RBI Assistant Quiz, RBI Assistant Prelims Online Test Series 3
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RBI Assistant Quiz, RBI Assistant Prelims Online Test Series 3. RBI Exam Online Test 2021, RBI Assistant Pre Free Mock Test Exam 2021. RBI Assistant Pre. Exam Free Online Quiz 2021,The RBI Assistant Exam pattern is same as other bank clerk exams followed by Preliminary, Main and Language Proficiency Test. Last year new changes were introduced in the exam pattern. The RBI Assistant Pre Full online mock test paper is free for all students. RBI Assistant Pre. Question and Answers in English and Hindi Series 3. Here we are providing RBI Assistant Pre. Full Mock Test Paper in English. RBI Assistant Pre. Mock Test Series 3rd 2021. Now Test your self for RBI Assistant Pre. Exam by using below quiz…
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Question 1 of 50
1. Question
A cricketer whose bowling average is 12.4 runs per wicket takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number age of the family now is:
Correct
Let the number of wickets taken till the last match be x. Then,
(12.4x + 26)/(x + 5) = 12
= 12.4x + 26 = 12x + 60
= 0.4x = 34
= x = 340/4 = 85.Incorrect
Let the number of wickets taken till the last match be x. Then,
(12.4x + 26)/(x + 5) = 12
= 12.4x + 26 = 12x + 60
= 0.4x = 34
= x = 340/4 = 85. 
Question 2 of 50
2. Question
A wholesale tea dealer 408 kilograms, 468 kilograms and 516 kilograms of three different qualities of tea. He wants it all to be packed into boxes of equal size without mixing. Find the capacity of the largest possible box?
Correct
HCF of 408, 468, 516 = 12
Incorrect
HCF of 408, 468, 516 = 12

Question 3 of 50
3. Question
The food in a camp lasts for 30 men for 40 days. If ten more men join, how many days will the food last?
Correct
one man can consume the same food in 30*40 = 1200 days.
10 more men join, the total number of men = 40
The number of days the food will last = 1200/40 = 30 days.Incorrect
one man can consume the same food in 30*40 = 1200 days.
10 more men join, the total number of men = 40
The number of days the food will last = 1200/40 = 30 days. 
Question 4 of 50
4. Question
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is?
Correct
Let the actual distance traveled be x km. Then,
x/10 = (x + 20)/14
4x – 200 =>x = 50 km.Incorrect
Let the actual distance traveled be x km. Then,
x/10 = (x + 20)/14
4x – 200 =>x = 50 km. 
Question 5 of 50
5. Question
The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?
Correct
2x * x = 128 => x= 8
Incorrect
2x * x = 128 => x= 8

Question 6 of 50
6. Question
The difference between a twodigit number and the number obtained by interchanging the two digits is 63. Which is the smaller of the two numbers?
Correct
Let the ten’s digit be x and units digit by y.
Then,
(10x + y) – (10y + x) = 63
9(x – y) = 63
x – y = 7
Thus, none of the numbers can be determined.Incorrect
Let the ten’s digit be x and units digit by y.
Then,
(10x + y) – (10y + x) = 63
9(x – y) = 63
x – y = 7
Thus, none of the numbers can be determined. 
Question 7 of 50
7. Question
A man saves Rs. 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years?
Correct
Amount = [200(1 + 5/100)^{3} + 200(1 + 5/100)^{2} + 200(1 + 5/100)]
= [200 * 21/20(21/20 * 21/20 + 21/20 + 1)] = Rs. 662.02Incorrect
Amount = [200(1 + 5/100)^{3} + 200(1 + 5/100)^{2} + 200(1 + 5/100)]
= [200 * 21/20(21/20 * 21/20 + 21/20 + 1)] = Rs. 662.02 
Question 8 of 50
8. Question
A cistern has three pipes, A, B and C. The pipes A and B can fill it in 4 and 5 hours respectively and C can empty it in 2 hours. If the pipes are opened in order at 1, 2 and 3 A.M. When will the cistern be empty?
Correct
1 to 2 = 1/4
2 to 3 = 1/4 + 1/5 = 9/20
After 3 AM = 1/4 + 1/5 – 1/2 = 1/20
1/4 + 9/20 = 14/20
1 h — 1/20
? —– 14/20
14 hours ==> 5 PMIncorrect
1 to 2 = 1/4
2 to 3 = 1/4 + 1/5 = 9/20
After 3 AM = 1/4 + 1/5 – 1/2 = 1/20
1/4 + 9/20 = 14/20
1 h — 1/20
? —– 14/20
14 hours ==> 5 PM 
Question 9 of 50
9. Question
Sreedhar and Sravan together can do a work in 25 days. With the help of Pavan, they completed the work in 8 days and earned Rs. 225. What is the share of Sravan, if Sreedhar alone can do the work in 75 days?
Correct
Sravan’s one day’s work = 1/25 – 1/75 = 2/75
Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75
Sravan completed 16/75th of total work.
So, his share is 16/75 * 225 = Rs. 48.Incorrect
Sravan’s one day’s work = 1/25 – 1/75 = 2/75
Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75
Sravan completed 16/75th of total work.
So, his share is 16/75 * 225 = Rs. 48. 
Question 10 of 50
10. Question
A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
Correct
90%
104%
——–
14% — 140
100% — ? => Rs.1000Incorrect
90%
104%
——–
14% — 140
100% — ? => Rs.1000 
Question 11 of 50
11. Question
1000 men have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now?
Correct
1000*15 = 1200*x
x = 12.5Incorrect
1000*15 = 1200*x
x = 12.5 
Question 12 of 50
12. Question
In a 1000 m race, A beats B by 200 meters or 25 seconds. Find the speed of B?
Correct
Since A beats B by 200 m or 25 seconds, i
t implies that B covers 200 m in 25 seconds.
Hence speed of B = 200/25 = 8 m/s.Incorrect
Since A beats B by 200 m or 25 seconds, i
t implies that B covers 200 m in 25 seconds.
Hence speed of B = 200/25 = 8 m/s. 
Question 13 of 50
13. Question
What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?
Correct
L.C.M of 12, 18, 21, 30
= 2 * 3 * 2 * 3 * 7 * 5 = 1260
Required number = 1260/2 = 630.Incorrect
L.C.M of 12, 18, 21, 30
= 2 * 3 * 2 * 3 * 7 * 5 = 1260
Required number = 1260/2 = 630. 
Question 14 of 50
14. Question
A group of 10 representatives is to be selected out of 12 seniors and 10 juniors. In how many different ways can the group be selected if it should have at least one senior?
Correct
The total number of ways of forming the group of ten representatives is ²²C₁₀.
The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way
The required number of ways = ²²C₁₀ – 1Incorrect
The total number of ways of forming the group of ten representatives is ²²C₁₀.
The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way
The required number of ways = ²²C₁₀ – 1 
Question 15 of 50
15. Question
A cistern is normally filled in 8 hours but takes two hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in?
Correct
1/8 – 1/x = 1/10
x = 40Incorrect
1/8 – 1/x = 1/10
x = 40 
Question 16 of 50
16. Question
In a mixture of 60 liters, the ratio of milk and water is 2:1. What amount of water must be added to make the ratio of milk and water as 1:2?
Correct
2:1 — 60
1:2
2:4
—————
3
3 ———– 60
3 ———– ? => 60 litersIncorrect
2:1 — 60
1:2
2:4
—————
3
3 ———– 60
3 ———– ? => 60 liters 
Question 17 of 50
17. Question
If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?
Correct
(3500*1.5*3)/100 => 157.50
Incorrect
(3500*1.5*3)/100 => 157.50

Question 18 of 50
18. Question
Indu gave Bindu Rs.1250 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
Correct
1250 = D(100/4)^{2}
D = 2Incorrect
1250 = D(100/4)^{2}
D = 2 
Question 19 of 50
19. Question
96% of the population of a village is 23040. The total population of the village is?
Correct
X * (96/100) = 23040
X = 240 * 100
X = 24000Incorrect
X * (96/100) = 23040
X = 240 * 100
X = 24000 
Question 20 of 50
20. Question
The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
Correct
Average of 20 numbers = 0
Sum of 20 numbers = (0 * 20) = 0
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (a).Incorrect
Average of 20 numbers = 0
Sum of 20 numbers = (0 * 20) = 0
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (a). 
Question 21 of 50
21. Question
Some pens are divided among A, B, C and D. A gets twice the number of pens that B gets. C gets the same number of pens as D gets. If A gets 25 pens more than D and the ratio of the number of pens that B and C get is 2:3, then find the number of pens that D gets?
Correct
Let the number of pens that A, B, C and D get be a, b, c and d respectively.
a:b = 2:1
a = c + 25
b:c = 2:3
a:b:c:d = 4:2:3:3
a, d get 4p, 3p pens
=> 4p – 3p = 25 => p = 25
=> D gets 3p = 3 * 25 = 75 pens.Incorrect
Let the number of pens that A, B, C and D get be a, b, c and d respectively.
a:b = 2:1
a = c + 25
b:c = 2:3
a:b:c:d = 4:2:3:3
a, d get 4p, 3p pens
=> 4p – 3p = 25 => p = 25
=> D gets 3p = 3 * 25 = 75 pens. 
Question 22 of 50
22. Question
If a solid sphere of radius 10 cms is moulded into 8 spherical solid balls of equal radius, then surface area of each ball (in cm^{2}) is?
Correct
4/3 π * 10 * 10 * 10 = 8 * 4/3 πr^{3}
r = 5
4π * 5 * 5 = 100πIncorrect
4/3 π * 10 * 10 * 10 = 8 * 4/3 πr^{3}
r = 5
4π * 5 * 5 = 100π 
Question 23 of 50
23. Question
If Rs.450 amount to Rs.540 in 4 years, what will it amount to in 6 years at the same rate % per annum?
Correct
90 = (450*4*R)/100
R = 5%
I = (450*6*5)/100 = 135
450 + 135 = 585Incorrect
90 = (450*4*R)/100
R = 5%
I = (450*6*5)/100 = 135
450 + 135 = 585 
Question 24 of 50
24. Question
(1000)^{9}/10^{24} = ?
Correct
Given Exp. = (1000)^{9}/10^{24}
= (10^{3})^{9}/10^{24} = 10^{27}/10^{24} = 10^{(27 – 24)} = 10^{3} =1000Incorrect
Given Exp. = (1000)^{9}/10^{24}
= (10^{3})^{9}/10^{24} = 10^{27}/10^{24} = 10^{(27 – 24)} = 10^{3} =1000 
Question 25 of 50
25. Question
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Correct
Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.
Incorrect
Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.

Question 26 of 50
26. Question
What will be the difference between simple and compound interest at 10% per annum on a sum of Rs. 1000 after 4 years?
Correct
S.I. = (1000 * 10 * 4)/100 = Rs. 400
C.I. = [1000 * (1 + 10/100)^{4} – 1000] = Rs. 464.10 Difference = (464.10 – 400) = Rs. 64.10Incorrect
S.I. = (1000 * 10 * 4)/100 = Rs. 400
C.I. = [1000 * (1 + 10/100)^{4} – 1000] = Rs. 464.10 Difference = (464.10 – 400) = Rs. 64.10 
Question 27 of 50
27. Question
Product of two coprime numbers is 117. Their L.C.M should be:
Correct
H.C.F of coprime numbers is 1.
So, L.C.M = 117/1 = 117.Incorrect
H.C.F of coprime numbers is 1.
So, L.C.M = 117/1 = 117. 
Question 28 of 50
28. Question
The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?
Correct
Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average = (P3) 10(P3) = 10P – 42 + Q => Q = 12Incorrect
Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average = (P3) 10(P3) = 10P – 42 + Q => Q = 12 
Question 29 of 50
29. Question
The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is:
Correct
Let the required means score be x. Then,
20 * 80 + 25 * 31 + 55 * x = 52 * 100
= 1600 + 775 + 55x = 5200
= 55x = 2825
= x = 565/11 = 51.4.Incorrect
Let the required means score be x. Then,
20 * 80 + 25 * 31 + 55 * x = 52 * 100
= 1600 + 775 + 55x = 5200
= 55x = 2825
= x = 565/11 = 51.4. 
Question 30 of 50
30. Question
A cricketer has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, there by increasing his average by 6 runs. His new average is:
Correct
Let average for 10 innings be x. Then,
(10x + 108)/11 = x + 6
= 11x + 66 = 10x + 108
= x = 42.
New average = (x + 6) = 48 runs.Incorrect
Let average for 10 innings be x. Then,
(10x + 108)/11 = x + 6
= 11x + 66 = 10x + 108
= x = 42.
New average = (x + 6) = 48 runs. 
Question 31 of 50
31. Question
The sum of five consecutive even numbers of set x is 440. Find the sum of a different set of five consecutive integers whose second least number is 121 less than double the least number of set x?
Correct
Let the five consecutive even numbers be 2(x – 2), 2(x – 1), 2x, 2(x + 1) and 2(x + 2)
Their sum = 10x = 440
x = 44 => 2(x – 2) = 84
Second least number of the other set = 2(84) – 121 = 47
This set has its least number as 46.
Sum of the numbers of this set = 46 + 47 + 48 + 49 + 50
= 48 – 2 + 48 – 1 + 48 + 48 + 1 + 48 + 2 => 5(48) = 240Incorrect
Let the five consecutive even numbers be 2(x – 2), 2(x – 1), 2x, 2(x + 1) and 2(x + 2)
Their sum = 10x = 440
x = 44 => 2(x – 2) = 84
Second least number of the other set = 2(84) – 121 = 47
This set has its least number as 46.
Sum of the numbers of this set = 46 + 47 + 48 + 49 + 50
= 48 – 2 + 48 – 1 + 48 + 48 + 1 + 48 + 2 => 5(48) = 240 
Question 32 of 50
32. Question
The volume of a cube is 1728 cc. Find its surface.
Correct
a^{3} = 1728 => a = 12
6a^{2} = 6 * 12 * 12 = 864Incorrect
a^{3} = 1728 => a = 12
6a^{2} = 6 * 12 * 12 = 864 
Question 33 of 50
33. Question
A contractor undertakes to complete the construction of a tunnel 720 meters long in 240 days and employs 60 men for the purpose. After 120 days, he finds that only 240 meters of the tunnel is complete. How many more men should be employ in order to complete the work in time?
Correct
In 120days, only 240m of the tunnel is constructed by 60 men.
The remaining 120days, 480m of the tunnel can be constructed by 120 men.
Additional number of men required = 120 – 60 = 60 men.Incorrect
In 120days, only 240m of the tunnel is constructed by 60 men.
The remaining 120days, 480m of the tunnel can be constructed by 120 men.
Additional number of men required = 120 – 60 = 60 men. 
Question 34 of 50
34. Question
Find the least number which when divided by 35 and 11 leaves a remainder of 1 in each case.
Correct
The least number which when divided by different divisors leaving the same remainder in each case
= LCM(different divisors) + remainder left in each case.
Hence the required least number
= LCM(35, 11) + 1 = 386.Incorrect
The least number which when divided by different divisors leaving the same remainder in each case
= LCM(different divisors) + remainder left in each case.
Hence the required least number
= LCM(35, 11) + 1 = 386. 
Question 35 of 50
35. Question
The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?
Correct
100 * 100 = 10000
80 * 110 = 8800
10000—— 1200
100 —— ? = 12%Incorrect
100 * 100 = 10000
80 * 110 = 8800
10000—— 1200
100 —— ? = 12% 
Question 36 of 50
36. Question
A can do a piece of work in 15 days and B in 20 days. They began the work together but 5 days before the completion of the work, A leaves. The work was completed in?
Correct
(x – 5)/15 + x/20 = 1
x = 11 3/7 daysIncorrect
(x – 5)/15 + x/20 = 1
x = 11 3/7 days 
Question 37 of 50
37. Question
If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?
Correct
9 = (1*40*R)/100
R = 22 1/2 %Incorrect
9 = (1*40*R)/100
R = 22 1/2 % 
Question 38 of 50
38. Question
The salary of Mr. X is 30% more than that of Mr. Y . Find what percent of Mr. Y’s salary is less than Mr. X’s?
Correct
y=100 x=130
130———30
100———? => 23 1/3%Incorrect
y=100 x=130
130———30
100———? => 23 1/3% 
Question 39 of 50
39. Question
If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
Correct
The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle = 1/2 * 24 * 10 = 120 cm^{2}Incorrect
The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle = 1/2 * 24 * 10 = 120 cm^{2} 
Question 40 of 50
40. Question
An engineering student has to secure 36% marks to pass. He gets 130 marks and fails by 14 marks. The maximum No. of marks obtained by him is?
Correct
130
14
——
361—— 144
100%——? => 400Incorrect
130
14
——
361—— 144
100%——? => 400 
Question 41 of 50
41. Question
Divide Rs.32000 in the ratio 3:5?
Correct
3/8 * 32000 = 12000
5/8 * 32000 = 20000Incorrect
3/8 * 32000 = 12000
5/8 * 32000 = 20000 
Question 42 of 50
42. Question
Which of the following fractions is the largest?
Correct
L.C.M of 8, 16, 40 and 80 = 80.
7/8 = 70/80; 13/16 = 65/80; 31/40 = 62/80
Since, 70/80 > 63/80 > 65/80 > 62/80,
So, 7/8 > 63/80 > 13/16 > 31/40
So, 7/8 is the largest.Incorrect
L.C.M of 8, 16, 40 and 80 = 80.
7/8 = 70/80; 13/16 = 65/80; 31/40 = 62/80
Since, 70/80 > 63/80 > 65/80 > 62/80,
So, 7/8 > 63/80 > 13/16 > 31/40
So, 7/8 is the largest. 
Question 43 of 50
43. Question
Solve the equation for x : 19(x + y) + 17 = 19(x + y) – 21
Correct
19x + 19y + 17 = 19x + 19y – 21
38x = 38 => x = 1Incorrect
19x + 19y + 17 = 19x + 19y – 21
38x = 38 => x = 1 
Question 44 of 50
44. Question
8 2/3 + 6 4/5 = ?
Correct
8 2/3 + 6 4/5 = (8 + 6) + (10/15 + 12/15) = 14 + 1 7/15 = 15 7/15
Incorrect
8 2/3 + 6 4/5 = (8 + 6) + (10/15 + 12/15) = 14 + 1 7/15 = 15 7/15

Question 45 of 50
45. Question
3251 + 587 + 369 – ? = 3007
Correct
Let 4207 – x = 3007
Then, x = 4207 – 3007 = 1200Incorrect
Let 4207 – x = 3007
Then, x = 4207 – 3007 = 1200 
Question 46 of 50
46. Question
A and B start a business jointly. A invests Rs.16000 for 8 months and B remains in the business for 4 months. Out of the total profit B claims 2/7th share. How much money is contributed by B?
Correct
16*8: x*4 = 5:2
x = 12.8 => Rs.12800Incorrect
16*8: x*4 = 5:2
x = 12.8 => Rs.12800 
Question 47 of 50
47. Question
The simple interest accrued on an amount Rs.10,000 at the end of two years is same as the compound interest on Rs.8,000 at the end of two years. The rate of interest is same in both the cases. What is the rate of interest?
Correct
Given that Rs.10,000 is invested in S.I for two years and Rs.8,000 in C.I for two years
=> C.I – S.I
=> 8,000 { [1 + r/100]^{2 } – 1} = (10,000)2r /100
=> 8{ 1 + 2r/100 + r^{2} / (100)^{2} – 1} = r/5
=> 16r/100 + 8r^{2}/(100)^{2} = 20r/100
=> 4r/10 = 8r^{2}/(100)^{2}
=> 8[r/100]^{2} – 4r/100 = 0
=> r/100 {8r/100 4} = 0
=> r = 0% of 50%
Since r!= 0%, r =50%Incorrect
Given that Rs.10,000 is invested in S.I for two years and Rs.8,000 in C.I for two years
=> C.I – S.I
=> 8,000 { [1 + r/100]^{2 } – 1} = (10,000)2r /100
=> 8{ 1 + 2r/100 + r^{2} / (100)^{2} – 1} = r/5
=> 16r/100 + 8r^{2}/(100)^{2} = 20r/100
=> 4r/10 = 8r^{2}/(100)^{2}
=> 8[r/100]^{2} – 4r/100 = 0
=> r/100 {8r/100 4} = 0
=> r = 0% of 50%
Since r!= 0%, r =50% 
Question 48 of 50
48. Question
The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 5 months, find for how much time did Q invest the money?
Correct
7*5: 5*x = 7:10
x = 10Incorrect
7*5: 5*x = 7:10
x = 10 
Question 49 of 50
49. Question
Simplify : (y^{4ba} . y^{4cb} . y^{4ac}) / (y^{a} . y^{b} . y^{c})^{3}
Correct
(y^{4ba} . y^{4cb} . y^{4ac}) / (y^{a} . y^{b} . y^{c})^{3}
= (y^{4ba} . y^{4cb} . y^{4ac}) / (y^{a+b+c})^{3}
= y^{4ba+4cb+4ac} / y^{3(a+b+c)}
= y^{3(a+b+c)} / y^{3(a+b+c)} = 1.Incorrect
(y^{4ba} . y^{4cb} . y^{4ac}) / (y^{a} . y^{b} . y^{c})^{3}
= (y^{4ba} . y^{4cb} . y^{4ac}) / (y^{a+b+c})^{3}
= y^{4ba+4cb+4ac} / y^{3(a+b+c)}
= y^{3(a+b+c)} / y^{3(a+b+c)} = 1. 
Question 50 of 50
50. Question
A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
Correct
100 — 10 DS = 10
? — 1
75 — 15 US = 5
? —– 1 S = (10 – 5)/2
= 2 2 ½ kmphIncorrect
100 — 10 DS = 10
? — 1
75 — 15 US = 5
? —– 1 S = (10 – 5)/2
= 2 2 ½ kmph