RRB NTPC Online Test 2021, RRB NTPC Mock Test, NTPC MCQ
RRB NTPC Online Test in English Series 2, RRB NTPC Mock Test
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RRB NTPC Online Test in English – Series 2, RRB NTPC Free Online Test Series 2. RRB Exam Online Test 2021, RRB NTPC Free Mock Test Exam 2021.RRB NTPC Full Online Mock Test Series 1st in English, RRB NTPC Full Online Mock Test Series 2nd in English. RRB Online Test for All Subjects, RRB NTPC Free Mock Test Series in English. RRB NTPC Free Mock Test Series 2. RRB NTPC English Language Online Test in English Series 2nd. RRB NTPC Quantitative Aptitude Quiz 2021, RRB NTPC Reasoning Ability Free Online Test. Take RRB NTPC Online Quiz. The RRB NTPC Full online mock test paper is free for all students. RRB NTPC Question and Answers in English and Hindi Series 2. Here we are providing RRB NTPC Full Mock Test Paper in English. RRB NTPC Mock Test Series 2nd 2021. Now Test your self for RRB NTPC Exam by using below quiz…
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 Answered
 Review

Question 1 of 50
1. Question
Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled?
Correct
Part filled by A + B + C in 1 hour = 1/5 + 1/10 + 1/30 = 1/3
All the three pipes together will fill the tank in 3 hours.Incorrect
Part filled by A + B + C in 1 hour = 1/5 + 1/10 + 1/30 = 1/3
All the three pipes together will fill the tank in 3 hours. 
Question 2 of 50
2. Question
A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?
Correct
40*(40/100) = 16 — 64
? — 12 => Rs.3Incorrect
40*(40/100) = 16 — 64
? — 12 => Rs.3 
Question 3 of 50
3. Question
The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
Correct
2C + 3T = 1300 — (1)
3C + 3T = 1200 — (2)
Subtracting 2nd from 1st, we get
C + T = 100 => T – C = 100Incorrect
2C + 3T = 1300 — (1)
3C + 3T = 1200 — (2)
Subtracting 2nd from 1st, we get
C + T = 100 => T – C = 100 
Question 4 of 50
4. Question
If 15% of 30% of 50% of a number is 90, then what is the number?
Correct
Let the number be a
Given, 15/100 * 30/100 * 50/100 * a = 90
=> 3/20 * 3/10 * 1/2 * a = 90
=> a = 10 * 20 * 10 * 2 = 4000.Incorrect
Let the number be a
Given, 15/100 * 30/100 * 50/100 * a = 90
=> 3/20 * 3/10 * 1/2 * a = 90
=> a = 10 * 20 * 10 * 2 = 4000. 
Question 5 of 50
5. Question
A sum of money becomes 7/6 of itself in 3 years at a certain rate of simple interest. The rate per annum is?
Correct
Let sum = x. Then, amount = 7x/6
S.I. = 7x/6 – x = x/6; Time = 3 years.
Rate = (100 * x) / (x * 6 * 3) = 5 5/9 %.Incorrect
Let sum = x. Then, amount = 7x/6
S.I. = 7x/6 – x = x/6; Time = 3 years.
Rate = (100 * x) / (x * 6 * 3) = 5 5/9 %. 
Question 6 of 50
6. Question
15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men?
Correct
3W = 2M
15M —— 21 * 8 hours
21 W —— x * 6 hours
14 M —— x * 6
15 * 21 * 8 = 14 * x * 6
x = 30Incorrect
3W = 2M
15M —— 21 * 8 hours
21 W —— x * 6 hours
14 M —— x * 6
15 * 21 * 8 = 14 * x * 6
x = 30 
Question 7 of 50
7. Question
In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?
Correct
A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (100 – 75) = 25 points to C.Incorrect
A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (100 – 75) = 25 points to C. 
Question 8 of 50
8. Question
A man buys two articles for Rs.1980 each and he gains 10% on the first and loses 10% on the next. Find his total gain or loss percent?
Correct
Incorrect

Question 9 of 50
9. Question
40% of a number is more than 20% of 650 by 190. Find the number?
Correct
(40/100) * X – (20/100) * 650 = 190
2/5 X = 320
X = 800Incorrect
(40/100) * X – (20/100) * 650 = 190
2/5 X = 320
X = 800 
Question 10 of 50
10. Question
Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 48 years. What will be the age of the B ten years hence?
Correct
Let the present ages of A, B and C be a, b and c respectively.
Given, [(a – 5) + (b – 5)] / 2 = 40 => a + b = 90 — (1)
(b + c)/2 = 48 => b + c = 96 — (2)
From (1) and (2), we cannot find b.Incorrect
Let the present ages of A, B and C be a, b and c respectively.
Given, [(a – 5) + (b – 5)] / 2 = 40 => a + b = 90 — (1)
(b + c)/2 = 48 => b + c = 96 — (2)
From (1) and (2), we cannot find b. 
Question 11 of 50
11. Question
In an exam, a candidate secured 504 marks our of the maximum mark of M. If the maximum mark M is converted into 800 marks, he would have secured 384 marks. What is the value of M?
Correct
504/M = 384/800
(504 * 800) / 384 = M
M = 1050Incorrect
504/M = 384/800
(504 * 800) / 384 = M
M = 1050 
Question 12 of 50
12. Question
Present ages of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. What is X’s present age in years?
Correct
Let the present ages of X and Y be 5x and 6x years respectively.
Then, (5x + 7)/(6x + 7) = 6/7
7(5x + 7) = 6(6x + 7) => x = 7
X’s present age = 5x = 35 years.Incorrect
Let the present ages of X and Y be 5x and 6x years respectively.
Then, (5x + 7)/(6x + 7) = 6/7
7(5x + 7) = 6(6x + 7) => x = 7
X’s present age = 5x = 35 years. 
Question 13 of 50
13. Question
An article was sold after a discount of 20% and there was a gain of 20%. If the profit made on it was Rs. 6 less than the discount offered on it, find its selling price?
Correct
Let CP = Rs. 100x
SP = Rs. 120x
MP = 120x/80 * 100 = Rs. 150x
D = Rs. 150x – Rs. 120x = Rs. 30x
D – P = 30x – 20x = Rs. 6, 10x = Rs. 6
120x = 120/10 * 6 = Rs. 72Incorrect
Let CP = Rs. 100x
SP = Rs. 120x
MP = 120x/80 * 100 = Rs. 150x
D = Rs. 150x – Rs. 120x = Rs. 30x
D – P = 30x – 20x = Rs. 6, 10x = Rs. 6
120x = 120/10 * 6 = Rs. 72 
Question 14 of 50
14. Question
Roja and Pooja start moving in the opposite directions from a pole. They are moving at the speeds of 2 km/hr and 3 km/hr respectively. After 4 hours what will be the distance between them?
Correct
Distance = Relative Speed * Time
= (2 + 3) * 4 = 20 km
[ They are travelling in the opposite direction, relative speed = sum of the speeds].Incorrect
Distance = Relative Speed * Time
= (2 + 3) * 4 = 20 km
[ They are travelling in the opposite direction, relative speed = sum of the speeds]. 
Question 15 of 50
15. Question
The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?
Correct
Total members in the group = 7
Average amount = Rs. 20
Total amount with them = 7 * 20 = Rs. 140
One number has Rs. 50. So, the amount with remaining 6 people = 140 – 50 = Rs. 90
The average amount with them = 90/6 = Rs. 15.Incorrect
Total members in the group = 7
Average amount = Rs. 20
Total amount with them = 7 * 20 = Rs. 140
One number has Rs. 50. So, the amount with remaining 6 people = 140 – 50 = Rs. 90
The average amount with them = 90/6 = Rs. 15. 
Question 16 of 50
16. Question
Find the one which does not belong to that group ?
Correct
The digits on either side of the letter in each of the groups 1P6, 2T0, 1M3 and 1R8 indicate the place value of the letter in the alphabet.
This pattern is not followed by 2Y4.Incorrect
The digits on either side of the letter in each of the groups 1P6, 2T0, 1M3 and 1R8 indicate the place value of the letter in the alphabet.
This pattern is not followed by 2Y4. 
Question 17 of 50
17. Question
A brick measures 20 cm * 10 cm * 7.5 cm how many bricks will be required for a wall 25 m * 2 m * 0.75 m?
Correct
25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x
25 = 1/100 * x => x = 25000Incorrect
25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x
25 = 1/100 * x => x = 25000 
Question 18 of 50
18. Question
(112 * 5^{4}) = ?
Correct
(112 * 5^{4}) = 112 * (10/2)^{4}
= (112 * 10^{4})/24 = 1120000/16 = 70000Incorrect
(112 * 5^{4}) = 112 * (10/2)^{4}
= (112 * 10^{4})/24 = 1120000/16 = 70000 
Question 19 of 50
19. Question
In what time a sum of money double itself at 3% per annum simple interest?
Correct
P = (P*3*R)/100
R = 33 1/3%Incorrect
P = (P*3*R)/100
R = 33 1/3% 
Question 20 of 50
20. Question
HCF of 3/16, 5/12, 7/8 is:
Correct
HCF of numerators = 1
LCM of denominators = 48
=> 1/48Incorrect
HCF of numerators = 1
LCM of denominators = 48
=> 1/48 
Question 21 of 50
21. Question
A money lender lends Rs.2000 for six months at 20% p.a. rate. It the interest is reckoned quarterly than find the amount given after time limit.
Correct
A = 2000(21/20)^{2} = 2205
Incorrect
A = 2000(21/20)^{2} = 2205

Question 22 of 50
22. Question
In a class there are 20 boys and 25 girls. In how many ways can a boy and a girl be selected?
Correct
We can select one boy from 20 boys in 20 ways.
We select one girl from 25 girls in 25 ways
We select a boy and girl in 20 * 25 ways i.e., = 500 ways.Incorrect
We can select one boy from 20 boys in 20 ways.
We select one girl from 25 girls in 25 ways
We select a boy and girl in 20 * 25 ways i.e., = 500 ways. 
Question 23 of 50
23. Question
A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?
Correct
HCF of 1189, 1073 = 29
1073/29 = 37Incorrect
HCF of 1189, 1073 = 29
1073/29 = 37 
Question 24 of 50
24. Question
A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?
Correct
6300:4200:10500
3:2:5
3/10 * 12100 = 3630Incorrect
6300:4200:10500
3:2:5
3/10 * 12100 = 3630 
Question 25 of 50
25. Question
If the price of an article went up by 20%, then by what percent should it be brought down to bring it back to its original price?
Correct
Let the price of the article be Rs. 100.
20% of 100 = 20.
New price = 100 + 20 = Rs. 120
Required percentage = (120 – 100)/120 * 100
= 20/120 * 100 = 50/3 = 16 2/3%.Incorrect
Let the price of the article be Rs. 100.
20% of 100 = 20.
New price = 100 + 20 = Rs. 120
Required percentage = (120 – 100)/120 * 100
= 20/120 * 100 = 50/3 = 16 2/3%. 
Question 26 of 50
26. Question
A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2662 in 3 years. Find the rate percent?
Correct
2420 — 242
100 — ? => 10%Incorrect
2420 — 242
100 — ? => 10% 
Question 27 of 50
27. Question
A train 400 m long can cross an electric pole in 20 sec and then find the speed of the train?
Correct
Length = Speed * time
Speed = L/T
S = 400/20
S = 20 M/Sec
Speed= 20*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 72 KmphIncorrect
Length = Speed * time
Speed = L/T
S = 400/20
S = 20 M/Sec
Speed= 20*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 72 Kmph 
Question 28 of 50
28. Question
Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern?
Correct
Work done by the third pipe in 1 min = 1/50 – (1/60 + 1/75) = – 1/100.
[ve sign means emptying]
The third pipe alone can empty the cistern in 100 min.Incorrect
Work done by the third pipe in 1 min = 1/50 – (1/60 + 1/75) = – 1/100.
[ve sign means emptying]
The third pipe alone can empty the cistern in 100 min. 
Question 29 of 50
29. Question
The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
Correct
2(3x + x) = 96
l = 36 b = 12
lb = 36 * 12 = 432Incorrect
2(3x + x) = 96
l = 36 b = 12
lb = 36 * 12 = 432 
Question 30 of 50
30. Question
Kim can do a work in 3 days while David can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Kim?
Correct
Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60Incorrect
Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60 
Question 31 of 50
31. Question
(56^{2} – 24^{2}) * 1/32 + ?% of 1200 = 146
Correct
(56^{2} – 24^{2}) * 1/32 + ?% of 1200 = 146
=> (3136 – 576) * 1/32 + ?/32 of 1200 = 146
=> 2560/32 + ? * 12 = 146 => ? * 12 = 146 – 80
=> ? = 66/12 => 5 1/2Incorrect
(56^{2} – 24^{2}) * 1/32 + ?% of 1200 = 146
=> (3136 – 576) * 1/32 + ?/32 of 1200 = 146
=> 2560/32 + ? * 12 = 146 => ? * 12 = 146 – 80
=> ? = 66/12 => 5 1/2 
Question 32 of 50
32. Question
Surface area of two spheres are in the ratio 1:4 what is the ratio of their volumes?
Correct
Incorrect

Question 33 of 50
33. Question
The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction?
Correct
The denominator be P, the numerator will be (P – 8).
The fraction will be (P – 8)/P.
Adding 3 to the numerator and subtracting 3 from the denominator, (P – 8 + 3)/(P – 3) = 3/4.
(P – 5)/(P – 3) = 3/4
P = 20 – 9 => P = 11.
The fraction is: 3/11.Incorrect
The denominator be P, the numerator will be (P – 8).
The fraction will be (P – 8)/P.
Adding 3 to the numerator and subtracting 3 from the denominator, (P – 8 + 3)/(P – 3) = 3/4.
(P – 5)/(P – 3) = 3/4
P = 20 – 9 => P = 11.
The fraction is: 3/11. 
Question 34 of 50
34. Question
There were two candidates in an election. Winner candidate received 62% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate?
Correct
W = 62% L = 38%
62% – 38% = 24%
24% ——– 288
62% ——– ? => 744Incorrect
W = 62% L = 38%
62% – 38% = 24%
24% ——– 288
62% ——– ? => 744 
Question 35 of 50
35. Question
(49^{2} * 18^{2}) / 324 = ?
Correct
(49^{2} * 324) / 324 = 49^{2}
Incorrect
(49^{2} * 324) / 324 = 49^{2}

Question 36 of 50
36. Question
Thirty men can do a work in 24 days. In how many days can 20 men can do the work, given that the time spent per day is increased by onethird of the previous time?
Correct
Let the number of hours working per day initially be x. we have M_{1} D_{1} H_{1}= M_{2} D_{2} H_{2}
30 * 24 * x = 20 * d_{2} * (4x)/3 => d_{2} = (30 * 24 * 3)/(24 * 4) = 27 days.Incorrect
Let the number of hours working per day initially be x. we have M_{1} D_{1} H_{1}= M_{2} D_{2} H_{2}
30 * 24 * x = 20 * d_{2} * (4x)/3 => d_{2} = (30 * 24 * 3)/(24 * 4) = 27 days. 
Question 37 of 50
37. Question
60% of a number is added to 120, the result is the same number. Find the number?
Correct
(60/100) * X + 120 = X
2X = 600
X = 300Incorrect
(60/100) * X + 120 = X
2X = 600
X = 300 
Question 38 of 50
38. Question
Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together?
Correct
LCM = 300/60 = 5 min
Incorrect
LCM = 300/60 = 5 min

Question 39 of 50
39. Question
A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?
Correct
5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 daysIncorrect
5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 days 
Question 40 of 50
40. Question
If 5 men and 2 boys working together, can do four times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time?
Correct
5M + 2B = 4(1M + 1B)
5M + 2B = 4M + 4B
1M = 2B
The required ratio of work done by a man and a boy = 2:1Incorrect
5M + 2B = 4(1M + 1B)
5M + 2B = 4M + 4B
1M = 2B
The required ratio of work done by a man and a boy = 2:1 
Question 41 of 50
41. Question
³√216400 + √280 + √322 = ?
Correct
³√216400 + √280 + √322
= 60 + 16.5 + 18 = 94.5 = 95Incorrect
³√216400 + √280 + √322
= 60 + 16.5 + 18 = 94.5 = 95 
Question 42 of 50
42. Question
Two trains, each 100 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is?
Correct
Let the speed of the slower train be x m/sec.
Then, speed of the train = 2x m/sec.
Relative speed = ( x + 2x) = 3x m/sec.
(100 + 100)/8 = 3x => x = 25/3.
So, speed of the faster train = 50/3 = 50/3 * 18/5 = 60 km/hr.Incorrect
Let the speed of the slower train be x m/sec.
Then, speed of the train = 2x m/sec.
Relative speed = ( x + 2x) = 3x m/sec.
(100 + 100)/8 = 3x => x = 25/3.
So, speed of the faster train = 50/3 = 50/3 * 18/5 = 60 km/hr. 
Question 43 of 50
43. Question
Two trains 121 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
Correct
T = (121 + 165)/ (80 + 65) * 18/5
T = 7.15Incorrect
T = (121 + 165)/ (80 + 65) * 18/5
T = 7.15 
Question 44 of 50
44. Question
I. a^{2} – 7a + 12 = 0,
II. b^{2} – 3b + 2 = 0 to solve both the equations to find the values of a and b?Correct
I.(a – 3)(a – 4) = 0
=> a = 3, 4
II. (b – 2)(b – 1) = 0
=> b = 1, 2
=> a > bIncorrect
I.(a – 3)(a – 4) = 0
=> a = 3, 4
II. (b – 2)(b – 1) = 0
=> b = 1, 2
=> a > b 
Question 45 of 50
45. Question
Find the number of ways of arranging the letters of the word “MATERIAL” such that all the vowels in the word are to come together?
Correct
In the word, “MATERIAL” there are three vowels A, I, E.
If all the vowels are together, the arrangement is MTRL’AAEI’.
Consider AAEI as one unit. The arrangement is as follows.
M T R L A A E I
The above 5 items can be arranged in 5! ways and AAEI can be arranged among themselves in 4!/2! ways.
Number of required ways of arranging the above letters = 5! * 4!/2!
= (120 * 24)/2 = 1440 ways.Incorrect
In the word, “MATERIAL” there are three vowels A, I, E.
If all the vowels are together, the arrangement is MTRL’AAEI’.
Consider AAEI as one unit. The arrangement is as follows.
M T R L A A E I
The above 5 items can be arranged in 5! ways and AAEI can be arranged among themselves in 4!/2! ways.
Number of required ways of arranging the above letters = 5! * 4!/2!
= (120 * 24)/2 = 1440 ways. 
Question 46 of 50
46. Question
All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
Correct
B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k – 5k = 3k.
Quantity of water in container C = 8k – 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k – 148 = 3k + 148 => 2k = 296 => k = 148
The initial quantity of water in A = 8k = 8 * 148 = 1184 liters.Incorrect
B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k – 5k = 3k.
Quantity of water in container C = 8k – 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k – 148 = 3k + 148 => 2k = 296 => k = 148
The initial quantity of water in A = 8k = 8 * 148 = 1184 liters. 
Question 47 of 50
47. Question
The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
Correct
Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) – (6 * 3) – 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5 = Rs. 4530Incorrect
Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) – (6 * 3) – 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5 = Rs. 4530 
Question 48 of 50
48. Question
If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is:
Correct
Let C.P. of each pen be Re. 1.
Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.
Gain % = 4/8 * 100 = 50%Incorrect
Let C.P. of each pen be Re. 1.
Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.
Gain % = 4/8 * 100 = 50% 
Question 49 of 50
49. Question
A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
Correct
10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050 = 450Incorrect
10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050 = 450 
Question 50 of 50
50. Question
If 35% of a number is 12 less than 50% of that number, then the number is?
Correct
Let the number be x. Then,
50% of x – 35% of x = 12
50/100 x – 35/100 x = 12
x = (12 * 100)/15 = 80.Incorrect
Let the number be x. Then,
50% of x – 35% of x = 12
50/100 x – 35/100 x = 12
x = (12 * 100)/15 = 80.