes X and Y can separately fill a cistern in 18 and 24 hours respectively. If they are turned on alternately for one hour each, how long will it take to fill the cistern?
Correct
1/18 + 1/24 = 7/72
72/7 = 10 2/7
7/72 * 10 = 35/36 —– 20 hours
WR = 1 – 35/36 = 1/36
1 h —– 1/18
? —– 1/36 = 1/2 hours
=> 20 1/2 hoursIncorrect
1/18 + 1/24 = 7/72
72/7 = 10 2/7
7/72 * 10 = 35/36 —– 20 hours
WR = 1 – 35/36 = 1/36
1 h —– 1/18
? —– 1/36 = 1/2 hours
=> 20 1/2 hours 
Question 40 of 50
40. Question
The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?
Correct
Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average = (P3) 10(P3) = 10P – 42 + Q => Q = 12Incorrect
Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average = (P3) 10(P3) = 10P – 42 + Q => Q = 12 
Question 41 of 50
41. Question
7 + 1/2 of [8 – 4 / 2 * 3 – 1 + 1 + (4 + 2) – 2 * 2] = ?
Correct
Applying BODMAS rule
= 7 + 1/2 of [8 – 4 / 2 * 3 – 2 + (4 + 2) – 2 * 2]
= 7 + 1/2 of [8 – 2 * 3 – 2 + 6 – 4]
= 7 + 1/2 of (2) = 8Incorrect
Applying BODMAS rule
= 7 + 1/2 of [8 – 4 / 2 * 3 – 2 + (4 + 2) – 2 * 2]
= 7 + 1/2 of [8 – 2 * 3 – 2 + 6 – 4]
= 7 + 1/2 of (2) = 8 
Question 42 of 50
42. Question
If an article is sold at 19% profit instead of 12% profit, then the profit would be Rs. 105 more. What is the cost price?
Correct
Let the cost price of an article be Rs. x.
(19% of x) – (12% of x) = 105
19x/100 – 12x/100 = 105 => 7x = 105 * 100
=> x = 1500
Cost price = Rs. 1500Incorrect
Let the cost price of an article be Rs. x.
(19% of x) – (12% of x) = 105
19x/100 – 12x/100 = 105 => 7x = 105 * 100
=> x = 1500
Cost price = Rs. 1500 
Question 43 of 50
43. Question
I. a^{2} – 7a + 12 = 0,
II. b^{2} – 3b + 2 = 0 to solve both the equations to find the values of a and b?Correct
I.(a – 3)(a – 4) = 0
=> a = 3, 4
II. (b – 2)(b – 1) = 0
=> b = 1, 2
=> a > bIncorrect
I.(a – 3)(a – 4) = 0
=> a = 3, 4
II. (b – 2)(b – 1) = 0
=> b = 1, 2
=> a > b 
Question 44 of 50
44. Question
A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?
Correct
5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 daysIncorrect
5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 days 
Question 45 of 50
45. Question
The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages.
Correct
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively.Incorrect
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively. 
Question 46 of 50
46. Question
Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?
Correct
1/10 + 1/15 = 1/6 * 4 = 2/3
1 – 2/3 = 1/3
1/10 + 1/15 – 1/x = 1/3
x = 8Incorrect
1/10 + 1/15 = 1/6 * 4 = 2/3
1 – 2/3 = 1/3
1/10 + 1/15 – 1/x = 1/3
x = 8 
Question 47 of 50
47. Question
The jogging track in a sports complex is 726 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in?
Correct
Clearly, the two will meet when they are 726 m apart.
To be (4.5 + 3.75) = 8.25 km apart, they take 1 hour.
To be 726 m apart, they take (100/825 * 726/1000) hrs = (242/2750 * 60) min = 5.28 min.Incorrect
Clearly, the two will meet when they are 726 m apart.
To be (4.5 + 3.75) = 8.25 km apart, they take 1 hour.
To be 726 m apart, they take (100/825 * 726/1000) hrs = (242/2750 * 60) min = 5.28 min. 
Question 48 of 50
48. Question
If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?
Correct
X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000Incorrect
X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000 
Question 49 of 50
49. Question
What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years?
Correct
160 = (180*4*R)/100
R = 5%Incorrect
160 = (180*4*R)/100
R = 5% 
Question 50 of 50
50. Question
The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years?
Correct
Let P’s age and Q’s age be 6x and 7x years respectively.
Then, 7x – 6x = 4 => x = 4
Required ratio = (6x + 4) : (7x + 4)
28 : 32 = 7:8Incorrect
Let P’s age and Q’s age be 6x and 7x years respectively.
Then, 7x – 6x = 4 => x = 4
Required ratio = (6x + 4) : (7x + 4)
28 : 32 = 7:8