# RRB JE Online Test 2020, RRB JE Mock Test, RRB JE MCQ 2020

## RRB JE Online Test, RRB JE Mock Test Series, RRB JE Online Exam

#### Finish Quiz

0 of 50 questions completed

Questions:

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50

#### Information

RRB JE Online Test in English Series 1, RRB JE Free Online Test Series 1. RRB Exam Online Test 2020, **RRB JE Mock Test** Exam 2020. RRB JE Exam Free Online Quiz 2020, RRB JE Online Mock Test **Series 1st** in English. RRB Online Test for All Subjects, RRB JE Free Mock Test Series in English. RRB JE Free Mock Test **Series 1.** RRB JE English Language Online Test in English **Series 1st**. RRB JE Quantitative Aptitude Quiz 2020, RRB JE Reasoning Ability Free Online Test. Take RRB JE Online Quiz. The RRB JE Full online mock test paper is free for all students. RRB JE Question and Answers in English and Hindi **Series 1**. Here we are providing** RRB JE Full Mock Test Paper in English. RRB JE **Mock Test **Series 1st** 2020. Now Test your self for RRB JE Exam by using below quiz…

This paper has** 50 questions**.

Time allowed is **50 minutes**.

The **RRB JE Online Test Series 1st, RRB JE Free Online Test Exam** is Very helpful for all students. Now Scroll down below n click on **“Start Quiz” or “Start Test” **and Test yourself.

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

#### Results

0 of 50 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

Average score | |

Your score |

#### Categories

- Not categorized 0%

Pos. | Name | Entered on | Points | Result |
---|---|---|---|---|

Table is loading | ||||

No data available | ||||

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50

- Answered
- Review

- Question 1 of 50
##### 1. Question

An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?

CorrectHCF of 4956, 3894 = 354

(4956 – 3894)/354 = 3IncorrectHCF of 4956, 3894 = 354

(4956 – 3894)/354 = 3 - Question 2 of 50
##### 2. Question

A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 27, what is the total amount?

Correctx:y:z = 100:45:30

20:9:6

9 — 27

35 — ? => 105Incorrectx:y:z = 100:45:30

20:9:6

9 — 27

35 — ? => 105 - Question 3 of 50
##### 3. Question

In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?

CorrectWhen A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.

When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.

In a race of 1000 m, A beats C by (1000 – 787.5) = 212.5 m to C.

In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 = 127.5 m.IncorrectWhen A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.

When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.

In a race of 1000 m, A beats C by (1000 – 787.5) = 212.5 m to C.

In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 = 127.5 m. - Question 4 of 50
##### 4. Question

The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?

CorrectP = 144(100/5)

^{2}=> P = 3600IncorrectP = 144(100/5)

^{2}=> P = 3600 - Question 5 of 50
##### 5. Question

The tens digit of a two-digit number is two more than its unit digit. The two-digit number is 7 times the sum of the digits. Find the units digits?

CorrectLet the two-digit number be 10a + b

a = b + 2 — (1)

10a + b = 7(a + b) => a = 2b

Substituting a = 2b in equation (1), we get

2b = b + 2 => b = 2

Hence the units digit is: 2.IncorrectLet the two-digit number be 10a + b

a = b + 2 — (1)

10a + b = 7(a + b) => a = 2b

Substituting a = 2b in equation (1), we get

2b = b + 2 => b = 2

Hence the units digit is: 2. - Question 6 of 50
##### 6. Question

The surface of a cube is 24sq cm. Find its volume?

Correct6a

^{2}= 24

a = 2 => a^{3}= 8ccIncorrect6a

^{2}= 24

a = 2 => a^{3}= 8cc - Question 7 of 50
##### 7. Question

Three men start together to travel the same way around a circular track of 11 kilometers in circumference. Their speeds are 4, 5 and 8 kilometers per hour respectively. When will they meet at a starting point?

CorrectTime for one round = 11/4, 11/5, 11/8

LCM of 11/4, 11/5, 11/8 = 11/1 = 11IncorrectTime for one round = 11/4, 11/5, 11/8

LCM of 11/4, 11/5, 11/8 = 11/1 = 11 - Question 8 of 50
##### 8. Question

Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran’s share in the profit?

CorrectSimran : Nanda = (50000 * 36) : (80000 * 30) = 3:4

Simran’s share = 24500 * 3/7 = Rs. 10500IncorrectSimran : Nanda = (50000 * 36) : (80000 * 30) = 3:4

Simran’s share = 24500 * 3/7 = Rs. 10500 - Question 9 of 50
##### 9. Question

A person can row at 9 kmph and still water. He takes 4 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?

CorrectLet the distance between A and B be x km.

Total time = x/(9 + 1) + x/(9 – 1) = 4.5

=> x/10 + x/8 = 9/2 => (4x + 5x)/40 = 9/2 => x = 20 km.IncorrectLet the distance between A and B be x km.

Total time = x/(9 + 1) + x/(9 – 1) = 4.5

=> x/10 + x/8 = 9/2 => (4x + 5x)/40 = 9/2 => x = 20 km. - Question 10 of 50
##### 10. Question

In how many ways can six members be selected from a group of ten members?

CorrectSix members can be selected from ten members in

¹⁰C₆ = ¹⁰C₄ ways.IncorrectSix members can be selected from ten members in

¹⁰C₆ = ¹⁰C₄ ways. - Question 11 of 50
##### 11. Question

If the annual rate of simple interest increases from 10% to 12 1/2 %, a man’s yearly income increases by Rs. 1250. His principal in Rs. is?

CorrectLet the sum be Rs. x. Then,

(x * 25/2 * 1/100) – (x * 10 * 1)/100 = 1250

25x – 20x = 250000

x = 50000IncorrectLet the sum be Rs. x. Then,

(x * 25/2 * 1/100) – (x * 10 * 1)/100 = 1250

25x – 20x = 250000

x = 50000 - Question 12 of 50
##### 12. Question

Ram’s age and Shyam’s age are in the ratio 3:4. Seven years ago the ratio of their ages was 2:3. Find the ratio of their ages five years hence?

CorrectLet ages of Ramu and Shyam be x and y respectively.

x/y = 3/4 => x = 3/4 y

(x- 7)/(y – 7) = 2/3

=> 3x – 21 = 2y – 14 => 3x = 2y + 7

But x = 3/4 y

3 * 3/4 y = 2y + 7

9y = 8y + 28 => y = 28years

=> x = 21 years

Ratio of their ages five years hence, (21 + 5)/(28 + 5) = 26/33.IncorrectLet ages of Ramu and Shyam be x and y respectively.

x/y = 3/4 => x = 3/4 y

(x- 7)/(y – 7) = 2/3

=> 3x – 21 = 2y – 14 => 3x = 2y + 7

But x = 3/4 y

3 * 3/4 y = 2y + 7

9y = 8y + 28 => y = 28years

=> x = 21 years

Ratio of their ages five years hence, (21 + 5)/(28 + 5) = 26/33. - Question 13 of 50
##### 13. Question

If the price of an article went up by 20%, then by what percent should it be brought down to bring it back to its original price?

CorrectLet the price of the article be Rs. 100.

20% of 100 = 20.

New price = 100 + 20 = Rs. 120

Required percentage = (120 – 100)/120 * 100

= 20/120 * 100 = 50/3 = 16 2/3%.IncorrectLet the price of the article be Rs. 100.

20% of 100 = 20.

New price = 100 + 20 = Rs. 120

Required percentage = (120 – 100)/120 * 100

= 20/120 * 100 = 50/3 = 16 2/3%. - Question 14 of 50
##### 14. Question

The diagonals of a rhombus are 15 cm and 20 cm. Find its area?

Correct1/2 * 15 * 20 = 150

Incorrect1/2 * 15 * 20 = 150

- Question 15 of 50
##### 15. Question

Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 30% profit?

CorrectC.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.

S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819.

S.P. per kg = 819/50 = Rs. 16.38 = 16.30.IncorrectC.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.

S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819.

S.P. per kg = 819/50 = Rs. 16.38 = 16.30. - Question 16 of 50
##### 16. Question

Find the 37.5% of 976 =

Correct37.5 % of 976

= 37.5/100 * 976 = 375/1000 * 976 = 3/8 * 976

= 3 * 122 = 366.Incorrect37.5 % of 976

= 37.5/100 * 976 = 375/1000 * 976 = 3/8 * 976

= 3 * 122 = 366. - Question 17 of 50
##### 17. Question

A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?

CorrectNet part filled in 1 hour = (1/4 – 1/9) = 5/36

The cistern will be filled in 36/5 hrs i.e., 7.2 hrs.IncorrectNet part filled in 1 hour = (1/4 – 1/9) = 5/36

The cistern will be filled in 36/5 hrs i.e., 7.2 hrs. - Question 18 of 50
##### 18. Question

On dividing number by 5, we get 3 as remainder. What will be the remainder when the square of this number is divided by 5?

CorrectIncorrect - Question 19 of 50
##### 19. Question

The S.I. on a certain sum of money for 3 years at 8% per annum is half the C.I. on Rs. 4000 for 2 years at 10% per annum. The sum placed on S.I. is?

CorrectC.I. = [4000 * (1 + 10/100)

^{2}– 4000]

= (4000 * 11/10 * 11/10 – 4000) = Rs. 840.

Sum = (420 * 100)/(3 * 8) = Rs. 1750IncorrectC.I. = [4000 * (1 + 10/100)

^{2}– 4000]

= (4000 * 11/10 * 11/10 – 4000) = Rs. 840.

Sum = (420 * 100)/(3 * 8) = Rs. 1750 - Question 20 of 50
##### 20. Question

The average salary of workers in an industry is Rs.200 the average salary of technicians being Rs.400 and that of non-technicians being Rs.125. What is the total number of workers?

CorrectIncorrect - Question 21 of 50
##### 21. Question

In a hostel there were 100 students. To accommodate 20 more students the average is decreased by rupees 5. But total expenditure increased by Rs.400. Find the total expenditure of the hostel now?

Correct100x + 400 = 12(x – 5)

x = 50

100 * 50 + 400 = 5400Incorrect100x + 400 = 12(x – 5)

x = 50

100 * 50 + 400 = 5400 - Question 22 of 50
##### 22. Question

What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?

CorrectL.C.M of 12, 18, 21, 30

= 2 * 3 * 2 * 3 * 7 * 5 = 1260

Required number = 1260/2 = 630.IncorrectL.C.M of 12, 18, 21, 30

= 2 * 3 * 2 * 3 * 7 * 5 = 1260

Required number = 1260/2 = 630. - Question 23 of 50
##### 23. Question

The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?

CorrectLet the numerator and denominator of the fraction be ‘n’ and ‘d’ respectively.

d = 2n – 1

(n + 1)/(d + 1) = 3/5

5n + 5 = 3d + 3

5n + 5 = 3(2n – 1) + 3 => n = 5

d = 2n – 1 => d = 9

Hence the fraction is : 5/9.IncorrectLet the numerator and denominator of the fraction be ‘n’ and ‘d’ respectively.

d = 2n – 1

(n + 1)/(d + 1) = 3/5

5n + 5 = 3d + 3

5n + 5 = 3(2n – 1) + 3 => n = 5

d = 2n – 1 => d = 9

Hence the fraction is : 5/9. - Question 24 of 50
##### 24. Question

Find the one which does not belong to that group ?

CorrectPart, Cart, Dart and Mart are rhyming words, but Trap does not sound similarly.

IncorrectPart, Cart, Dart and Mart are rhyming words, but Trap does not sound similarly.

- Question 25 of 50
##### 25. Question

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in?

CorrectNet part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60

The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs.IncorrectNet part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60

The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs. - Question 26 of 50
##### 26. Question

Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?

Correct1/10 + 1/15 = 1/6 * 4 = 2/3

1 – 2/3 = 1/3

1/10 + 1/15 – 1/x = 1/3

x = 8Incorrect1/10 + 1/15 = 1/6 * 4 = 2/3

1 – 2/3 = 1/3

1/10 + 1/15 – 1/x = 1/3

x = 8 - Question 27 of 50
##### 27. Question

In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 5:6:2. If there are in all Rs.42, the number of 25 paisa coins is?

Correct5x 6x 2x

50 25 100

250x + 150x + 200x = 4200

600x = 4200

x = 7 => 6x = 42Incorrect5x 6x 2x

50 25 100

250x + 150x + 200x = 4200

600x = 4200

x = 7 => 6x = 42 - Question 28 of 50
##### 28. Question

The average weight of 25 persons sitting in a boat had some value. A new person added to them whose weight was 46 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 25 persons?

Correct25x + 46 = 26(x – 5)

x = 176Incorrect25x + 46 = 26(x – 5)

x = 176 - Question 29 of 50
##### 29. Question

[(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = ?

Correct[(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = (63 + 24 + 3)/(36 + 9) = 90/45 = 2

Incorrect[(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = (63 + 24 + 3)/(36 + 9) = 90/45 = 2

- Question 30 of 50
##### 30. Question

If a and b are the roots of the equation x

^{2}– 9x + 20 = 0, find the value of a^{2}+ b^{2}+ ab?Correcta

^{2}+ b^{2}+ ab = a^{2}+ b^{2}+ 2ab – ab

i.e., (a + b)^{2}– ab

from x^{2}– 9x + 20 = 0, we have

a + b = 9 and ab = 20. Hence the value of required expression (9)^{2}– 20 = 61.Incorrecta

^{2}+ b^{2}+ ab = a^{2}+ b^{2}+ 2ab – ab

i.e., (a + b)^{2}– ab

from x^{2}– 9x + 20 = 0, we have

a + b = 9 and ab = 20. Hence the value of required expression (9)^{2}– 20 = 61. - Question 31 of 50
##### 31. Question

Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction?

CorrectRS = 5 ¾ – 4 ½ = 1 ¼

T = 3 ½ h.

D = 5/4 * 7/2 = 35/8 = 4 3/8 kmIncorrectRS = 5 ¾ – 4 ½ = 1 ¼

T = 3 ½ h.

D = 5/4 * 7/2 = 35/8 = 4 3/8 km - Question 32 of 50
##### 32. Question

4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?

CorrectLet 1 man’s 1 day work = x and 1 woman’s 1 day work = y.

Then, 4x + 6y = 1/8 and 3x + 7y = 1/10

Solving these two equations, we get:

x = 11/400 and y = 1/400

1 woman’s 1 day work = (1/400 * 10) = 1/40.

Hence, 10 women will complete the work in 40 days.IncorrectLet 1 man’s 1 day work = x and 1 woman’s 1 day work = y.

Then, 4x + 6y = 1/8 and 3x + 7y = 1/10

Solving these two equations, we get:

x = 11/400 and y = 1/400

1 woman’s 1 day work = (1/400 * 10) = 1/40.

Hence, 10 women will complete the work in 40 days. - Question 33 of 50
##### 33. Question

On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:

CorrectClearly, (2272 – 875) = 1397, is exactly divisible by N.

Now. 1397 = 11 * 127

The required 3-digit number is 127, the sum of whose digit is 10.IncorrectClearly, (2272 – 875) = 1397, is exactly divisible by N.

Now. 1397 = 11 * 127

The required 3-digit number is 127, the sum of whose digit is 10. - Question 34 of 50
##### 34. Question

A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangule, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?

CorrectThe circumference of the circle is equal to the permeter of the rectangle.

Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5

=> x = 1

Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm^{2}IncorrectThe circumference of the circle is equal to the permeter of the rectangle.

Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5

=> x = 1

Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm^{2} - Question 35 of 50
##### 35. Question

Excluding stoppages, the speed of a bus is 54 km/hr and including stoppages, it is 45 km/hr. For how many minutes does the bus stop per hour?

CorrectDue to stoppages, it covers 9 km less.

Time taken to cover 9 km = 9/54 * 60 = 10 min.IncorrectDue to stoppages, it covers 9 km less.

Time taken to cover 9 km = 9/54 * 60 = 10 min. - Question 36 of 50
##### 36. Question

A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?

CorrectA : B

(8000*4)+(4000*8) : (9000*6)+(6000*6)

64000 : 90000

32 : 45IncorrectA : B

(8000*4)+(4000*8) : (9000*6)+(6000*6)

64000 : 90000

32 : 45 - Question 37 of 50
##### 37. Question

A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?

CorrectSpeed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec

Total distance = 360+140 = 500 meter

Time = Distance/speed

= 500 * (2/25) = 40 secondsIncorrectSpeed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec

Total distance = 360+140 = 500 meter

Time = Distance/speed

= 500 * (2/25) = 40 seconds - Question 38 of 50
##### 38. Question

Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.5400. How much third person will get?

CorrectFirst persons investment = x

Second persons investment = x + 1000

Third persons investments = x + 2000

x + x + 1000 + x + 2000 = 9000

3x = 6000

x = 2000

Ratio = 2000 : 3000 : 4000

2:3:4

4/9 * 54000 = 2400IncorrectFirst persons investment = x

Second persons investment = x + 1000

Third persons investments = x + 2000

x + x + 1000 + x + 2000 = 9000

3x = 6000

x = 2000

Ratio = 2000 : 3000 : 4000

2:3:4

4/9 * 54000 = 2400 - Question 39 of 50
##### 39. Question

A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.75 less, he could have gained 25%. What is the cost price?

CorrectCP

_{1}= 100 SP_{1}= 120

CP_{2}= 80 SP_{2}= 80 * (125/100) = 100

20 —– 100

75 —– ? => 375IncorrectCP

_{1}= 100 SP_{1}= 120

CP_{2}= 80 SP_{2}= 80 * (125/100) = 100

20 —– 100

75 —– ? => 375 - Question 40 of 50
##### 40. Question

There are two numbers. If 40% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?

CorrectLet the two numbers be x and y.

40/100 * x + y = 5/4y

=> 2/5 x = 1/4 y => x/y = 5/8IncorrectLet the two numbers be x and y.

40/100 * x + y = 5/4y

=> 2/5 x = 1/4 y => x/y = 5/8 - Question 41 of 50
##### 41. Question

183.21 + 2.9928 * 66.84 = ?

Correct? = 183.21 + 200 = 383

Incorrect? = 183.21 + 200 = 383

- Question 42 of 50
##### 42. Question

The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).

CorrectCalculated average height of 35 boys = 180 cm.

Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm

= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm

= 180 cm – 1.71 cm = 178.29 cm.IncorrectCalculated average height of 35 boys = 180 cm.

Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm

= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm

= 180 cm – 1.71 cm = 178.29 cm. - Question 43 of 50
##### 43. Question

Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?

Correctx + y = 80

x – 4y = 5

x = 65 y = 15Incorrectx + y = 80

x – 4y = 5

x = 65 y = 15 - Question 44 of 50
##### 44. Question

A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in?

CorrectWork done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.

IncorrectWork done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.

- Question 45 of 50
##### 45. Question

A cistern which could be filled in 9 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it?

Correct1/9 – 1/x = 1/10

=> 90 hrsIncorrect1/9 – 1/x = 1/10

=> 90 hrs - Question 46 of 50
##### 46. Question

The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?

CorrectAny two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.

P + Q = 10 —– (1)

(10Q + P) – (10P + Q) = 54

9(Q – P) = 54

(Q – P) = 6 —– (2)

Solve (1) and (2) P = 2 and Q = 8

The required number is = 28IncorrectAny two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.

P + Q = 10 —– (1)

(10Q + P) – (10P + Q) = 54

9(Q – P) = 54

(Q – P) = 6 —– (2)

Solve (1) and (2) P = 2 and Q = 8

The required number is = 28 - Question 47 of 50
##### 47. Question

Oranges are bought at 11 for a rupee and an equal number more at 9 a rupee. If these are sold at 10 for a rupee, find the loss or gain percent?

CorrectIncorrect - Question 48 of 50
##### 48. Question

The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is:

CorrectLet the numbers be 2x and 3x.

Then, their L.C.M = 6x. So, 6x = 48 or x = 8.

The numbers are 16 and 24.

Hence, required sum = (16 + 24) = 40.IncorrectLet the numbers be 2x and 3x.

Then, their L.C.M = 6x. So, 6x = 48 or x = 8.

The numbers are 16 and 24.

Hence, required sum = (16 + 24) = 40. - Question 49 of 50
##### 49. Question

Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet?

CorrectThey are moving in opposite directions, relative speed is equal to the sum of their speeds.

Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.

The time required = d/s = 100/35 = 20/7 sec.IncorrectThey are moving in opposite directions, relative speed is equal to the sum of their speeds.

Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.

The time required = d/s = 100/35 = 20/7 sec. - Question 50 of 50
##### 50. Question

Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%?

Correct(x*5*1)/100 + [(2500 – x)*6*1]/100 = 140

X = 1000Incorrect(x*5*1)/100 + [(2500 – x)*6*1]/100 = 140

X = 1000