RRB JE Online Test, RRB JE Mock Test Series, RRB JE Online Exam
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RRB JE Online Test in English Series 1, RRB JE Free Online Test Series 1. RRB Exam Online Test 2021, RRB JE Mock Test Exam 2021. RRB JE Exam Free Online Quiz 2021, RRB JE Online Mock Test Series 1st in English. RRB Online Test for All Subjects, RRB JE Free Mock Test Series in English. RRB JE Free Mock Test Series 1. RRB JE English Language Online Test in English Series 1st. RRB JE Quantitative Aptitude Quiz 2021, RRB JE Reasoning Ability Free Online Test. Take RRB JE Online Quiz. The RRB JE Full online mock test paper is free for all students. RRB JE Question and Answers in English and Hindi Series 1. Here we are providing RRB JE Full Mock Test Paper in English. RRB JE Mock Test Series 1st 2021. Now Test your self for RRB JE Exam by using below quiz…
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Question 1 of 50
1. Question
An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?
Correct
HCF of 4956, 3894 = 354
(4956 – 3894)/354 = 3Incorrect
HCF of 4956, 3894 = 354
(4956 – 3894)/354 = 3 
Question 2 of 50
2. Question
A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 27, what is the total amount?
Correct
x:y:z = 100:45:30
20:9:6
9 — 27
35 — ? => 105Incorrect
x:y:z = 100:45:30
20:9:6
9 — 27
35 — ? => 105 
Question 3 of 50
3. Question
In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
Correct
When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.
In a race of 1000 m, A beats C by (1000 – 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 = 127.5 m.Incorrect
When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.
In a race of 1000 m, A beats C by (1000 – 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 = 127.5 m. 
Question 4 of 50
4. Question
The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?
Correct
P = 144(100/5)^{2} => P = 3600
Incorrect
P = 144(100/5)^{2} => P = 3600

Question 5 of 50
5. Question
The tens digit of a twodigit number is two more than its unit digit. The twodigit number is 7 times the sum of the digits. Find the units digits?
Correct
Let the twodigit number be 10a + b
a = b + 2 — (1)
10a + b = 7(a + b) => a = 2b
Substituting a = 2b in equation (1), we get
2b = b + 2 => b = 2
Hence the units digit is: 2.Incorrect
Let the twodigit number be 10a + b
a = b + 2 — (1)
10a + b = 7(a + b) => a = 2b
Substituting a = 2b in equation (1), we get
2b = b + 2 => b = 2
Hence the units digit is: 2. 
Question 6 of 50
6. Question
The surface of a cube is 24sq cm. Find its volume?
Correct
6a^{2} = 24
a = 2 => a^{3} = 8ccIncorrect
6a^{2} = 24
a = 2 => a^{3} = 8cc 
Question 7 of 50
7. Question
Three men start together to travel the same way around a circular track of 11 kilometers in circumference. Their speeds are 4, 5 and 8 kilometers per hour respectively. When will they meet at a starting point?
Correct
Time for one round = 11/4, 11/5, 11/8
LCM of 11/4, 11/5, 11/8 = 11/1 = 11Incorrect
Time for one round = 11/4, 11/5, 11/8
LCM of 11/4, 11/5, 11/8 = 11/1 = 11 
Question 8 of 50
8. Question
Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran’s share in the profit?
Correct
Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran’s share = 24500 * 3/7 = Rs. 10500Incorrect
Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran’s share = 24500 * 3/7 = Rs. 10500 
Question 9 of 50
9. Question
A person can row at 9 kmph and still water. He takes 4 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?
Correct
Let the distance between A and B be x km.
Total time = x/(9 + 1) + x/(9 – 1) = 4.5
=> x/10 + x/8 = 9/2 => (4x + 5x)/40 = 9/2 => x = 20 km.Incorrect
Let the distance between A and B be x km.
Total time = x/(9 + 1) + x/(9 – 1) = 4.5
=> x/10 + x/8 = 9/2 => (4x + 5x)/40 = 9/2 => x = 20 km. 
Question 10 of 50
10. Question
In how many ways can six members be selected from a group of ten members?
Correct
Six members can be selected from ten members in
¹⁰C₆ = ¹⁰C₄ ways.Incorrect
Six members can be selected from ten members in
¹⁰C₆ = ¹⁰C₄ ways. 
Question 11 of 50
11. Question
If the annual rate of simple interest increases from 10% to 12 1/2 %, a man’s yearly income increases by Rs. 1250. His principal in Rs. is?
Correct
Let the sum be Rs. x. Then,
(x * 25/2 * 1/100) – (x * 10 * 1)/100 = 1250
25x – 20x = 250000
x = 50000Incorrect
Let the sum be Rs. x. Then,
(x * 25/2 * 1/100) – (x * 10 * 1)/100 = 1250
25x – 20x = 250000
x = 50000 
Question 12 of 50
12. Question
Ram’s age and Shyam’s age are in the ratio 3:4. Seven years ago the ratio of their ages was 2:3. Find the ratio of their ages five years hence?
Correct
Let ages of Ramu and Shyam be x and y respectively.
x/y = 3/4 => x = 3/4 y
(x 7)/(y – 7) = 2/3
=> 3x – 21 = 2y – 14 => 3x = 2y + 7
But x = 3/4 y
3 * 3/4 y = 2y + 7
9y = 8y + 28 => y = 28years
=> x = 21 years
Ratio of their ages five years hence, (21 + 5)/(28 + 5) = 26/33.Incorrect
Let ages of Ramu and Shyam be x and y respectively.
x/y = 3/4 => x = 3/4 y
(x 7)/(y – 7) = 2/3
=> 3x – 21 = 2y – 14 => 3x = 2y + 7
But x = 3/4 y
3 * 3/4 y = 2y + 7
9y = 8y + 28 => y = 28years
=> x = 21 years
Ratio of their ages five years hence, (21 + 5)/(28 + 5) = 26/33. 
Question 13 of 50
13. Question
If the price of an article went up by 20%, then by what percent should it be brought down to bring it back to its original price?
Correct
Let the price of the article be Rs. 100.
20% of 100 = 20.
New price = 100 + 20 = Rs. 120
Required percentage = (120 – 100)/120 * 100
= 20/120 * 100 = 50/3 = 16 2/3%.Incorrect
Let the price of the article be Rs. 100.
20% of 100 = 20.
New price = 100 + 20 = Rs. 120
Required percentage = (120 – 100)/120 * 100
= 20/120 * 100 = 50/3 = 16 2/3%. 
Question 14 of 50
14. Question
The diagonals of a rhombus are 15 cm and 20 cm. Find its area?
Correct
1/2 * 15 * 20 = 150
Incorrect
1/2 * 15 * 20 = 150

Question 15 of 50
15. Question
Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 30% profit?
Correct
C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.
S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819.
S.P. per kg = 819/50 = Rs. 16.38 = 16.30.Incorrect
C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.
S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819.
S.P. per kg = 819/50 = Rs. 16.38 = 16.30. 
Question 16 of 50
16. Question
Find the 37.5% of 976 =
Correct
37.5 % of 976
= 37.5/100 * 976 = 375/1000 * 976 = 3/8 * 976
= 3 * 122 = 366.Incorrect
37.5 % of 976
= 37.5/100 * 976 = 375/1000 * 976 = 3/8 * 976
= 3 * 122 = 366. 
Question 17 of 50
17. Question
A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
Correct
Net part filled in 1 hour = (1/4 – 1/9) = 5/36
The cistern will be filled in 36/5 hrs i.e., 7.2 hrs.Incorrect
Net part filled in 1 hour = (1/4 – 1/9) = 5/36
The cistern will be filled in 36/5 hrs i.e., 7.2 hrs. 
Question 18 of 50
18. Question
On dividing number by 5, we get 3 as remainder. What will be the remainder when the square of this number is divided by 5?
Correct
Incorrect

Question 19 of 50
19. Question
The S.I. on a certain sum of money for 3 years at 8% per annum is half the C.I. on Rs. 4000 for 2 years at 10% per annum. The sum placed on S.I. is?
Correct
C.I. = [4000 * (1 + 10/100)^{2} – 4000]
= (4000 * 11/10 * 11/10 – 4000) = Rs. 840.
Sum = (420 * 100)/(3 * 8) = Rs. 1750Incorrect
C.I. = [4000 * (1 + 10/100)^{2} – 4000]
= (4000 * 11/10 * 11/10 – 4000) = Rs. 840.
Sum = (420 * 100)/(3 * 8) = Rs. 1750 
Question 20 of 50
20. Question
The average salary of workers in an industry is Rs.200 the average salary of technicians being Rs.400 and that of nontechnicians being Rs.125. What is the total number of workers?
Correct
Incorrect

Question 21 of 50
21. Question
In a hostel there were 100 students. To accommodate 20 more students the average is decreased by rupees 5. But total expenditure increased by Rs.400. Find the total expenditure of the hostel now?
Correct
100x + 400 = 12(x – 5)
x = 50
100 * 50 + 400 = 5400Incorrect
100x + 400 = 12(x – 5)
x = 50
100 * 50 + 400 = 5400 
Question 22 of 50
22. Question
What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?
Correct
L.C.M of 12, 18, 21, 30
= 2 * 3 * 2 * 3 * 7 * 5 = 1260
Required number = 1260/2 = 630.Incorrect
L.C.M of 12, 18, 21, 30
= 2 * 3 * 2 * 3 * 7 * 5 = 1260
Required number = 1260/2 = 630. 
Question 23 of 50
23. Question
The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?
Correct
Let the numerator and denominator of the fraction be ‘n’ and ‘d’ respectively.
d = 2n – 1
(n + 1)/(d + 1) = 3/5
5n + 5 = 3d + 3
5n + 5 = 3(2n – 1) + 3 => n = 5
d = 2n – 1 => d = 9
Hence the fraction is : 5/9.Incorrect
Let the numerator and denominator of the fraction be ‘n’ and ‘d’ respectively.
d = 2n – 1
(n + 1)/(d + 1) = 3/5
5n + 5 = 3d + 3
5n + 5 = 3(2n – 1) + 3 => n = 5
d = 2n – 1 => d = 9
Hence the fraction is : 5/9. 
Question 24 of 50
24. Question
Find the one which does not belong to that group ?
Correct
Part, Cart, Dart and Mart are rhyming words, but Trap does not sound similarly.
Incorrect
Part, Cart, Dart and Mart are rhyming words, but Trap does not sound similarly.

Question 25 of 50
25. Question
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in?
Correct
Net part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60
The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs.Incorrect
Net part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60
The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs. 
Question 26 of 50
26. Question
Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?
Correct
1/10 + 1/15 = 1/6 * 4 = 2/3
1 – 2/3 = 1/3
1/10 + 1/15 – 1/x = 1/3
x = 8Incorrect
1/10 + 1/15 = 1/6 * 4 = 2/3
1 – 2/3 = 1/3
1/10 + 1/15 – 1/x = 1/3
x = 8 
Question 27 of 50
27. Question
In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 5:6:2. If there are in all Rs.42, the number of 25 paisa coins is?
Correct
5x 6x 2x
50 25 100
250x + 150x + 200x = 4200
600x = 4200
x = 7 => 6x = 42Incorrect
5x 6x 2x
50 25 100
250x + 150x + 200x = 4200
600x = 4200
x = 7 => 6x = 42 
Question 28 of 50
28. Question
The average weight of 25 persons sitting in a boat had some value. A new person added to them whose weight was 46 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 25 persons?
Correct
25x + 46 = 26(x – 5)
x = 176Incorrect
25x + 46 = 26(x – 5)
x = 176 
Question 29 of 50
29. Question
[(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = ?
Correct
[(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = (63 + 24 + 3)/(36 + 9) = 90/45 = 2
Incorrect
[(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = (63 + 24 + 3)/(36 + 9) = 90/45 = 2

Question 30 of 50
30. Question
If a and b are the roots of the equation x^{2} – 9x + 20 = 0, find the value of a^{2} + b^{2} + ab?
Correct
a^{2} + b^{2} + ab = a^{2} + b^{2} + 2ab – ab
i.e., (a + b)^{2} – ab
from x^{2} – 9x + 20 = 0, we have
a + b = 9 and ab = 20. Hence the value of required expression (9)^{2} – 20 = 61.Incorrect
a^{2} + b^{2} + ab = a^{2} + b^{2} + 2ab – ab
i.e., (a + b)^{2} – ab
from x^{2} – 9x + 20 = 0, we have
a + b = 9 and ab = 20. Hence the value of required expression (9)^{2} – 20 = 61. 
Question 31 of 50
31. Question
Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction?
Correct
RS = 5 ¾ – 4 ½ = 1 ¼
T = 3 ½ h.
D = 5/4 * 7/2 = 35/8 = 4 3/8 kmIncorrect
RS = 5 ¾ – 4 ½ = 1 ¼
T = 3 ½ h.
D = 5/4 * 7/2 = 35/8 = 4 3/8 km 
Question 32 of 50
32. Question
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
Correct
Let 1 man’s 1 day work = x and 1 woman’s 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
1 woman’s 1 day work = (1/400 * 10) = 1/40.
Hence, 10 women will complete the work in 40 days.Incorrect
Let 1 man’s 1 day work = x and 1 woman’s 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
1 woman’s 1 day work = (1/400 * 10) = 1/40.
Hence, 10 women will complete the work in 40 days. 
Question 33 of 50
33. Question
On dividing 2272 as well as 875 by 3digit number N, we get the same remainder. The sum of the digits of N is:
Correct
Clearly, (2272 – 875) = 1397, is exactly divisible by N.
Now. 1397 = 11 * 127
The required 3digit number is 127, the sum of whose digit is 10.Incorrect
Clearly, (2272 – 875) = 1397, is exactly divisible by N.
Now. 1397 = 11 * 127
The required 3digit number is 127, the sum of whose digit is 10. 
Question 34 of 50
34. Question
A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangule, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?
Correct
The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm^{2}Incorrect
The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm^{2} 
Question 35 of 50
35. Question
Excluding stoppages, the speed of a bus is 54 km/hr and including stoppages, it is 45 km/hr. For how many minutes does the bus stop per hour?
Correct
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54 * 60 = 10 min.Incorrect
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54 * 60 = 10 min. 
Question 36 of 50
36. Question
A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws onethird of his capital. In what ratio should they share the profits at the end of the year?
Correct
A : B
(8000*4)+(4000*8) : (9000*6)+(6000*6)
64000 : 90000
32 : 45Incorrect
A : B
(8000*4)+(4000*8) : (9000*6)+(6000*6)
64000 : 90000
32 : 45 
Question 37 of 50
37. Question
A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
Correct
Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25) = 40 secondsIncorrect
Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25) = 40 seconds 
Question 38 of 50
38. Question
Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.5400. How much third person will get?
Correct
First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 54000 = 2400Incorrect
First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 54000 = 2400 
Question 39 of 50
39. Question
A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.75 less, he could have gained 25%. What is the cost price?
Correct
CP_{1} = 100 SP_{1} = 120
CP_{2} = 80 SP_{2} = 80 * (125/100) = 100
20 —– 100
75 —– ? => 375Incorrect
CP_{1} = 100 SP_{1} = 120
CP_{2} = 80 SP_{2} = 80 * (125/100) = 100
20 —– 100
75 —– ? => 375 
Question 40 of 50
40. Question
There are two numbers. If 40% of the first number is added to the second number, then the second number increases to its fivefourth. Find the ratio of the first number to the second number?
Correct
Let the two numbers be x and y.
40/100 * x + y = 5/4y
=> 2/5 x = 1/4 y => x/y = 5/8Incorrect
Let the two numbers be x and y.
40/100 * x + y = 5/4y
=> 2/5 x = 1/4 y => x/y = 5/8 
Question 41 of 50
41. Question
183.21 + 2.9928 * 66.84 = ?
Correct
? = 183.21 + 200 = 383
Incorrect
? = 183.21 + 200 = 383

Question 42 of 50
42. Question
The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).
Correct
Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm
= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm
= 180 cm – 1.71 cm = 178.29 cm.Incorrect
Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm
= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm
= 180 cm – 1.71 cm = 178.29 cm. 
Question 43 of 50
43. Question
Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?
Correct
x + y = 80
x – 4y = 5
x = 65 y = 15Incorrect
x + y = 80
x – 4y = 5
x = 65 y = 15 
Question 44 of 50
44. Question
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in?
Correct
Work done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.
Incorrect
Work done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.

Question 45 of 50
45. Question
A cistern which could be filled in 9 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it?
Correct
1/9 – 1/x = 1/10
=> 90 hrsIncorrect
1/9 – 1/x = 1/10
=> 90 hrs 
Question 46 of 50
46. Question
The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?
Correct
Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.
P + Q = 10 —– (1)
(10Q + P) – (10P + Q) = 54
9(Q – P) = 54
(Q – P) = 6 —– (2)
Solve (1) and (2) P = 2 and Q = 8
The required number is = 28Incorrect
Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.
P + Q = 10 —– (1)
(10Q + P) – (10P + Q) = 54
9(Q – P) = 54
(Q – P) = 6 —– (2)
Solve (1) and (2) P = 2 and Q = 8
The required number is = 28 
Question 47 of 50
47. Question
Oranges are bought at 11 for a rupee and an equal number more at 9 a rupee. If these are sold at 10 for a rupee, find the loss or gain percent?
Correct
Incorrect

Question 48 of 50
48. Question
The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is:
Correct
Let the numbers be 2x and 3x.
Then, their L.C.M = 6x. So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.Incorrect
Let the numbers be 2x and 3x.
Then, their L.C.M = 6x. So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40. 
Question 49 of 50
49. Question
Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet?
Correct
They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec.Incorrect
They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec. 
Question 50 of 50
50. Question
Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%?
Correct
(x*5*1)/100 + [(2500 – x)*6*1]/100 = 140
X = 1000Incorrect
(x*5*1)/100 + [(2500 – x)*6*1]/100 = 140
X = 1000