# RBI Assistant Quiz, RBI Assistant Prelims Online Test Series 3rd

## RBI Assistant Quiz, RBI Assistant Prelims Online Test Series 3

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**RBI Assistant Quiz, RBI Assistant Prelims Online Test Series 3**. RBI Exam Online Test 2020, RBI Assistant Pre Free Mock Test Exam 2020. RBI Assistant Pre. Exam Free Online Quiz 2020,The **RBI Assistant Exam pattern** is same as other bank clerk exams followed by Preliminary, Main and Language Proficiency Test. Last year new changes were introduced in the exam pattern. The RBI Assistant Pre Full online mock test paper is free for all students. RBI Assistant Pre. Question and Answers in English and Hindi **Series 3**. Here we are providing** RBI Assistant Pre. Full Mock Test Paper in English. RBI Assistant Pre. **Mock Test **Series 3rd** 2020. Now Test your self for RBI Assistant Pre. Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

A cricketer whose bowling average is 12.4 runs per wicket takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number age of the family now is:

CorrectLet the number of wickets taken till the last match be x. Then,

(12.4x + 26)/(x + 5) = 12

= 12.4x + 26 = 12x + 60

= 0.4x = 34

= x = 340/4 = 85.IncorrectLet the number of wickets taken till the last match be x. Then,

(12.4x + 26)/(x + 5) = 12

= 12.4x + 26 = 12x + 60

= 0.4x = 34

= x = 340/4 = 85. - Question 2 of 50
##### 2. Question

A wholesale tea dealer 408 kilograms, 468 kilograms and 516 kilograms of three different qualities of tea. He wants it all to be packed into boxes of equal size without mixing. Find the capacity of the largest possible box?

CorrectHCF of 408, 468, 516 = 12

IncorrectHCF of 408, 468, 516 = 12

- Question 3 of 50
##### 3. Question

The food in a camp lasts for 30 men for 40 days. If ten more men join, how many days will the food last?

Correctone man can consume the same food in 30*40 = 1200 days.

10 more men join, the total number of men = 40

The number of days the food will last = 1200/40 = 30 days.Incorrectone man can consume the same food in 30*40 = 1200 days.

10 more men join, the total number of men = 40

The number of days the food will last = 1200/40 = 30 days. - Question 4 of 50
##### 4. Question

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is?

CorrectLet the actual distance traveled be x km. Then,

x/10 = (x + 20)/14

4x – 200 =>x = 50 km.IncorrectLet the actual distance traveled be x km. Then,

x/10 = (x + 20)/14

4x – 200 =>x = 50 km. - Question 5 of 50
##### 5. Question

The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?

Correct2x * x = 128 => x= 8

Incorrect2x * x = 128 => x= 8

- Question 6 of 50
##### 6. Question

The difference between a two-digit number and the number obtained by interchanging the two digits is 63. Which is the smaller of the two numbers?

CorrectLet the ten’s digit be x and units digit by y.

Then,

(10x + y) – (10y + x) = 63

9(x – y) = 63

x – y = 7

Thus, none of the numbers can be determined.IncorrectLet the ten’s digit be x and units digit by y.

Then,

(10x + y) – (10y + x) = 63

9(x – y) = 63

x – y = 7

Thus, none of the numbers can be determined. - Question 7 of 50
##### 7. Question

A man saves Rs. 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years?

CorrectAmount = [200(1 + 5/100)

^{3}+ 200(1 + 5/100)^{2}+ 200(1 + 5/100)]

= [200 * 21/20(21/20 * 21/20 + 21/20 + 1)] = Rs. 662.02IncorrectAmount = [200(1 + 5/100)

^{3}+ 200(1 + 5/100)^{2}+ 200(1 + 5/100)]

= [200 * 21/20(21/20 * 21/20 + 21/20 + 1)] = Rs. 662.02 - Question 8 of 50
##### 8. Question

A cistern has three pipes, A, B and C. The pipes A and B can fill it in 4 and 5 hours respectively and C can empty it in 2 hours. If the pipes are opened in order at 1, 2 and 3 A.M. When will the cistern be empty?

Correct1 to 2 = 1/4

2 to 3 = 1/4 + 1/5 = 9/20

After 3 AM = 1/4 + 1/5 – 1/2 = -1/20

1/4 + 9/20 = 14/20

1 h —- 1/20

? —– 14/20

14 hours ==> 5 PMIncorrect1 to 2 = 1/4

2 to 3 = 1/4 + 1/5 = 9/20

After 3 AM = 1/4 + 1/5 – 1/2 = -1/20

1/4 + 9/20 = 14/20

1 h —- 1/20

? —– 14/20

14 hours ==> 5 PM - Question 9 of 50
##### 9. Question

Sreedhar and Sravan together can do a work in 25 days. With the help of Pavan, they completed the work in 8 days and earned Rs. 225. What is the share of Sravan, if Sreedhar alone can do the work in 75 days?

CorrectSravan’s one day’s work = 1/25 – 1/75 = 2/75

Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75

Sravan completed 16/75th of total work.

So, his share is 16/75 * 225 = Rs. 48.IncorrectSravan’s one day’s work = 1/25 – 1/75 = 2/75

Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75

Sravan completed 16/75th of total work.

So, his share is 16/75 * 225 = Rs. 48. - Question 10 of 50
##### 10. Question

A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?

Correct90%

104%

——–

14% —- 140

100% —- ? => Rs.1000Incorrect90%

104%

——–

14% —- 140

100% —- ? => Rs.1000 - Question 11 of 50
##### 11. Question

1000 men have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now?

Correct1000*15 = 1200*x

x = 12.5Incorrect1000*15 = 1200*x

x = 12.5 - Question 12 of 50
##### 12. Question

In a 1000 m race, A beats B by 200 meters or 25 seconds. Find the speed of B?

CorrectSince A beats B by 200 m or 25 seconds, i

t implies that B covers 200 m in 25 seconds.

Hence speed of B = 200/25 = 8 m/s.IncorrectSince A beats B by 200 m or 25 seconds, i

t implies that B covers 200 m in 25 seconds.

Hence speed of B = 200/25 = 8 m/s. - Question 13 of 50
##### 13. Question

What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?

CorrectL.C.M of 12, 18, 21, 30

= 2 * 3 * 2 * 3 * 7 * 5 = 1260

Required number = 1260/2 = 630.IncorrectL.C.M of 12, 18, 21, 30

= 2 * 3 * 2 * 3 * 7 * 5 = 1260

Required number = 1260/2 = 630. - Question 14 of 50
##### 14. Question

A group of 10 representatives is to be selected out of 12 seniors and 10 juniors. In how many different ways can the group be selected if it should have at least one senior?

CorrectThe total number of ways of forming the group of ten representatives is ²²C₁₀.

The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way

The required number of ways = ²²C₁₀ – 1IncorrectThe total number of ways of forming the group of ten representatives is ²²C₁₀.

The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way

The required number of ways = ²²C₁₀ – 1 - Question 15 of 50
##### 15. Question

A cistern is normally filled in 8 hours but takes two hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in?

Correct1/8 – 1/x = 1/10

x = 40Incorrect1/8 – 1/x = 1/10

x = 40 - Question 16 of 50
##### 16. Question

In a mixture of 60 liters, the ratio of milk and water is 2:1. What amount of water must be added to make the ratio of milk and water as 1:2?

Correct2:1 — 60

1:2

2:4

—————

3

3 ———– 60

3 ———– ? => 60 litersIncorrect2:1 — 60

1:2

2:4

—————

3

3 ———– 60

3 ———– ? => 60 liters - Question 17 of 50
##### 17. Question

If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?

Correct(3500*1.5*3)/100 => 157.50

Incorrect(3500*1.5*3)/100 => 157.50

- Question 18 of 50
##### 18. Question

Indu gave Bindu Rs.1250 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?

Correct1250 = D(100/4)

^{2}

D = 2Incorrect1250 = D(100/4)

^{2}

D = 2 - Question 19 of 50
##### 19. Question

96% of the population of a village is 23040. The total population of the village is?

CorrectX * (96/100) = 23040

X = 240 * 100

X = 24000IncorrectX * (96/100) = 23040

X = 240 * 100

X = 24000 - Question 20 of 50
##### 20. Question

The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?

CorrectAverage of 20 numbers = 0

Sum of 20 numbers = (0 * 20) = 0

It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (-a).IncorrectAverage of 20 numbers = 0

Sum of 20 numbers = (0 * 20) = 0

It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (-a). - Question 21 of 50
##### 21. Question

Some pens are divided among A, B, C and D. A gets twice the number of pens that B gets. C gets the same number of pens as D gets. If A gets 25 pens more than D and the ratio of the number of pens that B and C get is 2:3, then find the number of pens that D gets?

CorrectLet the number of pens that A, B, C and D get be a, b, c and d respectively.

a:b = 2:1

a = c + 25

b:c = 2:3

a:b:c:d = 4:2:3:3

a, d get 4p, 3p pens

=> 4p – 3p = 25 => p = 25

=> D gets 3p = 3 * 25 = 75 pens.IncorrectLet the number of pens that A, B, C and D get be a, b, c and d respectively.

a:b = 2:1

a = c + 25

b:c = 2:3

a:b:c:d = 4:2:3:3

a, d get 4p, 3p pens

=> 4p – 3p = 25 => p = 25

=> D gets 3p = 3 * 25 = 75 pens. - Question 22 of 50
##### 22. Question

If a solid sphere of radius 10 cms is moulded into 8 spherical solid balls of equal radius, then surface area of each ball (in cm

^{2}) is?Correct4/3 π * 10 * 10 * 10 = 8 * 4/3 πr

^{3}

r = 5

4π * 5 * 5 = 100πIncorrect4/3 π * 10 * 10 * 10 = 8 * 4/3 πr

^{3}

r = 5

4π * 5 * 5 = 100π - Question 23 of 50
##### 23. Question

If Rs.450 amount to Rs.540 in 4 years, what will it amount to in 6 years at the same rate % per annum?

Correct90 = (450*4*R)/100

R = 5%

I = (450*6*5)/100 = 135

450 + 135 = 585Incorrect90 = (450*4*R)/100

R = 5%

I = (450*6*5)/100 = 135

450 + 135 = 585 - Question 24 of 50
##### 24. Question

(1000)

^{9}/10^{24}= ?CorrectGiven Exp. = (1000)

^{9}/10^{24}

= (10^{3})^{9}/10^{24}= 10^{27}/10^{24}= 10^{(27 – 24)}= 10^{3}=1000IncorrectGiven Exp. = (1000)

^{9}/10^{24}

= (10^{3})^{9}/10^{24}= 10^{27}/10^{24}= 10^{(27 – 24)}= 10^{3}=1000 - Question 25 of 50
##### 25. Question

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

CorrectSpeed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.

IncorrectSpeed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.

- Question 26 of 50
##### 26. Question

What will be the difference between simple and compound interest at 10% per annum on a sum of Rs. 1000 after 4 years?

CorrectS.I. = (1000 * 10 * 4)/100 = Rs. 400

C.I. = [1000 * (1 + 10/100)^{4}– 1000] = Rs. 464.10 Difference = (464.10 – 400) = Rs. 64.10IncorrectS.I. = (1000 * 10 * 4)/100 = Rs. 400

C.I. = [1000 * (1 + 10/100)^{4}– 1000] = Rs. 464.10 Difference = (464.10 – 400) = Rs. 64.10 - Question 27 of 50
##### 27. Question

Product of two co-prime numbers is 117. Their L.C.M should be:

CorrectH.C.F of co-prime numbers is 1.

So, L.C.M = 117/1 = 117.IncorrectH.C.F of co-prime numbers is 1.

So, L.C.M = 117/1 = 117. - Question 28 of 50
##### 28. Question

The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?

CorrectInitial average age of the 10 persons be P.

Age of the new person Q.

Sum of the ages of the initial 10 persons = 10P

New average = (P-3) 10(P-3) = 10P – 42 + Q => Q = 12IncorrectInitial average age of the 10 persons be P.

Age of the new person Q.

Sum of the ages of the initial 10 persons = 10P

New average = (P-3) 10(P-3) = 10P – 42 + Q => Q = 12 - Question 29 of 50
##### 29. Question

The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is:

CorrectLet the required means score be x. Then,

20 * 80 + 25 * 31 + 55 * x = 52 * 100

= 1600 + 775 + 55x = 5200

= 55x = 2825

= x = 565/11 = 51.4.IncorrectLet the required means score be x. Then,

20 * 80 + 25 * 31 + 55 * x = 52 * 100

= 1600 + 775 + 55x = 5200

= 55x = 2825

= x = 565/11 = 51.4. - Question 30 of 50
##### 30. Question

A cricketer has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, there by increasing his average by 6 runs. His new average is:

CorrectLet average for 10 innings be x. Then,

(10x + 108)/11 = x + 6

= 11x + 66 = 10x + 108

= x = 42.

New average = (x + 6) = 48 runs.IncorrectLet average for 10 innings be x. Then,

(10x + 108)/11 = x + 6

= 11x + 66 = 10x + 108

= x = 42.

New average = (x + 6) = 48 runs. - Question 31 of 50
##### 31. Question

The sum of five consecutive even numbers of set x is 440. Find the sum of a different set of five consecutive integers whose second least number is 121 less than double the least number of set x?

CorrectLet the five consecutive even numbers be 2(x – 2), 2(x – 1), 2x, 2(x + 1) and 2(x + 2)

Their sum = 10x = 440

x = 44 => 2(x – 2) = 84

Second least number of the other set = 2(84) – 121 = 47

This set has its least number as 46.

Sum of the numbers of this set = 46 + 47 + 48 + 49 + 50

= 48 – 2 + 48 – 1 + 48 + 48 + 1 + 48 + 2 => 5(48) = 240IncorrectLet the five consecutive even numbers be 2(x – 2), 2(x – 1), 2x, 2(x + 1) and 2(x + 2)

Their sum = 10x = 440

x = 44 => 2(x – 2) = 84

Second least number of the other set = 2(84) – 121 = 47

This set has its least number as 46.

Sum of the numbers of this set = 46 + 47 + 48 + 49 + 50

= 48 – 2 + 48 – 1 + 48 + 48 + 1 + 48 + 2 => 5(48) = 240 - Question 32 of 50
##### 32. Question

The volume of a cube is 1728 cc. Find its surface.

Correcta

^{3}= 1728 => a = 12

6a^{2}= 6 * 12 * 12 = 864Incorrecta

^{3}= 1728 => a = 12

6a^{2}= 6 * 12 * 12 = 864 - Question 33 of 50
##### 33. Question

A contractor undertakes to complete the construction of a tunnel 720 meters long in 240 days and employs 60 men for the purpose. After 120 days, he finds that only 240 meters of the tunnel is complete. How many more men should be employ in order to complete the work in time?

CorrectIn 120days, only 240m of the tunnel is constructed by 60 men.

The remaining 120days, 480m of the tunnel can be constructed by 120 men.

Additional number of men required = 120 – 60 = 60 men.IncorrectIn 120days, only 240m of the tunnel is constructed by 60 men.

The remaining 120days, 480m of the tunnel can be constructed by 120 men.

Additional number of men required = 120 – 60 = 60 men. - Question 34 of 50
##### 34. Question

Find the least number which when divided by 35 and 11 leaves a remainder of 1 in each case.

CorrectThe least number which when divided by different divisors leaving the same remainder in each case

= LCM(different divisors) + remainder left in each case.

Hence the required least number

= LCM(35, 11) + 1 = 386.IncorrectThe least number which when divided by different divisors leaving the same remainder in each case

= LCM(different divisors) + remainder left in each case.

Hence the required least number

= LCM(35, 11) + 1 = 386. - Question 35 of 50
##### 35. Question

The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?

Correct100 * 100 = 10000

80 * 110 = 8800

10000——- 1200

100 ——- ? = 12%Incorrect100 * 100 = 10000

80 * 110 = 8800

10000——- 1200

100 ——- ? = 12% - Question 36 of 50
##### 36. Question

A can do a piece of work in 15 days and B in 20 days. They began the work together but 5 days before the completion of the work, A leaves. The work was completed in?

Correct(x – 5)/15 + x/20 = 1

x = 11 3/7 daysIncorrect(x – 5)/15 + x/20 = 1

x = 11 3/7 days - Question 37 of 50
##### 37. Question

If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?

Correct9 = (1*40*R)/100

R = 22 1/2 %Incorrect9 = (1*40*R)/100

R = 22 1/2 % - Question 38 of 50
##### 38. Question

The salary of Mr. X is 30% more than that of Mr. Y . Find what percent of Mr. Y’s salary is less than Mr. X’s?

Correcty=100 x=130

130———30

100———? => 23 1/3%Incorrecty=100 x=130

130———30

100———? => 23 1/3% - Question 39 of 50
##### 39. Question

If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?

CorrectThe triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.

Area of the triangle = 1/2 * 24 * 10 = 120 cm^{2}IncorrectThe triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.

Area of the triangle = 1/2 * 24 * 10 = 120 cm^{2} - Question 40 of 50
##### 40. Question

An engineering student has to secure 36% marks to pass. He gets 130 marks and fails by 14 marks. The maximum No. of marks obtained by him is?

Correct130

14

——-

361—— 144

100%——? => 400Incorrect130

14

——-

361—— 144

100%——? => 400 - Question 41 of 50
##### 41. Question

Divide Rs.32000 in the ratio 3:5?

Correct3/8 * 32000 = 12000

5/8 * 32000 = 20000Incorrect3/8 * 32000 = 12000

5/8 * 32000 = 20000 - Question 42 of 50
##### 42. Question

Which of the following fractions is the largest?

CorrectL.C.M of 8, 16, 40 and 80 = 80.

7/8 = 70/80; 13/16 = 65/80; 31/40 = 62/80

Since, 70/80 > 63/80 > 65/80 > 62/80,

So, 7/8 > 63/80 > 13/16 > 31/40

So, 7/8 is the largest.IncorrectL.C.M of 8, 16, 40 and 80 = 80.

7/8 = 70/80; 13/16 = 65/80; 31/40 = 62/80

Since, 70/80 > 63/80 > 65/80 > 62/80,

So, 7/8 > 63/80 > 13/16 > 31/40

So, 7/8 is the largest. - Question 43 of 50
##### 43. Question

Solve the equation for x : 19(x + y) + 17 = 19(-x + y) – 21

Correct19x + 19y + 17 = -19x + 19y – 21

38x = -38 => x = -1Incorrect19x + 19y + 17 = -19x + 19y – 21

38x = -38 => x = -1 - Question 44 of 50
##### 44. Question

8 2/3 + 6 4/5 = ?

Correct8 2/3 + 6 4/5 = (8 + 6) + (10/15 + 12/15) = 14 + 1 7/15 = 15 7/15

Incorrect8 2/3 + 6 4/5 = (8 + 6) + (10/15 + 12/15) = 14 + 1 7/15 = 15 7/15

- Question 45 of 50
##### 45. Question

3251 + 587 + 369 – ? = 3007

CorrectLet 4207 – x = 3007

Then, x = 4207 – 3007 = 1200IncorrectLet 4207 – x = 3007

Then, x = 4207 – 3007 = 1200 - Question 46 of 50
##### 46. Question

A and B start a business jointly. A invests Rs.16000 for 8 months and B remains in the business for 4 months. Out of the total profit B claims 2/7th share. How much money is contributed by B?

Correct16*8: x*4 = 5:2

x = 12.8 => Rs.12800Incorrect16*8: x*4 = 5:2

x = 12.8 => Rs.12800 - Question 47 of 50
##### 47. Question

The simple interest accrued on an amount Rs.10,000 at the end of two years is same as the compound interest on Rs.8,000 at the end of two years. The rate of interest is same in both the cases. What is the rate of interest?

CorrectGiven that Rs.10,000 is invested in S.I for two years and Rs.8,000 in C.I for two years

=> C.I – S.I

=> 8,000 { [1 + r/100]^{2 }– 1} = (10,000)2r /100

=> 8{ 1 + 2r/100 + r^{2}/ (100)^{2}– 1} = r/5

=> 16r/100 + 8r^{2}/(100)^{2}= 20r/100

=> 4r/10 = 8r^{2}/(100)^{2}

=> 8[r/100]^{2}– 4r/100 = 0

=> r/100 {8r/100 -4} = 0

=> r = 0% of 50%

Since r!= 0%, r =50%IncorrectGiven that Rs.10,000 is invested in S.I for two years and Rs.8,000 in C.I for two years

=> C.I – S.I

=> 8,000 { [1 + r/100]^{2 }– 1} = (10,000)2r /100

=> 8{ 1 + 2r/100 + r^{2}/ (100)^{2}– 1} = r/5

=> 16r/100 + 8r^{2}/(100)^{2}= 20r/100

=> 4r/10 = 8r^{2}/(100)^{2}

=> 8[r/100]^{2}– 4r/100 = 0

=> r/100 {8r/100 -4} = 0

=> r = 0% of 50%

Since r!= 0%, r =50% - Question 48 of 50
##### 48. Question

The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 5 months, find for how much time did Q invest the money?

Correct7*5: 5*x = 7:10

x = 10Incorrect7*5: 5*x = 7:10

x = 10 - Question 49 of 50
##### 49. Question

Simplify : (y

^{4b-a}. y^{4c-b}. y^{4a-c}) / (y^{a}. y^{b}. y^{c})^{3}Correct(y

^{4b-a}. y^{4c-b}. y^{4a-c}) / (y^{a}. y^{b}. y^{c})^{3}

= (y^{4b-a}. y^{4c-b}. y^{4a-c}) / (y^{a+b+c})^{3}

= y^{4b-a+4c-b+4a-c}/ y^{3(a+b+c)}

= y^{3(a+b+c)}/ y^{3(a+b+c)}= 1.Incorrect(y

^{4b-a}. y^{4c-b}. y^{4a-c}) / (y^{a}. y^{b}. y^{c})^{3}

= (y^{4b-a}. y^{4c-b}. y^{4a-c}) / (y^{a+b+c})^{3}

= y^{4b-a+4c-b+4a-c}/ y^{3(a+b+c)}

= y^{3(a+b+c)}/ y^{3(a+b+c)}= 1. - Question 50 of 50
##### 50. Question

A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?

Correct100 — 10 DS = 10

? —- 1

75 —- 15 US = 5

? —– 1 S = (10 – 5)/2

= 2 2 ½ kmphIncorrect100 — 10 DS = 10

? —- 1

75 —- 15 US = 5

? —– 1 S = (10 – 5)/2

= 2 2 ½ kmph