## SEBI Online Test in English Series 3, SEBI Online Mock Test 3

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**SEBI Online Test in English Series 3, SEBI Online Mock Test 3,** SEBI Free Online Test Series 3. RRB Exam Online Test 2019, SEBI Free Mock Test Exam 2019. SEBI Exam Free Online Quiz 2019, SEBI Full Online Mock Test **Series 3rd** in English. RRB Online Test for All Subjects, SEBI Free Mock Test Series in English. SEBI Free Mock Test **Series 3.** SEBI English Language Online Test in English **Series 3rd**. SEBI Quantitative Aptitude Quiz 2019, SEBI Reasoning Ability Free Online Test. Take SEBI Online Quiz. The SEBI Full online mock test paper is free for all students. SEBI Question and Answers in English and Hindi **Series 3**. Here we are providing** SEBI Full Mock Test Paper in English. SEBI **Mock Test **Series 3rd** 2019. Now Test your self for SEBI Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?

CorrectSpeed = 144 * 5/18 = 40 m/sec

Time taken = 100/40 = 2.5 sec.IncorrectSpeed = 144 * 5/18 = 40 m/sec

Time taken = 100/40 = 2.5 sec. - Question 2 of 50
##### 2. Question

A certain sum amounts to Rs.1725 in 3 years and Rs.1875 in 5 years. Find the rate % per annum?

Correct3 — 1725

5 — 1875

————–

2 — 150

N = 1 I = 75 R = ?

P = 1725 – 225 = 1500

75 = (1500*1*R)/100

R = 5%Incorrect3 — 1725

5 — 1875

————–

2 — 150

N = 1 I = 75 R = ?

P = 1725 – 225 = 1500

75 = (1500*1*R)/100

R = 5% - Question 3 of 50
##### 3. Question

Find the area of a parallelogram with base 24 cm and height 16 cm.

CorrectArea of a parallelogram = base * height = 24 * 16 = 384 cm

^{2}IncorrectArea of a parallelogram = base * height = 24 * 16 = 384 cm

^{2} - Question 4 of 50
##### 4. Question

Twelve men and six women together can complete a piece of work in four days. The work done by a women in one day is half the work done by a man in one day. If 12 men and six women started working and after two days, six men left and six women joined, then in hoe many more days will the work be completed?

CorrectWork done by a women in one day = 1/2 (work done by a man/day)

One women’s capacity = 1/2(one man’s capacity)

One man = 2 women.

12 men = 24 women.

12 men + 6 women = 30 women

30 women can complete the work in four days. In the first 2 days they can complete 1/2 of the work. Remaining part of the work = 1/2. If 6 men leave and 6 new women join, then new work force = 30 women – 12 women + 6 women = 24 women.

Time taken by them to complete the remaining work = 1/2 (Time taken by 24 women to complete the work) = 1/2 * (30 * 4)/24 = 2 (1/2) days.IncorrectWork done by a women in one day = 1/2 (work done by a man/day)

One women’s capacity = 1/2(one man’s capacity)

One man = 2 women.

12 men = 24 women.

12 men + 6 women = 30 women

30 women can complete the work in four days. In the first 2 days they can complete 1/2 of the work. Remaining part of the work = 1/2. If 6 men leave and 6 new women join, then new work force = 30 women – 12 women + 6 women = 24 women.

Time taken by them to complete the remaining work = 1/2 (Time taken by 24 women to complete the work) = 1/2 * (30 * 4)/24 = 2 (1/2) days. - Question 5 of 50
##### 5. Question

Find the one which does not belong to that group ?

Correct3, 5, 9 and 7 are odd numbers, but not 4.

Incorrect3, 5, 9 and 7 are odd numbers, but not 4.

- Question 6 of 50
##### 6. Question

A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in?

Correct(A + B + C)’s 1 day work = 1/6;

(A + B)’s 1 day work = 1/8

(B + C)’s 1 day work = 1/12

(A + C)’s 1 day work = (2 * 1/6) – (1/8 + 1/12)

= (1/3 – 5/24) = 1/8

So, A and C together will do the work in 8 days.Incorrect(A + B + C)’s 1 day work = 1/6;

(A + B)’s 1 day work = 1/8

(B + C)’s 1 day work = 1/12

(A + C)’s 1 day work = (2 * 1/6) – (1/8 + 1/12)

= (1/3 – 5/24) = 1/8

So, A and C together will do the work in 8 days. - Question 7 of 50
##### 7. Question

What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high?

Correctd

^{2}= 12^{2}+ 4^{2}+ 3^{2}= 13Incorrectd

^{2}= 12^{2}+ 4^{2}+ 3^{2}= 13 - Question 8 of 50
##### 8. Question

7394 – 1236 – 4652 = ?

CorrectIncorrect - Question 9 of 50
##### 9. Question

The average salary per head of the entire staff of an office including the officers and clerks is Rs.90. The average salary of officers is Rs.600 and that of the clerks is Rs.84. If the number of officers is 2, find the number of officers in the office?

CorrectIncorrect - Question 10 of 50
##### 10. Question

Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in.

CorrectThe part of the tank filled by three pipes in one hour = 1/8

=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.

The tank can be filled in 12 hours.IncorrectThe part of the tank filled by three pipes in one hour = 1/8

=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.

The tank can be filled in 12 hours. - Question 11 of 50
##### 11. Question

If x;Y = 5:2, then (8x + 9y):(8x + 2y) is :

CorrectLet x = 5k and y = 2k.

Then, (8x + 9y)/(8x + 2y)

= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22

(8x + 9y):(8x + 2y) = 29:22IncorrectLet x = 5k and y = 2k.

Then, (8x + 9y)/(8x + 2y)

= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22

(8x + 9y):(8x + 2y) = 29:22 - Question 12 of 50
##### 12. Question

A man can do a job in 15 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together?

Correct1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300

So, all three together will complete the work in 300/47 = 6.4 days.-Incorrect1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300

So, all three together will complete the work in 300/47 = 6.4 days.- - Question 13 of 50
##### 13. Question

Find the one which does not belong to that group ?

CorrectCrocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.

IncorrectCrocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.

- Question 14 of 50
##### 14. Question

Product of two co-prime numbers is 117. Their L.C.M should be:

CorrectH.C.F of co-prime numbers is 1.

So, L.C.M = 117/1 = 117.IncorrectH.C.F of co-prime numbers is 1.

So, L.C.M = 117/1 = 117. - Question 15 of 50
##### 15. Question

If the price has fallen by 10% what percent of its consumption be: increased so that the expenditure may be the same as before?

Correct100 – 10 = 90

90——10

100——? => 11 1/9%Incorrect100 – 10 = 90

90——10

100——? => 11 1/9% - Question 16 of 50
##### 16. Question

A man gets a simple interest of Rs.500 on a certain principal at the rate of 5% p.a in two years. Find the compound interest the man will get on twice the principal in two years at the same rate.

CorrectLet the principal be Rs.P

S.I at 5% p.a in 8 years on Rs.P = Rs.500

(P)(8)(5)/100 = 500

P = 1250

C.I on Rs.2P i.e., Rs.2500 at 5% p.a in two years

=2500{ [1 + 5/100]^{2}– 1} = 2500{ 21^{2}– 20^{2}/20^{2}}

= 2500/400(441 – 400)

= 25/4(41) = 1025/4 = Rs.256.25IncorrectLet the principal be Rs.P

S.I at 5% p.a in 8 years on Rs.P = Rs.500

(P)(8)(5)/100 = 500

P = 1250

C.I on Rs.2P i.e., Rs.2500 at 5% p.a in two years

=2500{ [1 + 5/100]^{2}– 1} = 2500{ 21^{2}– 20^{2}/20^{2}}

= 2500/400(441 – 400)

= 25/4(41) = 1025/4 = Rs.256.25 - Question 17 of 50
##### 17. Question

The ratio of the volumes of a cube to that of the sphere which will fit inside the cube is?

Correcta

^{3}: a^{3}/8 * 4/3 π => 6: πIncorrecta

^{3}: a^{3}/8 * 4/3 π => 6: π - Question 18 of 50
##### 18. Question

What annual payment will discharge a debt of Rs. 1025 due in 2 years at the rate of 5% compound interest?

CorrectLet each installment be Rs. x. Then,

x/(1 + 5/100) + x/(1 + 5/100)^{2}= 1025

820x + 1025 * 441

x = 551.25

So, value of each installment = Rs. 551.25IncorrectLet each installment be Rs. x. Then,

x/(1 + 5/100) + x/(1 + 5/100)^{2}= 1025

820x + 1025 * 441

x = 551.25

So, value of each installment = Rs. 551.25 - Question 19 of 50
##### 19. Question

The area of a sector of a circle of radius 5 cm formed by an arc of length 3.5 cm is?

Correct(5 * 3.5)/2 = 8.75

Incorrect(5 * 3.5)/2 = 8.75

- Question 20 of 50
##### 20. Question

Find the fraction which has the same ratio to 2/13 that 5/34 has to 7/48.

CorrectP : 2/13 = 5/34 : 7/48

As the product of the means is equal to the product of the extremes.

P*7/48 = 2/13 * 5/34

P*7/48 = 10/442

P = 480/3094 => P = 240/1547IncorrectP : 2/13 = 5/34 : 7/48

As the product of the means is equal to the product of the extremes.

P*7/48 = 2/13 * 5/34

P*7/48 = 10/442

P = 480/3094 => P = 240/1547 - Question 21 of 50
##### 21. Question

A, B and C can do a piece of work in 7 days, 14 days and 28 days respectively. How long will they taken, if all the three work together?

Correct1/7 + 1/14 + 1/28 = 7/28 = 1/4 => 4 days

Incorrect1/7 + 1/14 + 1/28 = 7/28 = 1/4 => 4 days

- Question 22 of 50
##### 22. Question

The third proportional to 1 and 2 is?

Correct(2*2)/1 = 4

Incorrect(2*2)/1 = 4

- Question 23 of 50
##### 23. Question

I. a

^{3}– 988 = 343,

II. b^{2}– 72 = 49 to solve both the equations to find the values of a and b?Correcta

^{3}= 1331 => a = 11

b^{2}= 121 => b = ± 11

a ≥ bIncorrecta

^{3}= 1331 => a = 11

b^{2}= 121 => b = ± 11

a ≥ b - Question 24 of 50
##### 24. Question

Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are:

CorrectLet the required numbers be x, 2x and 3x. Then, their H.C.F = x. So, x = 12.

The numbers are 12, 24, 36.IncorrectLet the required numbers be x, 2x and 3x. Then, their H.C.F = x. So, x = 12.

The numbers are 12, 24, 36. - Question 25 of 50
##### 25. Question

A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is:

CorrectSuppose he has 100 items. Let C.P. of each item be Re. 1.

Total cost = Rs. 100. Number of items left after theft = 80.

S.P. of each item = Rs. 1.10

Total sale = 1.10 * 80 = Rs. 88

Hence, loss % = 12/100 * 100 = 12%IncorrectSuppose he has 100 items. Let C.P. of each item be Re. 1.

Total cost = Rs. 100. Number of items left after theft = 80.

S.P. of each item = Rs. 1.10

Total sale = 1.10 * 80 = Rs. 88

Hence, loss % = 12/100 * 100 = 12% - Question 26 of 50
##### 26. Question

The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of time will they come together in the same position?

CorrectTime for one revolution = 60/15 = 4

60/ 20 = 3

60/48 = 5/4

LCM of 4, 3, 5/4

LCM of Numerators/HCF of Denominators =

60/1 = 60IncorrectTime for one revolution = 60/15 = 4

60/ 20 = 3

60/48 = 5/4

LCM of 4, 3, 5/4

LCM of Numerators/HCF of Denominators =

60/1 = 60 - Question 27 of 50
##### 27. Question

If x = √196 + √200, then x/2 + 2/x is?

Correctx = 14 + 10√2

x/2 = 7 + 5√2

2/x = (7 – 5√2) / (7 + 5√2)(7 – 5√2) = 5√2 – 7

x/2 + 2/x = 10√2 = 2√50Incorrectx = 14 + 10√2

x/2 = 7 + 5√2

2/x = (7 – 5√2) / (7 + 5√2)(7 – 5√2) = 5√2 – 7

x/2 + 2/x = 10√2 = 2√50 - Question 28 of 50
##### 28. Question

Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

CorrectSuppose they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x – 1) hours = 25(x – 1) km.

Therefore 20x + 25(x – 1) = 110

45x = 135

x = 3.

So, they meet at 10 a.m.IncorrectSuppose they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x – 1) hours = 25(x – 1) km.

Therefore 20x + 25(x – 1) = 110

45x = 135

x = 3.

So, they meet at 10 a.m. - Question 29 of 50
##### 29. Question

If the sum of one-half of a number exceeds one-third of that number by 7 1/3, the number is:

CorrectLet the number be x. Then,

(1/2 x + 1/5 x) – 1/3 x = 22/3

11/30 x = 22/3

x = 20IncorrectLet the number be x. Then,

(1/2 x + 1/5 x) – 1/3 x = 22/3

11/30 x = 22/3

x = 20 - Question 30 of 50
##### 30. Question

The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:

CorrectLet A, B, C represent their respective weights.

Then, we have:

A + B + C = (45 * 3) = 135 — (i)

A + B = (40 * 2) = 80 — (ii)

B + C = (43 * 2) = 86 — (iii)

Adding (ii) and (iii), we get: A + 2B + C = 166 — (iv)

Subtracting (i) from (iv), we get: B = 31

B’s weight = 31 kg.IncorrectLet A, B, C represent their respective weights.

Then, we have:

A + B + C = (45 * 3) = 135 — (i)

A + B = (40 * 2) = 80 — (ii)

B + C = (43 * 2) = 86 — (iii)

Adding (ii) and (iii), we get: A + 2B + C = 166 — (iv)

Subtracting (i) from (iv), we get: B = 31

B’s weight = 31 kg. - Question 31 of 50
##### 31. Question

In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case?

CorrectAssume X soldiers join the fort. 1200 soldiers have provision for 1200(days for which provisions last them)(rate of consumption of each soldier)

= 1200(30)(3) kg

Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg

As the same provisions are available

=> 1200(30)(3) = (1200 + x)(25)(2.5)

x = [1200(30)(3)]/[(25)(2.5)] – 1200

x = 528IncorrectAssume X soldiers join the fort. 1200 soldiers have provision for 1200(days for which provisions last them)(rate of consumption of each soldier)

= 1200(30)(3) kg

Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg

As the same provisions are available

=> 1200(30)(3) = (1200 + x)(25)(2.5)

x = [1200(30)(3)]/[(25)(2.5)] – 1200

x = 528 - Question 32 of 50
##### 32. Question

Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?

CorrectSI = 40 + 40

CI = 40 + 40 + 1.6 = 81.6IncorrectSI = 40 + 40

CI = 40 + 40 + 1.6 = 81.6 - Question 33 of 50
##### 33. Question

√3584 * 52.034 = ?

Correct√3600 * 52 = ?

=> ? = 60 * 52 = 3120Incorrect√3600 * 52 = ?

=> ? = 60 * 52 = 3120 - Question 34 of 50
##### 34. Question

On dividing number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder?

CorrectLet x be the number and y be the quotient.

Then, x = 357 * y + 39

= (17 * 21 * y) + (17 * 2) + 5

= 17 * (21y + 2) + 5.

Required remainder = 5.IncorrectLet x be the number and y be the quotient.

Then, x = 357 * y + 39

= (17 * 21 * y) + (17 * 2) + 5

= 17 * (21y + 2) + 5.

Required remainder = 5. - Question 35 of 50
##### 35. Question

The tens digit of a two-digit number is two more than its unit digit. The two-digit number is 7 times the sum of the digits. Find the units digits?

CorrectLet the two-digit number be 10a + b

a = b + 2 — (1)

10a + b = 7(a + b) => a = 2b

Substituting a = 2b in equation (1), we get

2b = b + 2 => b = 2

Hence the units digit is: 2.IncorrectLet the two-digit number be 10a + b

a = b + 2 — (1)

10a + b = 7(a + b) => a = 2b

Substituting a = 2b in equation (1), we get

2b = b + 2 => b = 2

Hence the units digit is: 2. - Question 36 of 50
##### 36. Question

A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 75, the runs scored by B are?

CorrectA:B = 2:3

B:C = 2:5

A:B:C = 4:6:15

6/25 * 75 = 18IncorrectA:B = 2:3

B:C = 2:5

A:B:C = 4:6:15

6/25 * 75 = 18 - Question 37 of 50
##### 37. Question

How many numbers up to 300 and 700 are divisible by 2, 3 and 7 both together?

Correct(700 – 300)/42 = 9 22/42 => 9 Numbers

Incorrect(700 – 300)/42 = 9 22/42 => 9 Numbers

- Question 38 of 50
##### 38. Question

The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?

CorrectP = 144(100/5)

^{2}=> P = 3600IncorrectP = 144(100/5)

^{2}=> P = 3600 - Question 39 of 50
##### 39. Question

Nitin’s salary is reduced by 10% and then reduced salary is increased by 10%. Find ,how many percentage his present salary is less as compared to his previous salary?

Correct10*10

——– = 1%

100Incorrect10*10

——– = 1%

100 - Question 40 of 50
##### 40. Question

The bus fare for two persons for travelling between Agra and Aligarh id four-thirds the train fare between the same places for one person. The total fare paid by 6 persons travelling by bus and 8 persons travelling by train between the two places is Rs.1512. Find the train fare between the two places for one person?

CorrectLet the train fare between the two places for one person be Rs.t

Bus fare between the two places for two persons Rs.4/3 t

=> 6/2 (4/3 t) + 8(t) = 1512

=> 12t = 1512 => t = 126.IncorrectLet the train fare between the two places for one person be Rs.t

Bus fare between the two places for two persons Rs.4/3 t

=> 6/2 (4/3 t) + 8(t) = 1512

=> 12t = 1512 => t = 126. - Question 41 of 50
##### 41. Question

The triplicate ratio of 1:2 is?

Correct1

^{3}: 2^{3}= 1:8Incorrect1

^{3}: 2^{3}= 1:8 - Question 42 of 50
##### 42. Question

12(13/18) + 16(11/27) – 10(5/9) = ?

Correct12 + 16 – 10 = 18

and 13/18 + 11/27 – 5/9 = (39 + 22 – 30)/(9 * 2 * 3) = 31/54 The answer is 18 (31/54)Incorrect12 + 16 – 10 = 18

and 13/18 + 11/27 – 5/9 = (39 + 22 – 30)/(9 * 2 * 3) = 31/54 The answer is 18 (31/54) - Question 43 of 50
##### 43. Question

Find the nearest to 25268 which is exactly divisible by 467?

CorrectIncorrect - Question 44 of 50
##### 44. Question

A mixture of 70 liters of wine and water contains 10% water. How much water must be added to make water 12 ½% of the total mixture?

Correct70 * (10/100) = 7

Wine Water

87 1/2% 12 1/2%

87 1/2% ——- 63

12 1/2% ——-? => 9-7=2Incorrect70 * (10/100) = 7

Wine Water

87 1/2% 12 1/2%

87 1/2% ——- 63

12 1/2% ——-? => 9-7=2 - Question 45 of 50
##### 45. Question

How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?

CorrectLet length of tunnel is x meter

Distance = 800+x meter

Time = 1 minute = 60 seconds

Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s

Distance = Speed*Time

800+x = (65/3) * 60

800+x = 20 * 65 = 1300

x = 1300 – 800 = 500 metersIncorrectLet length of tunnel is x meter

Distance = 800+x meter

Time = 1 minute = 60 seconds

Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s

Distance = Speed*Time

800+x = (65/3) * 60

800+x = 20 * 65 = 1300

x = 1300 – 800 = 500 meters - Question 46 of 50
##### 46. Question

The number of permutations of the letters of the word ‘MESMERISE’ is_.

Correctn items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.

The letter pattern ‘MESMERISE’ consists of 10 letters of which there are 2M’s, 3E’s, 2S’s and 1I and 1R.

Number of arrangements = 9!/(2!)^{2}3!Incorrectn items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.

The letter pattern ‘MESMERISE’ consists of 10 letters of which there are 2M’s, 3E’s, 2S’s and 1I and 1R.

Number of arrangements = 9!/(2!)^{2}3! - Question 47 of 50
##### 47. Question

After 38 liters of petrol were poured into the tank, it was still 5% empty. How much petrol must be poured into the tank in order to fill it?

Correct95% ———– 38

5% ———— ? => 2 litersIncorrect95% ———– 38

5% ———— ? => 2 liters - Question 48 of 50
##### 48. Question

A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?

CorrectSpeed of the train relative to man = 125/10 = 25/2 m/sec.

= 25/2 * 18/5 = 45 km/hr

Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.

x – 5 = 45 => x = 50 km/hr.IncorrectSpeed of the train relative to man = 125/10 = 25/2 m/sec.

= 25/2 * 18/5 = 45 km/hr

Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.

x – 5 = 45 => x = 50 km/hr. - Question 49 of 50
##### 49. Question

The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:

CorrectSpeed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.

IncorrectSpeed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.

- Question 50 of 50
##### 50. Question

If the cost price of 50 articles is equal to the selling price of 40 articles, then the gain or loss percent is?

CorrectGiven that, cost price of 50 article is equal to selling price of 40 articles.

Let cost price of one article = Rs. 1

Selling price of 40 articles = Rs. 50

But Cost price of 40 articles = Rs. 40

Therefore, the trader made profit.\Percentage of profit = 10/40 * 100 = 25%IncorrectGiven that, cost price of 50 article is equal to selling price of 40 articles.

Let cost price of one article = Rs. 1

Selling price of 40 articles = Rs. 50

But Cost price of 40 articles = Rs. 40

Therefore, the trader made profit.\Percentage of profit = 10/40 * 100 = 25%