# RBI Assistant Mock Test, RBI Assistant Prelims Online Test Series 2

## RBI Assistant Mock Test, RBI Assistant Prelims Online Test Series 2

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RBI Assistant Mock Test, RBI Assistant Prelims Online Test Series 2 RBI Exam Online Test 2020. Take CAknowledge Free RBI Assistant Pre Mock Test Exam 2020. RBI Online Test for All Subjects, RBI Assistant Pre Free Mock Test Series in English. RBI Assistant Pre. Free Mock Test **Series 2.** To Analyse your preparation, one should attempt the test series on a regular basis to score more in the examination. Start FREE mock test and get top rank among all applicants whoever are participating in the exam. Question and Answers in English and Hindi **Series 2**. Here we are providing** RBI Assistant Pre Full Mock Test Paper in English.** Now Test your self for RBI Assistant Pre. Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

The product of two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is:

CorrectLet the numbers be 37a and 37b.

Then, 37a * 37 b = 4107 => ab = 3

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 * 1, 37 * 3) i.e., (1, 111).

Greater number = 111.IncorrectLet the numbers be 37a and 37b.

Then, 37a * 37 b = 4107 => ab = 3

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 * 1, 37 * 3) i.e., (1, 111).

Greater number = 111. - Question 2 of 50
##### 2. Question

Rs.800 amounts to Rs.920 in 3 years at simple interest. If the interest is increased by 3%, it would amount to how much?

Correct(800*3*3)/100 = 72

920 + 72 = 992Incorrect(800*3*3)/100 = 72

920 + 72 = 992 - Question 3 of 50
##### 3. Question

A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:

CorrectSpeed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr. x – 5 = 45 ==> x = 50 km/hr.

IncorrectSpeed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr. x – 5 = 45 ==> x = 50 km/hr.

- Question 4 of 50
##### 4. Question

If 70% of an equal to 40% of b, then ratio between a and b is?

Correct70 a = 40 b

a: b = 4: 7Incorrect70 a = 40 b

a: b = 4: 7 - Question 5 of 50
##### 5. Question

Find the one which does not belong to that group ?

Correct525 => 5 5

^{2},

39 => 3 3^{2},

24 => 2 2^{2},

636 => 6 6^{2}. The above pattern is not followed in 426.Incorrect525 => 5 5

^{2},

39 => 3 3^{2},

24 => 2 2^{2},

636 => 6 6^{2}. The above pattern is not followed in 426. - Question 6 of 50
##### 6. Question

The ratio of the ages of Anil and his son at present is 7 : 3. Six years hence, the ratio of the ages of the Anil’s wife and the son will be 2 : 1. Find the ratio of the present ages of Anil and his wife?

CorrectLet the present ages of Anil and his son be 7x and 3x years respectively.

Let the present age of the son’s mother be m years.

(m + 6) / (3x + 6) = 2/1

m + 6 = 6x + 12 => m = 6x + 6

Ratio of the present ages of Anil and the son’s mother = 7x / (6x + 6).

This cannot be found uniquely.IncorrectLet the present ages of Anil and his son be 7x and 3x years respectively.

Let the present age of the son’s mother be m years.

(m + 6) / (3x + 6) = 2/1

m + 6 = 6x + 12 => m = 6x + 6

Ratio of the present ages of Anil and the son’s mother = 7x / (6x + 6).

This cannot be found uniquely. - Question 7 of 50
##### 7. Question

A 180 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train?

CorrectS = 180/6 * 18/5 = 108 kmph

IncorrectS = 180/6 * 18/5 = 108 kmph

- Question 8 of 50
##### 8. Question

A and B can finish a work in 16 days while A alone can do the same work in 24 days. In how many days B alone will complete the work?

CorrectB = 1/16 – 1/24 = 1/48 => 48 days

IncorrectB = 1/16 – 1/24 = 1/48 => 48 days

- Question 9 of 50
##### 9. Question

There are two positive numbers in the ratio 5 : 8. If the larger number exceeds the smaller by 15, then find the smaller number?

CorrectLet the two positive numbers be 5x and 8x respectively.

8x – 5x = 15 => 3x = 15 => x = 5.

Smaller number = 5x = 25.IncorrectLet the two positive numbers be 5x and 8x respectively.

8x – 5x = 15 => 3x = 15 => x = 5.

Smaller number = 5x = 25. - Question 10 of 50
##### 10. Question

5 * 5 ÷ 5 + 5 ÷ 5 = ?

Correct(5 * 5)/5 + 1/5 * 5 = 5 + 1 = 6

Incorrect(5 * 5)/5 + 1/5 * 5 = 5 + 1 = 6

- Question 11 of 50
##### 11. Question

A and B together have Rs. 1210. If 4/15 of A’s amount is equal to 2/5 of B’s amount, how much amount does B have?

Correct4/15 A = 2/5 B => A = (2/5 * 15/4)B

A =3/2 B => A/B = 3/2 => A:B = 3:2

B’s share = 1210 * 2/5 = Rs. 484.Incorrect4/15 A = 2/5 B => A = (2/5 * 15/4)B

A =3/2 B => A/B = 3/2 => A:B = 3:2

B’s share = 1210 * 2/5 = Rs. 484. - Question 12 of 50
##### 12. Question

A reduction of 20% in the price of salt enables a lady to obtain 10kgs more for Rs.100, find the original price per kg?

Correct100*(20/100) = 20 — 10

? — 1 => Rs.2

100 — 80

? — 2 => Rs.2.5Incorrect100*(20/100) = 20 — 10

? — 1 => Rs.2

100 — 80

? — 2 => Rs.2.5 - Question 13 of 50
##### 13. Question

A cistern is filled by a tap in 3 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how long will it take the leak to empty it?

Correct2/7 – 1/x = 1/4

x = 28Incorrect2/7 – 1/x = 1/4

x = 28 - Question 14 of 50
##### 14. Question

A man can row downstream at 18 kmph and upstream at 10 kmph. Find the speed of the man in still water and the speed of stream respectively?

CorrectLet the speed of the man in still water and speed of stream be x kmph and y kmph respectively.

Given x + y = 18 — (1)

and x – y = 10 — (2)

From (1) & (2) 2x = 28 => x = 14, y = 4.IncorrectLet the speed of the man in still water and speed of stream be x kmph and y kmph respectively.

Given x + y = 18 — (1)

and x – y = 10 — (2)

From (1) & (2) 2x = 28 => x = 14, y = 4. - Question 15 of 50
##### 15. Question

A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:

CorrectLet the length of the train be x meters and its speed be y m/sec.

They, x / y = 15 => y = x/15

x + 100 / 25 = x / 15

x = 150 m.IncorrectLet the length of the train be x meters and its speed be y m/sec.

They, x / y = 15 => y = x/15

x + 100 / 25 = x / 15

x = 150 m. - Question 16 of 50
##### 16. Question

12(13/18) + 16(11/27) – 10(5/9) = ?

Correct12 + 16 – 10 = 18

and 13/18 + 11/27 – 5/9 = (39 + 22 – 30)/(9 * 2 * 3) = 31/54 The answer is 18 (31/54)Incorrect12 + 16 – 10 = 18

and 13/18 + 11/27 – 5/9 = (39 + 22 – 30)/(9 * 2 * 3) = 31/54 The answer is 18 (31/54) - Question 17 of 50
##### 17. Question

A and B start a business jointly. A invests Rs.16000 for 8 months and B remains in the business for 4 months. Out of the total profit B claims 2/7th share. How much money is contributed by B?

Correct16*8: x*4 = 5:2

x = 12.8 => Rs.12800Incorrect16*8: x*4 = 5:2

x = 12.8 => Rs.12800 - Question 18 of 50
##### 18. Question

The radius of a circular wheel is 1.75 m, how many revolutions will it make in traveling 1 km?

Correct2 * 22/7 * 1.75 * x = 11000

x = 1000Incorrect2 * 22/7 * 1.75 * x = 11000

x = 1000 - Question 19 of 50
##### 19. Question

666 / 6 / 3 = ?

CorrectGiven Exp. = 666 * 1/6 * 1/3 = 37

IncorrectGiven Exp. = 666 * 1/6 * 1/3 = 37

- Question 20 of 50
##### 20. Question

Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?

Correct64000* 9/8 * 9/8 = 81000

Incorrect64000* 9/8 * 9/8 = 81000

- Question 21 of 50
##### 21. Question

Find the one which does not belong to that group ?

CorrectPart, Cart, Dart and Mart are rhyming words, but Trap does not sound similarly.

IncorrectPart, Cart, Dart and Mart are rhyming words, but Trap does not sound similarly.

- Question 22 of 50
##### 22. Question

12.5 + 10 1/4 of 100 ÷ 10% of 10 = ?

Correct12.5 + 10 1/4 of 100 ÷ 10% of 10

= 12.5 + 41/4 of 100 ÷ 10/100 of 10

= 12.5 + 41(25) ÷ 1 = 12.5 + 1025 = 1037.5Incorrect12.5 + 10 1/4 of 100 ÷ 10% of 10

= 12.5 + 41/4 of 100 ÷ 10/100 of 10

= 12.5 + 41(25) ÷ 1 = 12.5 + 1025 = 1037.5 - Question 23 of 50
##### 23. Question

If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?

CorrectThe triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.

Area of the triangle = 1/2 * 24 * 10 = 120 cm^{2}IncorrectThe triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.

Area of the triangle = 1/2 * 24 * 10 = 120 cm^{2} - Question 24 of 50
##### 24. Question

The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?

CorrectLet the length and the breadth of the floor be l m and b m respectively.

l = b + 200% of b = l + 2b = 3b

Area of the floor = 324/3 = 108 sq m

l b = 108 i.e., l * l/3 = 108

l^{2}= 324 => l = 18.IncorrectLet the length and the breadth of the floor be l m and b m respectively.

l = b + 200% of b = l + 2b = 3b

Area of the floor = 324/3 = 108 sq m

l b = 108 i.e., l * l/3 = 108

l^{2}= 324 => l = 18. - Question 25 of 50
##### 25. Question

A room is 4 meters 37 cm long and 3 meters 23cm broad. It is required to pave the floor with minimum square slabs. Find the number of slabs required for this purpose?

CorrectHCF of 323, 437 = 19

323 * 437 = 19 * 19 * x

x = 391IncorrectHCF of 323, 437 = 19

323 * 437 = 19 * 19 * x

x = 391 - Question 26 of 50
##### 26. Question

In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?

CorrectSpeed = 144 * 5/18 = 40 m/sec

Time taken = 100/40 = 2.5 sec.IncorrectSpeed = 144 * 5/18 = 40 m/sec

Time taken = 100/40 = 2.5 sec. - Question 27 of 50
##### 27. Question

A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?

CorrectSpeed of train relative to jogger = 45 – 9 = 36 km/hr.

= 36 * 5/18 = 10 m/sec.

Distance to be covered = 240 + 120 = 360 m.

Time taken = 360/10 = 36 sec.IncorrectSpeed of train relative to jogger = 45 – 9 = 36 km/hr.

= 36 * 5/18 = 10 m/sec.

Distance to be covered = 240 + 120 = 360 m.

Time taken = 360/10 = 36 sec. - Question 28 of 50
##### 28. Question

The roots of the equation 3x

^{2}– 12x + 10 = 0 are?CorrectThe discriminant of the quadratic equation is (-12)

^{2}– 4(3)(10) i.e., 24. As this is positive but not a perfect square, the roots are irrational and unequal.IncorrectThe discriminant of the quadratic equation is (-12)

^{2}– 4(3)(10) i.e., 24. As this is positive but not a perfect square, the roots are irrational and unequal. - Question 29 of 50
##### 29. Question

The population of a city increases at the rate of 4% p.a. but there is an additional annual increase of 1% in the population due to some job seekers. The percentage increase in the population after 2 years is?

Correct100

5 —- I

5

0.25 — II

———–

10.25%Incorrect100

5 —- I

5

0.25 — II

———–

10.25% - Question 30 of 50
##### 30. Question

A and B starts a business with Rs.8000 each, and after 4 months, B withdraws half of his capital . How should they share the profits at the end of the 18 months?

CorrectA invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000. So, the investment of B for remaining 14 months is Rs.4000 only.

A : B

8000*18 : (8000*4) + (4000*14)

14400 : 88000

A:B = 18:11IncorrectA invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000. So, the investment of B for remaining 14 months is Rs.4000 only.

A : B

8000*18 : (8000*4) + (4000*14)

14400 : 88000

A:B = 18:11 - Question 31 of 50
##### 31. Question

Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction?

CorrectRS = 5 ¾ – 4 ½ = 1 ¼

T = 3 ½ h.

D = 5/4 * 7/2 = 35/8 = 4 3/8 kmIncorrectRS = 5 ¾ – 4 ½ = 1 ¼

T = 3 ½ h.

D = 5/4 * 7/2 = 35/8 = 4 3/8 km - Question 32 of 50
##### 32. Question

In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?

CorrectWhen A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.

When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.

In a race of 1000 m, A beats C by (1000 – 787.5) = 212.5 m to C.

In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 = 127.5 m.IncorrectWhen A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.

When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.

In a race of 1000 m, A beats C by (1000 – 787.5) = 212.5 m to C.

In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 = 127.5 m. - Question 33 of 50
##### 33. Question

Nine men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?

CorrectAverage of 9 = x

9x = 8 * 3 + x * 2 x = 3.25

Total = 9 * 3.25 = 29.25IncorrectAverage of 9 = x

9x = 8 * 3 + x * 2 x = 3.25

Total = 9 * 3.25 = 29.25 - Question 34 of 50
##### 34. Question

Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a.

CorrectLet the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.

r = 15000(1 – 4/100) = 15000 – 600

m = 8000(1 + 10/100) = 8000 + 800

Total SP – Total CP = r + m – (15000 + 8000) = -600 + 800 = Rs. 200

As this is positive, an overall profit of Rs. 200 was made.IncorrectLet the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.

r = 15000(1 – 4/100) = 15000 – 600

m = 8000(1 + 10/100) = 8000 + 800

Total SP – Total CP = r + m – (15000 + 8000) = -600 + 800 = Rs. 200

As this is positive, an overall profit of Rs. 200 was made. - Question 35 of 50
##### 35. Question

The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?

CorrectThe ratio of the times taken is 2:1.

The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1

Speed of the stream = 42/3 = 14 kmph.IncorrectThe ratio of the times taken is 2:1.

The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1

Speed of the stream = 42/3 = 14 kmph. - Question 36 of 50
##### 36. Question

The population of a town is 45000; 5/9th of them are males and the rest females 40% of the males are married. What is the percentage of married females?

CorrectMale = 45,000* 5/9 = 25,000

Female = 45,000* 4/9 = 20,000

Married Male = 25,000* 40/100 = 10,000

Married Female = 10,000

20,000 ———— 10,000

100 ————- ? => 50%IncorrectMale = 45,000* 5/9 = 25,000

Female = 45,000* 4/9 = 20,000

Married Male = 25,000* 40/100 = 10,000

Married Female = 10,000

20,000 ———— 10,000

100 ————- ? => 50% - Question 37 of 50
##### 37. Question

Find the one which does not belong to that group ?

CorrectExcept mirage, all others are sources of water.

IncorrectExcept mirage, all others are sources of water.

- Question 38 of 50
##### 38. Question

5/8 * 2

^{(2/5 – 5/4)}/ 1^{1/4 }= ?Correct(5/8 * 12/5 – 5/4)/(5/4) (3/2 -5/4)/(5/4) = 1/5

Incorrect(5/8 * 12/5 – 5/4)/(5/4) (3/2 -5/4)/(5/4) = 1/5

- Question 39 of 50
##### 39. Question

Two pipes X and Y can separately fill a cistern in 18 and 24 hours respectively. If they are turned on alternately for one hour each, how long will it take to fill the cistern?

Correct1/18 + 1/24 = 7/72

72/7 = 10 2/7

7/72 * 10 = 35/36 —– 20 hours

WR = 1 – 35/36 = 1/36

1 h —– 1/18

? —– 1/36 = 1/2 hours

=> 20 1/2 hoursIncorrect1/18 + 1/24 = 7/72

72/7 = 10 2/7

7/72 * 10 = 35/36 —– 20 hours

WR = 1 – 35/36 = 1/36

1 h —– 1/18

? —– 1/36 = 1/2 hours

=> 20 1/2 hours - Question 40 of 50
##### 40. Question

The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?

CorrectInitial average age of the 10 persons be P.

Age of the new person Q.

Sum of the ages of the initial 10 persons = 10P

New average = (P-3) 10(P-3) = 10P – 42 + Q => Q = 12IncorrectInitial average age of the 10 persons be P.

Age of the new person Q.

Sum of the ages of the initial 10 persons = 10P

New average = (P-3) 10(P-3) = 10P – 42 + Q => Q = 12 - Question 41 of 50
##### 41. Question

7 + 1/2 of [8 – 4 / 2 * 3 – 1 + 1 + (4 + 2) – 2 * 2] = ?

CorrectApplying BODMAS rule

= 7 + 1/2 of [8 – 4 / 2 * 3 – 2 + (4 + 2) – 2 * 2]

= 7 + 1/2 of [8 – 2 * 3 – 2 + 6 – 4]

= 7 + 1/2 of (2) = 8IncorrectApplying BODMAS rule

= 7 + 1/2 of [8 – 4 / 2 * 3 – 2 + (4 + 2) – 2 * 2]

= 7 + 1/2 of [8 – 2 * 3 – 2 + 6 – 4]

= 7 + 1/2 of (2) = 8 - Question 42 of 50
##### 42. Question

If an article is sold at 19% profit instead of 12% profit, then the profit would be Rs. 105 more. What is the cost price?

CorrectLet the cost price of an article be Rs. x.

(19% of x) – (12% of x) = 105

19x/100 – 12x/100 = 105 => 7x = 105 * 100

=> x = 1500

Cost price = Rs. 1500IncorrectLet the cost price of an article be Rs. x.

(19% of x) – (12% of x) = 105

19x/100 – 12x/100 = 105 => 7x = 105 * 100

=> x = 1500

Cost price = Rs. 1500 - Question 43 of 50
##### 43. Question

I. a

^{2}– 7a + 12 = 0,

II. b^{2}– 3b + 2 = 0 to solve both the equations to find the values of a and b?CorrectI.(a – 3)(a – 4) = 0

=> a = 3, 4

II. (b – 2)(b – 1) = 0

=> b = 1, 2

=> a > bIncorrectI.(a – 3)(a – 4) = 0

=> a = 3, 4

II. (b – 2)(b – 1) = 0

=> b = 1, 2

=> a > b - Question 44 of 50
##### 44. Question

A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?

Correct5/30 + 20/x = 1

x = 24

1/30 + 1/24 = 3/40

40/3 = 13 1/3 daysIncorrect5/30 + 20/x = 1

x = 24

1/30 + 1/24 = 3/40

40/3 = 13 1/3 days - Question 45 of 50
##### 45. Question

The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages.

CorrectLet their present ages be 4x, 7x and 9x years respectively.

Then, (4x – 8) + (7x – 8) + (9x – 8) = 56

20x = 80 => x = 4

Their present ages are 16, 28 and 36 years respectively.IncorrectLet their present ages be 4x, 7x and 9x years respectively.

Then, (4x – 8) + (7x – 8) + (9x – 8) = 56

20x = 80 => x = 4

Their present ages are 16, 28 and 36 years respectively. - Question 46 of 50
##### 46. Question

Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?

Correct1/10 + 1/15 = 1/6 * 4 = 2/3

1 – 2/3 = 1/3

1/10 + 1/15 – 1/x = 1/3

x = 8Incorrect1/10 + 1/15 = 1/6 * 4 = 2/3

1 – 2/3 = 1/3

1/10 + 1/15 – 1/x = 1/3

x = 8 - Question 47 of 50
##### 47. Question

The jogging track in a sports complex is 726 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in?

CorrectClearly, the two will meet when they are 726 m apart.

To be (4.5 + 3.75) = 8.25 km apart, they take 1 hour.

To be 726 m apart, they take (100/825 * 726/1000) hrs = (242/2750 * 60) min = 5.28 min.IncorrectClearly, the two will meet when they are 726 m apart.

To be (4.5 + 3.75) = 8.25 km apart, they take 1 hour.

To be 726 m apart, they take (100/825 * 726/1000) hrs = (242/2750 * 60) min = 5.28 min. - Question 48 of 50
##### 48. Question

If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?

CorrectX * (105/100) * (105/100) * (105/100) = 138915

X = 138915/1.157625

X = 120000IncorrectX * (105/100) * (105/100) * (105/100) = 138915

X = 138915/1.157625

X = 120000 - Question 49 of 50
##### 49. Question

What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years?

Correct160 = (180*4*R)/100

R = 5%Incorrect160 = (180*4*R)/100

R = 5% - Question 50 of 50
##### 50. Question

The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years?

CorrectLet P’s age and Q’s age be 6x and 7x years respectively.

Then, 7x – 6x = 4 => x = 4

Required ratio = (6x + 4) : (7x + 4)

28 : 32 = 7:8IncorrectLet P’s age and Q’s age be 6x and 7x years respectively.

Then, 7x – 6x = 4 => x = 4

Required ratio = (6x + 4) : (7x + 4)

28 : 32 = 7:8